280Cm3 of a gas diffuse in 40 seconds and 350Cm3 of another gas diffuse in 10 seconds. calculate the rate of diffusion of two gases
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There are various parameters used to group people around the world. We can use the cost of living, place of residence, life style, culture etc. to compare different groups of people in the world.

According to the social comparison hypothesis, people evaluate their own social and personal worth by evaluating how they stack up against others. The comparison strategies people use to assess their actions, successes, and ideas in relation to those of other people are described by Leon Festinger's comparison theory, which was first presented in 1954.

In addition to influencing how people perceive themselves, social comparison also affects how they act. Think about how social comparisons, both positive and negative, can affect how you feel about yourself. belief, certainty, drive, and attitude.

Comparing the life styles, culture, socio-economic status, language  etc. are general features used to compare different group of people around the world.

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That is equivalent to 1.1 grams of ammonium hydroxide per gram of water if the solubility at 60 ° C is 110 grams of potassium chloride for every 100 gram of water.

The physiological actions of nitrate, which are comparable to those of NO, include lowering blood pressure, preventing platelet aggregation, and providing a protective impact on blood vessels.

Its monikers include nitrate of potash, nitre, and saltpeter (saltpetre). In addition to various different forms of pyrotechnics, it is used to make nitric acid and fuel for model rockets. It serves as both a fertilizer and a food preservative.

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Answer:

The solubility of KNO3 is approximately 110 g/100 mL

Explanation:

here is a proper explanation

V.) a)Empirical formula of naphthalene is C5H4. b)Empirical formula of benzene is CH. VI)a)Na2SO4 (aq) + Ca(NO3)2 (aq) → CaSO4 (s) + 2NaNO3 (aq); b)3Mg (s) + N2 (g) → Mg3N2 (s) VII)a)2Hg(NO3)2 (s) → 2Hg (l) + O2 (g) + 2NO2 (g) b)Ca3(PO4)2 (s) + 3H3PO4 (aq) → 6CaHPO4 (s)  c)FeCl3 (aq) + 3NaOH (aq) → Fe(OH)3 (s) + 3NaCl (aq)

Process that leads to the chemical transformation of one set of chemical substances to another is called chemical reaction.

V) a) Ratio of carbon to hydrogen atoms can be found by dividing each atom count by the greatest common factor (GCF) of the two numbers.

GCF of 10 and 8 is 2.

10/2 = 5 and 8/2 = 4.

Empirical formula of naphthalene is C5H4.

b) For benzene, the ratio of carbon to hydrogen atoms can be found by dividing each atom count by their GCF, which is 6.

6/6 = 1 and 6/6 = 1.

Empirical formula of benzene is CH.

VI)a) Chemical equation for the reaction is:

Na2SO4 (aq) + Ca(NO3)2 (aq) → CaSO4 (s) + 2NaNO3 (aq)

Reactants: Na2SO4 (aq) and Ca(NO3)2 (aq)

Products: CaSO4 (s) and 2NaNO3 (aq)

Type of reaction: Double displacement or metathesis reaction

b) Chemical equation for the reaction is:

3Mg (s) + N2 (g) → Mg3N2 (s)

Reactants: 3Mg (s) and N2 (g)

Product: Mg3N2 (s)

Type of reaction: Combination or synthesis reaction

VII)a) The balanced chemical equation :

2Hg(NO3)2 (s) → 2Hg (l) + O2 (g) + 2NO2 (g)

b) Balanced chemical equation:

Ca3(PO4)2 (s) + 3H3PO4 (aq) → 6CaHPO4 (s)

c) Balanced chemical equation :

FeCl3 (aq) + 3NaOH (aq) → Fe(OH)3 (s) + 3NaCl (aq)

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The chemical formula of a combination that provides the quantities (ratios) of the elements contained in the complex but not the actual numbers or order of atoms is known as an empirical formula. This would be the elemental compound's lowest whole integer percentage.

The empirical formula of a chemical substance in chemistry is the simplest whole number quantity of atoms contained in the product. [1] As an illustration, the empirical formula of sulfur monoxide, or SO, is merely SO, as is the empirical formula of disulfur dioxide, S2O2.

Thus, sulfur monoxide and disulfur dioxide, both sulfur and oxygen molecules, have the same empirical formula. Their molecular formulas, which describe the amount of atoms in each molecule of a chemical substance, are, however, not identical.

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Answer:

2

Explanation:

The water lost heat more quickly because the temperature difference between the classroom and the water was greater in the first few minutes.

When a mercury thermometer is immersed in hot water, the bulb initially absorbs heat from the outside and expands, causing the mercury column in the thermometer to initially descend slightly. Mercury expands as heat is transferred to it later.

This is because mercury is pushed up a tube as a column of air above the barometer presses on a mercury-filled dish. The mercury in the tube rises more rapidly in response to the greater force of the downward push.

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Phosphate of sodium: Nitrate of zinc, Na3PO4, Zn(No3)2, bromate of barium: Perchlorate of iron (II) and ba(BrO3)2: Cobalt (II) hydrogen carbonate, Fe(ClO4)2: Co(HCO3)2 as cobalt bicarbonate.

Acetic acid, also known as ethanoic acid, is an organic compound with the chemical formula CH3COOH (also written as C2H4O2, HC2H3O2) that is an acidic, colorless liquid.

As the oxidation state of their atoms increases during a chemical reaction with potassium dichromate, elements become more electronegative. Potassium dichromate is a potent oxidizer in an acidic environment. K2Cr2O7 is present as Cr2O7 - (orange) in acidic medium, but it is transformed into CrO4 - (yellow) in basic medium.

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57.14%  is the mass percentage of carbon in aspartame.

Define empirical formula.

An empirical formula is a compound's chemical formula that only specifies the ratios of the elements it contains and not the precise quantity or arrangement of atoms. This would be the compound's ingredient with the lowest whole number ratio.

Typically, the empirical formula is used to merely display the components of a structure. When one wishes to quickly identify the elements they are working with, this is helpful. When you want to know how many atoms of each element are present in the substance, the molecular formula is the most helpful.

The mass percentage of carbon is 14*12/(14*12 + 18*1 + 2*14 + 5*16) i.e. 57.14%

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The initial 50.0 ml solution had a 0.0765 M [tex]NH_{3}[/tex] concentration.

The amount of solute contained in a specific amount of solution is the substance's concentration. The quantity of moles per solution in 1 L of solution, or molarity, is used to represent concentrations.

The balanced chemical equation is :

[tex]NH_{3} +HCl[/tex] →  [tex]NH_{4} Cl[/tex]

moles of [tex]NH_{3}[/tex] = moles of HCl

To fond moles of HCl :

moles of HCl = concentration of HCl  * volume of HCl used

moles of HCl = 0.10 M * 0.003825

To find the concentration of [tex]NH_{3}[/tex] in the original solution is :

concentration of [tex]NH_{3}[/tex] = moles of [tex]NH_{3}[/tex] / volume of solution

concentration of [tex]NH_{3}[/tex] = 0.003825 mol / 0.050 L

concentration of [tex]NH_{3}[/tex] = 0.0765 M

Therefore, the concentration of [tex]NH_{3}[/tex]  in the original 50.0 ml solution is 0.0765 M.

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Answer:

7.859 g/cm³.

Explanation:

Density = Mass/Volume

the mass of the iron sample is 27.3162g and its volume is 3.475 cm³, so calculate its density as:

Density = 27.3162g/3.475 cm³ = 7.859 g/cm³

Therefore, the density of the iron sample is 7.859 g/cm³.

Taking into account the reaction stoichiometry, 0.546 grams of H₂O are produced when 0.485 grams of O₂ reacts with H₂.

In first place, the balanced reaction is:

2 H₂ + O₂  → 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 32 grams of O₂ form 36 grams of H₂O, 0.485 grams of O₂ form how much mass of H₂O?

mass of H₂O= (0.485 grams of O₂× 36 grams of H₂O) ÷32 grams of O₂

mass of H₂O= 0.546 grams

Finally, 0.546 grams of H₂O are formed.

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Answer:

The rate constant of a reaction is related to the activation energy (Ea) and the temperature (T) by the Arrhenius equation:

k = A * e^(-Ea/RT)

where k is the rate constant, A is the pre-exponential factor, R is the gas constant, and T is the absolute temperature.

Taking the natural logarithm of both sides of the equation, we get:

ln(k) = ln(A) - (Ea/RT)

We can use this equation to determine the activation energy for the reaction by comparing the rate constants at two different temperatures. For example, at 400.0 K and 450.0 K, we have:

ln(k1) = ln(A) - (Ea/RT1)

ln(k2) = ln(A) - (Ea/RT2)

where k1 is the rate constant at 400.0 K, k2 is the rate constant at 450.0 K, and RT1 and RT2 are the product of the gas constant and temperature at each temperature.

Taking the difference between the two equations, we get:

ln(k2/k1) = Ea/R * (1/RT1 - 1/RT2)

Solving for the activation energy (Ea), we get:

Ea = -R * ln(k2/k1) / (1/RT1 - 1/RT2)

Substituting the given values, we get:

Ea = -8.314 J/mol*K * ln(0.691/0.012) / (1/400.0 K - 1/450.0 K)

Ea = 93.8 kJ/mol

Therefore, the activation energy for the reaction is 93.8 kJ/mol.

The enthalpy of the following chemical equation is -393.5+(-296.8)+87.9=-602.4 kilojoules.

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

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The carbonyl stretching vibration of guanine is expected to give rise to a peak in the vibrational-Raman spectrum at a wavenumber of around 1660-1700 cm^-1.

How to explain the information

The specific location of the peak can be affected by a variety of factors, including the excitation wavelength, the sample preparation method, and the environment in which the sample is analyzed.

If the 514.5 nm line of an argon ion laser is used as the incident light source, the Raman shift associated with the carbonyl stretching vibration of guanine would be expected to be in the range of 620-670 cm^-1. However, it's important to note that the exact position of the peak may vary depending on the specific experimental conditions.

An overview was given as the information is incomplete.

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Answer:

0.00001 M

Explanation:

The pOH of a solution is defined as the negative logarithm of the hydroxide ion concentration:

pOH = -log[OH-]

Therefore, we can rearrange this equation to solve for [OH-]:

[OH-] = 10^(-pOH)

If the pOH of a solution is 5.0, then:

[OH-] = 10^(-5.0)

[OH-] = 1.0 x 10^(-5.0)

[OH-] = 0.00001

Therefore, the hydroxide ion concentration of the solution is 0.00001 M.

According to the question, there are 65,569 carbon atoms, 1,051.6 kg of gas, 0.716 g/L of methane density, and 65,569 mole of methane in the tank.

A mole is the volume of a material that includes 6.022 X 1023 of the substance's particles, atom, ions, molecules, etc. A mole is a unit for counting molecules, ions, or atoms.

a. The ideal gas law, PV = nRT, can be used to estimate how many moles of methane are present in the tank. The pressure and temperature are both 1 atm at STP. 0.0821 L atm/K mol is the real gases constant.

The result is that n = (PV) / (RT)

= (1 atm x 1550 m3) / (0.0821 Latm/Kmol x 273 K)

= 65,569 moles.

b. The molarity of methane should be used to determine the weight of methane in kilograms. Methane has a molar mass of 16.04 g/mol.

Methane's mass in kilos is as follows:

1,051.6 kg is equal to 65,569 moles times 16.04 g/mol/1000 g/kg.

c. The optimal gas law and the molecular concentration of methane can be used to get the density of methane.

Density is determined as follows: (16.04 g/mol at 1 atm) / (0.0821 L/atm/K mol at 273 K) = 0.716 g/L.

d. Using the amount of moles of methane that we established in part (a), we can use that information to calculate the amount of carbon atoms inside the tank.

As a result, the tank is filled 65,569 carbon atoms.

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Answer:

First, we need to calculate how much sodium hypochlorite is in 1 gallon of 0.110% bleach solution:

0.110% (m/v) = 0.110 g/100 mL

1 gallon = 3,785 mL

So, the mass of sodium hypochlorite in 1 gallon of 0.110% bleach solution is:

0.110 g/100 mL x 3,785 mL = 4.1635 g

Now we can use this information to calculate how much undiluted household bleach we need:

5.25% (m/v) = 5.25 g/100 mL

Let's call the volume of undiluted bleach we need "V".

We can set up a proportion:

5.25 g/100 mL = 4.1635 g/3785 mL

Solving for V:

5.25 g/100 mL = x/3785 mL

x = 199.0425 g

Finally, we need to convert grams to cups. The density of household bleach is about 1.08 g/mL, so:

199.0425 g ÷ 1.08 g/mL = 184.31 mL

There are 48 teaspoons in a cup, and 5 mL in a teaspoon, so:

184.31 mL ÷ 5 mL/teaspoon ÷ 48 teaspoons/cup ≈ 0.77 cups

Therefore, you should measure approximately 0.77 cups of household bleach to make 1.00 gallon of diluted bleach solution.

Answer:

Question 10: Which substance is insoluble in water?

Answer: Silver chloride (AgCl).

Question 11: Which ion is soluble in water?

Answer: Chloride (Cl-).

Question 12: Which combination will form a precipitate (solid) according to solubility rules?

Answer: Calcium sulfate (CaSO4) and sodium carbonate (Na2CO3).

Question 13: Which statement is true about dilute and concentrated solutions?

Answer: Concentrated solutions have more solute than dilute solutions.

Question 14: How much of a 0.500 M sodium chloride solution is needed to make 500 mL of a 0.100 M solution?

Answer: 0.100 L (100 mL).

Question 15: How much of a 0.500 M hydrochloric acid solution should be used to make 250 mL of a 0.100 M solution?

Answer: 50.0 mL.

Explanation:

If 484.06 grams of lead carbonate are produced, 307.68 grams of sodium nitrate will also be produced.

Stoichiometry refers to the study and calculation of quantitative (measurable) relationships of the reactants and products in chemical reactions (chemical equations).

According to this question, lead nitrate reacts with sodium carbonate to produce lead carbonate and sodium nitrate.

Based on the above equation, 1 mole of lead carbonate and 2 moles of sodium nitrate are produced.

484.06 grams of lead carbonate is equivalent to 1.81 moles.

1.81 moles of lead carbonate will produce 3.62 moles of sodium nitrate.

3.62 moles of sodium nitrate is equivalent to 307.68 grams.

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The molar quantity must be multiplied by Avogadro's number to be converted to moles or atoms.

How can a scientist use Avogadro's number?

One of the basic constants in chemistry is Avogadro's number. When the same amount of atoms or molecules are being compared, it allows comparison of the various atoms or molecules of a given substance.

A material's mole is equivalent to 6.022 x 10²³of that substance (such as atoms, molecules, or ions). The term "Avogadro's number" or "Avogadro's constant" refers to the integer 6.022*10²³. The mole idea can be used to convert between particle mass and number.

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Explanation:

Refer to pic..........

Answer:

The Order of reaction refers to the relationship between the rate of a chemical reaction and the concentration of the species taking part in it.

Explanation:

The first law of thermodynamics can be written as:

ΔU = Q - W

where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done by the system.

We know that ΔU = 9135 J and W = 346 J. We also know that the gas was heated from 25 ∘C to 225 ∘C. Therefore, the change in temperature is:

ΔT = 225 ∘C - 25 ∘C = 200 ∘C

We can use the specific heat formula to solve for the specific heat of the gas:

Q = mcΔT

where m is the mass of the gas and c is the specific heat of the gas.

Solving for c, we get:

c = Q / (mΔT)

Substituting the given values, we get:

c = 346 J / (80.0 g × 200 ∘C) = 0.0216 J/(g⋅ ∘C)

Therefore, the specific heat of the gas is 0.0216 J/(g⋅ ∘C).

Both conclusions can be valid as they are based on valid data and scientific reasoning. This is due to the fact that different data sets and scientific arguments can lead to different conclusions.

A conclusion is a summary of the main points discussed in an essay, report, presentation, or other document. It should be concise and well-written, and should not include any new information or arguments. A conclusion typically reviews the main points and ties them together, offering a final perspective on the topic. It is important to write a clear and effective conclusion, as it is the last thing the reader will read and will leave them with a lasting impression. A good conclusion can solidify the main idea of the document and leave the reader with a sense of closure.

For example, one data set may show that a particular drug is effective in treating a certain condition, while another data set may show that the same drug is not as effective. Therefore, both conclusions can be valid as long as the data and scientific reasoning used to draw them are valid.

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Answer:

The molar mass of sulfuric acid (H2SO4) can be calculated by adding the atomic masses of its constituent atoms:

Molar mass of H2SO4 = 2(1.008 g/mol) + 1(32.06 g/mol) + 4(15.99 g/mol) = 98.08 g/mol

Therefore, the mass of 2.25 moles of H2SO4 is:

mass = number of moles x molar mass

mass = 2.25 moles x 98.08 g/mol = 220.68 g

So, the mass of 2.25 moles of sulfuric acid is 220.68 grams.

There are 0.802 moles of gold present in 158 grams of gold.

Mass in grams of one mole of the compound is known as the molar mass of substance. It is the mass divided by amount-of-substance measured in moles. Molar mass of a compound can be found out by adding standard atomic masses of constituent atoms.

molar mass of gold : 196.967 g/mol.

To find the number of moles of gold in 158 grams, we use the following formula:

moles = mass / molar mass

moles = 158 g / 196.967 g/mol

moles = 0.802 mol

Therefore, there are 0.802 moles of gold in 158 grams of gold.

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Note: The question given on the Portal is incomplete. Here is the correct question.

Question: How many moles are in 158 grams of gold?

One of the way of writing the chemical formula of an ionic compound is to use crisscross method. In this method, the numerical value of each of the ion charges is crossed over to become the subscript of the other ion.

The symbolic representation of the composition of a compound is given by the chemical formula of the compound. In a chemical formula an anion is written on the right side whereas a cation is written on the left side.

1 Question answers:

a. Cr₂O₃

b. (NH₄)₃PO₄

c. CaSO₄

2 Question answers:

a. Iron (II) Chloride

b. Barium hydroxide

c. Lithium cyanide

d. Lead (II) Chloride

3 Question answers:

a. Sulfur tetrafluoride

b. Chloryl perchlorate

c. Dinitrogen trioxide

d. Phosphorous pentoxide

4 Question answers:

a. C₂H₂

b. C₂H₄

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Answer:

The balloon filled with 02 collapses because the gas molecules are attracted to each other and condense into a liquid when cooled. Helium, on the other hand, is a noble gas that does not form compounds with other elements and therefore does not condense into a liquid at low temperatures.