23. Formulating Hypotheses Suppose you want
to know if objects with different masses fall to
the ground at different rates. State a hypothesis
about falling objects.

-I NEED HELP PLEASE!!! ASAP

Using Stefan's equation, which states that the power of the emitted radiation will be proportional to the fourth power of the absolute temperature, we treat the filament of the evacuated light bulb as a black body.

P = σ AeT⁴

Where A is the surface area of the emitter, σ is Stefan's constant, and e is the emissivity of the surface.

Now, from Stefan's Law, the radiated power is proportional to the fourth power of temperature.

P =IV

IV ∝ T⁴

Therefore,

I₁ V₁ / (I₂ V₂) = (T₁ / T₂)⁴

T₁ / T₂ = (I₁ V₁ / I₂ V₂)^{1/4}

T₂ = T₂ [ (I₁ V₁ / I₂ V₂)^{1/4} ]

Now we have,

I₂ = 2I₁ and

V₂ = 8V₁

Therefore,

T₂ = T₁ [ (2I₁ )(8V₁)/(I₁ V₁) ]^{1/4}

T₂ = T₁ (16)^{1/4}

T₂ = 2T₁

The correct option is (d).

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Answer:

The independent variable is the cause. Its value is independent of other variables in your study. The dependent variable is the effect. Its value depends on changes in the independent variable.

Explanation:

Hope this helps!

the charge of each cylinder given the following additional information about each one is 10434.445 coulomb, 14906.35 Coulomb, 178876.2 coulomb, 223,595.25 coulomb.

To solve this question we are to use the equation 1 below :

Charge Q = uniform charge density p × Total area of the cylinder A

From the question, we are given radius, R to be 2.33 cm and length, L to be 5.82 cm.

Calculate for the total area of the cylinder, A. equation 2

Total area of the cylinder, A = area of the top surface + area of the bottom + area of the curved surface of the cylinder.

Hence, total area of the cylinder A is;

πR^2 + πR^2 + 2πRL.

Then, total area of the cylinder A is;

(L + R)2πR.

find the charge of each cylinder equation 3

For the first cylinder; we have the uniform charge density to be 35 nC/m^2.

Therefore, the combination of equation (1) and (3) gives equation 4

Charge Q= p × (L + R)2πR

Hence,

Charge Q = 35 × [(5.82 + 2.33) 2× 3.143 × 5.82]

Charge Q = 10434.445 coulomb.

For the cylinder B, we have a uniform charge density of 50 nC/m^2.

Using equation (4),

charge Q =  p × (L + R)2πR

= 50 × [(5.82 + 2.33) 2× 3.143 × 5.82]

= 14906.35 Coulomb

For The cylinder C, the uniform charge density is 600, we use of equation (4);

Charge Q = 600 × 298.127

Charge Q = 178876.2 coulomb.

For cylinder D, the uniform charge density is 750 nC/m^2. use of equation (4)

Charge Q = 298.127 x 750

charge Q = 223,595.25 coulomb.

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The magnitude of the minimum deceleration to avoid an accident is 2,186.5 m/s².

The minimum acceleration to avoid accident is calculated as follows;

s = ut + ¹/₂at²

where;

Substitute the given parameters and solve for the acceleration as follows;

350 = 12(0.56) +  ¹/₂(0.56²)a

350 = 6.72 + 0.157a

0.157a = 350 - 6.72

0.157a = 343.28

a = 343.28/0.157

a = 2,186.5 m/s²

Thus, the magnitude of the minimum deceleration to avoid an accident is 2,186.5 m/s².

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One of the main causes of fatalities in the commercial aviation sector is loss of airplane control while in flight. There are numerous causes of upsets in airplanes, but none of them are statistically significant.

Eliminating one cause of upsets won't definitely result in fewer fatalities and accidents involving loss of control. Reducing the number of upset causes requires ongoing training. Additionally, many environmental factors that cause upsets can't always be avoided, which makes avoidance the best course of action. Therefore, in order to recover an upset airplane, pilots must possess the requisite knowledge and abilities.

All makers of big, swept-wing commercial jet aircraft use the same aerodynamic concepts.

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Answer: 5.4 hours.

Explanation:

So, this would simply be divison. So, we can take 540 km, and seperate it into 500 km, and 40 km.

That being said, we can divide 500 km by 100, so we can see how many hours it takes for 500 km, which is 5.

Now, we divide 40/100, which gives us 0.4.

Add the two together, and it takes 5.4 hours to reach 540 km at a speed of 100 km/hr

The distance the proton traveled in the field is 2.09m.

A stable subatomic particle known as a proton with the symbols p, H+, or 1H+ and an elementary electric charge of +1e. It has a mass that is somewhat lower than that of a neutron, and because of the proton to electron mass ratio, it has an 1836-fold greater mass than an electron. The term "nucleons" refers to protons and neutrons, both of which have masses of roughly one atomic mass unit (particles present in atomic nuclei).

In the nucleus of every atom, there are one or more protons. They offer the central force of electrostatic attraction that holds the atomic electrons together.

Explanation:

Now as the initial and final velocity makes 180degree angle, So, the proton must have travelled only half a revolution. So, the distance ,d will be :

d=2πr/2=πR

d=2.09m

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The efficiency of moving the box is 60%.

Given in the question

Force exerted by peter = 500 N

Force due to friction on box = 200 N

Distance Traveled by box = 3 meters

Now work done by the force is given by

Work Done = (Magnitude of Force) × (Distance traveled)

Let us find work done by each force,

Work done by peter

Work Done = (Magnitude of Force) × (Distance traveled)

Put in the value, we get

Work Done =500 × 3

Work Done by peter = 1500 J

Similarly, Work done by friction

Work Done = (Magnitude of Force) × (Distance traveled)

Put in the value, we get

Work Done =200 × 3

Work Done by Friction = 600 J

As we know the work done by friction force is always negative,

Work Done by Friction = -600 J

So, net Work done = Work Done by peter + Work Done by Friction

net Work done = 1500 - 600

Net Work done = 900 J

Now Efficiency = (Net work done/work done by peter) × 100

Put in the values, we get

Efficiency = (900/1500) × 100

Efficiency = (3/5) × 100

Efficiency = 300/5

Efficiency = 60 %

So, the efficiency of moving the box is 60%.

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By unit conversion, the converted unit is

a. 1.8 km = 1.8 x 10⁹ μm

b. 1.8 μm = 1.8 x 10¯⁴ cm

c. 1.8 yard = 1645920 μm

We need to know about unit conversion to solve this problem. The unit conversion can be used to convert a unit to another unit. It can be defined as

a = xb

where a is unit a, b is unit b and x is the constant of conversion.

From the question above, we know that

a. 1.8 km = .... μm

b. 1.8 μm = .... cm

c. 1.8 yard = .... μm

Find the microns (1 km = 10⁹ μm)

1.8 km = 1.8 x 10⁹ μm

Find the centimeter (1 cm = 10⁴ μm)

1cm = 10⁴ μm

1/10⁴ cm = 1 μm

Hence,

1.8 μm = 1.8/10⁴ cm

1.8 μm = 1.8 x 10¯⁴ cm

Find the microns (1 yd = 914400 μm)

1.8 yard = 1.8 x 914400 μm

1.8 yard = 1645920 μm

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Answer:

84.83 ft/s^2 or 85 ft/s^2

Explanation:

A = Δ v Δ t

Acceleration is the rate of change of an objects speed; in other words, it's how fast velocity changes. According to Newton's second law, acceleration is directly proportional to the summation of all forces that act on an object and inversely proportional to its mass. It's all common sense - if several different forces are pushing an object, you need to work out what they add up to (they may be working in different directions), and then divide the resulting net force by your object's mass.

This acceleration definition says that acceleration and force are, in fact, the same thing. When the force changes, acceleration changes too, but the magnitude of its change depends on the mass of an object. This is not true in a situation when the mass also changes, e.g., in rocket thrust, where burnt propellants exit from the rocket's nozzle.

In the 17th century, Sir Isaac Newton, one of the most influential scientists of all time, published his famous book Principia. In it, he formulated the law of universal gravitation which states that any two objects with mass will attract each other with a force exponentially dependent on distance between these objects (specifically, it is inversely proportional to the distance squared). The heavier the objects are, the greater is gravitational force. It explains, for example, why planets orbit around the very dense Sun.

In Principia, Newton also includes three laws of motion which are central to understanding the physics of our world. The acceleration calculator is based on three various acceleration equations, where the third is derived from Newton's work:

a = (v_f - v_i) / Δt,

a = 2 * (Δd - v_i * Δt) / Δt²,

a = F / m,

where:

a is the acceleration,

v_i and v_f are respectively the initial and final velocities,

Δt is the acceleration time,

Δd is the distance traveled during acceleration,

F is the net force acting on an object that accelerates,

m is the mass of this object.

If you already know how to calculate acceleration let's focus on the units of acceleration. You can derive them from the equations we listed above. All you need to know is that speed is expressed in feet per second (imperial/US system) or in meters per second (SI system) and time in seconds. Therefore, if you divide speed by time (as we do in the first acceleration formula), you'll get acceleration unit ft/s² or m/s² depending on which system you use.

Alternatively, you can use the third equation. In this case, you need to divide force (poundals in US and newtons in SI) by mass (pounds in US and kilograms in SI) obtaining pdl/lb or N/kg. They both represent the same thing, as poundal is pdl = lb * ft/s² and the newton is N = kg * m/s². When you substitute it and reduce the units, you'll get (lb * ft/s²) / lb = ft/s² or (kg * m/s²) / kg = m/s².

There is also a third option that is, in fact, widely used. You can express acceleration by standard acceleration, due to gravity near the surface of the Earth which is defined as g = 31.17405 ft/s² = 9.80665 m/s². For example, if you say that an elevator is moving upwards with the acceleration of 0.2g, it means that it accelerates with about 6.2 ft/s² or 2 m/s² (i.e., 0.2*g).

Answer:

Touch the open ends of the two wires to each other to form a circuit and test the bulb. Touch the two open ends of the wire to each material you are testing, one at a time. If the bulb lights up, it is a good conductor. If it doesn't, it is a good insulator.How do you know if an object is a good conductor and poor conductor of electricity?

Image result for Suppose you have found a piece of material. You are not sure what the material is. You want to find out if it is a good conductor or a good insulator. Describe in words what you would do to determine if the material is an electrical conductor.​

Difference between Good Conductor and Bad Conductor of Electricity. Good conductors are those materials which allow electricity to pass through them easily. Bad conductors are those materials which do not allow electricity to pass through them easily.

Answer: Conclusion White matter hyperintensities predict an increased risk of stroke, dementia, and death. Therefore white matter hyperintensities indicate an increased risk of cerebrovascular events when identified as part of diagnostic investigations, and support their use as an intermediate marker in a research setting

The speed of rocket is ,V₀ = 268.42ft/sec

A projectile is an object upon which the only force is gravity.

a rocket launched in vertical direction by a group of students.

The path of projectile will be parabola.

to find the speed of the rocket is  we use the equation of a projectile motion the data determined by them is

Initial height is.[tex]y_{0 } =[/tex] 89.6 ft

 final height is  [tex]y_{f} =[/tex] 0ft

 time taken, t = 17sec

as we know , g = 32.2 ft/s²

g is acceleration due to gravity.

 [tex]y_{f} - y_{o} = V_{o}t - \frac{1}{2} g t^{2}[/tex]

0 = 89.6 + 17V₀ - 16.1 × (17)²

V₀ = 268.42ft/sec

The speed of rocket is ,V₀ = 268.42ft/sec

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We are given distance of the center of the source for two waves:

[tex]D_{1} =240 cm[/tex]

[tex]D_{2} =60 cm[/tex]

C) Calculating how their phases compares:

ΔФ240[tex]=\frac{D_{2} }{D_{1} } .[/tex]ΔФ60

[tex]\frac{240}{60} .[/tex]ΔФ60 = 4.ΔФ60

How can you determine a wave's phase?

Phase: The "Phase" of a waveform refers to the location of the moving particle and is expressed in "Radians or degrees."

Phase difference, also known as "Phase angle," is the amount of time that one wave precedes or follows another.

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The calculated mass is 10 kg.

Mass (kg) times acceleration (m/s2) equals force (N). A constant mass item will therefore accelerate in direct proportion to the force exerted. When two objects of differing masses are subjected to the same force, the heavier object accelerates more slowly than the lighter object. Mass times acceleration, or F=m x a, equals force. This means that in order to move an object at the same speed as an object with smaller mass, a stronger force is required.

So, Mass times acceleration equals force

100=Mass×10

To calculate mass on its own, divide 100 by 10 on both sides.

Mass = 10 kg

Because this formula was developed using kg rather than another unit of mass like the slug, the mass is expressed in kg.

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The reasons are discussed below -

We have a straight current carrying wire placed in a uniform magnetic field.

We have to explain why we can't determine the direction of the magnetic force from the information given in the problem.

The force on the current carrying wire will be -

F = IBL sinθ

According to the question -

It is impossible to determine the direction of magnetic force because of the following reasons -

Firstly, the length of the wire present in the region of magnetic field is given. If we assume it to be ∞, then -

F = IB sin(θ) x ∞ = ∞ (which is not a valid result)

Secondly, Although it is mentioned that a straight current carrying wire is placed perpendicular to the uniform magnetic field, there is no mention about  the exact orientation of the magnetic field direction. For example, if we consider the wire along +x axis then perpendicular could be any of the four directions -

+k, -k, +j, -j

Hence, these are the reasons why we can't determine the direction of the magnetic force from the information given in the problem.

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Plane used to remove the tip of your nose is known to be called option C. Frontal (front/back).

In regards to biology, If a person were to cut their nose off, it is one that is known to be called coronal.

The coronal plane is said to be a term that is often referred to as the frontal plane and it is seen as any vertical plane that shares the body into ventral as well as dorsal (belly and back) parts.

Therefore one can say that the coronal Plane (Frontal plane) used to remove the tip of your nose.

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The work it takes to slide a crate 20 m along a loading dock by pulling on it with a 200-n force at an angle of 30° from the horizontal is 346.4J.

The energy that is transmitted to or from an object when a force is applied along a displacement is referred to as work in physics. In its simplest form, it is typically explained as the outcome of force and displacement. Positive work is the term for the component of a force that moves the point of application when it is applied. A force is said to do negative work if, at the point of application, one of its components points in the opposite direction of the displacement.

Calculations:

Work done= component of force  along displacement x displacement

                  =  F cosΘ x d

                  = 200cos 30 x2

                  = 346.4 J

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Coefficient of static friction between the car’s tires and the road is 0.3

What is static friction ?

A force that holds an object at rest is called static friction. The definition of static friction is: The resistance people feel when they attempt to move a stationary object across a surface without actually causing any relative motion between their body and the surface they are moving the object across.

Give an illustration of static friction.

When something is sitting on a surface, static friction affects it. For instance, every time you place your foot on the trail when trekking in the woods, there is static friction between your shoes and the surface.

Assume that road is level

Friction force provides centripetal force to the car

The weight of the car is = 1250 kg

speed of the car is = 25 m/s

curve radius =r= 175m

we know the formula of centripetal force is given by

[tex]f_{s} =\frac{mv^{2} }{r}[/tex]         where m = mass of the object

                                   v=  velocity

                                    r=  curve radius

and we know  the static force is given by f= μN

                                                                     here, N= mg

so now,

μmg=[tex]\frac{mv^{2} }{r}\\[/tex]

now put the all give values then we get,

[tex]$$\mu_r=\frac{v^2}{r g}=\frac{(25 \mathrm{~m} / \mathrm{sec})^2}{(175 \mathrm{~m})\left(9.8 \mathrm{~m} / \mathrm{sec}^2\right)}$$[/tex]

μ=[tex]\frac{625}{1715}[/tex]

μ= 0.3 , This is the coefficient of friction between the car tire and the rode

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The density of crushed iron ore is equivalent to 2 500 kg/m3, or 2.5 grams per cubic centimeter, which is the weight of the material. The density is equal to 156.07 pounds per cubic foot in either the Imperial or US customary measuring systems.

When weights are expressed in kilograms of air, the air gives buoyancy, and because a kilogram of copper has a larger volume than a kilogram of lead, it displaces more air and hence receives more support. As a result, on a scale in the air, a kilogram of lead will weigh more than a kilogram of copper. Copper has a density of 8.94 grams per cubic centimeter, or 8 940 kilograms per cubic meter, or 20°C (68°F or 293.15K), at ordinary atmospheric pressure.

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By angular speed, the period of oscillation is 0.63 second.

We need to know about the angular speed of harmonic oscillation. the angular speed can be determined as

ω² = k / m

where ω is angular speed, k is spring constant,  and m is the mass.

The angular speed can be calculated by

ω = 2π/T

Hence,

ω² = k / m

(2π/T)² = k / m

where T is period.

From the question above, we know that:

m = 2 kg

k = 200 N/m

By substituting to the equation, we get

(2π/T)² = k / m

(2π/T)² = 200 / 2

(2π/T)² = 100

square root

2π/T = √100

T = 2π / √100

T = 0.63 second

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The total capacitance of the capacitor circuit is 40 μF.

We need to know about capacitor circuits to solve this problem. The capacitance will be summed up when the capacitor is combined in parallel. The total capacitance can be determined as

Ct = C1 + C2 + C3

From the question above, we know that:

C1 = 25 μF

C2 = 3 μF

C3 = 12 μF

By substituting the parameters, we can get

Ct = C1 + C2 + C3

Ct = 25 μF + 3 μF + 12 μF

Ct = 40 μF

Hence, the total capacitance of the circuit is 40 μF.

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The force per unit length exerted by I₁ on I₂ is [tex]8\times10^-^5 \ N/m[/tex] .

It is given that two long, parallel conductors, separated by 10.0cm having current  I₁ = 5.00A and  I₂ = 8.00 A.

If the current flowing through the wire are in same direction then they the wire attract each other and if the current flowing through the wire are opposite in direction then they the wire repel each other

Putting r = 10.0cm [tex]=10\times10^{-2}m[/tex] ,  I₁ = 5.00A and  I₂ = 8.00 A in equation (1) , we get

[tex]f=\frac{4\pi \times10^-^7\times5.00\times8.00}{2\times\pi\times10.00\times10^{-2}}\\\\f=\frac{2\times40\times10^-^5}{10} \\\\f=8\times10^{-5}N/m[/tex]

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Light source will pass through and form a shadow, when I hold the largest cardboard between the light source and the wall. Since, the cardboard is not so thick it will allow rays to pass through it.

Light rays always travel in a straight line. A shadow is formed when the light rays hit an opaque object. Sun is a natural source of light. The rays from the sun fall on objects on earth and forms shadows. Light rays do not interfere with each other if they come cross each other. Light rays travel from the direction of source to the direction of eye. They show property of reflection wherein after colliding a surface they trace their path back.

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The fuel required to gain minimum energy is (3.02 x 10²³ / ΔH) kg.

We need to know about relativistic energy to solve this problem. The rest energy of the object can be determined by

Eo = m₀ . c²

where Eo is rest energy, m₀ is rest mass and c is the speed of light (3 x 10⁸ m/s).

The total energy of object can be described as

E = Eo / √(1 - v²/c²)

where E is total energy, v is the object speed.

From the question above, we know that :

m₀ = 2.4 x 10⁶ kg

c = 3 x 10⁸ m/s

v = 0.7c

Find the rest energy

Eo = m₀ . c²

Eo = 2.4 x 10⁶ . (3 x 10⁸)²

Eo = 2.16 x 10²³ joule

Determine the total energy

E = Eo / √(1 - v²/c²)

E = 2.16 x 10²³ / √(1 - (0.7c)²/c²)

E = 2.16 x 10²³ / 0.71

E = 3.02 x 10²³ joule

Assume that the Heat of Combustion for Space fuel = ΔH J/kg

m = E / ΔH

m = 3.02 x 10²³ /  ΔH kg

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The velocity in meters per second of the object at t = 2 seconds is 2.5 m/s

Velocity is simply defined as the rate of change of displacement with time. Mathematically, it can be expressed as:

Velocity = displacement / time

From the question given above, the following data were obtained:

Velocity = displacement / time

Velocity = 5 / 2

Velocity = 2.5 m/s

Thus, the velocity is 2.5 m/s

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The ideal selection is C. The spheres will each grow evenly.

The coefficient of expansion of any material is the property of the material which defines the expansion or contraction of the material with the variation of the temperature.

The ratio of a body's length, area, or volume at a given temperature, usually 0° C, to its length, area, or volume at that temperature, respectively, while maintaining constant pressure.

Given that two spheres with the same radius and formed of the same metal are hollow and solid, respectively. The same temperature rise is applied to the spheres.

Since both bodies in this instance are formed of the same substance, their orientation has no bearing on how much it expands. Because the materials used to create both spheres were the same, we can thus conclude that they will expand equally.

Therefore, both materials will expand equally.

The complete options are given below:-

A Hollow sphere will expand more than the solid one.

B Solid sphere will expand more than the hollow one.

C Both spheres will expand equally.

D None of these

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The gauge pressure at the bottom of the second cylinder is 0.10 atm.

The pressure of a system above the atmospheric pressure is known as gauge pressure, commonly referred to as overpressure. The pressure from the weight of the atmosphere is included in gauge pressure readings because gauge pressure is zero-referenced against ambient air (or atmospheric) pressure. This indicates that gauge pressure varies in response to both weather and height above sea level. Gauge pressure measurement is adequate for the majority of industrial applications because every operation in a refinery or manufacturing facility operates at the same air pressure. Absolute pressure is a measurement of pressure that is based on a reference pressure of zero or absolutely no pressure. The only place where this happens naturally is in a perfect vacuum, which can only be found in space.

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Radio waves allows the charges in the receiving antenna to respond to the electric field portion of the carrier wave.

This refers to a type of disturbance which transports energy from one place to another without the actual movement of the particles and of various types such as  microwaves, radio waves etc.

The radio wave allows the electrons in the rod to vibrate with amplitudes which emulates those of the carrier wave and in this case, it is the antenna thereby resulting in the signals in the car radio being provided as a result of these type of interactions.

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Kinetic energy is K = 1.82 × 10⁻³ eV.

⁵⁷Fe nucleus emits 14 keV photons at rest.

We have, Mc² = 8.6 × 10⁻⁹ J in the final state of the nucleus.

Let p(nucleus) be the moment of the nucleus and p(photon) be the momentum of the photon.

Then, by conservation of momentum since the total moment is zero.

p(nucleus) = p(photon) = E(γ) / c = 140 keV / c

The energy for the recoiling nucleus is given as:

E² = p²c² + (mc²)²

Now, Mc² = 8.60 × 10⁻⁹J =5.38 × 10¹⁰ eV = 5.38  × 10⁷ keV

Therefore,

(Mc² + K²) ² = (14 keV)² + (Mc²)²

(1 + K²/Mc²)² =(14/Mc²)² +1

The term (1 + K²/Mc²)² is less than 1  therefore, (14/Mc²)² + 1 is equal to 1 by clacualtor.

Now using binomial theorem,

(1 + K²/Mc²)² = √[1 + ((14/Mc²)²] = 1 + (1/2)(14/Mc²)²

K = 1.82 × 10⁻³ eV

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