2 Tom Milk his cow and got 2 litres of Milk He gave Kevin 350 ml and Sold 500m to Bob. How much milk is left?​

The total distance that a round trip will cover is 5,600 miles, under the condition that The trip to California from Missouri was 2,800 miles one way.

After considering all the given data induced by the question we come to the state that here we have to apply the principles of multiplication, to evaluate the distance cover when a round trip is taken from California to Missouri.
Then the calculation is

Round trip distance = 2 × one way distance
Round trip distance = 2 × 2,800 miles
Round trip distance = 5,600 miles
Then the distance covered in the couse of making a round trip from California to Missouri is 5,600 miles.
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Answer: 5 divided by 465 is 0.010752688172

          465 divided by 5 is 93

Step-by-step explanation:

Rectangles are relatable to factors because of their areas and perimeter equations

From the question, we have the following parameters that can be used in our computation:

Explaining why rectangles are relatable to factors

Rectangles are relatable to factors because of the following reasons

Perimeter = 2 * (Length + width)

Area = Length * width

This means that in calculating the areas and the perimeters of a rectangles, we make use of arithmetic expressions

These arithmetic expressions, when expanded form terms and factors of  expression

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We can be 95% confident that the true average monthly salary earned by all employees of People Plus Pty is between R16 234.49 and R20 765.51. This means if created for several samples of the same size taken from the population, would contain the actual population mean.

To construct a 95% confidence interval for the true average monthly salary earned by all employees of People Plus Pty, we can use the following formula:

CI = x ± t(α/2, n-1) * (s/√n)

where:

x = sample mean = R18 500

s = sample standard deviation = R1 750

n = sample size = 19

t(α/2, n-1) = t-score at α/2 and n-1 degrees of freedom

Using a t-table or calculator with 18 degrees of freedom (n-1), we can find the t-score at α/2 = 0.025 to be 2.101.

Plugging in the values, we get:

CI = 18500 ± 2.101 * (1750/√19)

= (16234.49, 20765.51)

Therefore, we can be 95% confident that the true average monthly salary earned by all employees of People Plus Pty is between R16 234.49 and R20 765.51.

This means that if we were to take multiple samples of the same size from the population and construct 95% confidence intervals for each sample mean, about 95% of those intervals would contain the true population mean.

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In one gram of substance 0.22 grams of nickel is present. Then the amount of nickel in the 35 grams of the substance is 7.7 grams.

A ratio is an ordered couple of numbers a and b, written as a/b where b can not equal 0. A proportion is an equation in which two ratios are set equal to each other.

A single gram of a certain metallic substance has 0.52 grams of copper and 0.26 grams of zinc.

The remaining portion of the substance is nickel.

Let the gram of nickel be x. Then we have

[tex]\sf x + 0.52 + 0.26 = 1[/tex]

[tex]\sf x = 0.22[/tex]

0.22 grams of nickel.

Ben estimated that 0.2 gram of nickel is in 1 gram of the substance.

He used this to estimate the amount of nickel in 35 grams of the substance.

Then we have

[tex]\sf \rightarrow35 \times 0.2 = 7[/tex]

We know that in 1 gram the amount of nickel is 0.22 gram. Then we have

[tex]\sf \rightarrow 35 \times 0.22 = 7.7[/tex]

The amount of nickel in the 35 grams of the substance is 7.7 grams.

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The average price of milk in 2018 was 6.45 dollars per gallon.

The average price of milk in 2021 was 189.95 dollars per gallon.

The given function is: Price = 3.55 + 2.90(1 + x)³

In order to find the average price of milk in 2018, we need to set x = 0:

Price in 2018 = 3.55 + 2.90(1 + 0)³ = 3.55 + 2.90(1) = 6.45 dollars per gallon

Price in 2021 = 3.55 + 2.90(1 + 3)³ = 3.55 + 2.90(64) = 189.95 dollars per gallon

Hence, the average price of milk in 2021 was 189.95 dollars per gallon.

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Megha's total movement involves biking 20km north, 30km east, 20km south, and 30km west, resulting in a displacement of zero as she ends up back at her starting point.

Given that,

Megha bikes 20km north.

Megha then bikes 30km east.

After that, Megha bikes 20km south.

Lastly, Megha bikes 30km west.

Megha stops after completing the above movements.

Megha's displacement can be calculated by finding the straight-line distance between her starting point and ending point.

In this case,

She initially bikes 20km north, then 30km east, followed by 20km south, and finally 30km west.

Let's break it down:

The north and south distances cancel each other out, as she ends up back at her starting point vertically.

The east and west distances also cancel each other out, as she ends up back at her starting point horizontally.

Hence,

Megha's displacement is zero. She has returned to her original position.

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The only value of x where f'(x) = 0 is x = 0.

Let's find all values of x where the derivative of f(x) = [tex]arcsin(e^(2x) – 2x)[/tex] is equal to 0.

Step 1: Find the derivative f'(x) using the chain rule.

For this, we'll need to differentiate [tex]arcsin(u)[/tex] with respect to u, which is [tex](1/√(1-u^2))[/tex], and then multiply by the derivative of u [tex](e^(2x) – 2x)[/tex]with respect to x. So, f'(x) = [tex](1/√(1-(e^(2x) – 2x)^2)) * d(e^(2x) – 2x)/dx[/tex]

Step 2: Find the derivative of e^(2x) – 2x with respect to x. Using the chain rule and the derivative of [tex]e^u: d(e^(2x) – 2x)/dx = 2e^(2x) – 2[/tex]

Step 3: Combine the derivatives. f'(x) =[tex](1/√(1-(e^(2x) – 2x)^2)) * (2e^(2x) – 2)[/tex]

Step 4: Set f'(x) equal to 0 and solve for x. [tex](1/√(1-(e^(2x) – 2x)^2)) * (2e^(2x) – 2) = 0[/tex]

Since the first part of the product [tex](1/√(1-(e^(2x) – 2x)^2))[/tex] is never 0, we can focus on the second part: [tex]2e^(2x) – 2 = 0[/tex]

Step 5: Solve for x. [tex]2e^(2x) = 2 e^(2x) = 1[/tex]

The only way this is true is when 2x = 0, since [tex]e^0 = 1: 2x = 0 x = 0[/tex]

So, the only value of x where f'(x) = 0 is x = 0.

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The expected value of each warranty sold is $2.47.

The expected value of each warranty sold can be calculated by subtracting the cost of the warranty from the expected value of the potential savings on replacement costs.

Let's assume that the company sells 1000 warranties. Then, the expected number of products that will fail within 2 years is:

0.5% of 1000 = 0.005 x 1000 = 5

The expected cost of replacing these products is:

5 x $500 = $2500

Therefore, the expected value of the warranty is:

($2500 - $33 x 1000) / 1000 = $2.47

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Answer:

it will be P'(y,-x) since it is clockwise direction and I anti clockwise the formula to find the coordinates will be (-y,x)

52

There are 52 ways to draw the first card from a standard deck of 52 cards. Each card in the deck is distinct, so there are 52 different possibilities for the first card.

The deck consists of 4 suits (diamonds, hearts, spades, and clubs) with 13 cards in each suit. Therefore, there are 13 cards of the spades suit. Since each card is equally likely to be drawn, the probability of drawing a spade as the first card is 13/52 or 1/4.

This is because out of the 52 possible cards, 13 of them are spades. So, regardless of the specific spade that is drawn, there are 13 ways to draw a spade as the first card.

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Using quadratic formula, the value of x in the quadratic equation are 1.47 and -0.85

To find the value of x, we can either use quadratic formula or factorization method.

8x² - 2 - 5x = 8

Let's rewrite the equation properly

8x² - 5x - 2 - 8 = 0

8x² - 5x - 10 = 0

a = 8, b = -5, c = -10

Using quadratic formula;

-b ±[√b² - 4ac / 2a]

-(-5) ±[√(-5)² - 4(8)(-10) / 2(8)]

x = 5+ √345 / 16 or x = 5 - √345 / 16

x = 1.47 or x = -0.85

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Answer:

the answer for this problem would be -20

Answer:

-20

Step-by-step explanation:

The easiest way to do it is to change -3 3/7 and 5 5/6 into improper fractions. To do that, let’s take -3 3/7 for example. You would add the numerator by the whole number, and then multiply the denominator by the whole number. Getting you -24/7, the other number would be 35/6 then you multiply the two getting you -840/42, which it turned back into a proper fraction by dividing the two numbers, you would get -20. Hope this helps!

Ferris wheel has the same diameter as The Colossus is g(t) = 40 cos (π/45 t) +50. So, correct option is A.

To determine which of the given functions represents a Ferris wheel with the same diameter as The Colossus, we need to use the fact that the diameter of a Ferris wheel is equal to the amplitude of the sinusoidal function that models its height.

The amplitude of the function f(t) = 40 sin (π/45 t) +48 is 40, so the diameter of The Colossus is 40 feet. We need to find the function that also has an amplitude of 40.

Looking at the given answer choices, we see that function g(t) has an amplitude of 40 cos (π/45 t) +50, which is equal to 40. This means that the Ferris wheel represented by function g(t) has a diameter of 40 feet, the same as The Colossus.

Functions h(t), j(t), and k(t) all have amplitudes that are less than 40, so they represent Ferris wheels with smaller diameters than The Colossus.

Therefore, the answer is A.

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The given equation is 4h(x) = x - 4.

To find the domain of h(x), we need to determine the set of all possible input values for x that will result in a valid output value for h(x).

Since there are no restrictions on the input values for x in the given equation, the domain of h(x) is all real numbers.

Your answer: The domain of h(x) is all real numbers.

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The domain of the function 4h(x) = x - 4 is all real numbers, because there's no value of x that can make the equation undefined. It's represented as (-∞, ∞).

In the function 4h(x) = x - 4, the variable x is an independent variable and it can take any real number as value. Therefore, the domain of this function refers to the set of all possible x-values. In other words, the domain of this function is all real numbers.

A function's domain is essentially the set of all values that can be plugged into the function without causing problems such as division by zero or taking the square root of a negative number. In the given equation, there's nothing that would limit the possible values of x.

Therefore, the domain of h(x) in this case is all real numbers, symbolically represented as (-∞, ∞).

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The value of the scale factor for the similar figures is 1/2

From the question, we have the following parameters that can be used in our computation:

The similar figures

The corresponsing sides of the similar figures are

Original = 8

New = 4

Using the above as a guide, we have the following:

Scale factor = New /Original

substitute the known values in the above equation, so, we have the following representation

Scale factor = 4/8

Evaluate

Scale factor = 1/2

Hence, the scale factor for the similar figures is 1/2

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Answer:

x = 4 and y = 9

Step-by-step explanation:

Let x and y be the two numbers. Also,

Let the first number be x and the second number be y.

Converting the word expressions to an equation we get:

                   y = x + 5

               3x + 2y = 30

Only thing left is to substitute y = x + 5 into the second equation

     3x + 2y = 30

     3x + 2(x + 5) = 30   (substituting y as x + 5)

     3x + 2x + 10 = 30   (multiplying by both x and 5)

     5x = 30 - 10     (collecting like terms to one side)

     5x = 20

     [tex]\frac{5x}{5} = \frac{20}{5}[/tex]     (divide both sides by 5 to get the value of x)

     x = 4

 Now that we know the value of x, we can find y.

      y = x + 5

      y = 4 + 5

      y = 9

If you want to make sure your answer is correct, substitute x and y into the equation.

  3x + 2y = 30

  3(4) + 2(9) = 30

  12 + 18 = 30

  30 = 30

For the g(x) functions provided, here are their key features:

g(x) = (x + 2)(x − 1)(x − 2)

End behavior: As x approaches negative or positive infinity, g(x) approaches positive infinity.

Y-intercept: g(0) = -4

Zeros: x = -2, 1, 2

Ray and Kelsey could both be accurate, all depending on the stated third-degree polynomial function.

It is conceivable for a third-degree polynomial to present up to three zeros, thus corroborating Kelsey's point that the function can have up to three intersection points with the x-axis maximum. Moreover, it can even occur that this function possesses a repeatable zero, causing a fourth interception.

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The circumference of the tank is is 125.66m and the percentage of the circumference that is visible to the person is 10.24%.

a) To calculate the circumference of the cylindrical tank, using the formula C = 2πr, where C is the circumference and r is the radius of the tank. In this case, r = 20 m, so:

C = 2π(20 m) ≈ 125.66 m

b) To determine the percentage of the circumference visible to the person, we first need to calculate the angle (in degrees) that subtends the visible arc. This can be done using the inverse tangent function:

angle = atan(opposite/adjacent) = atan(20 m/60 m)

angle ≈ 18.43°

Since the visible arc is symmetrical on both sides, the total angle of the visible arc is twice the calculated angle:

total angle ≈ 36.86°

Now, calculate the percentage of the circumference that is visible by dividing the total angle by 360° and multiplying by 100%:

percentage = (36.86°/360°) × 100% ≈ 10.24%

So, the visible percentage of the circumference to the person is approximately 10.24%.

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The total number of Huns that migrated to the West is 111.

To find the total number of Huns that migrated to the West, we can use the expression:

Total number of Huns = Number of groups x Number of people per group

For the front and back sections, there were 3 groups of 5 people each, so the total number of Huns in each section is:

3 x 5 = 15

For the middle section, there were 9 groups of 9 people each, so the total number of Huns in the middle section is:

9 x 9 = 81

To find the total number of Huns that migrated to the West, we add up the number of Huns in each section:

15 + 81 + 15 = 111

Therefore, the total number of Huns that migrated to the West is 111.

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The value of the car after 8 years is given as follows:

$10,836.76.

An exponential function has the definition presented as follows:

[tex]y = ab^\frac{x}{n}[/tex]

In which the parameters are given as follows:

The parameter values for this problem are given as follows:

a = 86000, n = 5, b = 1 - 0.726 = 0.274.

Hence the function for the value of the car after x years is given as follows:

[tex]y = ab^\frac{x}{n}[/tex]

[tex]y = 86000(0.274)^\frac{x}{5}[/tex]

The value of the car after 8 years is then given as follows:

[tex]y = 86000(0.274)^\frac{8}{5}[/tex]

y = $10,836.76.

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The shooter was located approximately 36.15 feet off the ground.

We can use trigonometry to solve for the height of the shooter.

First, we need to find the horizontal distance from the shooter to the man on the park bench. We can use the angle of 26° and the distance of 92 feet to calculate this distance:

horizontal distance = 92 feet * cos(26°)

horizontal distance = 82.33 feet

Next, we can use the height of 3.7 feet and the horizontal distance of 82.33 feet to find the height of the shooter:

tan(26°) = height difference / horizontal distance

height difference = horizontal distance * tan(26°)

height difference = 82.33 feet * tan(26°)

height difference = 36.15 feet

Therefore, the shooter was located approximately 36.15 feet off the ground.

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The critical points of f(x) are x = 0 and x = e^(-1/2) / 3, and x = e^(-1/2) / 3 corresponds to a local minimum of f(x). Cmin = e^(-1/2) / 3 and Cmax = 0.

Taking the derivative of f(x) with respect to x using the product rule and the chain rule, we get:

f'(x) = 14x ln(3x) + 7x

Setting f'(x) equal to zero and solving for x, we get:

14x ln(3x) + 7x = 0

Factor out x:

7x(2ln(3x) + 1) = 0

So either x = 0 or 2ln(3x) + 1 = 0.

If x = 0, then f'(x) = 0 and x is a critical point.

If 2ln(3x) + 1 = 0, then ln(3x) = -1/2 and 3x = e^(-1/2). Solving for x, we get:

x = e^(-1/2) / 3

So e^(-1/2) / 3 is also a critical point.

Now we need to apply the second derivative test to determine whether these critical points correspond to a local minimum or maximum.

Taking the second derivative of f(x), we get:

f''(x) = 14 ln(3x) + 21

For x = 0, we have:

f''(0) = 14 ln(0) + 21

The natural logarithm of zero is undefined, so the second derivative does not exist at x = 0. Therefore, we cannot apply the second derivative test at x = 0.

For x = e^(-1/2) / 3, we have:

f''(e^(-1/2) / 3) = 14 ln(1/e^(1/2)) + 21

= -14/2 + 21

= 7/2

Since the second derivative is positive at this point, we can conclude that x = e^(-1/2) / 3 is a local minimum of f(x).

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Answer:

plugging in those values you get 40+(81/9)=40+9=49.

The best estimate of the volume of this cylindrical water dispenser is 2940 in³. The correct option is b.

To estimate the volume of the cylindrical water dispenser, we can use the formula for the volume of a cylinder, which is given by V = πr²h, where V is the volume, π is a mathematical constant approximately equal to 3.14, r is the radius, and h is the height.

Given that the radius of the water dispenser is 7 inches and the height is 20 inches, we can substitute these values into the formula:

V = π(7²)(20)

V = π(49)(20)

V ≈ 3.14 × 49 × 20

V ≈ 3.14 × 980

V ≈ 3075.2 in³

From the given options, the closest estimate to the calculated volume of approximately 3075.2 in³ is option B: 2940 in³. While it is not an exact match, it is the closest estimate among the options provided.

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Answer: 6 chocolates

Step-by-step explanation:

Keilantra had 24 chocolates to begin with, and she ate six lots of three. so the first step is 6 x 3 = 18. Now that we know how many chocolates Keilantra ate, we need to figure out how many chocolates she has left. So we take our product (18) and we subtract it from the total (24). So we end up with 24 - 18 = 6.

The volume of the different shapes have been calculated in the space below

Volume of rectangular prism = lwh

where we define the variables as :

l = length

w = width

h = height

then when we multiply, we will have

= 4 x 10 x 6

= 240

Volume of triangular pyramid = 1 / 3 b x h

where b = base

h = height

1 / 3 x 1.5 x 2

= 1

Volume of rectangular pyramid = lwh / 3

= 7.5 x 4.5 x 5 / 3

= 56.25

= 1/2 x b x h x l

= 1/2 x 3 x 8.5 x 7

= 89.25

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Answer:

1. 5,25,125,625,3125, 15625,78125

Rule: We multiply each term of the sequence by 5.

2.12, 24, 48, 96, 192, 384, 768

Rule: We multiply each term of the sequence by 2.

3. 85, 80, 75, 70, 65, 60, 55

Rule:subtract 5 from each term of the sequence

4.3;5,7,9,11,13,15

Rule: Add 2 to every term in the sequence

5.12, 13,15,16,18,19,21,22

Rule: We first add 1 to the previoys term then add 2 to the new term of the sequence and so on.

The domain of the set of points {(0,1),(5,2),(2,-3),(-3,-3),(-5,3)} is {0, 5, 2, -3, -5}, and the range is {-3, 1, 2, 3}.

Given the relations in the question:

(0,1), (5,2), (2,-3), (-3,-3), (-5,3)

To determine the domain and range of a set of points, we need to look at the x-coordinates of the points to determine the domain, and the y-coordinates of the points to determine the range.

{(0,1),(5,2),(2,-3),(-3,-3),(-5,3)}

The x-coordinates of these points are: 0, 5, 2, -3, and -5.

Therefore, the domain of this set of points is:

Domain = {0, 5, 2, -3, -5}

The y-coordinates of these points are: 1, 2, -3, and 3.

Therefore, the range of this set of points is:

Range = {-3, 1, 2, 3}

Therefore, the domain is {0, 5, 2, -3, -5}, and the range is {-3, 1, 2, 3}.

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The group of natural numbers is a subset of the whole numbers.

What is Whole number ?

Whole numbers are a set of numbers that includes all positive integers (1, 2, 3, ...) and zero (0). They do not include negative numbers or fractions. Whole numbers are often used to count objects or represent quantities that cannot be divided into smaller parts.

Out of the given options, the group of natural numbers is the only one that is a subset of whole numbers. The other options - Rational numbers, Real numbers, Irrational numbers, and Integers - are not subsets of the whole numbers.

Rational numbers include fractions and decimal numbers, which can be expressed as a ratio of two integers, including non-whole numbers.

Real numbers include all rational and irrational numbers, including non-whole numbers. Irrational numbers are non-repeating, non-terminating decimals that cannot be expressed as a fraction. Integers include both positive and negative whole numbers, as well as zero.

The subset of whole numbers is called natural numbers.

Therefore, the group of natural numbers is a subset of the whole numbers.

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