5. When you breathe, your lungs absorb oxygen
and release carbon dioxide. Which of these are
your lungs releasing?
(1) O
(2) O2
(3) CO
(4) CO2
(5) NH3

Answers

Answer 1
4 CO2 two atoms of oxygen combine with 1 atom of carbon and that’s CO2

Related Questions

What is bee venom an example of?
O nucleic acid
O carbohydrate
O fat
O protein

Answers

Answer:

O protein

Explanation:

Bee venom (BV) is a complex mixture of proteins and contains proteins such as phospholipase and melittin, which have an effect on blood clotting and blood clots.

HGD

25 points!!!! What’s the answer???

Answers

Explanation:

Constructive interference occurs when the maxima of two waves add together (the two waves are in phase), so that the amplitude of the resulting wave is equal to the sum of the individual amplitudes. Equivalently, the minima of the waves would be aligned.

I will mark as brainiest or what ever its called lol. Please helpp

Answers

Answer:

A - Cinder cone

B - Shield

C - Composite

Explanation:

Cinder cone volcanoes are formed when the volcano explodes and all the lava soldifies and falls steeply upon the sides of the mountain and forms cinders.

Shield volcanoes form when a centralized vent produces low-viscosity flows over a long period of time

Composite volcanoes are also called stratovolcanoes. They form when different types of eruptions deposit different materials around the sides of a volcano. Alternating eruptions of volcanic ash and lava cause layers to form. Over time these layers build up.

Answer:

Answer:A - Cinder coneB - Shield C - CompositeExplanation:Cinder cone volcanoes are formed when the volcano explodes and all the lava soldifies and falls steeply upon the sides of the mountain and forms cinders. Shield volcanoes form when a centralized vent produces low-viscosity flows over a long period of time Composite volcanoes are also called stratovolcanoes. They form when different types of eruptions deposit different materials around the sides of a volcano. Alternating eruptions of volcanic ash and lava cause layers to form. Over time these layers build up.:

Covalent bonding involves the sharing of electrons to create a full valence shell, and
occurs between nonmetals.
True
False

Answers

True. Covalent bonds involve sharing electrons to create a full valence shell.
The answer is: true
<3

Which molecule would provide the most accurate value for the bond length of a nitrogen-nitrogen double bond

Answers

Answer:

i dont know, i wish i could help

Explanation:

Which of the following is not a characteristic of both experiments and
surveys?
A. Subjects should be randomly selected.

B. The data collected might be studied for patterns.
C. The researcher exercises direct control over at least one variable.
D. Data are collected about a population.

Answers

Answer:

C. The researcher exercises direct control over at least one variable.

Explanation:

Your answer should be C. The researcher exercises direct control over at least one variable.

I hope it helps! Have a great day!

pan~

what is mass ? give two examples ​

Answers

mass it the  amount of matter present in any object or body. Everything we see around us has mass. For example, a table, a chair, your bed, a football, a glass, and even air has mass.

Elements in which family would require the least amount of ionization energy (the
amount of energy used to take away an electron)?

transition metals
Alkali metals
Alkaline earth metals

Answers

Alkali metals require least amount of ionization energy.

Peaky Blinder fan? haha

The pressure of a nitrogen gas, N2, cylinder is measured at 250 K and found to be 4.0 atm. What is the pressure of the same cylinder at room temperature, 293 K?

Answers

Apply Gay lussac's law

P_1T_2=P_2T_14(293)=250P_21172=250P_2586=125P_2P_2=586/125P_2=4.688atm

what would be the mass of 4.640 x 10^21 particles of aluminum

Answers

One mole of aluminum  contains 6.02 × 10²³ Al  particles. One mole of Al weighs 27 g. Hence 4.60 × 10²¹ Al particles or 0.007 moles weighs 0.208 g.  

What is one mole ?

One mole of a substance is its amount containing 6.02 × 10²³  atoms or molecules. This number is called Avogadro number. One mole of every elements contains Avogadro number of atoms.

Similarly one mole of every compound contains 6.02 × 10²³ molecules. The mass of one mole of compound is called its molar mass. Similarly mass of one mole of an element is called its atomic mass.

Al is 13th element in periodic table. Al is a metal.  One mole of Al contains 6.02 × 10²³ Al  atoms . Hence number of moles of   4.60 × 10²¹ Al particles is:

4.60 × 10²¹/ 6.02 × 10²³  = 0.0077 .

atomic mass of Al = 27 g/mol.

Then mass of 0.0077 moles =  0.0077 × 27 = 0.208 g

Therefore, the mass of  4.60 × 10²¹ Al particles is 0.208 g.

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In a neutralization reaction 30.0mL of 0.234M KOH solution is reacted with 30.0mL of 0.234M HNO3 solution and a temperature rise of 5.6C was observed. Density of base and acid=1.00g/mL and the specific heat of the mixture is 4.18j/g•C

a) write the balanced equation of the reaction
b) calculate the moles of water produced
c) calculate the total heat produced
d) calculate the enthalpy of neutralization of the reaction

Answers

Based on the data provided, the equation of the reaction is:

[tex]KOH + HNO_3 \rightarrow KCl + H_2O[/tex]moles of water produced = 0.00702 molesHeat produced = 1404.48 JEnthalpy of neutralization = 200 kJ/mol

What is enthalpy of neutralization?

Enthalpy of neutralization is the heat change when one mole of hydrogen ions from an acid reacts with one mole of hydroxide ions from an alkali to produce one mole of water.

The equation of the reaction of KOH and HNO3 is given below:

[tex]KOH + HNO_3 \rightarrow KCl + H_2O[/tex]

1 mole of KOH reacts with 1 mole of HNO3 to produce 1 mole of water.

Volume of KOH = 30 mL = 0.03 L

moles of KOH = 0.03 × 0.234 = 0.00702 moles

Therefore, 0.00702 moles of water are produced

Heat produce = mass × specific heat × temperature difference

Volume of solution = 60 mL

density of solution = 1.0 g/mL

mass of solution = 60 mL × 1.0 g/mL = 60 g

Heat produced = 60 × 4.18 × 5.6

Heat produced = 1404.48 J

Enthalpy of neutralization = 1404.48 J/0.00702 moles

Enthalpy of neutralization = 200068.37 J/mol

Enthalpy of neutralization = 200 kJ/mol

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PLEASEEEEE HELP
1 Explain why decan-1-ol CH,(CH,) CH,OH has

only limited solubility in water, whereas ethanol

CH,CH,OH is miscible with water in all proportions.

2 Give details of the reagents and the practical

procedures required to prepare each of the following

substances from a named alcohol:

a 1-Chloropropane

b 2-Bromopropane.

3 Explain why sodium metal reacts more slowly with

ethanol CH,CH,OH than with water HOH.

4 Draw Lewis structures to show the formation of the

ethoxide ion by the action of sodium on ethanol.

Answers

Answer:

Can you arrange it? I don't understand

A 0.250 mol sample of gas at 35.0°C exerts a pressure of 700 torr in it's container. What pressure will the container exert if the volume expands to 10.0L and the temperature is cooled to 5.0°C?

Answers

29 temperature because if the temperature is more then the 5.of

Why the positive emulsion for bread is not clear?

Answers

Because it’s gay and doesn’t listen

I really need to know the answer it will help

Answers

Answer:

so the answer is A 5.199mol please. rate. me brainliest. if its. correct

Explanation:

N=nL

[tex]3.131 \times {10}^{24} = n \times 6.022 \times {10}^{23} \\n = \frac{3.131 \times {10}^{24} }{6.022 \times {10}^{23} } \\ n = 5.199mol[/tex]

Listed below are the step equations for the reaction in which sulfur dioxide (SO2) and hydrogen disulfide (H2S) react to produce sulfur and water. Write the balanced target equation and use Hess’s law to calculate the ΔH of this reaction.

SO2 (g) → S (s) + O2 (g) ΔH = +300.1 kJ
H2 (g) + S (s) → H2S (g) ΔH = –19.5 kJ
H2 (g) + O2 (g) → H2O (g) ΔH = –290.1 kJ

Answers

Based on Hess law, the enthalpy change, ΔH of the reaction is +48.9 kJ.

What is the equation of the reaction?

The equation of the reaction of sulfur dioxide (SO2) and hydrogen disulfide (H2S) to produce sulfur and water is given below:

[tex]SO_2 + 2H_2S \rightarrow 3S + 2H_2O[/tex]

The ΔH of the reaction is calculated from the summation of the ΔH of the intermediate reactions according to Hess law.

SO2 (g) → S (s) + O2 (g) ΔH1 = +300.1 kJ

H2 (g) + S (s) → H2S (g) ΔH2 = –19.5 kJ

2H2 (g) + O2 (g) → 2H2O (g) ΔH3 = –290.1 kJ

ΔH of the reaction = ΔH1 + 2(-ΔH2) + ΔH3

ΔH of the reaction = 300 + 2 × -(-19.5) + (-290.1)

ΔH of the reaction = +48.9 kJ

Therefore, the ΔH of the reaction is +48.9 kJ.

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if you were to engineer an everyday solution for conserving water which activity do you think would be the most impactful ?

Answers

if you were to engineer an everyday solution for conserving water which activity do you think would be the most impactful ?

How many significant digits are in the following:

pH 7.02

Answers

Answer:

3

Explanation:

7.02     three sig digits

25 points!!! What’s the answer???

Answers

Answer:

C

Explanation:
Cause wave's get larger and larger and it will repeat over and over

(please mark me brainly est)

Find the pH of a 0.600 M solution of methylamine CH3NH2. Kb= 4.4 x 10^-4

Answers

Since methylamine (CH3NH2) is a weak base, the major species in solution are CH3NH2 and H2O.
Both are bases; however, since water can be neglected as a source of OH-, the dominant equilibrium is:
CH3NH2(aq) + H2O(l) = CH3NH3+(aq) + OH-(aq)
and



The concentrations are as follows:



[OH-] = [CH3NH3+] = x
[CH3NH2] = 1.0 - x
Then,




Assume that 1 >> x, then:
(1.0 - x) = 1.0
Kb = x2 / 1.0
x2 = Kb
x = (Kb)0.5 = (4.38×10-4)0.5 = 0.0209
x= [OH-] = 0.0209 M

We can convert between [OH-] and pOH using the following equations:
pOH = - log[OH-]
pOH = - log(0.0209) = 1.68
pOH = 1.68

For any aqueous solution at 25∘C:
pH + pOH = 14
pH = 14 - pOH = 14 - 1.68 = 12.32
pH = 12.32

Answer: pH = 12.32

The Ksp of scandium fluoride, ScF3, is 5.81×10−24. Calculate the molar solubility ,s, of this compound.

Answers

The Ksp shows the extent of solubility of a substance in another. The solubility of the compound is 1.2 * 10^-7 M.

What is solubility?

The term solubility shows the extent to which a substance dissolve in solution. The solubility of a substance is often typified by the Ksp of the substance.

Now;

ScF3(s) ⇄Sc^+(aq) + 3F^-

Ksp = [Sc^+] [F^-]^3

Ksp = x (3x)^3

Ksp = 27x^4

x = 4√5.81×10^−24/27

x = 1.2 * 10^-7 M

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Where would the points for 1-pentene be
expected to fall?

Answers

To the left of black points

Which adaptation do polar bears and camels have in common?
A. Thick layer of body fat for food storage and insulation.
B. A small surface area to volume to reduce heat loss.
C. Thin fur and little body fat.
D. Large feet to spread body weight.

Answers

Answer:

Thick layer of body fat for food storage and insulation

Explanation:

Polar bears store food for themselves and so do camels. Option B is not correct because bears do not definitely have small surface area and even if camels do they do not need to reduce heat loss because they stay in the deserts. For option C polar bears have thick fur and much body fat to protect itself from the cold. Lastly D cannot be true because camels don't normally have large feet they have small padded foot.

4.55 Classify the following redox reactions. (a) 2H2O2 ⟶ 2H2O + O2 (b) Mg + 2AgNO3 ⟶ Mg(NO3)2 + 2Ag (c) NH4NO2 ⟶ N2 + 2H2O (d) H2 + Br2 ⟶ 2HBr

Answers

A- Decomposition .
B- Single replacement.
C-Decomposition.
D-Synthesis.

The following redox reactions are classify as:

(a) 2H₂O₂ ⟶ 2H₂O + O₂: Disproportionation reaction (redox)

(b) Mg + 2AgNO₃ ⟶ Mg(NO₃)₂ + 2Ag: Single displacement reaction (redox)

(c) NH₄NO₂ ⟶ N₂ + 2H₂O: Decomposition reaction (redox)

(d) H₂ + Br₂ ⟶ 2HBr: Combination reaction (redox)

(a) 2H₂O₂ ⟶ 2H₂O + O₂

This reaction involves hydrogen peroxide (H₂O₂) breaking down into water (H₂O) and oxygen gas (O₂). The oxidation state of oxygen in hydrogen peroxide is -1, and in water, it is -2. Oxygen in oxygen gas has an oxidation state of 0. Therefore, oxygen is being reduced from -1 to 0. The oxidation state of hydrogen remains +1 in H₂O₂ and H₂O. Since one element (oxygen) is reduced and the other (hydrogen) remains unchanged, this is a disproportionation reaction (a type of redox reaction).

(b) Mg + 2AgNO₃ ⟶ Mg(NO₃)₂ + 2Ag

In this reaction, magnesium (Mg) reacts with silver nitrate (AgNO₃) to form magnesium nitrate (Mg(NO₃)₂) and silver (Ag). The oxidation state of magnesium changes from 0 to +2 in Mg(NO₃)₂, while the oxidation state of silver changes from +1 in AgNO₃ to 0 in Ag. This is a single displacement reaction (a type of redox reaction) because one element (magnesium) displaces another (silver) in the compound.

(c) NH₄NO₂ ⟶ N₂ + 2H₂O

This reaction involves ammonium nitrite (NH₄NO₂) decomposing into nitrogen gas (N₂) and water (H₂O). The oxidation state of nitrogen in NH₄NO₂ is +3, and in nitrogen gas (N₂), it is 0. The oxidation state of hydrogen changes from +1 in NH₄NO₂ to +1 in H₂O. Since nitrogen is being reduced from +3 to 0, and hydrogen remains unchanged, this is a decomposition redox reaction.

(d) H₂ + Br₂ ⟶ 2HBr

In this reaction, hydrogen gas (H₂) reacts with bromine gas (Br₂) to form hydrogen bromide (HBr). The oxidation state of hydrogen changes from 0 in H₂ to +1 in HBr, while the oxidation state of bromine changes from 0 in Br₂ to -1 in HBr. This is a combination reaction (a type of redox reaction) because two elements (hydrogen and bromine) combine to form a compound (hydrogen bromide), and their oxidation states change during the reaction.

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Soil that are light in color have a great amount of humus in
them. True or False

Answers

Answer:

please the answer Is false

A student places a 50.0 g sample of a metal at 96.8° C into a calorimeter full of 100.0 g of
water (specific heat of water = 4.18 J/g°C). The water, initially at 22.0 °C, eventually
comes to a temperature of 25.9 °C. Calculate the heat gained by the water.

Answers

Answer:

1630.2 j

Explanation:

100 gm * 4.18 J/gm-C  * ( 25.9-22 C ) = 1630.2 j

What is the heat capacity equation?

Answers

Answer:

The specific heat capacity is the heat or energy required to change one unit mass of a substance of a constant volume by 1 °C. The formula is Cv = Q / (ΔT ⨉ m)

A laboratory group measures an excess of a volatile liquid. They add this to an empty flask with a volume of 66 mL. They heat the sample to 86.9 degrees Celcius until all the liquid is vaporized. The pressure in the lab is 0.987 atm. If 0.287 grams of volatile liquid were left in the flask, what was the molar mass of the compound?

Answers

Answer:

130.159

Explanation:

P=0.987

V=66ml =66/1000=0.066 L

n/moles= ?

R=0.08206

T=86.9+273.15=360.5 K

Formula PV=RnT

n =PV/TR

n=(0.987 * 0.066)/(360.05 * 0.08206) = 0.002205

Now to obtain molar mass  you divide grams by mol.

0.287/0.002205 = 130.159

Write two half‑reactions to describe each of these metal displacement reactions. Include phase symbols.

Mg(s)+CoBr2(aq)⟶MgBr2(aq)+Co(s)

oxidation half‑reaction:

reduction half‑reaction:

Cu(s)+2AuCl(aq)⟶CuCl2(aq)+2Au(s)

oxidation half‑reaction:

reduction half‑reaction:

Answers

In redox reactions, an oxidation half reaction shows the oxusetoon occurring while the reduction half reaction shows the reduction occurring in the overall reaction.

What are redox reactions?

Redox reactions are reactions in which oxidation and reduction reactions occur together to the same extent.

A redox reaction can be split into two half oxidation and reduction reactions.

The half reactions of the given reactions are shown below:

Overall reaction;

[tex]A. Mg(s) + CoBr_2(aq) ⟶ MgBr_2(aq) + Co(s) \\ [/tex]

Oxidation half reaction:

[tex]Mg (s) ---> Mg ^{2+}(aq)[/tex]

Reduction half reaction:

[tex]Co^{2+} (aq) ---> Co (s)[/tex]

B. Overall reaction

[tex]Cu(s) + 2AuCl(aq) ⟶ CuCl_2(aq) + 2Au(s) \\ [/tex]

Oxidation half reaction:

[tex]Cu(s) ---> Cu^{2+}(aq)[/tex]

Reduction half reaction:

[tex]2Au^{+}(aq) ---> 2 Au (s)[/tex]

Therefore, redox equations can be spilt into oxidation and reduction half reactions.

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what foods can be stored in water and or ice

Answers

Whole, raw fruits or vegetables; cut, raw vegetables such as celery or carrot sticks or cut potatoes; and tofu may be immersed in ice or water.
Whole, raw fruits or vegetables; cut, raw vegetables such as celery or carrot sticks or cut potatoes; and tofu may be immersed in ice or water.
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