--[50 POINTS]--
1)A block of mass 25 kg is placed on flat ground. The coefficient of static friction and kinetic friction are 0.73 and 0.16
a.If a person pushes the block and the block is moving, what will be the acceleration of the block?


2) A block has a mass of 79 kg. The coefficient of static and kinetic friction between the sled and the ground is 0.87 and 0.37. Person A tries to pull the block with 210N, but fails.
a) Person B successfully pulls the sled with 909N. What is the acceleration of the sled?

Answers

Answer 1

Newton's second law allows us to find the results for the acceleration of the blocks are:

1) The acceleration is a = 559 m / s²

2) The acceleration is a = 7.88 m / s²

Newton's second law states that the net force is equal to the product of the mass and the acceleration of the body.

       ∑ F = m a

Where the bold letters indicate vectors, F is the force, m the mass and the acceleration of the body.

The reference system is a coordinate system with respect to which the decomposition of the forces is carried out, in the attached we have a free body diagram of the system.

1) They indicate that the body mass is 25 kg.

y-axis

       N - W = 0

       N = W = m g

x-axis

        F -fr = ma

The friction force is a macroscopic force that results from the sum of all the microscopic interactions between the two surfaces, it has the formula

        fr = μ N

Where fr is the friction force, N the normal and very the friction coefficient.

This friction coefficient has two values:

Static. For when with there is not relative motion between the two surfaces. Dynamic. When there is relative motion between the two surfaces.

We substitute.

         F - μ m g = m a

a) The system moves which is the acceleration.

Suppose that the force that star to move the system keeps constant, just before the system begins to move the coefficient of friction is static, let's find the applied force.

         F = μ m g

         F = 0.73 25 9.8

         F = 178.85 N

The block begins to move and the friction coefficient decreases to the dynamic value, we look for the acceleration.

         a = [tex]\frac{F - \mu \ m g}{m}[/tex]  

         a = [tex]\frac{178.85 - 0.16 \ 25 \ 9.8 }{25}[/tex]  

         a = 5.59 m / s²

2) In this case the mass of the block is 79 kg and the applied force is

        F = 909 N

We look for acceleration.        

        a = [tex]\frac{909 - 0.37 \ 79 \ 9.8 }{79}[/tex]  

        a = 7.88 m / S²

In conclusion using Newton's second law we can find the results for the acceleration of the blocks are:

         1) The acceleration is a = 559 m / s²

         2) The acceleration is a = 7.88 m / s²

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--[50 POINTS]-- 1)A Block Of Mass 25 Kg Is Placed On Flat Ground. The Coefficient Of Static Friction

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reinforcing stimulus

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Which of the following statements is true?
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In a vacuum light travels at which speed?

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Light traveling through a vacuum moves at exactly 299,792,458 meters (983,571,056 feet) per second. That's about 186,282 miles per second

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Để chuyển đổi phép đo electronvolt thành phép đo kilojoule, hãy nhân năng lượng với tỷ lệ chuyển đổi. Năng lượng tính bằng kilojoules bằng electronvolt nhân với 1,6022E-22.

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The correct answer is B

A rock falls to the ground with a force of 300N and air resistance pushes back up on the rock with a
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Answer:

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Explanation:

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Correct option is
C
y
max

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1

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×11×100=5×10×h

or h=11m

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Answer:

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A matter can be separated into three states.

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2. liquid
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Answer:

You would need to save $300 every month to meet your savings goal.

Explanation:

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Answer:

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As two objects are separated from each other, the force of gravitational attraction between them also decreases. ... If the separation distance between any two objects is tripled (increased by a factor of 3), then the force of gravitational attraction is decreased by a factor of 9 (3 raised to the second power).

I DO NOT WANT LINKES OR …………..

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B-
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Explanation:

[tex]V = IR \Rightarrow R = \dfrac{V}{I}[/tex]

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ALREADY SOLVED Thank you for looking.

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what nonsense you are say it have been solved when why did you put

Answer:

yes

Explanation:

A 500 kg car is at rest at the top of a 72 m high hill. The car rolls to the bottom of the hill. At the bottom of the hill, the car has a speed of 25.6 m/s. Calculate the mechanical energy of the car at the top and bottom of the hill. (Assume the bottom of the hill has a height of 0 m, g=9.80 ms2/).

Answers

Explanation: Solution

1.

Gravitational potential energy

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The mechanical energy at the top and bottom of the hill is equal to 352800 J and 163840 J respectively.

What is the kinetic energy and potential energy?

Kinetic energy (KE) can be described as the energy possessed by a moving object due to its motion. Work by a body will be done to change the kinetic energy. The kinetic energy is represented as K.E = ½mv².

Potential energy (P.E) can be described as the energy that is stored by an object due to its position and is represented in the equation as P.E = mgh, where ‘m’ is the mass, ‘g’ is the acceleration due to gravity and ‘h’ is the height.

The mechanical energy = Kinetic energy + potential energy

Given, the mass of the car, m = 500 Kg

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The potential energy at the top of the hill, = mgh

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The centripetal acceleration of the hummingbird is [tex]\frac{(3.65)^2}{0.25} = 53.29 \ m/s^2[/tex]

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Answers

Answer:

Explanation:

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A person on a bike (m = 90 kg) is traveling 4 m/s at the top of a 2 m hill. the total energy of the biker would be 2484 Joules.

What is mechanical energy?

Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total potential energy stored energy in the system which is represented by total potential energy.

As given in the problem a person on a bike (m = 90 kg) is traveling 4 m/s at the top of a 2 m hill.

The total kinetic energy of the biker

KE = 1/2 × m × v²

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    = 720

Similarly, the total potential energy of the biker

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     =90 × 9.8 × 2

      = 1764 Joules

The total energy of the biker = 720 + 1764

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Answer:

Explanation:

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