5n + 1/8 = 3n-5/4
Solve for n

Answer:

ดำหเภสยาแไ_ะทบบใืกไภเืวบวมเพนยชตึภ/ภึรื

Answer:

(2,8)

Step-by-step explanation:

m (4,2)

(6,-4)

(2,8)

Answer:

Step-by-step explanation:

Answer:

what the hell

Step-by-step explanation:

Answer:

x-intercept = 3.6

y-intercept = -1.2

Step-by-step explanation:

Answer:

22.28

Step-by-step explanation:

first add the decimals then the other number.

Answer:

This prism has: 5 Faces. 6 Vertices (corner points) 9 Edges.

Step-by-step explanation:

Answer:

664.94

Step-by-step explanation:

Give me brainlyest please

Answer:

664.94 is the answer to this question. I hope this helps.

Answer:

6

Step-by-step explanation:

When you need to estimate, if the number is .4 or below, bring it down (1.4 will now be 1.)

This goes for both 1.4

so, 1 + 1.

Next, you have 4.1 (which is also below .5, so .4 or below.)

It is 1 + 1 + 4.

That is 6. Hope this helps a bit ^^ :>

Answer:

(see explanation)

Step-by-step explanation:

Rounding to whole numbers,

1.4 rounds to 1

4.1 rounds to 4.

1+1+4 = 6

However, if you're rounding to the nearest 0.5,

1.4 rounds to 1.5

4.1 rounds to 4.0

1.5 + 1.5 + 4.0 = 7

Answer:

bxjfjxucjkkdndjkjhkjjnn

Answer:

Sean paid 0.25 more cents than Cal.

Step-by-step explanation:

Cal's problem: 2.4 * 2.55 = 6.12

Sean's problem: 2.6 * 2.45 = 6.37

Answer:

I think 0.25

Step-by-step explanation:

Multipled 2.4 and 2.55 then multipled 2.6 and 2.45. I got 6.12 and 6.37 Then subtracted them and got 0.25

The equation of the parallel line which is passing through the point (–3, –2) will be y = (10/3)x + 8.

Let the equation of the line be y = mx + c. Then the equation of the parallel line that is parallel to the line y = mx + c is given as,

y = mx + d

Line k has an equation of y= (10/3)x+9. Line l includes the point (–3, –2) and is parallel to line k.

y = (10/3)x + d

The equation of the line is passing through (–3, –2). Then the equation of the parallel line is given as,

–2 = (10/3)(–3) + d

–2 = –10 + d

d = 10 – 2

d = 8

The equation of the parallel line which is passing through the point (–3, –2) will be y = (10/3)x + 8.

More about the equation of a parallel line link is given below.

https://brainly.com/question/402319

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Answer :

D

Step By Step Explanation :

Hi this is the answer and explaination

I'm sorry if it's incorrect

hope's it's help

The circumcenter of a circle with a radius of 7 cm is, 44cm.

Circumference is the distance around the perimeter of a circular object. It is defined as the length of the circle that is found by multiplying the diameter of the circle by π (pi), which is approximately equal to 3.14.

The formula for the circumference of a circle is given by: C = 2πr,

Given that,

The radius of circle = 7 cm

Substituting the given value of radius as 7 and using pi = 3.14,

we get:

Circumference = 2 × 3.14 × 7

                         = 43.96

Rounding this to the nearest whole centimeter, we get:

Circumference ≈ 44

Therefore, the circumference of the circle with a radius of 7 centimeters is approximately 44 centimeters.

To know more about circumference check:

https://brainly.com/question/4268218

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Answer:

43-(+13)

43-13

=30

-× + would give you -

+×- would give you -

+×+ would give you -

-×-would give you +.

Determine the independent variable and dependent variable in the situation

The independent variable is the "amount of water the plant receives", and the dependent variable is the "height of the plant".

Therefore, the independent variable from the phenomena is "amount of water" and the dependent variable is the "height of the plant".

Read more:

https://brainly.com/question/23700645

Answer:

dy/dx = - (y/x)^4

Step-by-step explanation:

We are given the equation:

[tex] \displaystyle \large{ \frac{1}{ {x}^{3} } + \frac{1}{ {y}^{3} } = {a}^{3} }[/tex]

Recall important differential formulas such as:

[tex] \displaystyle \large{ \frac{d}{dx} (f(x) + g(x)) = \frac{d}{dx} f(x) + \frac{d}{dx} g(x)} \\ \displaystyle \large{ \frac{d}{dx} k = 0 \: \: \tt(k \: \: is \: \: a \: \: constant.)}[/tex]

Above is a basic property of differential. Looking at the equation above, differentiate both sides with respect to x. (dy/dx)

[tex] \displaystyle \large{ \frac{d}{dx}( \frac{1}{ {x}^{3} } + \frac{1}{ {y}^{3} } )= \frac{d}{dx} {a}^{3} }[/tex]

Apply the distribution property in.

[tex] \displaystyle \large{ \frac{d}{dx} \frac{1}{ {x}^{3} } + \frac{d}{dx} \frac{1}{ {y}^{3} } = \frac{d}{dx} {a}^{3} }[/tex]

We treat x^3 and y^3 as function to one another, this type of differential will be called implicit once another variable of function is involved f(x,y).

But we treat a^3 as a constant so we just put 0.

[tex] \displaystyle \large{ \frac{d}{dx} \frac{1}{ {x}^{3} } + \frac{d}{dx} \frac{1}{ {y}^{3} } = 0 }[/tex]

Recall the quotient rules for the numerator = 1.

[tex] \displaystyle \large{ \frac{d}{dx} (\frac{1}{f(x)}) = -\frac{ \frac{d}{dx} (f(x))}{ {(f(x))}^{2} } }[/tex]

Thus:

[tex] \displaystyle \large{ - \frac{ \frac{d}{dy} ( {x}^{3} )}{ ({x}^{3})^{2} } + \frac{d}{dx} \frac{1}{ {y}^{3} } = 0 } \\ \displaystyle \large{- \frac{ 3 {x}^{2} }{ {x}^{6} } + \frac{d}{dx} \frac{1}{ {y}^{3} } = 0 }[/tex]

Make sure to recall power rules for differential and exponent laws.

From 3x^2 / x^6.

[tex] \displaystyle \large{ - \frac{ 3 }{ {x}^{4} } + \frac{d}{dx} \frac{1}{ {y}^{3} } = 0 }[/tex]

Now what do we do with 1/y^3? We just differentiate it normally but we multiply with dy/dx once we differentiate the y function.

[tex] \displaystyle \large{- \frac{ 3 }{ {x}^{4} } -\frac{ \frac{d}{dx}( {y}^{3}) }{ ({y}^{3})^{2} } = 0 } \\ \displaystyle \large{ -\frac{ 3 }{ {x}^{4} } - \frac{ 3 {y}^{2} }{ {y}^{6}} = 0 } \\ \displaystyle \large{ - \frac{ 3 }{ {x}^{4} } - \frac{ 3 }{ {y}^{4}} \frac{dy}{dx} = 0 }[/tex]

Solve for dy/dx, add both sides by 3/x^4.

[tex] \displaystyle \large{ - \frac{ 3 }{ {x}^{4} } + \frac{3}{ {x}^{4} } - \frac{ 3 }{ {y}^{4}} \frac{dy}{dx} = 0 + \frac{3}{ {x}^{4} } } \\ \displaystyle \large{ - \frac{ 3 }{ {y}^{4}} \frac{dy}{dx} = \frac{3}{ {x}^{4} } } \\ [/tex]

Divide both sides by - 3/y^4.

[tex] \displaystyle \large{ \frac{- \frac{3}{ {y}^{4} } \frac{dy}{dx} }{ - \frac{3}{ {y}^{4} } } = \frac{ \frac{3}{ {x}^{4} } }{ - \frac{3}{ {y}^{4} } } } \\ \displaystyle \large{ \frac{dy}{dx} = \frac{3}{ {x}^{4} } \times (-\frac{ {y}^{4} }{3} )} \\ \displaystyle \large{ \frac{dy}{dx} = \frac{1}{ {x}^{4} } \times (- \frac{ {y}^{4} }{1}) } \\ \displaystyle \large{ \frac{dy}{dx} = - \frac{ {y}^{4} }{ {x}^{4} } } \\ \displaystyle \large{ \frac{dy}{dx} = - ( { \frac{y}{x} })^{4}}[/tex]

Given :

To find :-

Solution :-

As we know ,

Answer:

Grapgical charts and data plots

Step-by-step explanation:

Step-by-step explanation:

Answer:

make a chart and it will be easy for you

Step-by-step explanation:

[tex] \bf \underline\red{Question}[/tex]

Name the jelly like fluid that the other organelles float around in a cell?

[tex] \bf \underline\red{Answer}[/tex]

Cytoplasm.

Answer:

cytoplasm

step by step explanation

Step-by-step explanation:

hope this helps you dear sis.....

Answer:

Answer:

x = 10

Step-by-step explanation:

a² + b² = c²

(5√2)² + (5√2)² = x²

50 + 50 = x²

x² = 100

x= 10

Answer:

D

Step-by-step explanation:

Edmentum:))

Answer:

Step-by-step explanation:

Step-by-step explanation:

5x-7+3x+27=180

8x+20=180

8x=160

x=20°.

hope this helps you.

Answer:

[tex]5x - 7 + 3x + 27 = 180 \\ 5x + 3x + 27 - 7 = 180 \\ 8x + 20 = 180 \\ 8x = 180 - 20 \\ 8x = 160 \\ d \: b \: s \: by \: 8 \\ 8x \div 8 = 160 \div 8 \\ x = 20[/tex]

I think it is B

It makes the most sense to me to do that