4. The perimeter of an isosceles trapezoid ABCD is 27. 4 inches. If BC = 2 (AB), find AD, AB, BC, and CD. ​

Answer:

Step-by-step explanation:

The perimeter of a square is calculated by multiplying the length of one side by 4. Since the side length of the square is 8x units, the perimeter of the square is 4 * 8x = 32x units.

The perimeter of a rectangle is calculated by adding the lengths of all four sides or by using the formula 2 * (length + width). Since the length of the rectangle is (5x + 12) units and the width is 10 units, the perimeter of the rectangle is 2 * ((5x + 12) + 10) = 10x + 44 units.

Since both shapes have the same perimeter, we can set their perimeters equal to each other and solve for x:

32x = 10x + 44 22x = 44 x = 2

Substituting this value of x back into the expression for the perimeter of either shape, we find that the perimeter of both the square and the rectangle is 64 units.

It would take 1.53 years for the price of pizza to triple with a growth rate of 1.05.

To find the number of years it takes for the price of pizza to triple with a growth rate of 1.05, we need to use the formula for exponential growth:

A = P(1 + r)^t

Where:

A = final amount (triple the original price, or 3*$8 = $24)

P = initial amount ($8)

r = growth rate (1.05)

t = time in years

Substituting the values into the formula, we get:

$24 = $8(1 + 1.05)^t

Simplifying:

3 = (1 + 1.05)^t

Taking the logarithm of both sides with base 10:

log(3) = t*log(1 + 1.05)

t = log(3) / log(1 + 1.05)

Using a calculator, we get:

t ≈ 1.53

Therefore, it would take approximately 1.53 years for the price of pizza to triple with a growth rate of 1.05.

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One point that would lie on the second line is (0,-4). Another  possible point on the 2nd line is (0, 12).

To find the equation of the first line, we can use the slope-intercept form:

y = mx + b

where m is the slope and b is the y-intercept. The slope of the line passing through (-3,8) and (1,9) can be found using the formula:

m = (y2 - y1) / (x2 - x1)

m = (9 - 8) / (1 - (-3))

m = 1/4

Using one of the points and the slope, we can find the y-intercept:

8 = (1/4)(-3) + b

b = 9

So the equation of the first line is:

y = (1/4)x + 9

To find the equation of the second line, we need to use the fact that it is perpendicular to the first line. The slopes of perpendicular lines are negative reciprocals, so the slope of the second line is:

m2 = -1/m1 = -1/(1/4) = -4

Using the point-slope form, we can write the equation of the second line:

y - 4 = -4(x + 2)

y - 4 = -4x - 8

y = -4x - 4

To find a point that lies on this line, we can plug in a value for x and solve for y. For example, if we let x = 0, then:

y = -4(0) - 4

y = -4

So the point (0,-4) lies on the second line.

Therefore, another point that would lie on the second line is (0,-4).

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It would take approximately 21.2 minutes for 960 grams of Element X to decay to 295 grams.

The time it takes for 960 grams of Element X with a half-life of 15 minutes to decay to 295 grams can be found using the formula y = a [tex](0.5)^\frac{t}{h}[/tex] .

1: Identify the variables.

a = initial amount = 960 grams
y = final amount = 295 grams
h = half-life = 15 minutes
t = time in minutes (this is what we want to find)

2: Plug the variables into the formula.
295 = 960 [tex](0.5)^\frac{t}{15}[/tex]

3: Solve for t.
Divide both sides by 960.
(295/960) =  [tex](0.5)^\frac{t}{15}[/tex]

4: Take the logarithm of both sides to remove the exponent.
log(295/960) = log  [tex](0.5)^\frac{t}{15}[/tex]

5: Use the logarithm property to move the exponent to the front.
log(295/960) = (t/15) * log(0.5)

6: Solve for t.
t = (15 * log(295/960)) / log(0.5)

7: Calculate t.
t ≈ 21.2 minutes

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The piecewise defined function for fencing the backyard would be 30(300) + 25(x - 300), if x > 300, or 30x, if 0 < x ≤ 300, as seen below.

A piecewise defined function is a function that is defined by different formulas on different intervals or "pieces" of its domain. This means that the formula used to calculate the output (the function value) of the function depends on the value of the input (the independent variable).

For this particular question, let C be the cost of fencing a backyard and let x be the length of the fence in feet. Then, we can write the piecewise defined function as:

C(x) =  30x, if 0 < x ≤ 300 OR

C(x) = 30(300) + 25(x - 300), if x > 300

In other words, if the length of the fence is less than or equal to 300 feet, the cost is simply 30 times the length of the fence. If the length of the fence is greater than 300 feet, the cost is the cost of the first 300 feet (30 times 300), plus 25 times the additional length of the fence beyond 300 feet.

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The area enclosed by the figure at the right is 2856 square meters.

To find the area enclosed by the figure at the right, we first need to find the area of the square and the two semicircles on each side. The square has sides of 40 meters, so its area is 40 x 40 = 1600 square meters. Each semicircle has a radius of 20 meters (half the side length of the square), so its area is 1/2 x pi x r^2 = 1/2 x 3.14 x 20^2 = 628 square meters. Since there are two semicircles on each side, the total area of all four semicircles is 2 x 628 = 1256 square meters.

To find the total area enclosed by the figure, we add the area of the square and the area of the four semicircles:

1600 + 1256 = 2856 square meters

Therefore, the area enclosed by the figure at the right is 2856 square meters.

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The derivative of the vector function is: r'(t) = (-2t/(7-t^2)) i + (1/(2sqrt(13+t))) j - 36e^(9t) k

We are given a vector function r(t) = ln(7-t^2)i + sqrt(13+t)j – 4e^(9t)k, and we need to find its derivative r'(t).

The derivative of a vector function is obtained by differentiating each component of the vector function separately.

So, let's differentiate each component:

r(t) = ln(7-t^2)i + sqrt(13+t)j – 4e^(9t)k

r'(t) = (d/dt) ln(7-t^2) i + (d/dt) sqrt(13+t) j - (d/dt) 4e^(9t) k

Using the chain rule of differentiation, we have:

r'(t) = -2t/(7-t^2) i + 1/(2sqrt(13+t)) j - 36e^(9t) k

Therefore, the derivative of the vector function is:

r'(t) = (-2t/(7-t^2)) i + (1/(2sqrt(13+t))) j - 36e^(9t) k

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Each part of the circle given it’s equation should be identified as follows;

In Geometry, the standard or general form of the equation of a circle is modeled by this mathematical equation;

(x - h)² + (y - k)² = r²

Where:

Based on the information provided above, we have the following parameters:

Radius, r = √400 units.

Center, (h, k) = (9, 4).

By substituting the given radius and center into the equation of a circle, we have;

(x - h)² + (y - k)² = r²

(x - 9)² + (y - 4)² = (√400)²

(x - 9)² + (y - 4)² = 400.

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Advertising cricket bats in a national newspaper provides Sachin's business with increased brand visibility and reach, while also posing a potential disadvantage due to high advertising costs.

One advantage and one disadvantage of Sachin's business advertising cricket bats in a national newspaper are as follows:

Advantage: Increased brand visibility and reach.

By advertising in a national newspaper, Sachin's business can reach a wider audience, creating greater brand awareness among potential customers. This increased visibility can contribute to the rapid increase in demand for cricket bats, ultimately leading to higher sales and profits for the business.

Disadvantage: High advertising cost.

National newspaper advertising can be quite expensive, especially for a business that advertises every two weeks. The high advertising costs might put financial pressure on Sachin's business, which could potentially affect other aspects of the business operations, such as product quality or employee wages. It's important for Sachin to weigh the benefits of national newspaper advertising against its costs to determine the most effective marketing strategy.

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Using the quotient rule of logarithms, we have:

=log2 51.2 − log2 1.6

= [tex]log2 (51.2/1.6)[/tex]

Simplifying the numerator, we have:

[tex]log2(51.2/1.6) = log2(32)[/tex]

Using the fact that 32 = 2^5, we have:

log2 32 = log2 2^5 = 5

log2 51.2 − log2 1.6 = log2 (51.2/1.6) = log2 32 = 5

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The quotient of the expression (7¹⁸/7⁻⁹) expressed as a power of 7 is 7 ²⁷.

The quotient of the expression is calculated as follows;

When you divide two numbers with the same base, you subtract the exponents of the base. Using this rule, we can simplify the expression as follows;

7¹⁸ / 7⁻⁹

= 7 ⁽¹⁸ ⁻ ⁻⁹⁾

= 7 ⁽¹⁸ ⁺ ⁹⁾

= 7 ²⁷

Therefore, the quotient of the expression (7¹⁸/7⁻⁹) is 7 ²⁷.

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The 92% confidence interval for the population standard deviation is (0.199, 0.509).

To find the 92% confidence interval for the population standard deviation, we will use the chi-square distribution. We know that for a sample size of n=25, the degrees of freedom for the chi-square distribution is (n-1) = 24.

The chi-square distribution is a right-tailed distribution, so we need to find the chi-square values that will leave 4% in the right tail (for a total of 92% confidence interval).

From a chi-square distribution table, the chi-square value with 24 degrees of freedom that leaves 4% in the right tail is 41.337. The chi-square value that leaves 96% in the left tail is 13.119.

Using the formula for the confidence interval for the population standard deviation:

lower bound = [tex]sqrt((n-1)*s^2 / chi-square upper)[/tex]

upper bound = [tex]sqrt((n-1)*s^2 / chi-square lower)[/tex]

We can substitute the values we have:

lower bound = [tex]sqrt((25-1)*0.34^2 / 41.337) = 0.199[/tex]

upper bound = [tex]sqrt((25-1)*0.34^2 / 13.119) = 0.509[/tex]

Therefore, the 92% confidence interval for the population standard deviation is (0.199, 0.509).

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Answer:

AB = 15

Step-by-step explanation:

6(6 + x + 6) = 7(7 + 11)

72 + 6x = 126

6x = 126 - 72 = 54

x = 54/6

   = 9.

So AB = 9 + 6 = 15.

The critical points of [tex]f(x,y)[/tex] are: (0,0), (1,1), (-1,-1), [tex](1/\sqrt2,-1/\sqrt2)[/tex], [tex](-1/\sqrt2,1/\sqrt2), (i/\sqrt2,-i/\sqrt2)[/tex], and [tex](-i/\sqrt2,i/\sqrt2)[/tex]. The points (1,1) and (-1,-1) are local maxima, while the remaining critical points are saddle points

To find the critical points of the function [tex]f(x,y)[/tex], we need to find where its partial derivatives with respect to x and y are equal to zero:

∂f/∂x = 4x³ - 4y = 0

∂f/∂y = 4y³ - 4x = 0

From the first equation, we get y = x³, and substituting into the second equation, we get:

[tex]4x - 4x^9 = 0[/tex]

Simplifying this equation, we get:

[tex]x(1 - x^8) = 0[/tex]

So the critical points occur at x = 0, x = ±1, and [tex]x = (^+_-i)/\sqrt2[/tex].

To determine the nature of these critical points, we need to look at the second partial derivatives of [tex]f(x,y)[/tex]:

∂²f/∂x² = 12x²

∂²f/∂y² = 12y²

∂²f/ = -4

At (0,0), we have ∂²f/∂x² = ∂²f/∂y² = 0 and ∂²f/∂x ∂y = -4, so this is a saddle point.

At (1,1), we have ∂²f/∂x² = ∂²f/∂y² = 12, and ∂²f/∂x ∂y = -4, so this is a local maximum.

At (-1,-1), we have ∂²f/∂x² = ∂²f/∂y² = 12, and ∂²f/∂x ∂y = -4, so this is also a local maximum.

At , we have ∂²f/∂x² = 6, ∂²f/∂y² = 6, and ∂²f/∂x ∂y = -4, so these are saddle points.

At [tex](i/\sqrt2,-i/\sqrt2)[/tex] and [tex](-i/\sqrt2,i/\sqrt2)[/tex], we have ∂²f/∂x² = -6, ∂²f/∂y² = -6, and ∂²f/∂x ∂y = -4, so these are also saddle points.

Therefore, the critical points of [tex]f(x,y)[/tex] are: [tex](0,0), (1,1), (-1,-1), (1/\sqrt2,-1/\sqrt2), (-1/\sqrt2,1/\sqrt2), (i/\sqrt2,-i/\sqrt2)[/tex], and [tex](-i/\sqrt2,i/\sqrt2)[/tex]. The points (1,1) and (-1,-1) are local maxima, while the remaining critical points are saddle points

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The amount of money Justin saves in the first month would be 5 times the value of x, where x represents the number of months of gym membership, based on the discounted price provided.

A linear equation is an equation in mathematics that represents a relationship between two variables that is a straight line when graphed on a coordinate plane. It is an equation of the form:

y = mx + b

To calculate the amount of money Justin saves in the first month by joining the gym at the discounted price rather than the regular price, we need to know the discounted price.

The equation given is y = 15x + 20, where y represents the regular price in dollars and x represents the number of months of gym membership. However, we need to know the discounted price, which is not provided in the given information.

Once we have the discounted price, we can substitute it into the equation and calculate the savings. For example, if the discounted price is y = 10x + 20, then we can calculate the savings by subtracting the discounted price from the regular price:

Savings = Regular price - Discounted price

= (15x + 20) - (10x + 20)

= 15x - 10x

= 5x

Hence, the amount of money Justin saves in the first month would be 5 times the value of x, where x represents the number of months of gym membership, based on the discounted price provided.

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a. To show that R(B) is a subset of N(A), let y be any vector in R(B):

This means that there exists a vector x in R4 such that Bx = y.

Now, since ABx = 0 for all x in R5, we can write:

A(Bx) = 0

But we know that Bx = y, so we have:

Ay = 0

This shows that y is in N(A), and therefore R(B) is a subset of N(A).

To deduce that rank(B) is less than null(A), recall that by the Rank-Nullity theorem, we have:

rank(B) + null(B) = dim(R5) = 5

rank(A) + null(A) = dim(R4) = 4

Since R(B) is a subset of N(A), we have null(A) >= rank(B).

Therefore, using the above equations, we get:

rank(B) + null(A) <= null(B) + null(A) = 5

which implies:

rank(B) <= 5 - null(A) = 5 - (4 - rank(A)) = 1 + rank(A)

This shows that rank(B) is less than or equal to 1 plus the rank of A.

Since the rank of A can be at most 3 (since A is a 3 x 4 matrix),

we conclude that:

rank(B) < null(A)

b. To use the Rank-Nullity theorem to prove that rank(A) + rank(B) < 4

We simply add the equations:

rank(A) + null(A) = 4

rank(B) + null(B) = 5

to get:

rank(A) + rank(B) + null(A) + null(B) = 9

But since R(B) is a subset of N(A), we know that null(A) >= rank(B), and therefore:

rank(A) + rank(B) + 2null(A) <= 9

Using the first equation above, we can write null(A) = 4 - rank(A), so we get:

rank(A) + rank(B) + 2(4 - rank(A)) <= 9

which simplifies to:

rank(A) + rank(B) <= 1

Since rank(A) is at most 3,

we conclude that:

rank(A) + rank(B) < 4

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The stocks would need to increase in value by 23% to return to their original value. Rounding to the nearest tenth of a percent, the answer is 23.0%.

Let x be the percentage increase in the value of the stocks needed to return to their original value. Since the value of the stocks decreased by 23%, the new value of the stocks is 100% - 23% = 77% of the original value.

Therefore, we can set up the equation:

(100% + x%) = (77%)*(100%)

Simplifying this equation, we get:

100% + x% = 77%

x% = 77% - 100%

x% = -23%

Since we want to find the percentage increase, we need to take the absolute value of -23%, which is 23%.

Therefore, the stocks would need to increase in value by 23% to return to their original value. Rounding to the nearest tenth of a percent, the answer is 23.0%.

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By observing the given protractor we know that option (C) is correct which says ∠NOP = ∠ROS.

An instrument for measuring angles is a protractor, which is often made of transparent plastic or glass.

Protractors might be straightforward half-discs or complete circles. Protractors with more complex features, like the bevel protractor, include one or two swinging arms that can be used to measure angles.

To draw arcs or circles, use a compass.

To measure angles, one uses a protractor.

So, we need to observe the given image of the protractor:
We will easily find that ∠NOP = ∠ROS

Therefore, by observing the given protractor we know that option (C) is correct which says ∠NOP = ∠ROS.

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Answer: 2.704 2.74 4.2 4.27 4.72

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

The correct spot would be 5 because, on a number line, the opposite of a negative would be its positive counterpart and vise versa.

The expression that represents the perimeter of the triangle is 13a + 5c + 2b + 46 centimeters.

So, the expression for the perimeter of the triangle is:

(7a + 2b) + (6a + 3c) + (3c + 46)

Simplifying and combining like terms, we get:

13a + 5c + 2b + 46

Rational functions can also have holes in their graphs, which  do when a factor in the numerator and denominator cancel out.

For  illustration, the function

[tex]h( x) = ( x2- 4)/(x^{2} )( x- 2)[/tex]has a hole at x =  2,

where the factor ( x- 2) cancels out in the numerator and denominator.  

Graphing rational functions can be tricky, but it helps to identify the  perpendicular and vertical asymptotes, any holes in the graph, and the  of the function near these points.

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(a) Since the character occurs with a frequency higher than 2=5, it is guaranteed to be merged with another character with the same frequency or a lower frequency. Therefore, there is guaranteed to be a codeword of length 1 for this character. (b) Since all symbols occur with a frequency less than 1=3, the root of the tree will have a frequency less than 1=3. Therefore, there is guaranteed to be no codeword of length 1 for any symbol in this case.

(a) Let's assume that some character occurs with frequency more than 2=5.

The two nodes with the lowest frequency are merged into a single node, with the sum of their frequencies as the frequency of the new node.

This process is repeated until all the nodes are merged into a single node, which becomes the root of the tree.

Since the character occurs with a frequency higher than 2=5, it is guaranteed to be merged with another character with the same frequency or a lower frequency.

Therefore, there is guaranteed to be a codeword of length 1 for this character.

(b) Let's assume that all characters occur with frequency less than 1=3.

Consider the binary tree created by the Huffman algorithm. The root of the tree corresponds to the least frequent symbol, which will be assigned the longest codeword.

Since all symbols occur with a frequency less than 1=3, the root of the tree will have a frequency less than 1=3.

This means that the corresponding codeword for the root will be longer than 1 bit. Therefore, there is guaranteed to be no codeword of length 1 for any symbol in this case.

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Therefore, the maximum value of f(x,y) inside the triangle is 80/9, which occurs along the line y = (-1/2)x + 4 at the point (8/3, 10/3), and the minimum value is -32, which occurs at the critical point (-8,4).

To find the maximum and minimum values of f(x,y) = xy on the region inside the triangle whose vertices are (6,2), (0,3), and (6,0), we use the method of Lagrange multipliers.

First, we need to find the critical points of f(x,y) subject to the constraint that (x,y) lies inside the triangle. We can express this constraint using the equations of the lines that form the sides of the triangle:

y = (-1/2)x + 4

y = (3/2)x

y = 0

Next, we set up the Lagrange multiplier equation:

∇f = λ∇g

where g(x,y) is the equation of the constraint, i.e., the triangle.

We have:

f(x,y) = xy

∇f = <y, x>

g(x,y) = y - (-1/2)x - 4 = 0

∇g = <-1/2, 1>

Setting ∇f = λ∇g, we get:

y = (-1/2)λ

x = λ

Substituting these into the constraint equation, we get:

(-1/2)λ - 4 = 0

Solving for λ, we get:

λ = -8

Substituting this into y = (-1/2)λ and x = λ, we get:

x = -8 and y = 4

Therefore, the only critical point of f(x,y) inside the triangle is (-8,4).

Next, we need to check the values of f(x,y) at the vertices and along the sides of the triangle.

At the vertices:

f(6,2) = 12

f(0,3) = 0

f(6,0) = 0

Along the line y = (3/2)x:

f(x, (3/2)x) = (3/2)x^2

Using the vertex (6,2) and the x-intercept (4/3, 2), we can see that the maximum value of (3/2)x^2 on this line occurs at x = 4. Therefore, the maximum value of f(x,y) along this line is:

f(4,6) = 24

Along the line y = (-1/2)x + 4:

f(x, (-1/2)x + 4) = (-1/2)x^2 + 4x

Using the vertex (6,2) and the x-intercept (8,0), we can see that the maximum value of (-1/2)x^2 + 4x on this line occurs at x = 8/3. Therefore, the maximum value of f(x,y) along this line is:

f(8/3,10/3) = 80/9

Finally, we need to check the values of f(x,y) at the critical point (-8,4). We have:

f(-8,4) = -32

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Answer:

Markets behave the same way as individual customers because markets are made up of individual consumers.

Step-by-step explanation:

The number of people at the convention are bored by cable news are 11079

From the question, we have the following parameters that can be used in our computation:

Proportion = Nine out of eleven people at a math convention are bored to tears by cable news.

This means that

Proportion = 9/11

If 2462 people at the convention are not bored by cable news, then we have

(1 - 9/11) * x = 2462

This gives

x = 2462/(1 - 9/11)

Evaluate

x = 13541

Next, we have

Bored = 13541 - 2462

Bored = 11079

Hence, the number of people is 11079

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Answer:Let the cost of an orange and that of a mango during the first market day be Ksh. x and Ksh. y respectively.

From the first market day:

30x + 12y = 936

From the second market day:

15(1.2x) + 20(3/4y) = 780

Simplifying the second equation:

18x + 15y = 780

(ii) Using matrix to find the cost of an orange and that of a mango in the first market day:

Rewriting the equations in matrix form:

|30 12| |x| |936|

|18 15| x |y| = |780|

Multiplying the matrices:

|30 12| |x| |936|

|18 15| x |y| = |780|

|30x + 12y| |936|

|18x + 15y| = |780|

Using matrix inversion:

| x | |15 -12| |936 12|

| y | = | -18 30| x |780 15|

|x| |270 12| |936 12|

| | = |-360 30| x |780 15|

|y|

Simplifying the matrix multiplication:

|x| |1194| |12|

| | = | 930| x |15|

|y|

Therefore, the cost of an orange in the first market day was Ksh. 39 and the cost of a mango in the first market day was Ksh. 63.

(iii) Calculation of the total amount of money realized for the sales:

On the second market day, Fatuma bought 15 oranges and 20 mangoes.

Cost of 15 oranges = 15(1.2x) = 18x

Cost of 20 mangoes = 20(3/4y) = 15y

Total cost of fruits bought on the second market day = 18x + 15y = 18(39) + 15(63) = Ksh. 1629

Profit earned on 15 oranges at 10% = 1.1(1.2x)(15) - (1.2x)(15) = 0.18x(15) = 2.7x

Profit earned on 20 mangoes at 15% = 1.15(3/4y)(20) - (3/4y)(20) = 0.15y(20) = 3y

Total profit earned = 2.7x + 3y

Total amount of money realized for the sales = Total cost + Total profit

= Ksh. 1629 + 2.7x + 3y.

Step-by-step explanation:

When the subject or predicate is missing from a sentence, the sentence error is a sentence fragment.

Sentence Errors are errors related to grammar and mechanics within sentences in Standard Written English.

An example of a sentence error will be "The children re us"

The phrase "re" is the error word in this sentence.

The three types of sentence errors we have are run-on sentences, sentence fragments and overloaded sentence.

In this problem, the type of sentence error that occurs when a sentence is missing a subject of predicate is a sentence fragment

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The cell for women who suffer from depression and drink between 2-6 cups of caffeinated coffee per week contributes 4 to the overall chi-square test statistic.

To calculate the expected count for women who suffer from depression and drink between 2-6 cups of caffeinated coffee per week under the null hypothesis, you would first need to determine the overall proportion of women who suffer from depression and drink between 2-6 cups of caffeinated coffee per week in the sample. Let's say this proportion is 0.20.

Next, you would multiply this proportion by the total sample size to get the expected count. Let's say the total sample size is 500 women. The expected count for women who suffer from depression and drink between 2-6 cups of caffeinated coffee per week would be:

Expected count = 0.20 x 500 = 100

To calculate the contribution of the cell for women who suffer from depression and drink between 2-6 cups of caffeinated coffee per week to the chi-square test statistic, you would need to subtract the expected count from the observed count for this cell, square the difference, and divide by the expected count. Let's say the observed count for this cell is 80.

Contribution to chi-square = (80 - 100)^2 / 100 = 4

This means that the cell for women who suffer from depression and drink between 2-6 cups of caffeinated coffee per week contributes 4 to the overall chi-square test statistic.

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The estimate is 7/15.

The given expression is

4/5-1/3

We see that the denominators of both functions are different

So, the numerators can't be added/subtracted directly.

For this, we need to find the equivalent fraction of the given fractions, and the equivalent fractions should have the same denominator.

Now, the denominators are 5 and 3.

To have a common denominator in both fractions, we find the LCM of the denominators.

∴ The LCM of 5 and 3 = 15

Converting the fraction 4/5 into a fraction with 15 as the denominator,

4/5=4×3/5×3=12/15.

The same for 1/3

1/3= 1×5/3×5=5/15

Replacing 4/5 and 1/3 with the equivalent fractions in the given expression, we get,

12/15-5/15=(12-5)/15=7/15

Hence, the estimate is 7/15.

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Options B & C

There is an asymptote at y = 40.

There is an asymptote at x = 0.

Concept 1. Zeros of rational functions

Concept 2. Vertical asymptotes of rational functions

Concept 3. Horizontal asymptotes of rational functions

Concept 4. Transformations - vertical shift

Rational functions have zeros at values of x where the numerator is zero, while the denominator is not also zero.

[tex]f(x)=\dfrac{40x+99}{x}[/tex]

Values that make the denominator zero
Note that for the function f(x), x=0 is the only value that will make the denominator zero.

Values that make the numerator zero
To find the value that makes the numerator zero, set the numerator equal to zero, and solve for the value of x that makes it true:

[tex]40x+99=0[/tex]

[tex]40x=-99[/tex]

[tex]x=\frac{-99}{40}[/tex]

So, [tex]x=\frac{-99}{40}[/tex] is the only value that will make the numerator zero

Note that this doesn't simultaneously make the denominator zero, so [tex]x=\frac{-99}{40}[/tex] is a zero (and the only zero) of the function f(x).

Therefore, Option A is NOT a correct answer.

Rational functions have Horizontal Asymptotes if the degree of the polynomial in the numerator is less than or equal to the degree of the polynomial in the denominator.

If the Degree of the denominator is greater, the Horizontal Asymptote is at a y=0.

If the Degrees are equal, the Horizontal Asymptote is at a y-value equal to the ratio of the leading coefficients.

[tex]f(x)=\dfrac{40x+99}{x}[/tex]

Note that for f(x), the degrees of the polynomials in the numerator and denominator are both 1.  So, a horizontal asymptote does exist, and it is at a height of the ratio of the leading coefficients.

The leading coefficient of the numerator is 40, while the leading coefficient of the denominator is 1.

The ratio of the leading coefficients, 40/1, so the horizontal asymptote is y=40.

Therefore, Option B is a correct answer choice.

Rational functions have Vertical Asymptotes at values of x where the denominator is zero, while the numerator is not also zero (the opposite of finding "zeros" of the function).

Recalling the values that make the numerator and denominator zero from Concept 1:

Since x=0 doesn't also make the numerator zero, x=0 is a vertical asymptote for the function f(x).

Therefore, Option C is a correct answer choice.

Rational functions have been vertically shifted if after all the main rational function fraction, there is a number added or subtracted.

I provide an example of a different function (which I'll call g(x)) here:

[tex]g(x)=\dfrac{3}{x}+2[/tex]

Observe that the "+2" is after all of the main fraction, so the graph of 3/x would have been shifted vertically up 2 units.

This is NOT the case for the function f(x) from the question.  The "99" is part of the fraction, so it does not represent a vertical shift.

Therefore, Option D is NOT a correct answer choice.