As the speed of the car was less than the posted speed limit of 50 mi/h when the brakes were applied, skid marks provide evidence that driver was not speeding at the time of incident.
What is meant by coefficient of friction?Measure of the amount of friction existing between the two surfaces is called as coefficient of friction.
Change in kinetic energy is: ΔK = 0 - 1/2mv²
W = fd
As f = μN
N = mg
fd = ΔK
μN d = 1/2mv²
μmgd = 1/2mv²
v = √(2μgd/m)
v = √(20.8025*0.45/1) ≈ 29.9 mi/h
Since the car's speed was less than the posted speed limit of 50 mi/h when the brakes were applied, the skid marks provide evidence that the driver was not speeding at the time of the incident.
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What is the wavelength (in nm) of maximum intensity for a celestial body with a temperature of 50000 K?
The wavelength of maximum intensity for a celestial body with a temperature of 50000 K is approximately 577 nm.
What is wavelength?To find the wavelength of maximum intensity for a celestial body with a temperature of 50000 K, we can use Wien's displacement law, which relates the temperature of an object to the wavelength at which it emits the most radiation. The law is given by:
λ_max = b / T
where λ_max is the wavelength of maximum intensity, b is Wien's displacement constant (2.898 × 10⁻³ m·K), and T is the temperature in Kelvin.
We can convert the temperature of 50000 K to Kelvin by adding 273.15 to get:
T = 50000 K + 273.15 = 50273.15 K
Plugging in the values, we get:
λ_max = (2.898 × 10⁻³ m·K) / 50273.15 K
Simplifying, we get:
λ_max = 5.77 × 10⁻⁸ meters
To convert meters to nanometers, we can multiply by 10⁹:
λ_max = 5.77 × 10⁻⁸ meters × 10⁹ nm/m = 577 nm
Therefore, the wavelength of maximum intensity for a celestial body with a temperature of 50000 K is approximately 577 nm.
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As we've discussed, one model of material deformation links stress and strain by a material constant called a modulus. For a material under lengthwise stress (tension or compression), this is Young’s modulus (Y) and the relation may be stated as:
The data below was collected for five different materials using tools which allowed for the direct measurement of the stress and strain. By applying the model above, rank the Young’s modulus for each of these five materials from largest to smallest.
Young’s modulus for each of these five materials from largest to smallest are mentioned below.
What is Young’s modulus?
Many substances lack linearity and elasticity after very minor deformation. Only materials that are linearly elastic are subject to the constant Young's modulus. In this case, the ratio of stress to strain, which corresponds to the material's stress, determines the Young's modulus.
What is data?
Facts such as numbers, words, measurements, observations, or even simple descriptions of objects are grouped together as data. Both qualitative and quantitative data are possible. Qualitative data is information that is descriptive (describes something), whereas discrete data can only take particular values (like whole numbers).
Therefore, Young’s modulus for each of these five materials from largest to smallest are mentioned above.
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3. A shaft of 100 mm diameter rotates at 120 rad/s in a bearing 150 mm long. If the dial clearance is 0-2 mm and the absolute viscosity of the lubricant is 20 kg/ms find the power loss in the bearing.
The power loss in the bearing is 1.36 W shaft of 100 mm diameter rotates at 120 rad/s in a bearing 150 mm long.
What is viscosity?The viscosity of a fluid is a measure of its resistance to flow. A fluid with a high viscosity resists movement because its molecular structure causes a lot of internal friction.
The viscosity of a fluid is a measure of its resistance to flow. A fluid with a high viscosity resists movement because its molecular structure causes a lot of internal friction.
To calculate the power loss in the bearing, we can use the formula:
P = F × V
To calculate the frictional force, we can use the formula:
F = μ × A × P
Where μ is the coefficient of friction, A is the area of the bearing, and P is the pressure of the lubricant.
First, we need to calculate the pressure of the lubricant:
P = μ × Viscosity × (V/D)
Where D is the diameter of the shaft.
P = (0.02) × 20 × (120/0.1) = 480 N/[tex]m^2[/tex]
Next, we can calculate the area of the bearing:
A = π × (D/2)^2 × L
Where L is the length of the bearing.
A = π × (0.1/2)^2 × 0.15 = 0.001178 [tex]m^2[/tex]
Now we can calculate the frictional force:
F = μ × A × P = (0.02) × 0.001178 × 480 = 0.0113 N
Finally, we can calculate the power loss:
P = F × V = 0.0113 × 120 = 1.36 W
Therefore, the power loss in the bearing is 1.36 W.
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From the foot of a vertical cliff 28.8 m high, a stone was projected vertically upwards so as just to reach the top. Find its velocity of projection. One second after the first stone was projected, another stone was allowed to fall from rest from the top of the cliff. The stones passed one another after a further seconds at a height h m above the ground. Calculate the value of t and of h. (C)
The velocity of projection of a stone following projectile motion which is projected vertically upwards from the foot of a vertical cliff 28.8n high so as to just reach the top is 23.75 m/s
What is projectile motion?When something (a projectile) is launched towards the surface of the Earth and moves along a curved path only under the influence of gravity, it experiences projectile motion (in particular, the effects of air resistance are passive and assumed to be negligible). Galileo showed that although this curved path can also be a straight line when thrown immediately above, it is a parabola in this case.
Gravity is the sole force acting on the item that is mathematically relevant; it acts downward and accelerates the thing towards the mass of the Earth. Due to the object's inertia, the horizontal velocity component of its motion does not require any external force.
According to the equation,
H = [tex]\frac{u^{2} }{2g}[/tex]
where,
H is the maximum height,
u is the velocity of projection and,
g is the acceleration due to gravity.
substituting the values and solving for u,
velocity of projection = 23.75 m/s
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When weight training you should aim to be able to lift the weight ____ to _____ times without strain or injury but with enough resistance to give the muscles a good workout. 1 to 3 30 to 40 8 to 12 Show
What type of wave is:
a) Light
b) Sound
Answer:
Explanation:
a) transverse
b)longitudinal waves
I can’t figure it out
Answer:
Explanation: In anyway can you get a better picture just a close picture i cant read it
A 2,600 kg SUV traveling west at 15 m/s collides head on with a 1,300 kg four door sedan traveling east at 20 m/s. Determine the speed and direction of the two cars immediately after impact if they lock together.
Answer:
Explanation:
From Law of conservation of momentum,
m1u1+m2u2 = m1v1+m2v2 [Law of conservation of momentum]
m1 = 2600kg
u1 = 15m/s
m2 = 1300kg
u2 = -20m/s [as it is moving in opposite direction]
here, after impact, cars lock with each other so v (final velocity) is the same for both cars, i.e., v1 = v2
(2600)(15)+(1300)(-20) = (2600)v1+(1300)v2
39000-26000 = (2600+1300)v1 [as v1 = v2]
v1 = 13000/3900
v1 = 3.33 m/s
Here, m1v1 = 2600x3.33 = 8658kgm/s
m2v2 = 1300x3.33 = 4329kgm/s
As final momentum of car 1 is higher than that of car 2, both cars will move in direction of car1, that is, west direction.
Urgent!!!
Two students are testing out the law of conservation of momentum, by throwing balls of clay so that they collide. One student throws a 535g ball north at 12.4 m/s. The other throws a 725g ball south at 6.4 m/s. When the two balls of clay collide and form a single unit, what is the velocity of the combined unit?
1.86 m/s south
8.74 m/s north
1.86 m/s north
8.74 m/s south
Answer:
To solve this problem, we need to use the law of conservation of momentum, which states that the total momentum before a collision is equal to the total momentum after the collision.
The momentum of an object is given by its mass multiplied by its velocity, so we can calculate the initial momentum of each ball before the collision:
- The northbound ball has a momentum of 535g * 12.4 m/s = 6644 g*m/s north
- The southbound ball has a momentum of 725g * (-6.4 m/s) = -4640 g*m/s north (note that the negative sign indicates southward direction)
Adding these momenta together, we get a total momentum of 6644 g*m/s - 4640 g*m/s = 2004 g*m/s north.
After the collision, the two clay balls stick together and move as a single unit. Let's call the mass of the combined unit "M" and its velocity "v". By conservation of momentum, we know that the total momentum of the combined unit after the collision must be the same as the total momentum before:
M * v = 2004 g*m/s north
To solve for v, we need to figure out the mass of the combined unit. This is simply the sum of the masses of the two original balls:
M = 535g + 725g = 1260g
Substituting this into the equation above, we get:
1260g * v = 2004 g*m/s north
Solving for v, we get:
v = 1.59 m/s north
Therefore, the combined unit moves 1.59 m/s north after the collision.
However, the answer choices given in the problem are in meters per second, not meters per second north/south. To convert the answer, we need to add a direction. Recall that the northbound ball had a positive velocity and the southbound ball had a negative velocity. Since the combined unit is moving northward, we know its velocity must be positive.
Therefore, the final answer is 1.59 m/s north, which corresponds to answer choice C.
If you stretched a rubber band so that it had 100-J of potential energy, with how much kinetic energy will the rock leave the slingshot?
Answer:
less than 100-J
Explanation:
The potential energy held in the stretched rubber band is turned into kinetic energy of the rock when it is released, assuming that the rubber band is used to launch a rock from a slingshot.
The mass of the rock and the effectiveness of the slingshot in transmitting the energy from the rubber band to the rock are two elements that affect how much kinetic energy the rock will have. To estimate the kinetic energy, though, we may make certain generalizations.
Assume that no energy is lost as a result of friction or air resistance and that the entire potential energy held in the rubber band is transformed into the kinetic energy of the rock. In this hypothetical situation, the potential energy of the stretched rubber band would be equal to the kinetic energy of the rock.
As a result, the rock will have 100 J of kinetic energy when it exits the slingshot if the rubber band contains 100 J of potential energy. The actual kinetic energy of the rock would be less than 100 J since some energy will be wasted owing to things like friction.
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What is one direct way in which children impact their own acculturation?
Answer: The direct way that children affect their own acculturation is by peer watching and engagement.
Answer:One direct way in which children impact their own acculturation is through language acquisition. Children who are exposed to a new culture and language at a young age have the opportunity to learn and adopt the new language and cultural norms more easily than adults. As children interact with peers and adults in the new culture and use the new language, they develop their own sense of identity and acculturation, which can be different from that of their parents or other family members. Children may also participate in cultural activities or events, such as holidays or festivals, which further shape their understanding and experience of the new culture. Overall, children can actively participate in and shape their own acculturation process through language acquisition and cultural experiences.
Explanation:
Assume that bone will fracture if a shear stress more than 9.00 × 10^7 N/m^2 is exerted. What is the maximum force that can be exerted on the femur bone in the leg if it has a minimum effective diameter of 9.00 cm ? Young’s modulus for bone is 1.8 × 10^10 N/m^2 Answer in units of kN
The area of the bone is 0.785 m². Then the maximum force that can be exerted on the femur bone if the shear stress is 9 × 10⁷ N/m² is 70650 kN.
What is young's modulus ?The Young's modulus of a material is the ratio of its stress to strain. Where stress is the force per unit area and strain be the ratio of change in length to the original length.
given stress s = 9 × 10⁷ N/m²
diameter of the bone d = 9 cm = 0.09 m.
then area = π d²/4
a = 3.14 × (0.09 m )²/4 = 0.785 m².
Stress = maximum force/area
then Fmax = stress × area
Fmax = 9 × 10⁷ N/m² × 0.785 m²
= 70650 kN.
Therefore, the maximum force that can be exerted to the bone is 70650 kN.
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a. Make a drawing of the electric field lines around a positive charge, then make a second drawing of the electric field lines around a negative charge. (1 point)
A drawing of the electric field lines around a positive charge, then make a second drawing of the electric field lines around a negative charge is mentioned below.
What is electric field ?
According to mathematics, the electric field is described as a vector field that may be connected to each point in space and represents the force per unit charge that is applied to a positive test charge that is at rest at that location. Either the electric charge or time-varying magnetic fields can produce an electric field.
What is electric charge ?
The physical quality of matter—its electric charge—is what causes it to feel a force when exposed to an electromagnetic field. Protons and electrons, the two types of charge carriers, typically carry positive and negative electric charges. Charges moving through a system produce energy.
Therefore, A drawing of the electric field lines around a positive charge, then make a second drawing of the electric field lines around a negative charge is mentioned above.
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a charged cloud system produces an electric field in the air near the earth surface. When a particle (q=-2.0x10-9)is acted on by a downward electrostatic force of 3.0x10^-6 N when placed in this field, determine the magnitude of the electric field
The magnitude of the electrical field would be 1.5x10^3 N/C.
Electrical field calculationThe electrostatic force experienced by a charged particle in an electric field is given by the formula:
F = qE
Where F is the electrostatic force, q is the charge of the particle, and E is the electric field strength.
In this case, the electrostatic force acting on the particle is 3.0x10^-6 N and the charge of the particle is -2.0x10^-9 C. So we have:
3.0x10^-6 N = (-2.0x10^-9 C)E
Solving for E, we get:
E = (3.0x10^-6 N) / (-2.0x10^-9 C)
E = -1.5x10^3 N/C
Since the electric field is a vector quantity, its magnitude is always positive. Therefore, the magnitude of the electric field in this case is:
|E| = 1.5x10^3 N/C
So the magnitude of the electric field is 1.5x10^3 N/C, directed downward.
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a rock rolling down a slope from rest covers a distance of 4 m in the first second. What distance will it covers in 3 sec?
Answer: 12 meters
Explanation:
the rate is 4 meters per second
the rock rolled for 3 seconds
4 x 3 = 12
How much kinetic energy does a 2.50kg ball traveling at 2.00m/s have?
Answer:
Explanation:
The formula for kinetic energy is K = 1/2mv^2, where K is kinetic energy, m is mass, and v is velocity.
Substituting the given values:
K = 1/2(2.50 kg)(2.00 m/s)^2
K = 1/2(2.50 kg)(4.00 m^2/s^2)
K = 5.00 J
Therefore, the 2.50kg ball traveling at 2.00m/s has 5.00 J of kinetic energy.
A person can jump a horizontal distance of 1.31 m on the Earth. The acceleration of gravity is 12.3 m/s^2.
a) How far could he jump on the Moon, where the free-fall acceleration is 0.258g Answer in units of m.
b) Repeat for Mars, where the acceleration due to gravity is 0.293g. Answer in units of m.
Answer:
a) On the Moon, where the acceleration due to gravity is 0.258g:
First, we need to find the acceleration due to gravity on the Moon:
g_Moon = 0.258g_Earth
g_Moon = 0.258(12.3 m/s^2)
g_Moon = 3.17 m/s^2
Now we can use the range formula for projectile motion to find the distance he could jump:
R = (v^2/g) sin(2θ)
Assuming the same initial velocity and angle of jump, we can rearrange the formula to solve for R:
R = (v^2/g) sin(^2/g_Earth) sin(2θ) * (g_Moon/g_Earth)
R = (1.31 m)^2/ (212.3 m/s^2) * sin(2θ) * (3.17 m/s^2) / (12.3 m/s^2)
R = 0.191 m
Therefore, he could jump approximately 0.191 m on the Moon.
!
a) On the Moon, where the acceleration due to gravity is 0.258g:
First, we need to find the acceleration due to gravity on the Moon:
g_Moon = 0.258g_Earth
g_Moon = 0.258(12.3 m/s^2)
g_Moon = 3.17 m/s^2
Now we can use the range formula for projectile motion to find the distance he could jump:
R = (v^2/g) sin(2θ)
Assuming the same initial velocity and angle of jump, we can rearrange the formula to solve for R:
R = (v^2/g) sin(
network error
^2/g_Earth) sin(2θ) * (g_Moon/g_Earth)
R = (1.31 m)^2/ (212.3 m/s^2) * sin(2θ) * (3.17 m/s^2) / (12.3 m/s^2)
R = 0.191 m
Therefore, he could jump approximately 0.191 m on the Moon.
b) On Mars, where the acceleration due to gravity is 0.293g:
Similarly, we need to find the acceleration due to gravity on Mars:
g_Mars = 0.293g_Earth
g_Mars = 0.293(12.3 m/s^2)
g_Mars = 3.61 m/s^2
Using the same formula and rearrangement as in part a, we can find the distance he could jump on Mars:
R = (1.31 m)^2/ (212.3 m/s^2) * sin(2θ) * (3.61 m/s^2) / (12.3 m/s^2)
R = 0.223 m
Therefore, he could jump approximately 0.223 m on Mars.
The diameter of the asteroid Vesta is of the diameter of the planet Mercury. Mercury has a diameter of 5000 km. Calculate the diameter of Vesta. Show your working.
Answer:
5000 km
Explanation:
Sure, to calculate the diameter of Vesta, we can use the fact that Vesta's diameter is equal to the diameter of Mercury, which is 5000 km.
Therefore, the diameter of Vesta is also 5000 km.
We can show the working by using the following formula:
Diameter of Vesta = Diameter of Mercury
Diameter of Vesta = 5000 km
Ok so my question is “ blank heat is a measure of how much energy it takes to raise the temperature of a substance.” Help PLEASEE I’m stuck!
Specific heat is a measure of how much energy it takes to raise the temperature of a substance.
What is temperature ?Temperature is defined as the measurement of degree of amount of hotness or coldness of a body.
Here,
Specific heat is a measure of how much energy it takes to raise the temperature of a substance. More clearly, specific heat is the amount heat required to raise the temperature of unit mass through one degree.
If an amount of heat Q is given to a body of mass m and ΔT is the rise in temperature. Then specific heat capacity,
C = Q/mΔT
Its unit is Jkg⁻¹K⁻¹
Specific heat of a substance is a constant but it changes slightly with change in temperature.
The rise in temperature is small for body having large specific heat.
Hence,
Specific heat is a measure of how much energy it takes to raise the temperature of a substance.
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A coil of wire lies flat on a horizontal surface. The coil is carrying current in an anticlockwise sense when the coil is viewed from above. For the points inside the coil, determine the direction of the magnetic field caused by this current. Explain your answer with the aid of labelled diagram.
When current flows through a coil of wire, it generates a magnetic field. The direction of the magnetic field can be determined using the right-hand rule. If you point your right thumb in the direction of the current flow, your fingers will curl in the direction of the magnetic field.
What is the current flow about?In this case, the current is flowing in an anticlockwise sense when viewed from above. Using the right-hand rule, the direction of the magnetic field inside the coil can be determined to be perpendicular to the plane of the coil, and in a clockwise direction when viewed from above.
The diagram below shows the coil of wire lying flat on a horizontal surface with the direction of the magnetic field labelled:
+-----+-----+-----+-----+-----+
| |
| |
| |
+ X X +
| |
| |
| |
+-----+-----+-----+-----+-----+
Therefore, In this diagram, the X's represent the direction of the magnetic field lines inside the coil. As you can see, the magnetic field lines are oriented perpendicular to the plane of the coil and in a clockwise direction when viewed from above.
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Which describes how chemical changes are different from physical changes? (2 points) Group of answer choices Chemical changes can be measured, but physical changes cannot. Chemical changes release energy, but physical changes absorb energy. Chemical changes involve the formation of a new substance. Chemical changes cannot be caused by oxygen.
Answer: Both Chemical and physical changes can be measured, chemical changes can be caused by oxygen since its very reactive. Physical Change: There is no addition or deduction of energy during the physical change, but the energy required for completion of change is released when the change is reversed. Chemical Change: Energy like light, pressure, heat energy is required for chemical changes. When physical or chemical changes occur, they are generally accompanied by a transfer of energy. The law of conservation of energy states that in any physical or chemical process, energy is neither created nor destroyed.
Explanation:
Find the distance between two charges according to Coulomb's Law if F
= 460 N
, Q1=2.8×10−5
C
, and Q2=3.1×10−7
C
.
0.16*10^-3m is the distance between two charges according to Coulomb's Law
How does Coulomb's law work?
Coulomb listed the following characteristics of the electric field for charges in a resting state: Unlike charges draw each other while like charges repel one another. As a result, a positive charge pulls a negative charge toward it while two negative charges resist one another.
We can determine the electric force produced between two electrical charges using Coulomb's Law. In particular, it enables the determination of the direction and strength of electric energy. Coulomb's law states that the force of attraction or repulsion between two charged bodies is inversely proportional to the cube of the distance between them and directly proportional to the product of their charges. It operates on the segment connecting the two charges regarded as point charges.
F = kq1q2/r^2
460 = 9*10^9 *2.8*10^-5 *3.1*10^-7 / r^2
r = sqrt ( 9*10^9 *2.8*10^-5 *3.1*10^-7 / 460)
r = 0.16*10^-3m
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# Calculate the radius of water drop which look just remain suspendat in an electric-ff- eld of 300 viem and charged with one election-
The radius of a water droplet suspended in an electric field can be calculated using the following formula:
r = (3qE/4πρg)^(1/2)
where r is the radius of the droplet, q is the charge on the droplet, E is the strength of the electric field, ρ is the density of the droplet material (assumed to be that of water, which is 1000 kg/m^3), and g is the acceleration due to gravity.
What is the radius of water drop which look just remain suspendat in an electric-ff- eld of 300 viem and charged with one election?In this case, q = -1.602 × 10^-19 C (the charge on an electron), E = 300 V/m, ρ = 1000 kg/m^3, and g = 9.81 m/s^2.
Plugging in these values, we get:
r = (3(-1.602 × 10^-19 C)(300 V/m)/(4π(1000 kg/m^3)(9.81 m/s^2)))^(1/2)
= 1.83 × 10^-5 m
Therefore, the radius of the water droplet is approximately 1.83 × 10^-5 meters.
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If the diameter of the space station is 770 m, how many revolutions per minute are needed for the "artificial gravity" acceleration to be 9.80m/s^2 ?
Revolutions per minute are needed for the space station which is at 385m from center of the planet is 1.52 rev/min
What is Orbital Velocity ?Orbital velocity is also called as critical velocity. It is minimum velocity must be given to the satellite or the body, so that it can revolve around the planet. i.e. orbital velocity is minimum velocity of body to revolve in stable orbit around a planet.
Orbital velocity is given by,
[tex]v_{c} = \sqrt{\frac{GM}{R+h}}[/tex] where G = Gravitational constant (6.673×10⁻¹¹ Nm²/kg²
M = Mass of the planet
R = Radius of the planet
h = height of the object(satellite)
Orbital velocity depends on mass of the planet, radius of the planet and height of the object(satellite). It is independent of mass of the body(satellite).
Given,
Diameter of space station, D = 770m {Radius (R+h) = 385m}
Acceleration due to gravity [tex]g_{h}[/tex]= 9.8 m/s²
our given equation is,
[tex]v_{c} = \sqrt{\frac{GM}{R+h}}[/tex]
[tex]v_{c}^{2} = \frac{GM}{R+h}}[/tex].........1)
we know that v=rω
v²=r²ω²
where r = (R+h) = Radius of planet + height of space station from surface of the planet.
v²=(R+h)²ω²......2)
with equation 2), equation 1 becomes.
(R+h)²ω² = [tex]\frac{GM}{R+h}}[/tex]
ω² = GM÷ (R+h)³.............3)
we know that [tex]g_{h} = \frac{GM}{(R+h)^{2} }[/tex].....4)
equ 3 becomes,
ω² = [tex]\frac{g_{h}}{(R+h)}[/tex]
Putting all values in equation,
ω² = 9.8 ÷ 385
ω² = 0.025454
ω = 0.1595 ≅ 0.16 rad/s
let,
ω = 2πn
n= ω ÷ 2π
n = 0.02547 rev/s
n= 0.02547*60 = 1.52 rev/min
Hence 1.52 rev/min is needed for space station at artificial gravity of 9.8 m/s
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I = 1/2MR^2 is rolling with a translational speed v along a horizontal surface without slipping. The work required to stop the disk is
A. 1/2 mv^2
B. 1/2mv^2 + 1/2Iw^2
C. 1/2Iw^2
D. 1/2mv^2 - 1/2Iw^2
Answer:
B. 1/2mv^2 + 1/2Iw^2
Explanation:
What happens to the atoms
that make up hydrogen fuel
as it burns?
An object starts at position 12 on a horizontal line with a reference point of 0. What is the position of the object if moves 14 units to the left?
If the object starts at position 12 on a horizontal line with a reference point of 0, then its initial position relative to the reference point is:
Initial position = Reference point + Object's position = 0 + 12 = 12
If the object then moves 14 units to the left, its new position relative to the reference point is:
New position = Initial position - Distance moved to the left = 12 - 14 = -2
Therefore, the position of the object is -2 units from the reference point, which means that it has moved 2 units to the left of the reference point.
What is the velocity of a 1,000.0 kg car if its kinetic energy is 200 kJ?
Answer: 20
Explanation:
If the energy released by an electron making a transition from one hydrogen atom orbit to another is 3.02 ✕ 10^−19 J, what is the wavelength (in nm) of the photon?
Answer:
The wavelength of the photon can be calculated using the equation E = hc/λ, where E is the energy, h is Planck's constant (6.626 ✕ 10^−34 J s), c is the speed of light (2.998 ✕ 10^8 m/s), and λ is the wavelength.
λ = hc/E = (6.626 ✕ 10^−34 J s) (2.998 ✕ 10^8 m/s) / (3.02 ✕ 10^−19 J) = 656.4 nm
Explanation:
A 500 g object is dropped from a height of 2 meters. What is its kinetic energy just before it hits the ground?
Answer: 9.8 J
Explanation:
Since the gravitational potential energy of the object is mgh or mass*acceleration due to gravity*initial height, its [tex]U_{g}[/tex] is 9.8 J. Due to the Law of Conservation of Energy, its kinetic energy will also be 9.8 J. This can be seen in the equation [tex]KE_{i}+ PE_{i}= KE_{f} + PE_{f}[/tex]. Since there is no initial kinetic energy and no final potential energy, its initial potential energy is equal to its final kinetic energy.