20 points!!! Emergency help required.
Florence is spinning a 770 g weight tied to a string over her head. The string is 0.94 m long, and the weight is moving with a speed of 4.24 m/s. What is the centripetal force pulling the weight inward?

14.7 N

20.6 N

11.0 N

19.7 N

The lever's mechanical advantage would be 8.

The mechanical advantage of a lever is calculated as the ratio of the length of the effort arm to the length of the resistance arm.

In this case, the effort arm is the distance Dave pushes down on one side of the lever (2 meters), and the resistance arm is the distance the stump is lifted (0.25 meters). Therefore, the mechanical advantage of the lever is:

Mechanical Advantage = Effort Arm/Resistance Arm

Mechanical Advantage = 2/0.25

Mechanical Advantage = 8

So the lever's mechanical advantage is 8.

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Explanation:

E1 = k Q1 / (0.075 m)^2

= 9 x 10^9 Nm^2/C^2 * 10 x 10^-9 C / 0.075^2 m^2

= 400 N/C

E2 = k Q2 / (0.075 m)^2

= 9 x 10^9 Nm^2/C^2 * (-3 x 10^-9 C) / 0.075^2 m^2

= -120 N/C

Since the electric fields due to the two charges are in opposite directions, we can find the net electric field at the midway point by taking the difference between the two:

E = E1 - E2

= 400 N/C - (-120 N/C)

= 520 N/C

The comet will disintegrate at a height of 70,479,900 m.

To find the height at which the comet would disintegrate, we need to determine Earth's Roche limit with respect to the comet.

Roche limit = 2.5 [(density of planet)/(density of moon or other object)]^(1/3) (radius of planet)

Let's assume that the moon has a similar density to the comet, so we can use the Roche limit formula with the following values:

density of planet = 5500 kg/m^3

density of moon or other object = 500 kg/m^3

radius of planet = 6378 km = 6,378,000 m

Roche limit = 2.5 [(5500 kg/m^3)/(500 kg/m^3)]^(1/3) (6,378,000 m)

Roche limit = 76,857,900 m

This means that any object that comes closer to Earth than 76,857,900 m would be torn apart by tidal forces.

Therefore, the comet would disintegrate at a height of 76,857,900 m - 6,378,000 m = 70,479,900 m above Earth's surface.

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Answer:

46.6 m/s in the positive y-direction.

Explanation:

Answer:

d

Explanation:

Write a function that takes in two parameters and returns the average of those two parameters.

Parameters are variables that are used to control or adjust the behavior of a particular system or model. They are used to improve the accuracy of a model or to establish baseline values for comparison. Parameters may be used to adjust the size or complexity of a system, the level of accuracy of a model, or the range of a system's inputs. Parameters can also be used to identify specific characteristics of a system, such as its maximum or minimum values, or to monitor its performance. Parameters are an important tool in helping to understand and control the behavior of a system.

The function below takes in two parameters, a and b, and returns the average of those two parameters.
function avg(a, b) {return (a + b) / 2;}

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Answer:

ρ (density) = M / V          mass / volume

V = M / ρ = 19 kg / 800 kg/m^3 = .024 m^3

When a ball leaves a ramp with a horizontal velocity, it will follow a curved path known as a projectile motion. The ball will move both horizontally and vertically, with the horizontal velocity remaining constant and the vertical velocity changing due to the force of gravity.

At the point where the ball leaves the ramp, it will have a certain height and horizontal distance from the starting point. As it moves through the air, it will travel a certain horizontal distance before landing on the ground at a lower height.

Projectile motion is a type of motion in which an object is launched or thrown into the air, and then moves under the influence of gravity and air resistance. In projectile motion, the object follows a curved path called a trajectory, which consists of both horizontal and vertical components.

The motion of a projectile can be described in terms of its velocity, acceleration, and displacement. At the instant of launch, the object has an initial velocity that can be broken down into horizontal and vertical components. The horizontal component of velocity remains constant throughout the motion, while the vertical component changes due to the effect of gravity.

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NASA's Juno spacecraft has been orbiting Jupiter since 2016, providing scientists with unprecedented views of the gas giant. One of the most striking features of Jupiter is its Great Red Spot, a massive storm that has been raging for centuries.

What is Great Red Spot?

On Jupiter, a huge storm known as the Big Red Spot has been raging for at least 400 years and possibly longer. It is a zone of persistently high pressure that is present in the planet's southern hemisphere. The storm, which is thought to be around two to three times the size of our globe, is so enormous that it could easily devour the entire planet.

When it began orbiting Jupiter in 2016, NASA's Juno probe has given scientists hitherto unheard-of pictures of the gas giant. The Great Red Spot, a huge storm that has been raging for ages, is one of Jupiter's most stunning characteristics. The polar regions of Jupiter are however home to numerous additional storms, including sizable and intricate cyclones.

The scale and intricacy of the cyclones on Jupiter's poles, especially a centre cyclone on the north pole known as "Jupiter's North Pole Hexagon," first astounded scientists. These storms can endure for decades or even centuries and are more larger and better organised than any cyclones on Earth.

It's not apparent to me which tornado you're referring about in particular. But, researchers looking at Jupiter's The variety and complexity of these storms have probably fascinated storms, and they may be attempting to comprehend the underlying physical mechanisms. Jupiter's storms can be studied to learn more about planetary weather, including our own.

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The work done on the ship by the tugboat is calculated as 15,000,000 joules.

Force can be a push or a pull but always with magnitude and direction.

The work done on the ship is given by the equation as : work = force × distance × cos(Ф)

force is the constant horizontal force applied by tugboat, distance is  distance moved by ship, and theta is angle between force and direction of motion of the ship. In this case, Ф is zero because the force is in same direction as the motion of ship.

Thus, we calculate the work done on the ship as: work = 5000 N × 3000 m × cos(0)

work = 15,000,000 joules

Therefore, the work done on the ship by the tugboat is 15,000,000 joules.

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The gravitational potential energy of the object is -176J. Option 4 is the answer.

The gravitational potential energy (U) of an object of mass (m) at a height (h) relative to a reference point where gravitational potential energy is defined to be zero is given by:

U = mgh

where g is the acceleration due to gravity (9.81 m/s^2).

In this problem, the object is 3.00 m below the ground relative to a point 5.00 m below the ground. So, the height of the object relative to the reference point is:

h = -3.00 m - (-5.00 m) = 2.00 m

Note that we use a negative sign for h because the object is below the reference point.

Plugging in the values, we get:

U = (9.00 kg) x (9.81 m/s^2) x (-2.00 m) = -176.22 J

Rounding off to two significant figures, the gravitational potential energy of the object is -176 J. Therefore, the answer is -176J.

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1.18∗10^24 kg is the mass of the planet where a 4950 kg rock weighs 22,030 N with planet having a radius of 4200 km.

Define Newton's law of gravitation.

According to Newton's law of gravitation, every particle of matter in the universe is attracted to every other particle with a force that varies directly as the product of their masses and inversely as their distance from one another.

The universal power of attraction acting on all matter is known as gravity, also known as gravitation. It has no impact on defining the internal characteristics of common matter because it is by far the weakest known force in nature.

The object weighs m = 4950 kg.

The planet's radius is 4200 km, or 4200*1000 meters.

F= 22030 N, the object's weight

That which we are aware of is G the gravitational constant 6.674x10-11.

We must ascertain: planet's mass is given by M =?

F= GMm/r2

22030 = 6.674x10-11[(4950M)/(42001000)2]

⇒ M =1.18∗10^24 kg

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Answer:

f =ma

hope helps ..... ...

Answer:

1 Minutes =2Pi/60

21 Minutes=2Pi/60*21

so the answer is, 2.198

Explanation:

we know that

there is 60 min one hour

so the there is 2Pi radians

so 21 minutes is 21/60

and we know the clock hand will travel anticlock wise

and a full circle measures 2Pi radians

and we know that one minute =2Pi /60 radians

so, 21 minutes = (21Pi/60)*60

(Pi=3.14)

21 minutes = 2.19

The change in momentum of the ball is 1.0 kg m/s [E].

The change in momentum of the ball can be calculated using the momentum equation:

Δp = pf - pi

Where

The momentum of an object can be calculated as the product of its mass and velocity:

p = mv

Where

Using the given values, we can calculate the initial momentum of the ball:

pi = mvi = (0.1 kg)(5 m/s [W]) = 0.5 kg m/s [W]

Similarly, we can calculate the final momentum of the ball:

pf = mvf = (0.1 kg)(5 m/s [E]) = 0.5 kg m/s [E]

Substituting these values into the momentum equation, we get:

Δp = pf - pi = 0.5 kg m/s [E] - 0.5 kg m/s [W] = 1.0 kg m/s [E]

Therefore, the change in momentum of the ball is 1.0 kg m/s [E].

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Answer:

The correct answer is: 361 W

Explanation:

Answer:

Since the net torque is negative, this means that the counterclockwise torque is greater than the clockwise torque. As a result, the wheel will rotate in the counterclockwise direction. Therefore, the answer is:

The wheel will rotate counterclockwise.

Explanation:

To determine the resulting motion of the wheel, we need to calculate the net torque acting on the wheel. Clockwise torque is positive, while counterclockwise torque is negative. Therefore, the net torque can be calculated as follows:

Net torque = (Clockwise torque) - (Counterclockwise torque)

Net torque = (24.4 N) x (0.22 m) - (7.9 N) x (0.74 m)

Net torque = 5.368 Nm - 5.846 Nm

Net torque = -0.478 Nm

The correct responses are C because opals are found in sedimentary and metamorphic rocks.

3 Location There are two different varieties of opal that are found: volcanic opal, which fills vesicles and fissures in igneous rocks, and the more well-known sedimentary or sandstone type, which is found in Australia's major areas. Volcanic opal makes up the majority of deposits around the world, and a lot of it is prone to crazing.

A synthetic stone may be flawlessly flat since the two pieces are flattened so they may be bonded together, however the majority of real strong opals have an imperfection in this area that is curved or bumpy due to their natural development.

Thus it's obvious that Position 3 in the image depicts where opal is located.

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Complete question -

The locations of mineral and gem formation depend on different Earth processes. Some gems need heat, extreme pressure, or even a certain type of rock layer to form.

Which location in the figure shows where opal is most likely to form?

Select the correct location.

The GI tract has a plexus in the muscalaris, submucosal plexus, and nerves in the mucosa.

Hirschsprung disease (HD) is a congenital condition defined by the lack of ganglion cells (GC) at the Meissner's plexus (submucosa) and Auerbach's plexus (muscularized) of the terminal rectum.

Vomiting and extensive laxative use can cause digestive system disruption, resulting in stomach bleeding and regurgitation. By vomiting frequently, the esophagus relaxes, allowing stomach contents to ascend up into the pharynx and mouth.

Pepsin, for example, is a protein-degrading enzyme. Another enzyme that breaks down lipids is stomach lipase.

Stomach enzymes are essential for breaking down the food you consume. These proteins hasten molecular processes that convert nutrients into substances that can be absorbed by your digestive system.

Handwashing with detergent reduces the chance of gastroenteritis by up to 47%. Of course, avoiding tainted meals that may contain harmful germs and parasites is essential.

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The angle of application of the force ​ is theta = arccos(500 J / (F * 20 m))

We can use the work-energy principle to solve this problem. The work done by the gardener's force is equal to the change in kinetic energy of the mower. Since the mower starts from rest, the initial kinetic energy is zero. Therefore, the work done by the gardener's force is equal to the final kinetic energy of the mower:

Work = Change in kinetic energy

500 J = (1/2)mv^2

where m is the mass of the mower and v is its final velocity.

Since we don't know the mass of the mower or its final velocity, we cannot directly solve for the angle of application of the force. However, we can use the fact that the work done by a force is equal to the product of the magnitude of the force, the displacement, and the cosine of the angle between the force and the displacement:

Work = Fd cos(theta)

where F is the magnitude of the force, d is the displacement, and theta is the angle between the force and the displacement.

Substituting the given values, we have:

500 J = F(20 m) cos(theta)

Solving for the cosine of the angle:

cos(theta) = 500 J / (F * 20 m)

Since we don't know the magnitude of the force, we cannot directly solve for the angle. However, we can rearrange the equation to isolate the angle:

theta = arccos(500 J / (F * 20 m))

Therefore,  we need to know the magnitude of the force to find the angle of application.

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To lift an object off the ground a distance of 3m, Grace applies 50N of force and generates 75J/s. The time taken by Grace for the lift is 2 seconds.

A force is an effect that changes, or accelerates, the velocity of a mass-moving object (such as one that is travelling from a state of rest). It is a vector quantity since it can be a push or a pull and always has magnitude and direction. It is denoted by the letter F and is measured in newtons (N), the SI unit of force.

According to Newton's second law, an object's net force is equal to the speed at which its momentum is changing over time. This rule suggests that the acceleration of an object is directly proportional to the net force exerted on the object, is in the direction of the net force, and is inversely proportional to the mass of the object if its mass is constant.

According to the equation,

P = [tex]\frac{W}{t}[/tex]

where,

P is the power,

W is the work done and,

t is the time taken.

W = F×S

where,

F is the applied force and

S is the distance.

Substituting the values and solving for t,

time taken = 2 seconds

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The terminal velocity of the block is approximately 2.08 m/s when it is traveling downward with a drag coefficient of 0.822.

How to calculate terminal velocity?

To calculate the terminal velocity of the block, we need to use the equation for terminal velocity which is:

v_terminal = sqrt((2mg)/(ρAC_d))

where:

First, let's convert the dimensions of the block from centimeters to meters:

width = 16.0 cm = 0.16 m

length = 19.0 cm = 0.19 m

height = 25.0 cm = 0.25 m

Next, let's calculate the cross-sectional area of the block:

A = width * length = 0.16 m * 0.19 m = 0.0304 m^2

Now we can substitute the values into the equation for terminal velocity:

v_terminal = sqrt((24.55 kg9.81 m/s^2)/(1.43 kg/m^30.0304 m^20.822))

v_terminal = 2.08 m/s

Therefore, the terminal velocity of the block is approximately 2.08 m/s when it is traveling downward with a drag coefficient of 0.822.

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Answer:40m East

Explanation:

Initially, the two capacitors are charged up to the same voltage V, so the charge on the capacitor of capacitance C is Q = CV, and the charge on the capacitor of capacitance 2C is Q' = 2CV.

When the battery is removed and a dielectric medium of constant K is inserted between the plates of the first capacitor (of capacitance C), the capacitance of this capacitor becomes KC. The capacitance of the second capacitor remains the same at 2C.

The total charge on the capacitors remains the same, as no charge is lost or gained during this process. Therefore, we have:

Q = Q' = 2CV

After the insertion of the dielectric medium, the potential difference across the two capacitors will be different, as their capacitances have changed. Let V1 be the new potential difference across the capacitor of capacitance KC, and V2 be the potential difference across the capacitor of capacitance 2C.

We know that the total charge on the capacitors remains the same, so we can write:

Q = C1V1 + C2V2

where C1 = KC is the capacitance of the first capacitor (after insertion of the dielectric), and C2 = 2C is the capacitance of the second capacitor.

Substituting the values of C1, C2 and Q, we get:

CV = KV1 + 2CV2

Simplifying, we get:

V1 = (C/K) V - 2V2

But we also know that the potential difference across the two capacitors must be the same, i.e., V = V1 + V2. Substituting the value of V1 in this equation, we get:

V = [(C/K) V - 2V2] + V2

Simplifying, we get:

V2 = (1/3) V/K

Therefore, the potential difference across the capacitor of capacitance KC (after insertion of the dielectric) is:

V1 = (C/K) V - 2V2 = (5/3) V - (2/3) V/K

Thus, the potential on each capacitor after the insertion of the dielectric is V1 = (5/3) V - (2/3) V/K for the capacitor of capacitance KC, and V2 = (1/3) V/K for the capacitor of capacitance 2C.

The rotation per second of the spin of the tube is 1200 rps. The diameter of the tube is 35 cm or 0.35 m. Then, its velocity is 1308 m/s.

Angular velocity is a physical quantity that is the rotational analogue of the linear velocity. The angular velocity of an object is the velocity of rotation that is distance covered by one rotation per second.

Given  number of rotations  = 1200 rotation per second

circumference of the tube  = 2 π r = πd

c = 3.14 × 0.35 m = 1.09 m.

It means that, for one rotation, the tube covers a distance of 1.09 m. In one second it spins 1200 times.

Hence, the total distance travelled in one second = 1200/s × 1.09 m = 1308 m/s.

Therefore, the velocity of the 1 m tube is 1308 m/s.

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All of the following describe the region in which an electron is most likely to be found except an isotope. Thus, the correct option is B.

Isotopes can be defined as the distinct nuclear species of the same element. They have the same atomic number and the position in the periodic table as the main atom, however they differ in number of nucleons due to different numbers of neutrons in their nucleus.

Orbital is a volume of space present within an atom where an electron is most likely to be found. The s-orbitals are spherical in shape.

Cloud is the region present near the nucleus where the probability of finding an atom is highest. Cloud are the region of negative charge.

Path can also be defined as orbital. It is the exact route in which the electrons travel in an atom.

Therefore, the correct option is B.

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(a) Time taken, T is 11.83 s

(b) Acceleration is 1.428 m/s²

A body is said to be in uniform acceleration when it is moving in a straight line with an increase in velocity in equal intervals of time.

Here,

s = 100 m

v = u + at

a = (v - u)/t = (10 - 0)/7

a = 10/7 m/s²

(a) s = ut + 1/2 at²

   100 = 0 + 1/2 x 10/7 x t²

    t² = 140

    t = √140 = 11.83 s

(b) Acceleration, a = 10/7 =1.428 m/s²

Hence,

(a) Time taken, T is 11.83 s

(b) Acceleration is 1.428 m/s²

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Answer:

Find his gravitational then divide it by your potential

If a clock expends 2 W of power from a 1.5 V battery, 1.3A of current is supplying the clock

What is meant byelectric current ?

When an external voltage is given to one of the conductor's ends, the movement of particles known as an electric current begins. As a result, the negatively charged electrons that are drawn to the positive terminal of the exterior voltage are subject to an electric field.

The current through a conductor is proportional to the voltage across the conductor, according to Ohm's rule. As long as the temperature (and other physical factors) stay constant, this is true for many materials, including metals. The connection between voltage, current, and resistance in an electrical circuit can be calculated using Ohm's Law.

P ⇒ IV

I ⇒ P/V ⇒ 2/1.5 i.e. 1.3A

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As the speed of the car was less than the posted speed limit of 50 mi/h when the brakes were applied, skid marks provide evidence that driver was not speeding at the time of incident.

Measure of the amount of friction existing between the two surfaces is called as coefficient of friction.

Change in kinetic energy is: ΔK = 0 - 1/2mv²

W = fd

As f = μN

N = mg

fd = ΔK

μN d = 1/2mv²

μmgd = 1/2mv²

v = √(2μgd/m)

v = √(20.8025*0.45/1) ≈ 29.9 mi/h

Since the car's speed was less than the posted speed limit of 50 mi/h when the brakes were applied, the skid marks provide evidence that the driver was not speeding at the time of the incident.

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