2 LiOH + CO2 > Li2CO3 + H2O

How many milliliters H20(density = .997 g/mL could form from 29.3g LiOH

Answers

Answer 1

Answer:

We can use stoichiometry to determine the amount of water produced when 29.3 g of LiOH reacts with CO2.

First, we need to convert 29.3 g of LiOH to moles:

moles of LiOH = mass/molar mass = 29.3 g / (6.941 g/mol + 15.999 g/mol + 1.008 g/mol) = 0.5 mol

From the balanced chemical equation, we see that 2 moles of LiOH react with 1 mole of CO2 to produce 1 mole of H2O. Therefore, we can say:

0.5 mol LiOH × (1 mol H2O / 2 mol LiOH) = 0.25 mol H2O

Now, we can use the molar mass of water to convert moles to grams:

mass of H2O = moles × molar mass = 0.25 mol × 18.015 g/mol = 4.504 g

Finally, we can use the density of water to convert grams to milliliters:

volume of H2O = mass / density = 4.504 g / 0.997 g/mL = 4.52 mL

Therefore, approximately 4.52 mL of water could form from 29.3 g of LiOH.


Related Questions

2.62 Predict the chemical formulas of the compounds formed by the following pairs of ions: (a) Cr3+ and Br, (b) Fe3+ and O2, (c) Hg22+ and CO2, (d) Ca2+ and CIO3, (e) NH4+ and PO³

Answers

The compounds formed are;

1) [tex]CrBr_{3}[/tex]

2) [tex]Fe_{2} O_{3}[/tex]

3)  [tex]((Hg)_2}) _{2} (CO_{3}) _{2}[/tex]

4) [tex]Ca(ClO_{3} )_{2}[/tex]

5)[tex](NH_{4}) _{3} PO_{4}[/tex]

How are ionic compounds formed?

Ionic compounds are formed through a type of chemical bonding called ionic bonding. Ionic bonding occurs when one or more electrons are transferred from one atom to another, resulting in the formation of ions, which are atoms or molecules that have a net electric charge due to a loss or gain of electrons.

The formation of ionic compounds typically occurs between atoms with large differences in electronegativity, or the ability of an atom to attract electrons.

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The periodic table is shown below.



When a highly reactive metal, such as magnesium (Mg), is mixed with a reactive nonmetal such as sulfur (S), the two elements will most likely combine to form a new substance, magnesium sulfide (MgS).

Based on the trends of the periodic table, which other element is likely to combine with magnesium?

Answers

According to the periodical table's trends, an element with qualities like to sulfur (S) is most likely to mix with mag (Mg), as magnesium has a predisposition to react with sensitive nonmetals the same as sulfur and produce compounds.

Is daily magnesium intake okay?

For the majority of individuals, regular doses under 350 mg are safe. The adverse effects of magnesium can also include nausea, nausea, diarrhea, and upset stomach in some people. Magnesium is POSSIBLY SAFE Only if TAKEN IN VERY HIGH AMOUNTS (more than 350 mg daily).

Anybody shouldn't take magnesium, right?

And then use magnesium, individuals who have diabetes, digestive disease, heart disease, or renal disease should see their healthcare professional.

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What is the water of crystallization for a hydrate composed of 45.1% water? The anhydrous salt has a mass of 178 amu.

Answers

The 8 anhydrοus salt has a mass οf 178 amu..

What is mοle?

A mοle is the atοm's elementary particle, an iοn. The mοle οf the substance is always related tο the Avοgadrο number. The mοle is always assοciated with the weight οr mass οf the element οr substance. The standard unit οf a mοle is mοl. The mοle is a significant factοr οf the reactant and prοducts tο fοrm an equatiοn. A mοle calculates the atοm, iοn, and substance weighs.

The amοunt οf matter in a bοdy is referred tο as its mass. The kilοgrams is the kilοgrams, which is the SI unit οf mass (kg). Mass is defined as: Mass = Density /Vοlume.

mass οf water =45.1%    = 45.1 g

means that 45.1 g οf water in 100 g salt

hence mass οf anhydrοus salt(As)= 100 g  - 45.1 g =  54.9 g

mοlar mass οf anhydrοus salt (As) = 178 amu=178 g /mοl

mοlar mass οf water (H2O)=18.015 g /mοl

1st step:-     Find mοl οf  water

mοl οf water =   mass οf water /  mοlar mass οf water

=   45.1 g / 18.015 g /mοl

=  2.5035 mοl

2nd step:-      find mοl οf Anhydrοus salt

mοl οf  Anhydrοus salt (As) = mass οf anhydrοus salt /     mοlar mass οf anhydrοus salt

=     54.9 g  /  178 g /mοl

=  0.3084 mοl

3rd step:-calculate water οf crysatlisatiοn

=    mοl οf water  /   mοl οf  Anhydrοus salt    

=    2.5035 mοl /  0.3084

=  8.118  

=  8 (apprοx)

hence tοtal 8 mοl οf water present in Anhydrοus salt(As)   = As*8H20

Therefοre, 8 anhydrοus salt has a mass οf 178 amu.

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What can you deduce about the molecular composition of the reactants in a chemical reaction with the following atomic masses?
Reactants: (12 + 1 + 1 + 1 + 1) + (24 +16) = 56 u

Answers

Stoichiometric amounts relate to the proportional amounts of reactants and products in a balanced chemical equation.

What transpires during a chemical reaction to the molecules of the reactants?

Only atoms from the reactants can wind up in the products of a chemical reaction. No atoms are annihilated or made into new ones. To create the products, the reactants come into contact with one another, the bonds between their atoms are broken, and the atoms then rearrange and establish new bonds.

The frequency of collisions between the two reactants will grow as the reactant concentration rises. There are times when collisions don't cause a response (atoms misaligned or insufficient energy, etc.). More collisions and reaction possibilities result from higher concentrations.

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Find the concentration of I in 0.10 M AgNO, saturated with AgI. Include activity coefficients in the solubility-product
expression. The Ksp of AgI is 8.3 x 10-17.

Answers

The concentration of I in 0.10 M AgNO, saturated with AgI in the solubility product  is 8.3 x 10^-16 M.

Solubility product calculation.

The solubility product expression for AgI is:

Ksp = [Ag+][I-]

At equilibrium, the concentration of Ag+ ions is equal to the solubility of AgI, which is equal to the molar solubility of AgI in 0.10 M AgNO3. Let's assume that the molar solubility of AgI is x. Then, the equilibrium concentrations of Ag+ and I- ions are:

[Ag+] = 0.10 M + x

[I-] = x

The solubility product expression can be written as:

Ksp =[tex]\sqrt{x}[/tex] ([Ag+] * [I-])

Substituting the equilibrium concentrations into the solubility product expression, we get:

Ksp = √(0.10 M + x) * (x)

Using the quadratic equation, we can solve for x:

Ksp =√ 8.3 x 10^-17

0.10 M is much greater than x, so we can assume that (0.10 M + x) ≈ 0.10 M

Ksp = (0.10 M) * (x)

x = Ksp / (0.10 M)

x = 8.3 x 10^-16

So, the molar solubility of AgI is 8.3 x 10^-16 M. Since the concentration of I- ions is equal to the solubility of AgI, the concentration of I- ions is also 8.3 x 10^-16 M.

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please help!!! A, B, C, or D

Answers

Answer:

A

Refer to pic for explanation

Method for naming ionic compounds

Answers

The cation is mentioned first, followed by the anion, when identifying an ionic compound. Positive and negative charges must be equal. Certain anions with various forms are denoted by Roman numerals.

What procedures are employed while naming ionic compounds?

Ionic compounds, which are neutral substances, are made up of positively charged ions, known as cations, and negatively charged ions, known as anions. substances with binary ions (ionic compounds that contain only two types of elements).

What is a naming guideline for ionic compounds?

The anion is written after the cation in the name. When a formula unit contains two or more of the same polyatomic ion, the subscript is written outside of the parenthesis.

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rate law problem need help on

Answers

The rate of a reaction is proportional to the some power of the molar concentration of each of the reactants. The order gives us an idea about the kinetics of the reaction.

What is order of a reaction?

The order of a reaction is defined as the sum of the powers of the concentration terms of the reactants in the experimentally determined rate equation for the reaction. It is an experimental quantity.

a. The order of the alkene is 1

b. The order of the bromine s 2

c. The overall kinetic order is 3

Since the reaction is third order, the overall rate constant is mol²L⁻²s⁻¹ or M⁻²s⁻¹.

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Zn + 2HCI H2 + ZnCI2 caculate the grams of zinc chloride produced if .236 grams of zinc react completely

Answers

The grams of zinc chloride produced if .236 grams of zinc react completely is 0.492 grams

Grams calculation

The balanced chemical equation for the reaction is:

Zn + 2 HCl → H2 + ZnCl2

The molar mass of Zn is 65.38 g/mol and the molar mass of ZnCl2 is 136.29 g/mol.

To calculate the grams of zinc chloride produced, we first need to find the number of moles of zinc used in the reaction:

moles of Zn = mass of Zn / molar mass of Zn

moles of Zn = 0.236 g / 65.38 g/mol

moles of Zn = 0.00361 mol

From the balanced chemical equation, we can see that the stoichiometric ratio of Zn to ZnCl2 is 1:1. This means that 0.00361 mol of Zn will produce 0.00361 mol of ZnCl2.

To calculate the mass of ZnCl2 produced, we can use the following equation:

mass of ZnCl2 = moles of ZnCl2 x molar mass of ZnCl2

mass of ZnCl2 = 0.00361 mol x 136.29 g/mol

mass of ZnCl2 = 0.492 g

Therefore, if 0.236 grams of zinc react completely, 0.492 grams of zinc chloride will be produced.

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To be considered a cognitive psychologist, you typically need what degree?

All cognitive psychologists work in academia performing research. T OR F

If you want to pursue a career in cognitive psychology, it is important to participate in a DIS during your undergraduate career. T or F

Answers

A Ph.D. or Psy.D. in psychology with a cognitive psychology concentration is normally required to be categorized as a cognitive psychologist. Thus, the choice is between a Ph.D. and a Psy.D.

All cognitive psychologists work in academia performing research. T OR F

False. While most cognitive psychologists do their study in academic institutions, some may work in governmental, nonprofit, or commercial organizations.

If you want to pursue a career in cognitive psychology, it is important to participate in a DIS during your undergraduate career. T or F

False. It is not compulsory to pursue a career in cognitive psychology, even though taking part in a Directed Independent Study (DIS) during your undergraduate studies may be advantageous to get research experience in the field. Other options for developing one's research abilities and experience include working in a lab or doing an internship.

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Calculate the pH at the equivalence point for the following titration: 0.20 M HCl versus 0.10 M NaOH.

Answers

The pH at the equivalence point for the titration of 0.20 M HCl versus 0.10 M NaOH is 7.0.

The reaction between HCl and NaOH is a strong acid-strong base titration. At the equivalence point, all of the HCl has reacted with an equal amount of NaOH to form water and NaCl.

Steps

The balanced equation for the reaction is:

HCl + NaOH → NaCl + H2O

Since the reaction between HCl and NaOH is a 1:1 stoichiometric ratio, we can say that at the equivalence point, the moles of HCl consumed are equal to the moles of NaOH added.

Moles of HCl = concentration of HCl × volume of HCl used

Moles of NaOH = concentration of NaOH × volume of NaOH added

At the equivalence point, Moles of HCl = Moles of NaOH. Therefore,

concentration of HCl × volume of HCl used = concentration of NaOH × volume of NaOH added

Since we have equal volumes of HCl and NaOH at the equivalence point, we can simplify the equation to:

concentration of HCl = concentration of NaOH

Therefore, the concentration of HCl and NaOH at the equivalence point is both 0.15 M (the average of the initial concentrations of 0.20 M HCl and 0.10 M NaOH).

To find the pH at the equivalence point, we can use the equation for the dissociation of water:

H2O ⇌ H+ + OH-

At 25°C, the concentration of water is 55.5 M. At the equivalence point, the concentration of H+ and OH- are both equal, so we can write:

Kw = [H+][OH-]

where Kw is the ion product constant for water, which has a value of 1.0 × 10^-14 at 25°C.

At the equivalence point, the concentration of H+ and OH- are both equal to the concentration of NaOH and HCl, which is 0.15 M.

Therefore:

Kw = [H+][OH-]

1.0 × 10^-14 = [0.15][0.15]

[H+] = [OH-] = sqrt(1.0 × 10^-14) = 1.0 × 10^-7 M

The pH at the equivalence point is equal to the negative logarithm of the H+ concentration:

pH = -log[H+]

pH = -log(1.0 × 10^-7)

pH = 7.0

Therefore, the pH at the equivalence point for the titration of 0.20 M HCl versus 0.10 M NaOH is 7.0.

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Magnesium carbonatea n d hydrochloric acid react to produce salt, water and carbon
dioxide.
MgcO, + 2 HCt m MgCh + H,0 +CO. .
What is the volume of CO, produced when 21 g of magnesium carbonate reacts
completely with excess hydrochloric acid?
A 4 dma
B 8dm°
C 6dm D 2dm

Answers

Answer:

Explanation:

The balanced chemical equation for the reaction between magnesium carbonate and hydrochloric acid is:

MgCO3 + 2HCl → MgCl2 + H2O + CO2

From the equation, we can see that 1 mole of magnesium carbonate reacts with 2 moles of hydrochloric acid to produce 1 mole of carbon dioxide. The molar mass of magnesium carbonate is 84.3 g/mol, which means that 21 g of magnesium carbonate is equal to 0.25 moles (21/84.3). Therefore, 0.25 moles of magnesium carbonate will react with 0.5 moles of hydrochloric acid to produce 0.25 moles of carbon dioxide.

The volume of carbon dioxide can be calculated using the ideal gas law, which is PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. Assuming standard temperature and pressure (STP) of 273 K and 1 atm, we can use the molar volume of a gas at STP, which is 22.4 L/mol, to calculate the volume of carbon dioxide produced.

V = n × 22.4 L/mol

V = 0.25 mol × 22.4 L/mol

V = 5.6 L

Therefore, the volume of carbon dioxide produced when 21 g of magnesium carbonate reacts completely with excess hydrochloric acid is 5.6 L. The answer is option A, 4 dm³, which is approximately equal to 5.6 L.

which of the following is a single replacement reaction?
A) FeS+2HCl --> H2S+FeCl2
B) Fe+CuSO4 --> FeSO4+Cu
C) AgNO3+NaCl --> AgCl+NaNO3
D) None of the above​

Answers

Answer: None of the above

Explanation:

Can someone help explain how to solve this question? A 250 ml flask contains 0.75 miles of O2, 0.13 miles of N2, and enough moles of H2 that produces a partial pressure of 0.74 atm. The temperature of the gas mixture is 297k. Calculate the total pressure of the flask and calculate the mole fraction of H2.

Answers

Did you know that dogs can walk on water me to I didn’t even know until I look at young boy never broke again post

Consider the Haber-Bosch process for the synthesis of ammonia from its elements.
Calculate the theoretical yield in moles NH, from the complete reaction of 15.6
grams H₂ in the presence of excess N, gas according to the following balanced
chemical equation:
ADD FACTOR
3 H₂(g) → 2 NH,(g)
N₂(g) + 3

Answers

Answer:

The theoretical yield in moles of NH3 is 5.2 moles. This is calculated by dividing the mass of H2 (15.6 g) by the molar mass of H2 (2.016 g/mol) to get the number of moles of H2 (7.76 moles). Then, using the mole ratio from the balanced equation, we can calculate the number of moles of NH3 produced (5.2 moles).

Explanation:

2 Al + 6 HCI 2 AICI, +3 H2 What mass of aluminum is required to produce 30 grams of H2​

Answers

Answer:

269.8

Explanation:

The balanced chemical equation for the reaction between aluminum and hydrochloric acid is:

2 Al + 6 HCl -> 2 AlCl3 + 3 H2

From the equation, we can see that 2 moles of aluminum react with 3 moles of H2 to produce 2 moles of AlCl3. Therefore, the molar ratio of aluminum to hydrogen gas is 2:3.

To find the mass of aluminum required to produce 30 grams of H2, we need to use the molar mass of hydrogen gas and the molar ratio between aluminum and hydrogen gas. The molar mass of hydrogen is approximately 1 g/mol.

First, we need to calculate the number of moles of hydrogen gas produced:

30 g H2 x (1 mol H2/2 g H2) = 15 mol H2

Since the molar ratio of aluminum to hydrogen gas is 2:3, we can calculate the number of moles of aluminum required:

15 mol H2 x (2 mol Al/3 mol H2) = 10 mol Al

Finally, we can calculate the mass of aluminum required:

10 mol Al x (26.98 g Al/mol) = 269.8 g Al

Therefore, approximately 269.8 grams of aluminum are required to produce 30 grams of H2.

Answer the following:

Answers

The molecular formula of acetylene is C₂H₂ and ethylene is C₂H₄.

What is the difference between molecular and empirical formulas?

The simplest whole-number ratio of the atoms in a compound is shown by empirical formulae, the number of each type of atom in a molecule is shown by molecular formulas, and the bonds between the atoms in a molecule are shown by structural formulas. The empirical formula of naphthalene is C₁₀H₈ and benzene is C₆H₆.

The chemical formula of the reactants and products are:

Na₂SO₄ + Ca(NO3)₂ →  NaNO₃ + CaSO₄Mg + N₂ → MgN₂

The balanced reactions are:

Hg(NO₃)₂ → HgO + 2NO₂ + O₂Ca₃(PO₄)₂(aq) + 4H₃PO₄(aq) → 3Ca(H₂PO₄)₂(aq)3NaOH(aq) + FeCl₃(aq) → Fe(OH)₃(aq) + 3NaCl(aq)

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11. A chemist mixed two samples together: a brown solid that melts at about 1,300°C and a colorless liquid that melts at about 20°C. She analyzed the results and found two ending substances. One of the ending substances melts at about 250°C. This ending substance is made up of the repeating group of atoms shown above. Which of the diagrams to the left shows the repeating groups of atoms that make up the samples the chemist mixed together?

Answers

Diagram c to the left shows the repeating groups of atoms that make up the samples the chemist mixed together.

What is atoms?

Atoms are the smallest unit of matter that make up all physical objects. Atoms are composed of three main components: protons, neutrons, and electrons. Protons and neutrons are found in the nucleus of the atom and have a positive charge, while electrons orbit the nucleus and have a negative charge. Atoms can join together to form molecules, which are the building blocks of all matter. Atoms of different elements can join together in different ways to form compounds and these compounds are the basis of all substances. Atoms are also the basis of all chemical reactions and can exist in different physical states, such as solid, liquid, or gas. Atoms can also be combined to form isotopes, which are atoms of the same element with different numbers of neutrons.

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How many moles are in 1.55x10^23

Answers

Answer:

0.257383555 moles

Explanation:

Determine if each set of the quantum numbers is allowed or not allowed.

Answers

Rules Governing the Allowed Combinations of Quantum Numbers

The principal quantum range (n) can't be zero. The allowed values of n are consequently 1, 2, 3, 4, and so on. The angular quantum quantity (l) can be any integer between zero and n - 1. If n = 3, for example, l can be either 0, 1, or 2.

Which of the following units of quantum numbers are not allowed and why?

The set of quantum numbers n=1,l=1,ml=0,ms=+21 is no longer viable for an electron.

Which of the following units quantum numbers is allowed?

So right set of quantum numbers is n=2,l=1,m=0,s=+21.

Which of the following is an allowed set of quantum numbers for an electron in the 4p orbital?

Solution : The designation `4p` indicates that the orbital has a important quantum number `n = 4` and an angular-momentum quantum wide variety `l = 1`. The magnetic quantum quantity can have any of the values `-1, 0`, or `+1`.

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a sample of crystaline compound when heated in an open test tube produced sevrral droplets of water on the cool upper region of the tube the residue

Answers

The presence of water droplets on the cool upper portion of the test tube after heating the compound suggests that water molecules are trapped within its crystal structure. If the substance were a real hydrate, heating it would have caused all of the water molecules to evaporate, leaving behind an anhydrous substance.

What do you mean by crystalline compound?

A substance is said to be crystalline if it contains a repeating pattern of well-defined, organised, three-dimensionally arranged atoms or molecules throughout its structure. The compound's distinctive crystalline shape comes from this ordered arrangement, which also gives it additional crystalline solid-specific physical and chemical features.

Crystalline compounds can take on a variety of shapes, from straightforward atomic or molecule crystals to intricate mineral formations, and they can be made up of a variety of different elements and compounds. Crystalline substances include, among many others, diamond (carbon), sugar (sucrose), table salt (NaCl), and sugar.

The presence of water droplets on the cool upper portion of the test tube after heating the compound suggests that water molecules are trapped within its crystal structure. If the substance were a real hydrate, heating it would have caused all of the water molecules to evaporate, leaving behind an anhydrous substance.

However, the residue created a yellow-brown solution after being further dissolved in water, which is a certain sign of contaminants. When dissolved in water, true hydrates always produce a clear, colourless solution. Thus, the fact that the residue resulted in a coloured solution implies that the compound had impurities.

Together, the water stains and contaminants in the leftovers indicate that the original substance was not a genuine hydrate, but rather a mixture of the anhydrous substance and water, which may have been non-stoichiometrically trapped inside the crystal lattice or adsorbed onto the surface of the crystals.

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need help with % yield please : (

When 48.91 grams of SiC are reacted with 14.048 liters of Cl2, 31.527 grams of SiCl4 are produced at STP. What is the percent yield of this reaction?

Answers

To calculate the percent yield of the reaction, we first need to calculate the theoretical yield of the reaction, which we can calculate using stoichiometry:

From the balanced chemical equation: SiC + 2Cl2 -> SiCl4 + C

Molar mass of SiC = 40.10 g/mol
Molar mass of Cl2 = 70.91 g/mol
Molar mass of SiCl4 = 169.9 g/mol

Number of moles of SiC = 48.91 g / 40.10 g/mol = 1.221 mol
Number of moles of Cl2 = (14.048 L) * (1 mol / 22.414 L) = 0.6268 mol (using the ideal gas law at STP)
Using the stoichiometric coefficients, we can see that 1 mol of SiC produces 1 mol of SiCl4, so the theoretical yield of SiCl4 is equal to the number of moles of SiC, which is 1.221 mol.

We can calculate the mass of theoretical yield of SiCl4 using its molar mass:
Mass of SiCl4 (theoretical) = 1.221 mol * 169.9 g/mol = 207.4 g

Now, we can calculate the percent yield:

Percent yield = (actual yield / theoretical yield) * 100%

We are given that the actual yield of SiCl4 is 31.527 grams.

Percent yield = (31.527 g / 207.4 g) * 100% = 15.2%

Therefore, the percent yield of the reaction is approximately 15.2%.


Decaborane is a compound with the molecular formula B1014
What is the empirical formula of decaborane?

Answers

The empirical formula of decaborane is B5H7.

Empirical formula calculation.

To find the empirical formula of decaborane, we need to determine the simplest whole-number ratio of atoms in the compound.

The molecular formula of decaborane is B10H14, which means it contains 10 boron atoms and 14 hydrogen atoms.

To determine the simplest ratio of boron to hydrogen atoms, we can divide each by the greatest common factor (GCF) of the two numbers.

The GCF of 10 and 14 is 2, so we divide each by 2:

B10H14 becomes B5H7

Therefore, the empirical formula of decaborane is B5H7 from B10H14

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What element is this?
Its electron-dot structure has six dots, and its atoms bond in a one-to-one ratio with magnesium. It has the highest electronegativity in its group.

Answers

Answer:

the element is oxygen.

Explanation:

oxygen has six Valence electron which is why it's electron-dot structure also know as Lewis structure has six dots. it also has high electronegativity and form one-to-one bond with magnesium

PLEASE URGENT ! 100 POINTS

If 16.0 g of AgNO3 react with an excess of BaCl2 according to the following equation, what mass of AgCl gets produced?

2 AgNO3+ BaCl2 → 2 AgCl +Ba(NO3)2

If only 10.0 g of AgCl were recovered, what is the percent yield of this reaction?

Answers

The molar mass of AgNO3 is 169.87 g/mol, and the molar mass of AgCl is 143.32 g/mol. We can use these values to calculate the theoretical yield of AgCl:

First, we need to determine the limiting reagent in the reaction. We have 16.0 g of AgNO3, which is:

16.0 g AgNO3 x (1 mol AgNO3/169.87 g AgNO3) = 0.0942 mol AgNO3

If we assume an excess of BaCl2, we can calculate the maximum amount of AgCl that can be produced:

0.0942 mol AgNO3 x (2 mol AgCl/2 mol AgNO3) x (143.32 g AgCl/1 mol AgCl) = 26.99 g AgCl (theoretical yield)

However, only 10.0 g of AgCl were recovered. We can calculate the percent yield of the reaction as follows:

Percent yield = (actual yield/theoretical yield) x 100%

Percent yield = (10.0 g AgCl/26.99 g AgCl) x 100% = 37.05%

Therefore, the percent yield of the reaction is 37.05%.

Which substance are needed for cellular respiration 

Answers

Answer: Oxygen and glucose are both reactants in the process of cellular respiration. The main product of cellular respiration

When 43 g of ethyl lactate, which has an empirical formula of C5H10O3, is burned in excess oxygen gas, how many grams of CO2 are formed? mC = 12.011 g/mol, mH = 1.00794 g/mol, and mO = 15.9994 g/mol.
Answer in units of g.

Answers

When 43 g of ethyl lactate is burned in excess oxygen gas, 80.098 g of CO2 are formed.

What is Molecular Formula?

A molecular formula represents the actual number and type of atoms that make up a molecule of a compound. It shows the chemical symbols for the different elements in the compound and the subscript numbers that indicate the number of atoms of each element. For example, the molecular formula for water is H2O, which shows that each molecule of water contains two hydrogen atoms (H) and one oxygen atom (O).

First, we need to determine the molecular formula of ethyl lactate. The empirical formula of C5H10O3 has a molecular weight of approximately 118 g/mol (5 * 12.011 g/mol for carbon + 10 * 1.00794 g/mol for hydrogen + 3 * 15.9994 g/mol for oxygen).

To find the molecular formula, we need to know the actual molecular weight of ethyl lactate. We can use the given amount of ethyl lactate (43 g) to calculate the number of moles:

n = m/M = 43 g / 118 g/mol = 0.3644 mol

Now, we need to find the molecular formula. We can do this by dividing the molecular weight (118 g/mol) by the empirical formula weight (which we already calculated as 118 g/mol):

118 g/mol / 118 g/mol = 1

This tells us that the empirical formula is also the molecular formula, so ethyl lactate is C5H10O3.

Now we can use the balanced chemical equation for the combustion of ethyl lactate:

C5H10O3 + 8 O2 → 5 CO2 + 5 H2O

From the equation, we can see that 1 mol of ethyl lactate produces 5 mol of CO2. We already calculated that we have 0.3644 mol of ethyl lactate, so we can use this to find the amount of CO2 produced:

n(CO2) = 5 mol CO2/mol ethyl lactate * 0.3644 mol ethyl lactate = 1.822 mol CO2

Finally, we can convert this to grams of CO2:

m(CO2) = n(CO2) * M(CO2) = 1.822 mol * 44.0095 g/mol = 80.098 g

Therefore, when 43 g of ethyl lactate is burned in excess oxygen gas, 80.098 g of CO2 are formed.

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Which of the following is not an assumption in Bohr's theory. a) Energy is not dissipated when electrons move in an orbital b) Electrostatic force balances force tending to throw electron out of orbital c) Pairing of electrons reduces orbital stability d) Electrons move from one orbital to another by either absorbing or radiating energy​

Answers

Answer: C

Explanation: The assumption that pairing of electrons reduces orbital stability is not part of Bohr's theory.

Bohr's theory of atomic structure mainly focuses on the behavior of electrons in the atom and makes several key assumptions:

a) Energy is not dissipated when electrons move in an orbital (postulate of quantization)

b) Electrostatic force balances force tending to throw electron out of orbital (Coulomb's law)

d) Electrons move from one orbital to another by either absorbing or radiating energy (postulate of transitions)

Therefore, the correct answer is option (c) Pairing of electrons reduces orbital stability.

You have a glass of water and a piece of metal. The water in the glass weighs 250 g and is at 25 C. The metal is at 155 C. You measure the final temperature of the water plus metal to be 38.5 C. The specific heat of the metal is .345 J/gC and for water the specific heat is 4.184 J/gC. How many grams did the piece of metal weigh?

Answers

You use q = mcT again, but this time you assume qaluminum = qwater and solve for T, which is the ultimate temperature. You must research the specific heat values (c) of aluminum and water.

How do you find the specific heat capacity of a metal in water?

To calculate the heat capacity of a metal, use Q = smT. (In this calculation, make careful to include the heat given out by the metal, the mass of the metal, and the temperature change of the metal.)

The metal will cool and the water will heat up over time. The two things will eventually have the same temperature. They are then considered to be thermally balanced with one another.

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2KClO3-2KCl+3O2 how many moles of O2 can be produced by decomposing 12 moles of KClO3?

Answers

18 moles of oxygen can be produced by decomposing 12 moles of KClO₃.

How many moles are produced from 12 moles of KClO₃?

The balanced chemical equation for the decomposition of KClO₃ is:

2KClO₃ → 2KCl + 3O₂

According to the equation, for every 2 moles of KClO₃ decomposed, 3 moles of O₂ are produced. So, to determine how many moles of O₂ are produced by decomposing 12 moles of KClO₃, we can use the following proportion:

2 moles KClO₃ / 3 moles O₂ = 12 moles KClO₃ / x moles O₂

where x is the number of moles of O₂ produced.

Solving for x, we get:

x = (3 moles O₂)(12 moles KClO₃) / (2 moles KClO₃)

x = 18 moles O₂

Therefore, 12 moles of KClO₃ can produce 18 moles of O₂.

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