A major problem with interval lengths that are too small is that it masks the shape of the distribution.
The interval length used in a distribution may be described as the size of the class or the class width. The interval length is usually important when drawing histograms and other related graphs for a grouped distribution.
The most significant effect of using a class interval which is too small is that it masks the actual shape of distribution, Hence preventing it from being distinct.
For best practice, it is essential that the class interval is of moderate width, hence enabling us to have a distribution which isn't maksed nor exaggerated.
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Find the distance between the points.
(9.7, -2.1), (-3.2, 8.1)
what property is being used in 2a+5a=(2+5)a
Answer:
distributive property
plzzzz help (wrong answers will be deleted )...(100 points!!)
16x^4−24x^3+3 / 4x^2+3 fill in the boxes(spaces lol) = x^2 - x - + /
[tex]\boxed{\sf \dfrac{a^m}{a^n}=a^{m-n}}[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{16x^4-24x^3+3}{4x^2+3}[/tex]
Take 4x^2+3 common out[tex]\\ \rm\Rrightarrow 4x^2+3\left(\dfrac{4x^2-24x+1}{1}\right)[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{4x^2-24x+1}{1}[/tex]
[tex]\\ \rm\Rrightarrow 4x^2-24x+1[/tex]
Answer:
4x² - 24x + 1
Step-by-step explanation:
[tex]\frac{16x^{4}-24x^{3}+3}{4x^{2}+3}[/tex]
~Factor out the denominator and apply quotient rule [ a^b / a^c = a^b-c ]
[tex]4x^{2}+3 (\frac{\frac{16}{4} x^{4-2}-24x^{3-2}+\frac{3}{3} }{1})[/tex]
[tex]\frac{4x^{2}-24x+1}{1}[/tex]
~Divide everything by 1
[tex]4x^{2} -24x+1[/tex]
Best of Luck!
write 2.5 repeating as a mixed number in simplest form.
Answer:
2 5/9
Step-by-step explanation:
2.5 repeating is 2 5/9 as a fraction (mixed number) or 23/9 (fraction)
The repeating decimal 2.5 can be written as the mixed number 2 5/9 in simplest form.
Here, we have,
To convert the repeating decimal 2.5 to a mixed number in simplest form, we can follow these steps:
Step 1:
Let's assume x = 2.5
Step 2:
Multiply both sides of the equation by 10 to shift the decimal point one place to the right: 10x = 25.5
Step 3:
Subtract the original equation from the one obtained in Step 2 to eliminate the repeating part:
10x - x = 25.5- 2.5
9x = 23 (since the repeating part subtracts to zero).
Step 4: Solve for x by dividing both sides by 9:
x = 23 / 9.
Step 5: Express the fraction 23/9 as a mixed number:
23 ÷ 9 = 2 remainder 5.
Therefore, x = 2 remainder 5/9.
so, we get,
Thus, the repeating decimal 2.5 can be written as the mixed number 2 5/9 in simplest form.
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at a certain certain point in time the sun of an alien world is directly overhead that
world's equator
Can someone help me on this?? Im really struggling
Determine the largest integer value of xx in the solution of the following inequality.[tex]2x-2\leq 11[/tex]
Answer:
6
Step-by-step explanation:
Add 2 to both sides, then divide both sides by 2.
[tex]2x \leq 13 \\x \leq 13/2[/tex]
x is less than or equal to 13/2, So the largest value is 13/2, or 6.5. Meaning the largest integer value is 6
At a charity fund-raiser, adult tickets were sold for $10 each and children's tickets were sold for $4 each. Write an algebraic expression for the total amount of money raised from the sale of tickets. How much money was raised if the fundraiser sold 244 adult tickets and 387 children's tickets?
Answer:
the all adult tickets made out 2440$
the all children tickets made out 1548
A street map uses a scale of 1 cm: 200 m.
a) Simplify this ratio.
B) Find the actual distance, in kilometres, represented by each scaled distance.
i) 7 cm
ii) 9.5 cm
iii)12.4 cm
C) Find the scaled distance, in centimetres, used to represent each actual distance,
i) 18 km
ii) 1500 m
iii) 9.6 km
Answer:
B)
1400m
1900m
2480m
C)
90cm
7.5cm
4.8cm
Given the function g of x is equal to the quantity 2 x squared plus 3 x plus 5 end quantity over the quantity x plus 3 end quantity determine the equation for the slant asymptote.
y = –2x + 3
y = 2x + 3
y = 2x – 3
y = 2x + 9
Answer: 2x-3
Step-by-step explanation:
2x-3
---------------
X+3 /2x^2+3x+5
( - )2x^2+6x Multiply x • 2x^2
______. and subtract it from 2x^2
-3x+5. Multiply x • -3 and subtract it
(-)-3x-9 from -3x
______
14
Answer:
y=2x-3
Step-by-step explanation:
Express cos9x cos3x as a sum of two trigonometry function
Step-by-step explanation:
the answer is in the image above
5x-4[7+(2x-4)], for x=-3
Answer:
-3
Step-by-step explanation:
Plug in x = -3
5(-3) - 4[7+(2(-3)-4)]
We'll use order of operations (PEMDAS) from here on out.
Evaluate what is in the innermost parentheses first (2(-3) - 4: the parentheses inside of the brackets). We first multiply 2 * -3, then subtract -4.
2(-3) - 4 = -6 - 4 = -10
So the whole expression becomes
5(-3) - 4[7+ -10]
Now evaluate what is in brackets.
5(-3) - 4[-3]
Multiplication next, before addition.
-15 + 12
Finally, addition
-3
Find the midpoint in geometry.
[tex]\\ \rm\longmapsto (x,y)=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)[/tex]
[tex]\\ \rm\longmapsto (x,y)=\left(\dfrac{3+3}{2},\dfrac{6-2}{2}\right)[/tex]
[tex]\\ \rm\longmapsto (x,y)=\left(\dfrac{6}{2},\dfrac{4}{2}\right)[/tex]
[tex]\\ \rm\longmapsto (x,y)=(3,2)[/tex]
PLEASE HELP I NEED HELP!!!!!! 30 POINTS
Figure B is a scaled copy of Figure A.
What is the scale factor from Figure A to figure B?
Answer:
1/3
Step-by-step explanation:
The left side of Figure A is 6 units long
The left side of Figure B is 2 units long
6 * what = 2
Divide each side by 6
what = 2/6
what = 1/3
The scale factor is 1/3
Answer:
[tex]\frac{1}{3}[/tex]
Step-by-step explanation:
Figure A has a base of [tex]6[/tex] units.
Figure B has a base of [tex]2[/tex] units.
So, 6 * [tex]x[/tex] (the scaled factor) = 2 which simplified is [tex]6x=2[/tex].
Now, we divide 6 on both sides giving us [tex]x = \frac{2}{6}[/tex] which can be further simplified into [tex]\frac{1}{3}[/tex]
-6, 20, 4.3, -59/-9
Order from least to greatest
Add.
-1 3/4 + (-3/5) + (-1/4)
Enter your answer as a simplified mixed number in the box.
Answer:
-2 3/5
Step-by-step explanation:
that is the answer yep
write the 3 terms of ( 2a+ax)^5 given the first terms in the expansion (b +2x) (2+ ax)^5 are 96 - 176x+cx^2. find the values of a,b,c
Answer:
a^5x^5, 10a^5x^4, 40a^5x^3
Step-by-step explanation:
Use pascal's triangle for the first one
(2+x)^5 * a^5
= x^5a^5 + 5*2^1*x^4*a^5 + 10*2^2*x^3*a^5 ...
= a^5x^5 + 10a^5x^4+ 40a^5x^3 ...
IXL PLEASE HELP
Ayana bought new equipment for her bowling alley, including a ball return machine. There is a 55% chance that the machine returns a bowling ball with the finger holes facing up.
If the machine returns 4 bowling balls, what is the probability that exactly 3 will have the finger holes facing up?
Write your answer as a decimal rounded to the nearest thousandth.
The answer would be .090
which numbers are equivalent to 3 tenths ? Choose all that apply.
Order the numbers from least to greatest.
A) 3.41%, 0.31, 0.314, 0.3333
B) 0.3333, 0.31, 0.314, 3.41%
C) 3.41%, 0.314, 0.3333, 3.51%
D) 0.31, 0.314, 0.333, 3.41%
Answer:
a) 3.41%, 0.31, 0.314, 0.3333
Name the pair of opposite rays with endpoint N.
Answer:
Possible Answers: NA and NX or NM and NC.Step-by-step explanation:
PLS MARK ME BRAINLEIEST AND FLW ME
10-7X-5+12x=0
Explain
Answer:
x = -1
Step-by-step explanation:
[tex]10 - 7x - 5 + 12x = 0[/tex]
➡️ [tex]5 - 7x + 12x = 0[/tex]
➡️ [tex]5 + 5x = 0[/tex]
➡️ [tex]5 + 5x - 5 = 0 - 5[/tex]
➡️ [tex]5x = 0 - 5[/tex]
➡️ [tex]5x = - 5[/tex]
➡️ [tex]5x \div 5 = - 5 \div 5[/tex]
➡️ [tex]x = - 5 \div 5[/tex]
➡️ [tex]x = - 1[/tex]
what is the solution to the compound inequality in interval notation
Answer:
First choice is the right answer (-∞, -9] or (2, ∞)
Step-by-step explanation:
I. Solve 1st problem 2(2x - 1) > 6
4x-2 > 6
4x > 6+2
x > 2
II. Solve 2nd problem x + 3 <= -6
x <= -6-3
x <= -9
III. Prove the answer
if x > 2 then x = 3
2( 2(3)-1 ) > 6
2(5) > 6
10 > 6 so the answer is true
if x <= -9 then x = -9
-9 + 3 <= -6
-6 <= -6 so the answer is true
Hope that help :D
John's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs John $5.95 per pound, and type B coffee costs $4.65 per pound. This month's blend used three times as many pounds of type B coffee as type A, for a total cost of $656.70. How many pounds of type A coffee were used?
Answer:
Let x = the number of lbs of Type A coffee.
We know that this month's blend used 3 times as many pounds of type B coffee as type A coffee.
Total lbs of coffee = x + 3x
The total cost then is:
($ cost for Type A)(x) + ($ cost for Type B)(3x) = $717.60
$5.65x + $4.25(3x) = $717.60
$5.65x + $12.75x = $717.60
$18.40x = $717.60
x = 39 lbs
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→
PQ and RS are in the same plane and do not intersect. What geometric term describes PQ and RS?
perpendicular lines
complementary lines
skew lines
parallel lines
Answer:
Parallel lines
Step-by-step explanation:
Can someone please help me I don’t get this (Due today)
Answer:
Which grade's book exercise is this?
finish 9 and 10 (giving lots of points!!!!)
Answer:
#9Rule for rotation 90 clockwise about the origin:
(x, y) → (y, -x)Apply to the given points:
S(1, -4) → S'(-4, -1)W(1, 0) → W'(0, -1)J(3, -4) → J'(-4, -3)#10Rule for rotation 180 about the origin:
(x, y) → (-x, -y)Apply to the given points:
V(-5, -3) → V'(5, 3)A(-3, 1) → A'(3, -1)G(0, -3) → G'(0, 3)102 A marathon is 26.2 miles long. There is a water station every 1 1/4 miles along the race route. How many water stations are needed for this marathon? tills
Answer:
21 stations
Step-by-step explanation:
1 1/4 = 5/4
26.2 / 5/4 = 20.96
rounded up to 21
Show 713.65 in expanded notation
Answer:
713.65 = (7 x 100) + (1 x 10) + (3 x 1) + (6/10) + (5/100)
Step-by-step explanation:
When a new cellphone is put on the market, the demand each month can be described by the function C of t is equal to negative square root of the quantity t squared plus 4 times t minus 12 end quantity plus 3 where C (t) represents the demand of the cellphone (measured in millions of people) and the time, t, is measured in months. Which of the following solution(s) are valid for a positive demand?
A function is positive where it is above the x-axis
The valid solution for positive demand are; t = 3, and t = 2
The reason the above values are correct is as follows:
Known parameters:
The given function of the demand is; [tex]C(t) = \mathbf{ -\sqrt{t^2 + 4 \times t - 12} +3}[/tex]
Where;
C(t) = The demand of the cellphone (in millions of people)
t = The number of months
The condition positive demand is C(t) ≥ 0
Therefore;
[tex]-\sqrt{t^2 + 4 \times t - 12} +3 \geq 0[/tex]
[tex]-\sqrt{t^2 + 4 \times t - 12} \geq -3[/tex]
[tex]\sqrt{t^2 + 4 \times t - 12} \leq 3[/tex]
t² + 4·t - 12 ≤ 9
t² + 4·t - 12 - 9 ≤ 0
t² + 4·t - 21 ≤ 0
(t - 3) × (t + 7) ≤ 0
∴ t ≤ 3, or t ≥ -7
At t = 2 < 3, we have;
C(2) = -√(2² + 4×2 - 12) + 3 = 3
At t = 1 < 3, the function is; C(1) = -√(1² + 4×1 - 12) + 3 (Is undefined)
Therefore, the valid solution for positive demand are;
t = 3, and t = 2
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Answer:
3,3
Step-by-step explanation: