The number of particles in the gas is [tex]4.72 * 10^{24}[/tex], the volume of the gas at 4 atm is 40 L, and the volume of the gas at 300 K is 30 L.
Avogadro's Law: Equal volumes of gases at the same temperature and pressure contain equal numbers of particles (molecules or atoms).
Boyle's Law: For a fixed amount of gas at a constant temperature, the pressure and volume are inversely proportional to each other.
Charles's Law: For a fixed amount of gas at a constant pressure, the volume and temperature are directly proportional to each other.
PV = nRT is the formula for the ideal gas law,
where P is pressure, V is volume, n is the number of molecules of gas, R is gas constant, and T is temperature in Kelvin.
Mass of gas (m) = 4 g
Temperature (T) = 200 K
Pressure (P) = 8 atm
Volume (V) = 20 L
First, we can use the ideal gas law to calculate the number of moles of gas:
n = PV/RT
n = (8 atm * 20 L) / (0.0821 L.atm/mol.K * 200 K)
n = 7.85 moles
Next, we can use Avogadro's Law to find the number of particles (molecules or atoms):
1 mole of gas = [tex]6.02 * 10^23[/tex] particles
7.85 moles of gas =[tex]7.85 * 6.02 * 10^23[/tex]particles
= [tex]4.72 * 10^24[/tex] particles
We can also use Boyle's Law and Charles's Law to find the volume of the gas at different conditions:
Boyle's Law:
[tex]P_1V_1 = P_2V_2[/tex]
If we keep the temperature constant at 200 K, we can use this relationship to find the volume of the gas at a different pressure. Let's say we want to know the volume of the gas at 4 atm:
[tex]P_1[/tex] = 8 atm
[tex]V_1[/tex] = 20 L
[tex]P_2[/tex] = 4 atm
[tex]V_2[/tex]= ?
[tex]P_1V_1 = P_2V_2[/tex]
8 atm x 20 L = 4 atm x [tex]V_2[/tex]
[tex]V_2[/tex] = (8 atm x 20 L) / 4 atm
[tex]V_2[/tex] = 40 L
Charles's Law:
[tex]V1/T1 = V2/T2[/tex]
If we keep the pressure constant at 8 atm, we can use this relationship to find the volume of the gas at a different temperature.
Let's say we want to know the volume of the gas at 300 K:
[tex]V_1[/tex] = 20 L
[tex]T_1[/tex]= 200 K
[tex]V_2[/tex] = ?
[tex]T_2[/tex] = 300 K
[tex]V_1/T_1 = V_2/T_2[/tex]
20 L / 200 K = [tex]V_2[/tex] / 300 K
[tex]V_2[/tex] = (20 L / 200 K) x 300 K
[tex]V_2[/tex] = 30 L
Therefore, the number of particles in the gas is [tex]4.72 * 10^{24}[/tex], the volume of the gas at 4 atm is 40 L, and the volume of the gas at 300 K is 30 L.
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You are a NASA engineer and your superiors have instructed you to analyze the situation. The space craft consists of a command module and a lunar module. The command module is intended to house the three astronauts for most of the duration of the mission and enter lunar orbit, while the lunar module was designed only for the short trip from lunar orbit to the Moon’s surface and back to the command module. The lunar module is only built to support two people, with the third remaining on the command module during a lunar excursion. You have the following information: There are enough CO2 absorbers on the command module to last more than 10 days, but the LiOH cannisters are not easily compatible with the containment units on the lunar module. Each CO2 absorber on the command module contains 600g of lithium hydroxide. Each CO2 absorber on the lunar module contains 365g of lithium hydroxide. The lunar module is expected to reach Earth 3 days from now and has more than enough oxygen supply for the trip. The lunar lander is equipped with six CO2 absorbers. Each astronaut uses approximately 2500 kilocalories per day, and there are 4 kilocalories per gram of glucose. You can assume that metabolism of the astronauts can be approximated by the (unbalanced) equation for glucose metabolism given below: __6126 + __2 → __2 + __2 You need to determine: Can the three astronauts safely make the trip back to Earth with only the CO2 absorbers contained in the lunar module? If not, how many additional CO2 absorbers need to be retrieved from the command module? Write out all calculations and relevant reactions equations that you used to come to this conclusion. Could these calculations be done without using the mole?
Yes, the three astronauts can safely make the trip back to Earth with only the CO2 absorbers contained in the lunar module.
What is lunar module?The Lunar Module (LM) was a spacecraft built by the United States and used in the Apollo program to land humans on the Moon. The LM was designed and built to be used only in the vacuum of space, and it had no capability to operate in the Earth's atmosphere or on the surface of the Moon.
To determine this, we can calculate the amount of glucose needed to sustain the astronauts for the 3-day trip.
We know that each astronaut needs 2500 kilocalories per day, and there are 4 kilocalories per gram of glucose.
Therefore, each astronaut needs 625 grams of glucose per day, or 1875 grams of glucose total for the 3-day trip.
We can then convert this to moles of glucose needed, using the molar mass of glucose (180.156 g/mol).
Therefore, 1875 grams of glucose is equal to 10.4 moles of glucose.
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(b) A 10.32g of AlCl3 are allowed to vapourize in 1dm³ vessel at 80°C a pressure of 1.7 x 10 NM2 develops. What is the degree of association into AICI3 into Al2Cl6?
The degree of association of AlCl3 into Al2Cl6 is 0.663. The degree of association of AlCl3 into Al2Cl6 can be determined using the ideal gas law and the van't Hoff factor.
Firstly, we need to calculate the number of moles of AlCl3 present in the vessel using the formula n = m/M, where m is the mass of AlCl3 and M is the molar mass of AlCl3.
n = 10.32g / 133.34 g/mol = 0.0774 mol
Next, we can use the ideal gas law equation PV = nRT to calculate the number of moles of particles in the gas phase. Rearranging this equation, we get:
n = PV/RT
where P is the pressure, V is the volume, R is the gas constant and T is the temperature in Kelvin.
n = (1.7 x 10 N/m²) x 1 dm³ / (8.31 J/mol/K x 353 K) = 7.55 x 10⁻⁴ mol
The van't Hoff factor (i) is the ratio of the actual number of particles in solution to the number of formula units dissolved. For a completely dissociated compound, the van't Hoff factor is equal to the number of ions produced. In the case of AlCl3, it undergoes a degree of association to form Al2Cl6, so the van't Hoff factor is less than 1.
We can now use the formula i = 1 + (α - 1)β, where α is the degree of association and β is the number of particles in solution per formula unit. For AlCl3, β = 4 (AlCl3 contains one Al and three Cl atoms), and assuming a degree of association of x, we get:
i = 1 + (x - 1) x 4 = 4x - 3
Substituting the values for n and i into the equation n = iC, where C is the concentration in mol/dm³, we get:
7.55 x 10^-4 mol = (4x - 3) C
Solving for x, we get:
x = 0.663
Therefore, the degree of association of AlCl3 into Al2Cl6 is 0.663.
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SO4+BaCl2 double replacement
A double replacement is Na2SO4 (aq) + BaCl2 BaSO4 (s) + 2 NaCl (aq) + 2 NaCl (aq). The reaction Na2SO4 + BaCl2 is endothermic. When barium chloride (BaCl2) and sodium sulphate (Na2SO4) combine, sodium chloride and barium sulphate are formed.
What is the chemical formula for barium chloride's double replacement?When Sodium sulphate(Na 2 SO 4) interacts with Barium chloride solution (), a white precipitate of Barium sulphate() and Sodium chloride is generated.
When barium chloride is introduced to dilute sulphuric acid, a white precipitate of barium sulphate forms as a result of barium displacement from its chloride, as seen below: BaCl2 + H2SO4 BaSO4 + 2HCl.
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The total enzyme concentration is [Et]=________ nM, if [S]=6mM, Vo=480 nM/min, Km = 4
uM, and the catalytic rate constant (kcat) of the enzyme is 20. min-1
The total enzyme concentration [Et] is 6 nM.
Enzyme concentration is the amount of an enzyme present in a given solution. The concentration of enzymes can have an effect on the rate of reaction. If the concentration of enzymes is higher, the rate of reaction will be faster, and if the concentration of enzymes is lower, the rate of reaction will be slower.Enzyme concentration is important because it can affect the outcome of a reaction, and therefore, it must be carefully monitored.
The total enzyme concentration [Et] can be calculated using the Michaelis-Menten equation, which states that[tex]Vo= [Et] * kcat * (\frac{[S]}{Km} + [S])[/tex]
Plugging in the given values, we get:
[tex]480 nM/min = [Et] * 20 min^{-1}* (\frac{6mM}{4uM} + 6mM)[/tex]
Solving for [Et], we get:
[Et] = 6 nM
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what is percent yield if 56.9 g of WO3 yields 41.4 g of tungsten
Answer: 69.9 g
Explanation:
A car accelerates from 15 m/s to 30 m/s with an acceleration of 5m/s/s how long did this take?
The car took 3 seconds to accelerate from 15 m/s to 30 m/s with an acceleration of 5 m/s^2.
To find how long did this take?
We can use the following kinematic equation to solve this problem:
v = u + at
Where
v is the final velocityu is the initial velocitya is the acceleration t is the time takenGiven:
u = 15 m/s (initial velocity)
v = 30 m/s (final velocity)
a = 5 m/s^2 (acceleration)
Substituting the given values into the equation, we get:
30 m/s = 15 m/s + 5 m/s^2 × t
Simplifying and solving for t, we get:
5 m/s^2 × t = 15 m/s
t = 15 m/s ÷ 5 m/s^2 = 3 seconds
Therefore, the car took 3 seconds to accelerate from 15 m/s to 30 m/s with an acceleration of 5 m/s^2.
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H₂SO₂+2 KOH →→ K₂SO₂ + 2H₂O
A sample of sulfuric acid (H₂SO) is titrated with potassium Hydroxide (KOH) 0.5M. If 300 mL of KOH are required
to completely neutralize a 15.0 mL sample of H₂SO, what is the molar concentration of H₂SO₂?
5 M H₂SO
(magenta)
4.5 M H₂SO4
(red orange)
10 M H₂SO4
(yellow green)
The balanced chemical equation for the reaction between H₂SO₂ and KOH is:
H₂SO₂ + 2KOH → K₂SO₂ + 2H₂O
From the equation, we can see that 1 mole of H₂SO₂ reacts with 2 moles of KOH.
Given that 300 mL of 0.5 M KOH are required to neutralize 15.0 mL of H₂SO₂, we can calculate the number of moles of KOH used:
moles of KOH = Molarity × Volume (in liters) = 0.5 × 0.3 = 0.15
Since 2 moles of KOH react with 1 mole of H₂SO₂, the number of moles of H₂SO₂ in the 15.0 mL sample can be calculated as:
moles of H₂SO₂ = 0.15/2 = 0.075
The molar concentration of H₂SO₂ can be calculated as:
Molarity = moles/volume (in liters) = 0.075/(15/1000) = 5 M
Therefore, the molar concentration of H₂SO₂ is 5 M, which is magenta in the given color options.
Answer:
The balanced chemical equation for the reaction between sulfuric acid (H₂SO₄) and potassium hydroxide (KOH) is:
H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O
From the balanced equation, we can see that the stoichiometry of the reaction is 1:2, which means that 1 mole of H₂SO₄ reacts with 2 moles of KOH.
Given that 300 mL of 0.5 M KOH is required to completely neutralize a 15.0 mL sample of H₂SO₄, we can use the following equation to determine the molarity of H₂SO₄:
Molarity of H₂SO₄ x Volume of H₂SO₄ = 2 x Molarity of KOH x Volume of KOH
Molarity of H₂SO₄ = (2 x Molarity of KOH x Volume of KOH) / Volume of H₂SO₄
Molarity of H₂SO₄ = (2 x 0.5 M x 0.300 L) / 0.015 L = 20 M
Therefore, the molar concentration of the initial H₂SO₄ solution was 20 M, which corresponds to option (yellow green).
PLEASE HELP ASAP!!
Consider FIVE types of solids:
Ionic (NaCl)
Metallic (Ca)
Covalent Network (Quartz, SiO2)
Polar Molecular (sugar, C6H12O6)
Non-polar molecule
RECALL THE PHYSICAL PROPERTIES -> hardness, brittleness, the conductivity of electricity and heat, melting and boiling points, solubility in water, etc.
1. Design an experimental procedure to test these properties with the procedures below.
-> the ones I have so far
- ionic solids -> use NaCl and dissolve in water to test the solubility
- conductivity - by putting the solid under two free ends of the wire
-> solubility - using boiling water for all as ionic solids break into ions & conduct electricity
- brittleness - using a hammer or any other form of stress (if brittle, tends to break under stress)
- hardness - using a hydraulic press/Rockwell testing
- melting/boiling point - add heat to a sample after placing in a beaker or test tube to test
SOME OTHER THINGS WE CAN USE (but I'm unsure as to what we can use it for): a thermal camera
2. WRITE A HYPOTHESIS for ONE TYPE of solid with a brief explanation.
3. Design a Table of Observations for your experiments.
The tests that can be used to determine the kinds of solids that have been listed are shown below.
What are the solid types?Here are some tests that can be used to show that a solid is:
Ionic (NaCl):
Solubility test: NaCl is highly soluble in water, and a high degree of solubility can confirm the ionic nature of NaCl.
Conductivity test: In its molten or dissolved state, NaCl conducts electricity due to the presence of charged ions.
Metallic (Ca):
Conductivity test: Metals such as Ca conduct electricity due to the presence of free electrons in their crystal structure.
Ductility and malleability test: Metals are ductile and malleable, and can be easily deformed under pressure.
Covalent Network (Quartz, SiO2):
Hardness test: Covalent network solids such as quartz are extremely hard due to the strong covalent bonds between atoms.
Melting point test: Covalent network solids often have high melting and boiling points due to the strong intermolecular forces between atoms.
Polar Molecular (sugar, C6H12O6):
Solubility test: Polar molecules such as sugar are soluble in polar solvents such as water but insoluble in nonpolar solvents.
Melting and boiling point test: Polar molecular solids have lower melting and boiling points compared to ionic or covalent network solids due to weaker intermolecular forces.
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7.25 g of a mixture of KCl and KClO3 is heated with MnO2 catalyst and the mass of the mixture is found to be 5.50 g after heating. What is the mass percentage of KClO3 in the initial mixture? (K: 39.0 g/mol, Cl: 35.5 g/mol, O: 16.0 g/mol)
The mass percentage of KClO₃ in the initial mixture, given that the initial mixture has a mass of 7.25 g, is 62.2%
How do i determine the mass percentage of KClO₃?First, we shall determine the molar mass of KClO₃ and KCl. Details below:
For KClO₃
Molar mass of K = 39 g/molMolar mass of Cl = 35.5 g/molMolar mass of O = 16 g/molMolar mass of KClO₃ = ?Molar mass of KClO₃ = 39 + 35.5 + (3 × 16)
Molar mass of KClO₃ = 39 + 35.5 + 48
Molar mass of KClO₃ = 122.5 g/mol
For KCl
Molar mass of K = 39 g/molMolar mass of Cl = 35.5 g/molMolar mass of KCl =?Molar mass of KCl = 39 + 35.5
Molar mass of KCl = 74.5 g/mol
Next, we shall determine the mass of KClO₃ in the initial mixture. Details below:
Molar mass of KClO₃ = 122.5 g/molMolar mass of KCl = 74.5 g/molMass of mixture = 7.25 gMass of KClO₃ =?Mass of KClO₃ = [molar mass of KClO₃ / molar mass of (KClO₃ + KCl)] × mass of mixture
Mass of KClO₃ = [122.5 / (122.5 + 74.5)] × 7.25
Mass of KClO₃ = 4.51 g
Finally, we shall determine the mass percentage of KClO₃. Details below:
Mass of KClO₃ = 4.51 gMass of mixture = 7.25 gMass percentage of KClO₃ =?Mass percentage of KClO₃ = (mass of of KClO₃ / mass of mixture) × 100
Mass percentage of KClO₃ = (4.51 / 7.25) × 100
Mass percentage of KClO₃ = 62.2%
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What makes Hess' Law useful? Try to cite the information you provided in question #9 for this.
above is question #9
Magnesium oxide turns a white powder as a result. Magnesium creates by transferring two electrons oxygen atoms. This reaction is exothermic. Magnesium + oxygen → magnesium oxide. 2Mg + O2 → 2MgO.
What happens when magnesium ribbon burns?An illustration of a combination reaction is the burning of magnesium ribbon to produce magnesium oxide. One chemical splits into two compounds, one with a high oxidation state and the other with a low oxidation state, in a disproportionation reaction.
Burning is a form of reaction, right?The evolution of light and heat causes an exothermic chemical reaction that results in fire. Three essential components—oxygen, heat, and fuel—must all be present for such a fire to start. The kind of reaction that results in flames is referred to as a combustion reaction in chemistry.
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What is the molarity (M) of a bleach solution containing 9.50 grams of bleach (NaOCI) in 2,000 ml of solution? BLEACH
SHOW workkk
The bleach solution has a molarity of 0.0637 M.
What is NaOCl, a substance present in numerous bleaches?Sodium hypochlorite is an inorganic chemical compound with the formula NaOCl (or NaClO), consisting of a sodium cation (Na+) and a hypochlorite anion (OCl or ClO). It is usually referred to in diluted solutions as (chlorine) bleach. It can also be thought of as hypochlorous acid's sodium salt.
Converting the mass of bleach (NaOCl) to moles is the first step.
moles of NaOCl = mass of NaOCl / molar mass of NaOCl
The molar mass of NaOCl is approximately 74.44 g/mol (22.99 g/mol for Na, 15.99 g/mol for O, and 35.45 g/mol for Cl).
moles of NaOCl = 9.50 g / 74.44 g/mol
moles of NaOCl = 0.1274 mol
Next, we may determine the molarity (M) of the bleach solution using the notion of molarity:
Molarity = moles of solute / liters of solution
The solution's volume is supplied to us in millilitres, so we must convert it to litres:
2,000 ml = 2,000 / 1,000 = 2.00 L
Molarity = 0.1274 mol / 2.00 L
Molarity = 0.0637 M
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Why would a gas fire not be a plasma?
What volume is occupied by 16.4 grams of mercury? The density of mercury is 13.6g/ml
If the density of mercury is 13.6 g/mL, the volume of a 155-gram sample of mercury is 11.397 mL.
What is meant by volume?The area contained by an object's limits in three-dimensional space is referred to as its volume. Another name for it is an object's capacity.A student could measure the volume of a chemical solution in millilitres using a graduated cylinder as an illustration of volume. A quart of milk might be obtained. Gases are frequently offered for sale in volumetric units like cubic centimetres, or cm3, or cubic litres. For example, the capacity of a rectangular container, the basic formula for understanding volume is length x width x depth. The space an object occupies is simply referred to as its volume. There are several techniques for measuring volume, depending on the physical characteristics of an object.It follows that:
Mercury has a density of 13.6 g/mL.
155 grammes make to the mercury's weight.
The fact is,
A three-dimensional space enclosed by an object or thing is referred to as its volume.
Mass times volume equals density.
13.6 = Volume 155
quantity = 155/13.6
11.397 mL is the capacity.
As a result, assuming mercury has a density of 13.6 g/mL, a 155-gram sample of mercury has a volume of 11.397 mL.
The complete question is:
The density of mercury is 13.6 g/mL. What is the volume of a 155-gram sample of mercury?
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how many hydrogen-bonds does this molecule have?
how many acceptors does it have?
How many h-bonds can this molecule form with another identical
How many h-bonds can it form with water?
The compound would have six hydrogen bonds.
It has 3 H bond acceptors. It can form six H bonds with an identical molecule. It can form three hydrogen bonds with water.
What are hydrogen bonds?Hydrogen bonds are a type of intermolecular force that occurs between a hydrogen atom bonded to an electronegative atom (such as nitrogen, oxygen, or fluorine) and a nearby electronegative atom on another molecule.
The hydrogen bond is a weak electrostatic attraction between the partially positive hydrogen and the partially negative atom, which is typically a lone pair of electrons on the other molecule.
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How many moles of glucose (C,H,O,) are needed to make a 800 ml of a 3.0 M glucose solution? SHOW WORK
Answer:
To make an 800 mL solution of 3.0 M glucose (C6H12O6), you would need 2.4 moles of glucose.
Here’s the work: Molarity (M) = moles of solute / liters of solution Rearranging the equation to solve for moles of solute: moles of solute = Molarity (M) * liters of solution Since you have 800 mL or 0.8 L of a 3.0 M glucose solution: moles of glucose = 3.0 M * 0.8 L = 2.4 moles.
A balloon filled with helium has a volume of 18.2 L
at 303 K.
What volume will the balloon occupy at 271 K?
What is the molarity (M) of a solution made by dissolving 75 g of Epsom salt (MgSO,) in 2.3 Liters of solution?
SHOW WORK
The molarity of a solution made by dissolving 75 g of Epsom salt in 2.3 liters of solution would be 0.27 M.
Molarity calculationThe first step in calculating the molarity of the solution is to determine the number of moles of MgSO4 dissolved in 2.3 liters of solution.
The molar mass of MgSO4 is:
24.31 g/mol (for Mg) + 32.06 g/mol (for S) + 4x16.00 g/mol (for 4 O) = 120.37 g/mol
The number of moles of MgSO4 can be calculated using the formula:
moles = mass / molar mass
moles = 75 g / 120.37 g/mol = 0.623 moles
Next, we need to calculate the molarity (M) of the solution, which is defined as the number of moles of solute (MgSO4) per liter of solution:
Molarity = moles of solute / liters of solution
Molarity = 0.623 moles / 2.3 L = 0.27 M
Therefore, the molarity of the solution made by dissolving 75 g of Epsom salt (MgSO4) in 2.3 Liters of solution is 0.27 M.
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Draw the major product(s) of electrophilic chlorination of m-methoxybenzoic acid.
Here is your answer. Please mark me as Brainliest if possible! :) You can redraw this.
Ammonia (NH3) chemically reacts with oxygen gas (O2) to produce nitric oxide (NO) and water (H2O).
What mass of water is produced by the reaction of 1.06 of oxygen gas?
Round your answer to 3 significant digits.
The mass of water, H₂O produced by the reaction of 1.06 grams of oxygen gas, O₂ is 0.72 grams
How do I determine the mass of water, H₂O produced?The mass of water, H₂O produced by the reaction of 1.06 grams of oxygen gas, O₂ can be obtained as shown below:
The balanced equation for the reaction is given below
4NH₃ + 5O₂ -> 4NO + 6H₂O
Molar mass of O₂ = 32 g/molMass of O₂ from the balanced equation = 5 × 32 = 160 g Molar mass of H₂O = 18 g/molMass of H₂O from the balanced equation = 6 × 18 = 108 gFrom the balanced equation above,
160 g of oxygen gas, O₂ reacted to produce 108 g of water, H₂O
Therefore,
1.06 g of oxygen gas, O₂ will react to produce = (1.06 × 108) / 160 = 0.72 g of water, H₂O
Thus, the mass of water, H₂O produced from the reaction is 0.72 g
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how many moles of h3po4 form from 8.0 moles of H2O?
5.3 moles of H3PO4 form from 8.0 moles of H2O.
What is Moles?
Moles (mol) is a unit of measurement used in chemistry to express amounts of a chemical substance. One mole of a substance is defined as the amount of that substance that contains as many elementary entities (such as atoms, molecules, or ions) as there are atoms in 12 grams of carbon-12, which is Avogadro's number (6.022 × 10²³) of particles.
According to the balanced chemical equation, 1 mol of P4010 reacts with 6 mol of H2O to produce 4 mol of H3PO4. Therefore, we can set up a proportion:
6 mol H2O/1 mol P4010 = 4 mol H3PO4/x mol H2O
Solving for x, we get:
x = (8.0 mol H2O * 4 mol H3PO4) / 6 mol H2O
x = 5.3 mol H3PO4
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can someone balance?
__Fe+__HCl=__FeCl2+__H2
[tex]Fe +2 HCl[/tex] yields [tex]FeCl_2[/tex] and [tex]H_2[/tex]. One atom of [tex]Fe[/tex] combines with two compounds of [tex]HCl[/tex] to create 1 molecule of [tex]FeCl_2[/tex] or one molecule of [tex]H_2[/tex], as shown by the equation's balanced form. [tex]2Fe + 2HCl = 2FeCl_2 + H_2[/tex]
What is the balanced chemical equation?A mathematical statement known as an equation is created when two expressions are joined by the equal sign. An example is [tex]3x - 5[/tex] 16 in mathematics. By resolving this equation, we may find that the variable x has a value of 7.
[tex]Fe^ +2[/tex] [tex]HCl[/tex] produces [tex]H_2[/tex] and [tex]FeCl2.[/tex] According to the equation's balanced version, one atom of Fe reacts with two [tex]HCl[/tex] molecules to make one molecule of [tex]FeCl_2[/tex] or one molecule of [tex]H_2[/tex].
Therefore, [tex]2Fe + 2HCl = 2FeCl_2 + H_2[/tex] one atom of Fe reacts with two [tex]HCl[/tex] molecules to make one molecule of [tex]FeCl_2[/tex] or one molecule of [tex]H_2[/tex].
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2. Radical chlorination of 2-methylpentane yields a mixture of monochlorinated products. (i) Draw all monochlorinated products resulting from reaction of 2 methylpentane. (ii) Identify the major product. Iii) Show step-wise mechanism for the radical halogenation of the major product. (8) i. mixture of isomers 2-methylPentane
The chlorine radicals can also react with each other to form chlorine molecules, which terminates the chain reaction.
(i) The monochlorinated products resulting from the reaction of 2-methylpentane are:
1-chloro-2-methylpentane
2-chloro-2-methylpentane
3-chloro-2-methylpentane
(ii) The major product in this reaction is 2-chloro-2-methylpentane.
(iii) The step-wise mechanism for the radical halogenation of 2-chloro-2-methylpentane are:
1. Initiation :- This step involves the homolytic cleavage of the chlorine molecule to form two chlorine radicals.
[tex]Cl^ 2[/tex]→ [tex]2Cl[/tex]·
2.Propagation:- [tex]Cl[/tex]· + 2-methylpentane → [tex]HCl[/tex] + 2-methylpentyl•
2-methylpentyl• +[tex]Cl^ 2[/tex] → 2-chloro-2-methylpentyl• + [tex]Cl[/tex]·
The 2-methylpentane molecule reacts with the chlorine radical to form a 2-methylpentyl radical and hydrogen chloride. The 2-methylpentyl radical then reacts with another chlorine molecule to form the 2-chloro-2-methylpentyl radical and another chlorine radical.
3.Termination:- 2-methylpentyl• + [tex]Cl[/tex]· → 2-chloro-2-methylpentane
2-methylpentyl• + 2-methylpentyl• → 2,2-dimethylpentane
[tex]Cl[/tex]· + [tex]Cl[/tex]· → [tex]Cl^ 2[/tex]
The 2-chloro-2-methylpentyl radical reacts with a chlorine radical to form the major product, 2-chloro-2-methylpentane. The 2-methylpentyl radical also reacts with another 2-methylpentyl radical to form 2,2-dimethylpentane.
Finally, the chlorine radicals can also react with each other to form chlorine molecules, which terminates the chain reaction.
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Ammonia (NH3) chemically reacts with oxygen gas (O2) to produce nitric oxide (NO) and water (H2O). What mass of oxygen gas is consumed by the reaction of 2.0 g of ammonia?
4.69 g of oxygen gas is consumed by the reaction of 2.0 g of ammonia.
What is Atomic Mass?
Atomic mass is the mass of an atom of a chemical element, expressed in atomic mass units (amu). It is a measure of the total number of protons and neutrons in the nucleus of an atom. The atomic mass is usually given relative to the mass of a carbon-12 atom, which is assigned a mass of exactly 12 atomic mass units.
The balanced chemical equation for the reaction is:
4NH3 + 5O2 → 4NO + 6H2O
From the equation, we can see that 4 moles of NH3 reacts with 5 moles of O2. We need to determine how many moles of NH3 we have, and then use the mole ratio to calculate the number of moles of O2 needed.
First, we calculate the number of moles of NH3:
moles of NH3 = mass of NH3 / molar mass of NH3
moles of NH3 = 2.0 g / 17.03 g/mol (molar mass of NH3)
moles of NH3 = 0.1174 mol
Now we use the mole ratio from the balanced chemical equation to calculate the number of moles of O2:
moles of O2 = (5/4) x moles of NH3
moles of O2 = (5/4) x 0.1174 mol
moles of O2 = 0.1468 mol
Finally, we can use the number of moles of O2 to calculate the mass of O2 consumed:
mass of O2 = moles of O2 x molar mass of O2
mass of O2 = 0.1468 mol x 32.00 g/mol (molar mass of O2)
mass of O2 = 4.69 g
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Determine the quantity of molecules in 2.00 moles of P4
50 points
what type of process is this
chemical
physical
nuclear
Answer:
Nucular
Explanation:
When one atom splits into 2, it's nucular
.In a popular classroom demonstration, solid lithium is added to liquid water and reacts to produce hydrogen gas and aqueous lithium hydroxide.
Part A
Enter a balanced chemical equation for this reaction.
Express your answer as a chemical equation including phases
Because sodium is such a highly reactive metal, it interacts with water quickly to produce sodium hydroxide and hydrogen gas. The correct chemical formula is: H2O + Na(s) = NaOH (aq) + H2 (g)
What is the name of the acid that, when combined with lithium hydroxide, yields lithium chloride and water?Hydrochloric acid and lithium oxide react, neutralising the acid. Lithium chloride and water are the results of the process.
Why does potassium, which releases less energy, react forcefully and catch fire whereas lithium reacts calmly with water?A larger surface area is exposed to the water as the molten metal flows across it. Moreover, among all alkali metals, lithium has the largest hydrated radius. This reduces the ionic mobility, which causes the molten metal to move more slowly.
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HELP PLEASE I NEED IT BY TOMORROW photo attached
The specific heat capacity of the metal, given that the metal was heated to 97 °C and transferred to water at 20.5 °C, is 0.203 Cal/gºC
How do I determine the specific heat capacity of the metal?We'll begin by obtaining the heat absorbed by the water. Details below:
Mass of water (M) = 86.0 gInitial temperature (T₁) = 20.5 °CFinal temperature (T₂) = 24.1 °CTemperature change (ΔT) = 24.1 - 20.5 = 3.6 °CSpecific heat capacity of water (C) = 1 Cal/gºC Heat absorbed (Q) =?Q = MCΔT
Q = 86 × 1 × 3.6
Q = 309.6 Cal
Finally, we shall determine the specific heat capacity of the metal. Details below:
Heat absorbed by water (Q) = 309.6 CalHeat released by metal (Q) = -309.6 CalMass of metal (M) = 20.9 gInitial temperature (T₁) = 97 °CFinal temperature (T₂) = 24.1 °CTemperature change (ΔT) = 24.1 - 97 = -72.9 °CSpecific heat capacity of metal (C) = ?Q = MCΔT
-309.6 = 20.9 × C × -72.9
-309.6 = -1523.61 × C
Divide both sides by -1523.61
C = -309.6 / -1523.61
C = 0.203 Cal/gºC
Thus, we can conclude that the specific heat capacity of the metal is 0.203 Cal/gºC
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How many grams of H3PO4 are produced when 43.6 moles of
water react with an excess of
P40(s) → 4H3PO4(aq)
a. 2850
b. 5.34
c. 158
d. 6410
Answer is closest to option (a) 2850 g. The mole is a fundamental concept in chemistry and is used extensively in calculations involving chemical reactions and stoichiometry.
What is Mole?
The mole is used to convert between the mass of a substance and the number of particles it contains. For example, the molar mass of a substance (the mass of one mole of that substance) can be used to convert the mass of a sample to the number of moles of that substance present.
The balanced chemical equation for the reaction is:
P4O10(s) + 6H2O(l) → 4H3PO4(aq)
From the equation, we can see that for every 6 moles of water that react, 4 moles of H3PO4 are produced.
So, to calculate the moles of H3PO4 produced, we first need to calculate the moles of water that react. The question states that 43.6 moles of water react, so we can use this value to calculate the moles of H3PO4 produced:
moles of H3PO4 = (4/6) x 43.6 = 29.07 moles
Finally, we can use the molar mass of H3PO4 to convert moles to grams:
grams of H3PO4 = moles of H3PO4 x molar mass of H3PO4
= 29.07 moles x 98 g/mol
= 2848.86 g
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Which of the following is the correct (and complete) formula for solid sodium sulfide? NaS₂ SOS NaS Na₂S (s) Na₂S
1. What is the molarity of a solution that contains 0.25 moles of NaOH dissolved in 3.0 Liters solution?
Answer:
A 3.0 M solution of NaOH has 3.0 moles of NaOH per liter of solution. There are 0.25 L of solution (250mL⋅1L1000mL), so there are 0.25L⋅3.0mol/L=0.75mol of NaOH. The molar mass of NaOH is 40.0 g/mol, so there are 0.75mol⋅40.0g/mol=30g of NaOH, 30.
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