3. (a) Find the student's total displacement for the entire trip.

(b) What was his total time for the entire trip?

(c) What was his average velocity for the entire trip?

4. (a) What was the student's total distance (the length of his path) for the entire trip?

Plz help ​

Answer:

a

Step-by-step explanation:

on x line it = 3 and there is no slope/no steep hill yk

Answer:

Slope= 0 , X= 3

Step-by-step explanation:

the slope goes up 1 over 0.

I hope this helps

Have a good day.

Answer:

114688

Step-by-step explanation:

i think this is the answer

Answer:

114,688

Step-by-step explanation:

the previous term is multiplied by 4 to get the next term.if you continue with this sequence you would eventually get 114 688

Answer:

Are you in Mr. Burg...'s class?  I have no clue what the answer is though.

Step-by-step explanation:

Answer:

y = 4/3x - 14/3

Step-by-step explanation:

y2 - y1/ x2 - x1

6 - (-2) / 8 - 2

4/3

y = 4/3x + b

-2 = 4/3(2) + b

-2 = 8/3 + b

-14/3 = b

Answer:

charles

Step-by-step explanation:

Answer:

20.39

Step-by-step explanation:

15% of 29.99 is 4.4985

so

29.99-4.5

=

25.49

subtract the 20%

20% of 25.49

=

5.1

lastly,

25.49-5.1

=

20.39

Answer:

your answer is D  

the circle is filled in which means AND equal too  

the arrow is bold and its pointing down showing that X is less than 4.  

your answer is D and thats final.

Answer:

Were you looking for the x and y intercepts? The question is very misleading.

If you were the x intercepts are (4-√2,0), (4+√2,0)

And the y intercept is (0,−14)

If you did not mean this in your question please specify what you meant.

Answer:

[tex]x=4-\sqrt{2}[/tex] or [tex]x=4+\sqrt{2}[/tex]

Step-by-step explanation:

Plug in given values of a, b, and c into the quadratic formula and solve for x:

[tex]x=\frac{-b±\sqrt{b^{2}-4ac } }{2a}[/tex]

[tex]x=\frac{-8±\sqrt{8^{2}-4(-1)(-14) } }{2(-1)}[/tex]

[tex]x=\frac{-8±\sqrt{64-56 } }{-2}[/tex]

[tex]x=\frac{-8±\sqrt{8} }{-2}[/tex]

[tex]x=\frac{-8±2\sqrt{2} }{-2}[/tex]

[tex]x=4±-\sqrt{2}[/tex]

Therefore, the roots are [tex]x=4-\sqrt{2}[/tex] or [tex]x=4+\sqrt{2}[/tex]

Answer:

A.

Step-by-step explanation:

12 = 1 feet

50 =4ft 2in

Answer:

B. 4 ft 2 in.

Step-by-step explanation:

1 ft = 12 in

50/12 = 4.2

Answer: 16

Step-by-step explanation:

Answer:

sdfghhhj

Step-by-step explanation:

ther is no qustions

Answer:

Nothing there.

Step-by-step explanation:

Please add a photo of the equation or something.

Answer:

yes

Step-by-step explanation:

4<8*2+8

4<16+8

4<24

4 ≥2+1

4 ≥3

Answer:

89m ^2

Step-by-step explanation:

purple 8x13 = 104

triangle 1/2(5)(6) = 15

104-15 = 89

Answer:

13.8 I believe is the answer

Answer:

A. 243/469

Step-by-step explanation:

Looking at the terms here, it seems that the this powers of 3 divided by 469.

3 is 3¹. 9 is 3². 27 is 3³. 81 is 3⁴.

Knowing that, then 3⁵/469 is the next term. 3⁵ is 243, so the next term is 243/469, which is A.

Answer:

[tex]\angle\ ABC=70[/tex]

Step-by-step explanation:

[tex]We\ are\ given\ that,\\AB\ and\ AC\ are\ two\ equal\ chords\ on\ the\ circle\ ABC.\\ Let\ the\ center\ of\ the\ circle\ ABC\ be\ O.\\ Angle\ subtended\ at\ the\ Center\ of\ the\ circle\ by\ Chord\ AB\ is\ 110.\\Hence,\\Lets\ connect\ AC\ to\ form\ a\ triangle- \triangle ABC.\\Also,\\O\ forms\ the\ Centroid\ of\ \triangle ABC.[/tex]

[tex]By\ joining\ sides\ AO\ and\ OB,\ we\ obtain\ \triangle ABO.\\Hence,\\\angle BOA=110\ \\Now,\\Considering\ point\ C\ on\ Circle\ ABC,\ lets\ consider\ \angle BCA.[/tex]

[tex]We\ know\ that,\\'Angle\ subtended\ by\ a\ chord\ at\ the\ center\ is\ double\ the\ angle\\ subtended\ by\ the\ same\ chord\ at\ the\ respective\ arc\ of\ the\ circle'.\\Here,\\As\ BOA\ is\ an\ angle\ subtended\ by\ the\ chord\ AB\ at\ the\ center\ of\ circle\ ABC\\ while,\ BCA\ is\ an\ angle\ subtended\ by\ the\ same\ chord\ AB\ at\ the\ major\ arc\ of\\ the\ Circle\ ABC.[/tex]

[tex]Here,\\\angle BOA=2 \angle BCA\\Hence,\\Substituting\ \angle BOA=110,\\110=2*\angle BCA\\Hence,\\\angle BCA=\frac{110}{2}=55[/tex]

[tex]Now,\\We\ also\ know\ that,\\'Base\ angles\ opposite\ to\ equal\ sides\ are\ equal\ too'.\\Here,\\In\ \triangle ABC,\\As\ BA=BC,\\\angle BAC= \angle BCA\\\\\therefore \angle BAC= \angle BCA=55[/tex]

[tex]The\ Angle\ Sum\ Property\ of\ a\ Triangle\ States\ that,\\'The\ Sum\ of\ all\ Interior\ Angles\ of\ a\ Triangle\ is\ 180.'\\Hence,\\As\ Polygon\ ABC\ is\ a\ triangle,\\\angle BCA +\angle BAC +\angle ABC=180\\Substituting\ \angle BCA=\angle BAC=55,\\55+55+ \angle ABC=180\\Hence,\\110+ \angle ABC=180\\Or,\\\angle ABC=180-110=70[/tex]

Answer:

6.7 hours

Step-by-step explanation:

If one can do 50 then three can do 150.

So 1000÷150=6.66666666666

Hope this helps

Answer:

AB= 16❤

Step-by-step explanation:

OB= 10

EB²+6²= 10²

EB²= 64

EB=8

2×8=16

The length of line AB in the intersecting chords is determined as 16 units.

The length of line AB is calculated by applying intersecting chord theorem as follows;

The radius of the circle = 10

Applying Pythagorean theorem as follows;

EB² + 6²= r²

where;

EB² + 6²= 10²

EB² = 10² - 6²

EB² = 100 - 36

EB²= 64

EB = √ 64

EB = 8

Since EB is the half of length AB, then the value of the length AB is calculated as;

AB = 2 x 8

AB = 16 units

Learn more about intersecting chords here: https://brainly.com/question/13950364

#SPJ2

Answer:

174.1 degrees

Step-by-step explanation:

180 - 5.9 = 174.1

Answer:probably just mutiply all the numbers!

Step-by-step explanation:

Answer:

would be awesome if u had attached a pic of the graph. we can't help u with this little information

Answer:

35

Step-by-step explanation:

Area of a triangle= B*H/2 so 14*5/2=35

Answer:

35

Step-by-step explanation:

I took the quiz

Answer:

20/5 = 4

Step-by-step explanation:

since each person will get 1/5 of the original 20 ounces, you would divide the pretzels into 5 equal portions of 4.

Answer:

You use 2 cups of blue paint.

Step-by-step explanation:

In this case, you can use a rule of three to find the amount of blue paint you need when you use 4 cups of yellow paint given that you mix 1/3 cups of blue paint for every 2/3 cup of yellow paint:

2/3 cup of yellow paint    →    1/3 cups of blue paint

4 cups of yellow paint    →                 x

x=(4*1/3)÷2/3

x=4/3÷2/3

x=4*3/3*2

x=12/6

x=2

According to this, the answer is that you use 2 cups of blue paint.

Answer:

[tex]153\ in^2[/tex]

Step-by-step explanation:

1. Approach

Divide the given figure up into two simple figures, a trapezoid, and a rectangle. Calculate the area of each figure by using their respective area formula. Then add up the results to get the value for the area of the entire figure.

2. Area of the trapezoid

The first figure is a trapezoid, calculate its area by using the following formula,

[tex]A_t= \frac{b_1+b_2}{2}(h)[/tex]

Where parameters ([tex]b_1[/tex]) and ([tex]b_2[/tex]) represent the base of the trapezoid, and ([tex]h[/tex]) represents the height. Substitute in the given values and solve.

[tex]A_t = \frac{16 + 5}{2}(10)[/tex]

Simplify,

[tex]=\frac{21}{2}(10)[/tex]

[tex]=10.5(10)[/tex]

[tex]=105[/tex]

3. Area of the rectangle

The other figure formed by the partition of the two figures is a rectangle. The formula to find the area of a rectangle is the following,

[tex]A_r =(b)(h)[/tex]

Where ([tex]b[/tex]) represents the base of the figure, and ([tex]h[/tex]) represents the height of the figure. Substitute in the values for the given parameters and solve,

[tex]A_r=(16)(3)[/tex]

Simplify,

[tex]=48[/tex]

4. Find the total area

Now add up the values for the area of each figure. The result will be the total area of the figure,

[tex]A_t + A_r = A[/tex]

Substitute,

[tex]105 + 48 = A[/tex]

Simplify,

[tex]153 = A[/tex]

Answer:

[tex]A=339.42\ cm^2[/tex]

Step-by-step explanation:

The diameter of the roll of paper, d = 4.5 cm

Radius, r = 2.25 cm

Height of the roll of papaer, h = 24 cm

We need to find how much is needed to make the inner tube for a roll of paper. The surface area of a cylinder for inner tube is given by :

[tex]A=2\pi r h\\\\=2\times \dfrac{22}{7}\times 2.25\times 24\\\\=339.42\ cm^2[/tex]

So, the required area is [tex]339.42\ cm^2[/tex].