3. What will be the final volume of a 3. 50 L sample of nitrogen at 20. 0 °C if it is heated to 200. °C?

4. The volume of a gas decreased from 2. 40 L to 830. ML and the final temperature is set at 40. 0 °C. Assuming a constant pressure, calculate the initial temperature of the gas in kelvins.

5. A sample of helium gas at 1. 40 atm is heated from 23. 0 °C to 400. 0 K. How many atmospheres is the final pressure of the helium gas?

6. A sample of hydrogen gas is added in a 5. 80 L container at 56. 0 °C. How many moles of the gas are present in the container if the pressure is 6. 70 atm?

7. What is the pressure in a 26. 0 L container with 5. 40 moles of nitrogen dioxide if the temperature is 64. 0°C?

8. A 3. 7 L gas sample, initially at STP, is heated to 280. °C at constant volume. Calculate the final pressure of the gas in atm.

9. Use kinetic molecular theory to relate (translational) kinetic energy to temperature.

10. A flask is charged with 0. 100 mol of A and allowed to react to form B according to the hypothetical gas-phase reaction A(g) ¡ B(g). The following data are collected:

Time (s) 0 40 80 120 160 Moles of A 0. 100 0. 067 0. 045 0. 030 0. 020

11. For each of the following gas-phase reactions, indicate how the rate of disappearance of each reactant is related to the rate of appearance of each product:

(a) C2H5NH2 C2H4 + NH3 (b) N2 + 3 H2 2 NH3

12. Consider the combustion of H2(g): 2 H2(g) + O2(g) 2 H2O(g). If hydrogen is burning at the rate of 0. 48 mol. L-1/s, what is the rate of consumption of oxygen? What is the rate of formation of water vapor?

13. Consider the combustion of ethylene, C2H4 + 3 O2(g) 2 H2O(g). If the concentration of C2H4 is decreasing at the rate of 0. 036 M/s, what are the rates of change in the concentrations of CO2 and H2O?

Answers

Answer 1

3.The final volume of the nitrogen gas is 5.65 L.

4.The initial temperature of the gas was 319 K.

5.The final pressure of the helium gas is 1.90 atm.

6.There are 1.48 moles of hydrogen gas in the container.

7.we get:P = nRT/V = (5.40 mol * 0.08206 L atm/mol

8.The final pressure of the gas is 2.11 atm.

9.The average velocity and kinetic energy of its molecules also decrease.

10. Rate of reaction t = 160 s: rate = -(0.030-0.020)/40 = 0.0025 mol/s

11.Rate of appearance of NH3 = 2 x Rate of the reaction

12.The rate of formation of H2O is equal to the rate of consumption of H2, which is 0.48 mol/L/s.

13.The rate of change in the concentration of CO2 is 0.108 M/s, and the rate of change in the concentration of H2O is 0.072 M/s.

3.To solve this problem, we can use the Ideal Gas Law, PV=nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.Therefore, we can use the formula V1/T1=V2/T2, where V1 and T1 are the initial volume and temperature, and V2 is the final volume and T2 is the final temperature.

V2 = V1(T2/T1) = 3.50 L * (473 K / 293 K) = 5.65 L

Therefore, the final volume of the nitrogen gas is 5.65 L.

4.Gas Law, which states that PV/T = constant for a given amount of gas. Since the pressure is constant, we can use the formula V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature. Solving for the initial temperature, we get:

T1 = (V1/T1) * (T2/V2) = (2.40 L / 40.0 °C) * (273.15 + 40.0) K / (830. mL / 1000 mL/L) = 319 K

Therefore, the initial temperature of the gas was 319 K.

5.To solve this problem, we can use the formula for the Ideal Gas Law, PV=nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.Therefore, we can use the formula P1/T1 = P2/T2, where P1 and T1 are the initial pressure and temperature, and P2 and T2 are the final pressure and temperature. Plugging in the values, we get:

P2 = P1(T2/T1) = 1.40 atm * (400.0 K / 296.15 K) = 1.90 atm

Therefore, the final pressure of the helium gas is 1.90 atm.

6.the Ideal Gas Law, PV=nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. We can assume that the number of moles of hydrogen gas is constant since there is no indication of a chemical reaction. Plugging in the values, we get:

n = PV/RT = (6.70 atm * 5.80 L) / (0.08206 L atm/mol K * 329.15 K) = 1.48 mol

Therefore, there are 1.48 moles of hydrogen gas in the container.

7.To solve this problem, we can use the formula for the Ideal Gas Law, PV=nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

P = nRT/V = (5.40 mol * 0.08206 L atm/mol

8. PV/T = constant. Since the gas is kept at constant volume, V is constant. so n is constant. At STP, P = 1 atm and T = 273.15 K. Converting the temperature to Kelvin gives 553.15 K for the final temperature. Using the combined gas law, we get:

P₁/T₁ = P₂/T₂

1 atm/273.15 K = P₂/553.15 K

P₂ = 2.11 atm

Therefore, the final pressure of the gas is 2.11 atm.

9.According to kinetic molecular theory, the temperature of a gas is related to its average translational kinetic energy.

10.The rate of the reaction can be calculated using the formula:

rate = -Δ[A]/Δt = Δ[B]/Δt

where Δ[A] is the change in the concentration of A over time Δt, and Δ[B] is the change in the concentration of B over time Δt. Using the data provided, we can calculate the rate of the reaction at different time intervals:

t = 40 s: rate = -(0.100-0.067)/40 = 0.00825 mol/s

t = 80 s: rate = -(0.067-0.045)/40 = 0.0055 mol/s

t = 120 s: rate = -(0.045-0.030)/40 = 0.00375 mol/s

t = 160 s: rate = -(0.030-0.020)/40 = 0.0025 mol/s

11.In the gas-phase reactions (a) C2H5NH2 C2H4 + NH3 and (b) N2 + 3 H2 2 NH3, the rate of appearance of each product is equal to its stoichiometric coefficient multiplied by the rate of the reaction. Therefore:

(a) Rate of disappearance of C2H5NH2 = -1 x Rate of the reaction

Rate of appearance of C2H4 = 1 x Rate of the reaction

Rate of appearance of NH3 = 1 x Rate of the reaction

(b) Rate of disappearance of N2 = -1 x Rate of the reaction

Rate of disappearance of H2 = -3 x Rate of the reaction

Rate of appearance of NH3 = 2 x Rate of the reaction

12.In the combustion of H2(g), 2 H2(g) + O2(g) 2 H2O(g), the balanced equation shows that for every 2 moles of H2 burned, 1 mole of O2 is consumed and 2 moles of H2O are formed. The rate of formation of H2O is equal to the rate of consumption of H2, which is 0.48 mol/L/s.

13.The rate of change in the concentration of CO2 is 0.108 M/s, and the rate of change in the concentration of H2O is 0.072 M/s.

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Related Questions

If a student measures the density of aluminum as 2. 87 g/mL and the actual value is 2. 69 g/mL, what is the student's % error?

Answers

If the student measures the density of the aluminum as 2. 87 g/mL and the actual value is the 2.69 g/mL,  the student's % error is 6.6 %.

The measures density of the aluminum  = 2.87 g/mL

The actual density of the aluminum = 2.69 g/mL

The expression of the percent error is as follows :

% error = (|actual value - measured value | / actual value ) × 100 %

% error = (|2.87 - 2.69 | / 2.69 ) × 100 %

% error = 0.066 × 100 %

% error  = 6.6 %

Thus, the percent error is 6.6 %.

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Find and calculate the heat released using the following equation.

Q = (451 g)(4.18 J/(g·°C)(18 degrees)

q = mCΔT

m– mass of water in grams (g)

C– specific heat capacity, in this case of liquid water [4.18 J/(g-°C)]; a subscript may be added to C to note the type of fluid

ΔT– temperature change of the water (°C)

(I've gathered the data for the equation, I just need help solving it if anyone would be nice enough to lend a quick hand with it. Thank you in advance.)

Answers

According to the given data, by using formula q = mCΔT, the heat released is approximately 34,534.68 J.

What is a heat?

Heat is the interchange of "thermal" energy caused by a temperature difference. Think about an isolated system with two subsystems that are originally operating at two different temperatures. Energy is moved from the subsystem 2 with a greater temperature to the subsystem 1 with a lower temperature.The energy that results to the movement of molecules and atoms in a material is known as thermal energy, also known as heat. These particles get hotter as they travel more quickly. The thermal energy of the ground is known as geothermal energy. Energy that is held in motion is called motion energy.

Using the given formula:

Q = (451 g)(4.18 J/(g·°C)(18 degrees)

Q = (451 g) x (4.18 J/(g·°C)) x (18°C)

Q = 34,534.68 J

Therefore, the heat released is approximately 34,534.68 J.

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How could you describe, in three different ways, the reaction that occurs when heating magnesium and oxygen to form magnesium oxide

Answers

Answer:

For example, when magnesium reacts with oxygen to form magnesium oxide, the magnesium atom loses two electrons to form the Mg2+ cation, which has electronic configuration 2,8. The oxygen atom gains these electrons to form the O2– anion, with electronic configuration 2,8.

What mass of iron (III) hydroxide precipitate can be produced by reacting 75.0 mL of 0.105 M iron (III) nitrate with 125 mL of 0.150 M sodium hydroxide?​

Answers

Explanation:

Refer to pic above.........

Final answer:

The amount of iron (III) hydroxide that can be produced by the reaction of 75.0 mL of 0.105 M iron (III) nitrate with 125 mL of 0.150 M sodium hydroxide is 0.841 g.

Explanation:

This problem can be solved using stoichiometry. The balanced reaction is: Fe(NO₃)₃ + 3 NaOH -> Fe(OH)₃ + 3 NaNO₃. This tells us that one mole of iron (III) nitrate reacts with three moles of sodium hydroxide to produce one mole of iron (III) hydroxide.

First, we need to convert the volumes of the solutions to moles using their molarities. So, for iron (III) nitrate: (0.105 moles/L) x (0.075 L) = 0.007875 moles, and for sodium hydroxide: (0.150 moles/L) x (0.125 L) = 0.01875 moles.

Iron (III) nitrate and sodium hydroxide react in a 1:3 ratio. Here, sodium hydroxide is in excess and iron (III) nitrate is the limiting reagent, as (0.01875 moles)/(3) > 0.007875 moles. So, the amount of iron (III) hydroxide formed will be equal to the amount of iron (III) nitrate used.

The molar mass of iron (III) hydroxide is 106.87 g/mol. Therefore, the mass of iron (III) hydroxide precipitate is: (0.007875 moles) x (106.87 g/mol) = 0.841 g.

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The volume and number of moles of a gas are held constant. Which of the following is true for the pressure of the gas? (1 point) Select one: a. It is inversely proportional to the temperature of the gas. b. It is directly proportional to the temperature of the gas. c. It is inversely proportional to the mass of the gas. d. It is equal to the mass of the gas.

Answers

The correct answer is

a. It is inversely proportional to the temperature of the gas.

What is Mass?

Mass is a fundamental physical property of matter that determines the weight and force of an object in a gravitational field. It is the amount of matter in an object, and is typically measured in units such as kilograms or grams. The mass of an object is constant and does not change with location, while weight can vary depending on the gravitational force at a given location. Mass is also a measure of the inertia of an object, which is its resistance to a change in motion.

This question relates to the gas laws, specifically the relationship between pressure, volume, temperature, and number of moles of a gas. According to Boyle's Law, when the number of moles of a gas is held constant, pressure and volume are inversely proportional to each other.

However, the question states that volume and number of moles are held constant, so this relationship doesn't apply. Instead, we need to consider Charles's Law, which states that at constant pressure and number of moles, the volume of a gas is directly proportional to its temperature.

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What best describes the interaction described below:
Dodder and shrub. The Dodder plant grows on the shrub. The dodder takes water from the shrub and the branches of the dodder pierce the tissues of the shrub. Eventually the shrub will die.
Group of answer choices

Answers

One method of obtaining these nutrients from the shrub is through the branches of the Dodder plant penetrating the tissues of the shrub. This is an illustration of a partnership in which only one creature benefits.

What really is tissue and what does it do?

Tissue is a collection of cells with a common structure and function that work as a single unit. The brain give it shape and help it retain heat and energy. ibrocartilage, epithelial tissue, muscle tissue, and nervous tissue are the four different types of tissues.

What do cells in tissue do?

Your organism is made up of cells, and tissues are created when groupings of cells carry out similar tasks. Your body consists mostly of four different tissue types: connective, epithelial, muscular, and nervous tissue. Organs are cushioned and joined together by connective tissue. The skin's outer layer is made up of epithelial tissue.

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How it is easier to break an N-H bond and N-O bond than it is to break a N2 bond

Answers

It is easier to break the N-H bond and the N-O bond than it is to break the N₂ bond as the triple bond is the strongest bond as compared to the single bond.

The Bond length reduces as the bond strength will increases, the single bonds will breaks more quickly than the double and the triple bonds. The triple bond has the stronger bond strength and the shorter bond lengths than the single and the double bonds.

Thus, it is easier to the the N-H bond and the N-O bond as compared to the  N₂ bond or the N ≡ N.

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4. In an experiment, 170.9 g of C_{2}*H_{4} was reacted with 52.75L of , 64.1 g of C*O_{2} is produced .What is the limiting reagent? ) What is the percent yield of this reaction?

Answers

O₂ is the limiting reagent and C₂H₄ is in excess.

The percent yield is 92.8%

The Limiting Reagent

To determine the limiting reagent, we need to compare the amounts of reactants and products using stoichiometry. The balanced equation for the reaction between C₂H₄ and O₂ to produce CO₂ and H₂O is:

C₂H₄ + 3 O₂ → 2 CO₂ + 2 H₂O

From the given data, we can calculate the number of moles of each reactant:

moles of C₂H₄ = 170.9 g / 28.05 g/mol = 6.089 mol

moles of O₂ = 52.75 L * (1 mol / 22.4 L) = 2.357 mol

moles of CO₂ produced = 64.1 g / 44.01 g/mol = 1.456 mol

Now we can use the stoichiometric coefficients from the balanced equation to determine which reactant is limiting:

For every 1 mole of C₂H₄, we need 3 moles of O₂ to produce 2 moles of CO₂.

The moles of O₂ available (2.357 mol) are less than what is required (3 × 6.089 mol = 18.267 mol) if all the C₂H₄ reacts, so O₂ is the limiting reagent.

Therefore, O₂ is the limiting reagent and C₂H₄ is in excess.

To calculate the theoretical yield of CO₂, we use the amount of limiting reagent:

moles of CO₂ produced = 2.357 mol O₂ × (2 mol CO₂ / 3 mol O₂) = 1.571 mol CO₂

theoretical yield of CO₂ = 1.571 mol × 44.01 g/mol = 69.12 g CO₂

The percent yield of the reaction can be calculated by dividing the actual yield (64.1 g) by the theoretical yield (69.12 g) and multiplying by 100:

percent yield = (64.1 g / 69.12 g) × 100% = 92.8%

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Phosphorus reacts with chlorine gas to produce phosphorus trichloride:
1. Write the chemical equation and balance
2. How many moles of chlorine gas are required to produce 17 moles of PCI3 ?

Answers

Answer:

1. P4 + 6Cl2 → 4PCI3; already balanced

2. 25.5 moles Cl2

Explanation:

1. The chemical equation for the reaction of phosphorus with chlorine gas to produce phosphorus trichloride is:

P4 + 6Cl2 → 4PCI3

The equation is already balanced

2. The equation shows that 6 moles of chlorine gas are required to produce 4 moles of phosphorus trichloride.

set up a proportion:

6 moles Cl2 / 4 moles PCI3 = x moles Cl2 / 17 moles PCI3

solve for x:

x = (6 moles Cl2 / 4 moles PCI3) x 17 moles PCI3

x = 25.5 moles Cl2

Therefore, 25.5 moles of chlorine gas are required to produce 17 moles of phosphorus trichloride.

Answer:

25.5 moles of Cl₂ required

Explanation:

2P + 3Cl₂ --> 2PCl₃

Since, the stoichiometry (molar ratio) of the reaction is 2 : 3 : 2,

thus, number of moles of Cl₂ = 3/2 × number of moles of PCl₃

∴ number of moles of Cl₂ required is 25.5 moles

How much silver phosphate is produced if 15.5 grams of silver acetate are reacted with excess sodium phosphate?

Answers

15.5 grams of silver acetate reacted with excess sodium phosphate will produce 39.1 grams of silver phosphate.

What is the balanced chemical equation?

The balanced chemical equation for the reaction between silver acetate and sodium phosphate is:

AgC2H3O2 + Na3PO4 → Ag3PO4 + 3NaC2H3O2

From the equation, we can see that one mole of silver acetate (AgC2H3O2) reacts with one mole of sodium phosphate (Na3PO4) to produce one mole of silver phosphate (Ag3PO4).

To calculate the amount of silver phosphate produced, we need to first determine the number of moles of silver acetate present in 15.5 grams of the compound.

We can use the molar mass of silver acetate (calculated as the sum of the atomic masses of its constituent elements) to convert from grams to moles:

Molar mass of AgC2H3O2 = 107.87 + 24.02 + 3(12.01) + 2(1.01) + 2(16.00) = 166.12 g/mol

Number of moles of AgC2H3O2 = 15.5 g / 166.12 g/mol = 0.0934 mol

Since there is excess sodium phosphate in the reaction, all of the silver acetate will react. Therefore, the number of moles of silver phosphate produced will be equal to the number of moles of silver acetate:

Number of moles of Ag3PO4 = 0.0934 mol

Finally, we can use the molar mass of silver phosphate to convert from moles to grams:

Molar mass of Ag3PO4 = 108.00 + 3(31.00) + 4(16.00) = 418.00 g/mol

Mass of Ag3PO4 produced = 0.0934 mol x 418.00 g/mol = 39.1 g

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can somebody help me out with this its chemicals pls help asap im gonna fail if i dont finish them

Answers

The chemicals shown represent molecules of compounds that are formed from the reaction between molecules and atoms of elements.

What are chemical compounds?

Chemical compounds are substances composed of two or more different elements that are chemically bonded together in a fixed ratio.

Chemical compounds can be classified into various categories, such as organic compounds (which contain carbon), inorganic compounds (which do not contain carbon), and biochemical compounds (which are involved in biological processes).

Examples of chemical compounds are NaCl, MgO, etc.

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1. To determine the total magnification of the microscope as you are the power of the eye piece by the power of the _____​

Answers

To determine the total magnification of the microscope as you are the power of the eye piece by the power of the objective lens.

What is total magnification of the microscope?

Magnification of a microscope refers to the degree of enlargement of an object or specimen viewed through the microscope. It is expressed as a numerical value and represents the ratio of the size of the image seen through the microscope to the size of the actual object.

The total magnification of a microscope is calculated by multiplying the magnification of the objective lens by the magnification of the eyepiece. The magnification of the objective lens is determined by the lens itself and is usually marked on the lens, whereas the magnification of the eyepiece is typically 10x.

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HELP WILL GIVE BRAINLIEST
I’m confused pls help mee(solving the water equation)

Answers

Answer:

Excess lemon juice: 162.25 - 92.54 = 69.71

Excess water: 910.08 - 169.55 = 740.53

Explanation:

Excess reactant #2: Water

158.32 x 1/215 x 2/2 x 230.25 = 169.55 g water

Excess lemon juice: 162.25 - 92.54 = 69.71

Excess water: 910.08 - 169.55 = 740.53

higher amounts of energy flow through _ which are known as _
8th grade need an answer ASAP!!!!!!!!!!!!!!!!!!!!

Answers

Each trophic level represents a transfer of energy, with only about 10% of the energy being transferred from one level to the next.

What is Energy ?

Energy is a fundamental concept in physics and refers to the ability of a system to perform work. It is a property of objects and substances that can be transferred to other objects or converted into different forms, but it cannot be created or destroyed. There are different forms of energy, such as kinetic energy (the energy of motion), potential energy (the energy stored in an object due to its position or shape), thermal energy (the energy associated with the temperature of an object), electrical energy (the energy associated with the movement of charged particles), and many others. Energy plays a crucial role in many natural processes and is essential for life and human activities.

Higher amounts of energy flow through trophic levels, which are known as food chains. In a food chain, energy is transferred from one organism to another as they eat each other. The first trophic level consists of primary producers, such as plants, which convert solar energy into chemical energy through photosynthesis. The second trophic level consists of herbivores, which consume the primary producers. The third trophic level consists of carnivores, which consume the herbivores.

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START
What is the
mass of 2.75
moles of CO₂?

Answers

The mass of 2.75 moles of CO2 is approximately 121.03 grams.

What is the mass of 2.75 moles of CO₂?

To calculate the mass of 2.75 moles of CO2, we need to use the molar mass of CO2.

The molar mass of CO2 is approximately 44.01 g/mol (12.01 g/mol for carbon + 2x 16.00 g/mol for oxygen).

To calculate the mass of 2.75 moles of CO2, we can use the following formula:

mass = moles x molar mass

Substituting the given values, we get:

mass = 2.75 moles x 44.01 g/mol

mass = 121.0275 g

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In one experiment, 7.62 g of iron are allowed to react with 8.67 g of sulfur. Calculate the mass of iron (Ill) sulfide that can be formed.

1) What’s the Mass of Fe2S3?
2) What is the limiting reactant?

Answers

Answer:

The mass of iron sulphide formed is 14.2 g

Explanation:

Starting off with a balanced chemical equation:

2Fe + 3S --> Fe₂S₃

to find the mass of Fe₂S₃ and thus the limiting reagent, we can first find the number of moles of each reactant. Number of moles is found by dividing mass by molar mass (found using a standard IUPAC Periodic Table).

n(Fe) present = m/M = 7.62/55.85 = 0.13644 mol

n(S) present = m/M = 8.67/32.07 = 0.27035 mol.

Using the values for the number of moles of each reactant, we can find the limiting reagent by testing each with the molar ratio of the equation.

If (Fe) is the limiting reagent, then moles of sulphur required = n(Fe)/2 × 3

= 0.20466 mol. Since we have excess of what's required of sulphur, then iron could be the limiting reagent.

Now we test it with (S). If (S) is the limiting reagent, then moles of iron required = n(S)/3 × 2 = 0.18023 mol. Since we have less than what is required, therefore, sulphur is NOT the limiting reagent.

Hence, Iron is the limiting reagent.

Now we have the limiting reagent, we can use this to calculate the number of moles of Fe₂S₃, since the limiting reagent is the reactant that is completely consumed.

Since stoichiometry of Fe : Fe₂S₃ = 2 : 1, therefore:

moles of (Fe) = 2× moles of (Fe₂S₃).

hence, moles of (Fe₂S₃) = 1/2 × 0.13644 mol = 0.06822.

Finally, we can multiply the moles of iron sulphide by the molar mass, to get the mass.

m(Fe₂S₃) = nM = 0.06822 × (55.85×2 + 32.07×3) = 14.2 g (3 significant figures, since all the data in the question is in 3 sig. figs).

If 500. g of magnesium chloride is produced in the above reaction, how many grams of hydrogen gas would be produced?

Answers

If 500 g if magnesium chloride are created, the reaction described above would result in 8.23 grams of hydrogen gas.

What is the benefit of magnesium chloride?

To prevent and cure low levels of magnesium inside the blood, this drug is a mineral supplement. The symptoms of having too much stomach acid, such as indigestion, heartburn, and stomach discomfort, are also treated with some brands.

Molar masses of MgCl2 are calculated as follows: moles od MgCl2 = mass of MgCl2 / (24.31 g/mol Plus 2(35.45 g/mol))

Moles of MgCl2 are equal to 4.07 mol, and the mass of H2 is equal to 4.07 mol times the molar mass of H2, or 2.02 g/mol, for a total mass of 8.23 g.

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Which calculation determines power?
f t − l b s/ sec sec/ f t − l b s
f t × l b s × sec
sec − l b s/ f t
PLS someone help me

Answers

It's important to note that in the International System of Units (SI), the unit of power is watts (W), which is equivalent to joules per second (J/s).

What is Power?

In physics, power is the rate at which work is done or energy is transferred. It is a scalar quantity that measures how quickly work can be done or how quickly energy can be transferred from one system to another. Power is typically measured in watts (W), which are equivalent to joules per second (J/s).

The equation for power is:

Power = Work / Time

where Power is measured in watts, Work is measured in joules, and Time is measured in seconds.

Alternatively, power can be calculated as the product of force and velocity:

Power = Force x Velocity

None of the options you provided are the correct calculation for determining power.

Power (P) is defined as the rate at which work is done or energy is transferred, and it can be calculated using the following formula:

P = W/t

Alternatively, if the force (F) applied to an object is known and the object moves a distance (d) over a period of time (t), then power can be calculated using the following formula:

P = F × d / t

Where P is power (in watts), F is force (in newtons), d is distance (in meters), and t is time (in seconds).

It's important to note that in the International System of Units (SI), the unit of power is watts (W), which is equivalent to joules per second (J/s).

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If 2.19 moles of chlorine gas is trapped over water at 754 mmHg and 21°C, calculate the volume of the gas collected.

Answers

Answer:

V = 0.0506 m^3

Explanation:

PV = nRT

V = (nRT) / P

V = (2.19 mol * 8.31 J/(mol·K) * 294.15 K) / 100000 Pa

4Al + 3O2 -> 2Al203

How many moles of aluminum oxide can be produced from 24 grams of oxygen gas?

Answers

Answer: 0.5 moles of aluminum oxide can be produced from 24 grams of oxygen gas.

Explanation:

balanced chemical equation for the reaction between aluminum and oxygen is:

4Al + 3O2 → 2Al2O3

moles of O2 = mass / molar mass = 24 g / 32 g/mol = 0.75 mol

moles of Al2O3 = (2/3) * moles of O2 = (2/3) * 0.75 mol = 0.5 mol

Therefore, 0.5 moles of aluminum oxide can be produced from 24 grams of oxygen gas.

If the goalkeeper exerts a 20 N force on the puck, what force does the puck exert on the goalkeeper?

The puck exerts an equal force of 20 N back on the goalkeeper.
The puck exerts a force less than 20 N.
The puck exerts a force greater than 20 N.

Answers

During every action, there's an opposite and equal response, states Newton's third rule of motion. The goalie experiences a force of 20 N in return from the puck. The best choice is A.

What in science is a force?

That term "force" has a specific meaning in science. At this point, describing a force as being pushed or pulled is perfectly appropriate. It is not possible for a force to "be in it" and "be held by" a thing.

What exactly are force as well as its unit?

Force is indeed a physical factor that alters or has the potential to alter an object's state of rest and motion as well as its form. Newton is the SI unit of force.

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The Complete Question :

If the goalkeeper exerts a 20 N force on the puck, what force does the puck exert on the goalkeeper?

A. The puck exerts an equal force of 20 N back on the goalkeeper.

B. The puck exerts a force less than 20 N.

C. The puck exerts a force greater than 20 N.

mass of 8 kg is accelerating at 5 m·s
Determine the resultant force that causes the acceleration. ​​​

Answers

The acceleration of an object is directly proportional to the net force acting on it, as per Newton's second law of motion.

Newton's second law of motion

To determine the resultant force causing the given acceleration, we need to use the formula F = ma, where F is the net force, m is the mass of the object, and a is the acceleration.

In this case, the given mass of the object is 8 kg, and the acceleration is 5 m/s². Substituting these values in the formula, we get:

F = ma F = 8 kg x 5 m/s²F = 40 N

Therefore, the resultant force acting on the object is 40 N. This means that there is a net force of 40 N acting on the object, which is causing it to accelerate at a rate of 5 m/s².  

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How many grams of phosphorus trichloride will be formed upon a complete reaction of 28.7 g of chloride gas with excess phosphorus.(P4)

Answers

The molar mass of phosphorus trichloride is 137.33 g/mol. 28.7 g of chloride gas corresponds to 0.20882 mol.

What is mol ?

Mol is an abbreviation for molarity, which is a measure of concentration in a solution. It is expressed as amount of solute (in moles) per litre of solution. Molarity is used to describe the strength of an acid or base, the concentration of a substance in a solution, and the amount of a given substance in a given volume of solution. Molarity is also used in the context of dilution, where a solution of known molarity is used to make a solution of a desired molarity. In this case, the number of moles of solute per litre of solution is used as a measure of dilution.

Therefore, 28.7 g of chloride gas reacts with excess phosphorus to form 0.20882 mol of phosphorus trichloride, or 28.20 g of phosphorus trichloride.

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calculate the mole in 4.5 molecules of carbon dioxide​

Answers

Explanation:

Refer to pic...........

Answer:

4.51 moles of carbon dioxide

Step by step explanation

To calculate the number of moles in 4.5 molecules of carbon dioxide, we need to use the Avogadro's number, which is the number of particles in one mole of a substance.

Avogadro's number (Nᴀ) is 6.022 x 10²³ particles per mole.

Therefore, we can calculate the number of moles of carbon dioxide as follows:

Number of moles = Number of particles / Avogadro's number

Number of particles of CO2 = 4.5 molecules x 6.022 x 10²³ particles per mole
= 2.711 x 10²⁴ particles

Number of moles of CO2 = 2.711 x 10²⁴ particles / 6.022 x 10²³ particles per mole
= 4.51 moles (rounded to two decimal places)

Therefore, 4.5 molecules of carbon dioxide is equal to 4.51 moles of carbon dioxide

The density of a gaseous organic compound is 340g/L at 45°C and 1.7atm. what is it's mole​

Answers

To determine the number of moles of the gaseous organic compound, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

How to calculate ?

First, we need to convert the density to mass per volume. The density of the gas is given as 340g/L. Therefore, the mass of 1 L of the gas is 340 g.

Next, we need to use the ideal gas law to calculate the number of moles. We know that the pressure is 1.7 atm, the temperature is 45°C (which is 318 K), and the volume can be calculated using the density and the molar mass of the compound. The molar mass can be determined from the molecular formula of the compound.

Assuming the compound is a hydrocarbon, we can use an average molar mass of 28. Thus, the volume of 1 mole of the gas can be calculated as follows:

V = (molar mass/density) × 1000 ml/L = (28/340) × 1000 = 82.35 ml/mol

Using the ideal gas law equation and plugging in the given values, we get:

n = (PV) / (RT) = (1.7 atm × 82.35 ml) / (0.0821 L atm/mol K ×318 K) = 0.839 mol

Therefore, the number of moles of the gaseous organic compound is 0.839 mol

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30. 0 ml of pure water at 282 k is mixed with 50. 0 ml of pure water at 306 k. What is the final temperature of the mixture?

Answers

The mixture's final temperature is roughly 293.67 K. At this temperature, all of the components in the combination have an equal distribution of the heat energy present in the system.

The temperature that a mixture of two or more substances will achieve once they have been blended and given time to reach thermal equilibrium is known as the "final temperature". At this temperature, all of the components in the combination have an equal distribution of the heat energy present in the system. The principles of thermodynamics, such as the conservation of energy and the specific heat capacities of the constituent substances, can be used to compute the final temperature. For designing heating and cooling systems, processing materials, and studying chemical reactions, among other scientific and engineering applications, the end temperature is a crucial element to consider. Solving for :

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Identify the statements that accurately describe the structure of the pyruvate dehydrogenase (pdh) complex. Select all that apply.

Answers

The PDH complex is composed of five different enzymes and three different cofactors.

The PDH complex is located in the mitochondrial matrix

The PDH complex links the metabolic pathways of glycolysis and the citric acid cycle.

The correct options are a, b and c.

PDH is made up of five separate enzymes and three different cofactors. These enzymes and cofactors collaborate to convert pyruvate into acetyl-CoA, a molecule capable of entering the citric acid cycle.

The PDH complex is found in the mitochondrial matrix, which is the mitochondria's innermost compartment. Here is also where the citric acid cycle occurs.

The PDH complex connects the glycolysis and citric acid cycle metabolic processes. Glycolysis converts glucose to pyruvate, which the PDH complex subsequently converts to acetyl-CoA. The citric acid cycle then uses acetyl-CoA to create energy in the form of ATP.

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The probable question may be:

Identify the statements that accurately describe the structure of the pyruvate dehydrogenase (pdh) complex. Select all that apply.

a) The PDH complex is composed of five different enzymes and three different cofactors.

b) The PDH complex is located in the mitochondrial matrix

c) The PDH complex links the metabolic pathways of glycolysis and the citric acid cycle.

Introduction:

Define the following terms:

Chemical reaction,
reactant,
product,
precipitate,
Law of Conservation of Mass

Answers

Answer:

chemical reaction: substances are converted to one or more different substances

reactant: A chemical substance that is present at the start of a chemical reaction and changes.

product: a substance that is present at the end of a chemical reaction.

Precipitate: an insoluble solid that emerges from a liquid solution

Law of conservation of mass: a discovery that mass is neither created nor destroyed in chemical reactions.

Explanation:

The frequency of a FM radio station is 96.3 MHz. What is the wavelength (in meters)?


2.90 × 104 m


0.324 m


3.15 × 106 m


3.11 m

Answers

The frequency of a FM radio station is 96.3 MHz.The wavelength of the FM radio station is approximately 3.11 meters.

What is wavelength ?

Wavelength is a physical quantity that measures the distance between two successive points on a wave that are in phase with each other. In other words, it is the distance between two identical points on the wave, such as the distance between two peaks or two troughs.

Wavelength is usually denoted by the Greek letter lambda (λ) and is typically measured in meters (m) or some multiple or fraction of meters, such as nanometers (nm) or micrometers (μm).

Wavelength is an important characteristic of waves, whether they are electromagnetic waves such as light or radio waves, or mechanical waves such as sound waves. It is closely related to other wave properties such as frequency, amplitude, and wave speed, and can be used to describe and analyze many different types of wave phenomena.

The formula to calculate the wavelength of a wave is:

wavelength = speed of light / frequency

where the speed of light is approximately 3.00 × 10^8 meters per second.

Using this formula, we can calculate the wavelength of the FM radio station:

wavelength = 3.00 × 10^8 / 96.3 × 10^6

wavelength = 3.11 meters

Therefore, the wavelength of the FM radio station is approximately 3.11 meters. Answer: 3.11 m.

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You have 550mL of 7M solution HCI and you want to make 3L of diluted solution, what will the new concentration be?

Answers

According to the molar concentration, if you  have 550 ml of 7 M solution HCI and you want to make 3 L of diluted solution,the new concentration will be 1.28 M.

What is molar concentration?

Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.

The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.In case of two solutions it is calculated as, M₁V₁=M₂V₂ on substitution gives M₂=7×550/3000=1.28 M.

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