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b. Complete the double number line diagram that represents the situation.
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PLEASE HELP I NEEEDA LIKE FINISH IT RN HELP

The responses which represents the area of the rectangle are 23 ⅝ and 198/8

The correct answer choice is option A and B

Area of a rectangle = Length × Width

Length = 5 ¼ metros

Width = 4 ½ metros

Area of a rectangle = Length × Width

= 5 ¼ metros × 4 ½ metros

= 21/4 × 9/2

= (21 × 9) / (4 × 2)

= 189 / 8 square metros

= 23 5/8 square metros

Hence, the area of the rectangle is given by 189 / 8 square metros or 23 5/8 square metros.

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Answer:

5n = 1.75

Step-by-step explanation:

We are given 1.75 and n 5 times, so

5n = 1.75

Answer: n=0.35

Step-by-step explanation:

Divide 1.75 into fifths and that equals 1 n

Answer:

2.90

Step-by-step explanation:

One hundredth is 0.01. 2.89+0.01= 2.90.

Hope this helps, please mark brainliest!

Answer:

Step-by-step explanation:

(h)

[tex]KE= \frac{1}{2}mv^{2} \\KE=\frac{mv^{2} }{2} \\2KE=mv^{2}\\2KEm=v^{2} \\v=\sqrt{2KEm}[/tex]

(g)

[tex]s=\frac{(u+v)t}{2} \\2s=(u+v)t\\\frac{2s}{t}=u+v\\u= \frac{2s}{t}-v[/tex]

(i)

[tex]s=ut+\frac{1}{2} at^{2} \\s-ut=\frac{at^{2} }{2} \\2s-2ut=at^{2} \\\sqrt{2s-2ut}=at\\a=\sqrt{2s-2ut}-t[/tex]

(j)

[tex]\frac{pV}{T} =nR\\T=\frac{pV}{nR}[/tex]

(k)

[tex]a^{2} -b^{2} +c^{2} \\a^{2} +c^{2} =b^{2} \\b=\sqrt{a^{2} +c^{2} }[/tex]

(i)sinθ[tex]=\frac{a}{b}[/tex]

       θ=[tex]\frac{a}{sin(b)}[/tex]

[tex]5 < - 8[/tex]

__________

The determinant of matrix A is -6.

A. To evaluate det(A) by a cofactor expansion along a row or column of your choice, we can choose any row or column and multiply each element by its corresponding minor and sign.

For example, let's choose the first row:

det(A) = (-6)(4*3-0*1) + (0)(2*3-(-1)*2) + (2)(2*0-(-1)*4)

det(A) = (-6)(12) + (0)(6) + (2)(4)

det(A) = (-72) + (0) + (8)

det(A) = -64

Therefore, the determinant of matrix A is -64.

B. Alternatively, we could have chosen any other row or column and the result would have been the same. For example, if we chose the third column:

det(A) = (2)(4*0-2*0) + (-1)(-6*3-2*0) + (3)(-6*0-2*4)

det(A) = (2)(0) + (-1)(-18) + (3)(-8)

det(A) = (0) + (18) + (-24)

det(A) = -6

Therefore, the determinant of matrix A is -6.

Note that the determinant of a matrix is a scalar value, and it is the same regardless of which row or column we choose to expand along.

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Fοr an equilateral triangle, sketch is drawn fοr side length = 5 cm.

Triangles are a particular sοrt οf pοlygοn in geοmetry that have three sides and three vertices. Three straight sides make up the twο-dimensiοnal figure shοwn here. An example οf a 3-sided pοlygοn is a triangle. The tοtal οf a triangle's three angles equals 180 degrees. One plane cοmpletely enclοses the triangle.

An equilateral triangle in geοmetry is a triangle with equal-length sides οn all three sides.

In the well-knοwn Euclidean geοmetry, an equilateral triangle is alsο equiangular, meaning that each οf its three internal angles is 60 degrees and cοngruent with the οthers.

The given triangle has a side length οf 5 cm.

Sο, each sire measures the same.

Therefοre, the sketch is drawn fοr the same.

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The perimeter is the tοtal length οf a shape's bοundary, and the rule fοr finding the οuter perimeter οf Jian's equilateral triangle designs is p = n + 1.

The perimeter οf a twο-dimensiοnal shape is the tοtal length οf its bοundary, which is the sum οf the lengths οf all its sides. It is typically measured in units such as centimeters, inches, οr meters.

Fοr example, the perimeter οf a square with side length s is 4s, since it has fοur sides οf equal length. The perimeter οf a rectangle with length l and width w is 2l + 2w, since it has twο pairs οf sides οf different lengths.

Nοw, let's cοnsider the relatiοnship between the number οf triangles and the οuter perimeter οf Jian's design. Frοm the table, we can see that the οuter perimeter increases by 1 as the number οf triangles increases by 1. Specifically, the οuter perimeter is always 1 mοre than the number οf triangles used in the design.

Therefοre, we can write the rule fοr finding the οuter perimeter p in terms οf the number οf triangles n as:

p = n + 1

This rule tells us that if we knοw the number οf triangles used in a design, we can find the οuter perimeter by adding 1 tο that number.

Hence, The perimeter is the tοtal length οf a shape's bοundary, and the rule fοr finding the οuter perimeter οf Jian's equilateral triangle designs is p = n + 1.

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Answer:

To determine which two statements are correct for this situation, we need to analyze the given information.

The water faucet leaks 35 of a liter of water in 34 of an hour, which means that:

In one hour (60 minutes), the faucet will leak:

60/34 x 35 = 61.76 milliliters (ml) of water.

In one minute, the faucet will leak:

35/34 = 1.0294 ml of water.

In one day (24 hours), the faucet will leak:

24 x 61.76 = 1482.24 ml or 1.48224 liters of water.

In one week (7 days), the faucet will leak:

7 x 1.48224 = 10.37568 liters of water.

Based on this information, the correct statements are:

The faucet leaks approximately 61.76 milliliters of water in one hour.

The faucet leaks approximately 10.37568 liters of water in one week.

Answer:

I think 2nd option..........

Answer:

AB and CD.

Step-by-step explanation:

To check if two sides of a quadrilateral are congruent, we need to find the length of each side. We can use the distance formula to calculate the length of each side:

AB = √[(1 - 4)^2 + (4 - 1)^2] = √(9 + 9) = 3√2

BC = √[(5 - 1)^2 + (1 - 4)^2] = √(16 + 9) = √25 = 5

CD = √[(1 - 1)^2 + (-2 - 1)^2] = √9 = 3

AD = √[(-3 - 1)^2 + (1 - (-2))^2] = √(16 + 9) = √25 = 5

Therefore, AB and CD have the same length and are congruent, while BC and AD have the same length and are congruent.

So the correct answer is AB and CD.

To make the solid figure true using column A and column B are as follow,

1.ice cube → cube

2.tissue roll → cylinder

3.match box →rectangular prism

4.volleyball →sphere

5.can of sardines →cylinder

6.milk box → rectangular prism

7.volcano →cone

8.toblerone →triangular prism

9.bus→rectangular prism

10.roof of a nipa hut→ triangular pyramid

Solid figure represents the following shape,

1. Ice cube represents the cube shape as all the sides are of same length.

2. Tissue roll represents the cylindrical shape.

3. Match box is an perfect example for rectangular prism.

4. Volleyball represents the spherical shape.

5. Can of sardines is one of the perfect example of cylinder.

6. Milk box is also one of the example of rectangular prism

7.volcano represents the cone.

8.toblerone is representing triangular prism.

9.bus is a example of rectangular prism

10.roof of a nipa hut it is an example of triangular pyramid

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The above question is incomplete, the complete question is:

Choose the solid figure in Column B to make each statement is true of column A.

Column A.

1.ice cube

2.tissue roll

3.match box

4.volleyball

5.can of sardines

6.milk box

7.volcano

8.toblerone

9.bus

10.roof of a nipa hut

Column B.

A. cone

B. cube

C. cylinder

D. rectangular prism

E. sphere

F. square pyramid

G. triangular prism

H. triangular pyramid​

The points F(8,-1), G(2,1), H(1, -2), and I(7,-4) form a quadrilateral. The desired slopes and lengths are follows:

The type of quadrilateral that BEST identifies the given points is a parallelogram.

To find the slopes and lengths of the quadrilateral, we will use the slope formula and the distance formula.

Slope formula: m = (y2 - y1)/(x2 - x1)
Distance formula: d = √((x2 - x1)² + (y2 - y1)²)

Slopes:
FG: m = (1 - (-1))/(2 - 8) = -1/3
GH: m = (-2 - 1)/(1 - 2) = 3
HI: m = (-4 - (-2))/(7 - 1) = -1/3
IF: m = (-1 - (-4))/(8 - 7) = 3

Lengths:
FG: d = √((2 - 8)² + (1 - (-1))²) = √(40) = 2√(10)
GH: d = √((1 - 2)²+ (-2 - 1)²) = √(10)
HI: d = √((7 - 1)^2 + (-4 - (-2))²) = √(40) = 2√(10)
IF: d = √((8 - 7)² + (-1 - (-4))^2) = √(10)

From the above calculations, we can see that the slopes of FG and HI are equal, and the slopes of GH and IF are equal. This means that the opposite sides of the quadrilateral are parallel. Additionally, the lengths of FG and HI are equal, and the lengths of GH and IF are equal. This means that the opposite sides of the quadrilateral are also congruent.

Therefore, the type of quadrilateral that BEST identifies the given points is a parallelogram.

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Answer:So the common factor of the numerator and denominator is (x+7)(x+7) or (x+7)^2, and the simplified expression is (x+1)(x−1).

Step-by-step explanation:

To find the common factor of the numerator and denominator of the expression (x+1)(x+7)(x+7)(x−1), we need to factorize it completely.

(x+1)(x+7)(x+7)(x−1) = (x+1)(x−1)(x+7)(x+7)

Now we can see that the common factor of the numerator and denominator is (x+7)(x+7) or (x+7)^2.

Therefore, we can simplify the expression by dividing both the numerator and denominator by (x+7)^2:

(x+1)(x−1)(x+7)(x+7)/(x+7)(x+7) = (x+1)(x−1)

So the common factor of the numerator and denominator is (x+7)(x+7) or (x+7)^2, and the simplified expression is (x+1)(x−1).

The speed of the river's current is 3 miles per hour.

To determine the speed of the river's current, we can use the formula d = rt, where d is the distance, r is the rate, and t is the time.

We can set up two equations, one for upstream and one for downstream, and solve for the speed of the river's current.

For upstream:

9 = (6 - c)t

For downstream: 27 = (6 + c)t

Since it takes her the same amount of time to paddle 9 miles upstream as it does to travel 27 miles downstream, we can set the two equations equal to each other:

9 = (6 - c)t = 27 = (6 + c)t

Simplifying and solving for c:

9(6 + c) = 27(6 - c) 54 + 9c = 162 - 27c 36c = 108 c = 3

Therefore, the speed of the river's current is 3 miles per hour.

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Answer:

38

Step-by-step explanation:

Interquartile Range

IQR = Q3 - Q1

Quartiles are the values that divide a list of numbers into quarters:

301, 301, 304, 309, 311, 328, 330, 341, 342, 343, 345

Hence,

Quartiles:

Q1 --> 304

Q2 --> 328

Q3 --> 342

And since, IQR = Q3 - Q1

Then,

342 - 304 = 38

As a result, the interquartile range for the data set is 38.

RevyBreeze

(a) The three points are:
(x,y) = ( 2.25 , -3.5 ) (smallest x-value)
(x,y) = ( 2.5 , -4 )
(x,y) = ( 2.75 , -4.5 ) (large x-value)

(b) The three points are:
(x,y) = ( -0.75 , -0.75 ) (smallest x-value)
(x,y) = ( -0.5 , -0.5 )
(x,y) = ( -0.25 , -0.25 ) (large x-value)

To find the three points that divide the line segment joining the given points into four equal parts, we need to use the formula for a point that divides a segment in a given ratio. The formula is:

(x,y) = ( (x1 + rx2)/(1+r) , (y1 + ry2)/(1+r) )

Where (x1,y1) and (x2,y2) are the given points, r is the ratio, and (x,y) is the point that divides the segment in the given ratio.

(a) For the given points (2,-3) and (3,-5), we need to find the points that divide the segment in the ratio 1:3, 2:2, and 3:1.

For the first point, we use the formula with r=1/3:
(x,y) = ( (2 + (1/3)*3)/(1+(1/3)) , (-3 + (1/3)*(-5))/(1+(1/3)) )
(x,y) = ( 2.25 , -3.5 )

For the second point, we use the formula with r=2/2:
(x,y) = ( (2 + (2/2)*3)/(1+(2/2)) , (-3 + (2/2)*(-5))/(1+(2/2)) )
(x,y) = ( 2.5 , -4 )

For the third point, we use the formula with r=3/1:
(x,y) = ( (2 + (3/1)*3)/(1+(3/1)) , (-3 + (3/1)*(-5))/(1+(3/1)) )
(x,y) = ( 2.75 , -4.5 )

So the three points are:
(x,y) = ( 2.25 , -3.5 ) (smallest x-value)
(x,y) = ( 2.5 , -4 )
(x,y) = ( 2.75 , -4.5 ) (large x-value)

(b) For the given points (-1,-1) and (0,0), we need to find the points that divide the segment in the same ratios as before.

For the first point, we use the formula with r=1/3:
(x,y) = ( (-1 + (1/3)*0)/(1+(1/3)) , (-1 + (1/3)*0)/(1+(1/3)) )
(x,y) = ( -0.75 , -0.75 )

For the second point, we use the formula with r=2/2:
(x,y) = ( (-1 + (2/2)*0)/(1+(2/2)) , (-1 + (2/2)*0)/(1+(2/2)) )
(x,y) = ( -0.5 , -0.5 )

For the third point, we use the formula with r=3/1:
(x,y) = ( (-1 + (3/1)*0)/(1+(3/1)) , (-1 + (3/1)*0)/(1+(3/1)) )
(x,y) = ( -0.25 , -0.25 )

So the three points are:
(x,y) = ( -0.75 , -0.75 ) (smallest x-value)
(x,y) = ( -0.5 , -0.5 )
(x,y) = ( -0.25 , -0.25 ) (large x-value)

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The solutions to the given equations are x = 10 and m = 1.5.

Using the one-to-one property of logarithms, we can solve the given equations as follows:

First, we will solve the equation: 15.Ln(10−3x)=ln(−4x)
The one-to-one property of logarithms states that if logb(a) = logb(c), then a = c. Therefore, we can use this property to set the arguments of the logarithms equal to each other:

10 - 3x = -4x
Simplifying this equation gives:

10 = x

So the solution to the first equation is x = 10.

Next, we will solve the equation: 16.log4​(6−m)=log4​3(m)
Again, using the one-to-one property of logarithms, we can set the arguments of the logarithms equal to each other:

6 - m = 3m
Simplifying this equation gives:

6 = 4m
m = 6/4
m = 1.5

So the solution to the second equation is m = 1.5.

Therefore, the solutions to the given equations are x = 10 and m = 1.5.

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Harbin was colder than Beijing on that particular day in December because the temperature difference between the two cities was -6ºC.

To figure out which city was colder, we need to compare the difference between the temperatures of the two cities. The temperature difference is the numerical value we get when we subtract one temperature from the other.

In this case, the temperature in Harbin was -8ºC and the temperature in Beijing was -2ºC. To find out which city was colder, we need to calculate the temperature difference between the two cities.

To do this, we subtract the temperature in Beijing from the temperature in Harbin:

-8ºC - -2ºC = -6ºC

So the temperature difference between the two cities is -6ºC. This means that Harbin was colder than Beijing on that day.

We can see that the temperature difference is negative, which tells us that the temperature in Harbin was lower than the temperature in Beijing.

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The number of fruits that Kim bought in all, given the apples and oranges was ;

Let's call the number of oranges that Kim bought "O" and the number of apples that Kim bought "A".

From the problem, we know that Kim bought fewer than 20 pieces of fruit, so we can write:

A + O < 20

A = O + 3

Simplifying:

2O + 3 < 20

2O < 17

O < 8.5

Since O represents the number of oranges, we know that Kim bought fewer than 8.5 oranges. Since she can't buy a fraction of an orange, this means that she must have bought either 8 oranges or fewer.

Now we can use the equation A = O + 3 to find the number of apples she bought:

A = 8 + 3 = 11

So Kim bought 8 oranges and 11 apples.

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ds/dt = sec(t)

To find the length of the curve, we need to find the arc length. The arc length of the curve r(t) is given by:

LENGTH = $\int_{0}^{1} \sqrt{6^{2}\cos^2(t) + 1 + 5^{2}\sin^2(t)} dt$

To find ds/dt, we can take the derivative of the above equation with respect to t:

$\frac{ds}{dt} = \frac{d}{dt} \sqrt{6^{2}\cos^2(t) + 1 + 5^{2}\sin^2(t)}$

$\frac{ds}{dt} = \frac{6^2\cos(t)\sin(t) + 10\sin(t)\cos(t)}{\sqrt{6^{2}\cos^2(t) + 1 + 5^{2}\sin^2(t)}}$

$\frac{ds}{dt} = \frac{16\sin(t)\cos(t)}{\sqrt{6^{2}\cos^2(t) + 1 + 5^{2}\sin^2(t)}}$

$\frac{ds}{dt} = \frac{16\sin(t)\cos(t)}{\sqrt{1+tan^2(t)}}$

Thus, ds/dt = sec(t).

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The like terms are √2, − 3√2 and 5√2. The radicals are 2√3 and 2√5, √32.

The radical and root of a number are the same thing. The root can be an nth root, a square root, or a cube root. Hence, a radical is any number or phrase that employs a root. The Latin word Radix, which meaning root, is where the word "radical" originates. The radical can be used to explain various types of roots for a number, including square, cube, fourth, and so on. The index number or degree is the number that appears before the radical.

Similar terms are ones whose exponent power and variables are the same. These variables' coefficients might differ. Terms with algebraic similarities are those that are comparable to one another.

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The six primary sources of greenhouse gas emissions in the United States are:

2. The seven types of greenhouse gases of climate change are:

3. The four types of Machine learning are:

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Louise has 2 1/4 feet more of green yarn than white yarn.

What is the fractions ?

A fraction is a way to represent a part of a whole or a ratio between two quantities.

To compare the amounts of green and white yarn, we need to express the amounts in the same units. Let's convert 2/4 yards of white yarn to feet, since the green yarn is already measured in feet.

1 yard = 3 feet

2/4 yard = 2/4 * 3 feet/yard = 1.5 feet

Now we can compare the amounts of green and white yarn in feet:

Amount of green yarn = 3 3/4 feet

Amount of white yarn = 1.5 feet

To find how many more feet of green yarn Louise has than white yarn, we can subtract the amount of white yarn from the amount of green yarn:

3 3/4 feet - 1.5 feet = 2 1/4 feet

Hence, Louise has 2 1/4 feet more of green yarn than white yarn.

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The solver for this expression is x = -5/2, 5/2, 2, -1/3, 1, 2.

To solve this expression, we will first need to factor the numerator and denominator of each fraction.

For the first fraction, we can factor the numerator as follows:
[tex]25 - 4x^2 = (5 + 2x)(5 - 2x)[/tex]

The denominator can be factored as follows:
[tex]6x^2 + 9x - 15 = (2x + 5)(3x - 3)[/tex]

For the second fraction, the numerator can be factored as follows:
[tex]6x^2 - 2x - 4 = (2x - 4)(3x + 1)[/tex]

The denominator can be factored as follows:
[tex]2x^2 - x - 10 = (2x + 5)(x - 2)[/tex]

Now we can simplify the expression by canceling out any common factors:
[tex](5 + 2x)(5 - 2x)/(2x + 5)(3x - 3) * (2x - 4)(3x + 1)/(2x + 5)(x - 2)[/tex]
[tex]= (5 + 2x)(5 - 2x)(2x - 4)(3x + 1)/(2x + 5)(3x - 3)(2x + 5)(x - 2)[/tex]

[tex]= (5 + 2x)(5 - 2x)(2x - 4)(3x + 1)/(3x - 3)(x - 2)[/tex]

Since the expression is equal to 0, we can set each factor equal to 0 and solve for [tex]x[/tex]:

[tex]5 + 2x = 0 \\5 - 2x = 0 \\2x - 4 = 0 \\3x + 1 = 0 \\3x - 3 = 0 \\x - 2 = 0 \\[/tex]

Solving for x, we get the following solutions:
[tex]x = -5/2 \\x = 5/2 \\x = 2 \\x = -1/3\\ x = 1 \\x = 2 \\[/tex]

Therefore, the solver for this expression is [tex]x = -5/2, 5/2, 2, -1/3, 1, 2[/tex].

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Answer:8/3

Step-by-step explanation:

Total number of hours: 24

Total number of guards: 9

Equation: Total number of hours/ total number of guards

24/9= 8/3 hour shifts or 2.66667 hour shifts for each guard.

The input values are all the values of the x-coordinates and the output values are all the values of the y-coordinate corresponding the x-value: (0, 3), (2, 2), (-1, 1).

An ordered pair (a, b) is a pair of objects in mathematics. Because the ordered pair (a, b) differs from the ordered pair (b, a) unless a = b, the order in which the items occur in the pair is important. The unordered pair a, b, on the other hand, equals the unordered pair b, a.

Ordered pairs are sometimes known as 2-tuples, or sequences of length 2 (or, in computer science, sometimes, lists). 2-dimensional vectors are occasionally used to refer to ordered pairs of scalars.

The input values are all the values of the x-coordinates and the output values are all the values of the y-coordinate corresponding the x-value.

Some of the input, output pair are:

(0, 3)

(2, 2)

(-1, 1)

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Answer:

20 feet

Step-by-step explanation:

You can use trigonometry to solve this problem. The height of the kite can be found using the sine function. The sine of an angle in a right triangle is equal to the length of the side opposite the angle divided by the length of the hypotenuse.

In this case, the side opposite the 30° angle is the height of the kite (h), and the hypotenuse is the length of the string (40 feet). So we have:

sin(30°) = h / 40

Solving for h, we get:

h = 40 * sin(30°)

Since sin(30°) = 0.5, we have:

h = 40 * 0.5

So, h = 20 feet.

The kite is 20 feet high in the air.

Answer:

To solve this problem, we can use trigonometry. Let's assume that the height of the kite from the ground is h. Then, we can use the tangent function to find the value of h.

We know that the tangent of an angle is equal to the opposite side over the adjacent side. In this case, the opposite side is the height of the kite (h) and the adjacent side is the distance from you to the point directly below the kite on the ground, which is 40 feet.

So we have:

tan(30°) = h/40

Multiplying both sides by 40, we get:

h = 40 tan(30°)

Using a calculator, we can find the value of tangent of 30 degrees, which is approximately 0.5774. So:

h = 40 × 0.5774 ≈ 23.1

Therefore, the height of the kite in the air is approximately 23.1 feet.

The value of x from the proportion is x = 1.6

The proportion formula is used to depict if two ratios or fractions are equal. The proportion formula can be given as a: b::c : d = a/b = c/d where a and d are the extreme terms and b and c are the mean terms.

The proportional equation is given as y ∝ x

And , y = kx where k is the proportionality constant

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Given data ,

Let the proportion equation be represented as A

Now , the value of A is

( x / 4 ) = ( 2 / 5 )

On simplifying , we get

Multiply by 4 on both sides , we get

x = ( 2 * 4 ) / 5

x = 8/5

On further simplification , we get

x = 1.6

Therefore , the value of x is 1.6

Hence , the proportion is x = 1.6

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