There are 2000 milligrams in 2 grams of a substance, and it constitutes 40% of a 5-gram sample.
How to solveConvert grams to milligrams:
2 grams = 2 * 1000 milligrams
2 grams = 2000 milligrams
Calculate the percentage in a 5-gram sample:
Percentage = (2000 milligrams / 5000 milligrams) * 100
Percentage = (2 / 5) * 100
Percentage = 0.4 * 100
Percentage = 40%
Thus, there are 2000 milligrams in 2 grams of a substance, and it constitutes 40% of a 5-gram sample.
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2 grams = milligrams
How many milligrams are there in 2 grams of a substance, and what is the percentage of this amount in a 5-gram sample?
if a spinner has 2 blue, 2 green and 2 red what is the probability of landing on red when it is spinned
The probability of landing on red is given by the number of red sections divided by the total number of sections. In this case, there are 2 red sections out of a total of 6 sections. Therefore, the probability of landing on red is:
P(red) = 2/6 = 1/3
So the probability of landing on red is 1/3.
Hey I was wondering if anyone can help me solve this and maybe graph it to.
The line described by y = 3/4x+5 is tangent to a circle at the point (0, 5). The line described by 3x + 4y = 38 is tangent to the same circle at the point (6, 5). Find the equation of the circle.
The equation of the circle is determined as (x + 3)² + (y - 9)² = 25.
What is the equation of the circle?The equation of the circle is calculated as follows;
For the equation;
y = 3/4x+5
Slope = 3/4, the slope of the line perpendicular to the line = -4/3.
it is pass through the (0, 5).
The equation of the line: y - 5 = -4x/3
For the equation;
3x + 4y = 38
4y = -3x + 38
y = -3x/4 + 38
slope = -3/4, the slope of the line perpendicular to the line = 4/3
it is pass through the (6, 5)
The equation of the line: y - 5 = 4/3(x - 6)
Solve the two equations together to find the point of intersection;
(-4/3)x + 5 = (4/3)(x - 6) + 5
-4x/3 = 4x/3 - 8
8x/3 = -8
8x = -24
x = -3
y - 5 = -4x/3
y - 5 = -4(-3)/3
y - 5 = 4
y = 9
The center of the circle = (-3, 9)
The radius of the circle is calculated as;
r = √ (-3 -0)² + (9 - 5)²
r = √(9 + 16)
r = 5
The equation of the circle becomes;
(x - a )² + (y - b)² = r²
(x + 3)² + (y - 9)² = 5²
(x + 3)² + (y - 9)² = 25
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what are the answers to these questions
The dimensions that minimizes the perimeter are undefined and DNE
Calculating the dimensions that minimizes the perimeterFrom the question, we have the following parameters that can be used in our computation:
Base = w
Heights = h and T
Where
T = 1.6w
The area of the window is calculated as
A = 1/2Tw + hw
So, we have
A = 1/2 * 1.6w * w + hw
A = 0.8w² + hw
Differentiate with respect to w
A' = 1.6w + h
Set to 0
1.6w + h = 0
Solve for h
h = -1.6w
The above means that the perimeter cannot be minimized
This is because h and w cannot be negative
Hence, h = undefined and w = undefined
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Rationalize the denominator and simplify:
4/4+√x
Answer: 16-4√x/16-x is the answer.
Step-by-step explanation:
=> 4/4+√x*4-√x/4-√x
=> 4(4-√x)/(4)²-(√x)² {using identity - (a+b) (a-b)=a² - b²}
=> 16-4√x/16-x
The discrete random variable X can take values 0, 1, 2 and 3 only. Given that P (x≤2) = 0.70, P (x≤1) = 0.55, P (x=2)=0.15 and E(x) = 29/20. Find P (x=1) .
The value of P(x=1) from the given discrete data is 0.5.
From the given data
Let P(x=2)=x
p+p+x=1
x=1-2p
E(x²)=∑PiXi²=P(0)²+p(1)²+(1-2p)(2)²
= 0+p+(1-2p)4
= 4-7p
E(x)=∑PiXi=P(0)+P(1)(1-2p)(2)
= 0+p+2-4p
= 2-3p
Given that, E(x²)=E(x)
4-7p=2-3p
4p=2
p=0.5
Therefore, the value of P(x=1) from the given discrete data is 0.5.
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Geometry
All I need is the letter that is correct. Don’t mind the ones I already circled
The translation of ABC by (Rx + Ry) is UVW and the rigid composition of XYZ to X'Y'Z' cannot be determined
Translation image of the triangleThe rule (Rx + Ry) represents a translation image of a shape, where R is a vector representing the direction and distance of the translation, and (x, y) are the coordinates of the original shape.
To apply this rule to a shape, we simply add the vector R to each point of the shape, which moves the shape in the direction and distance specified by R.
Using the above as a guide, we have the following the translation of ABC by (Rx + Ry) to be UVW
The rigid composition of XYZ to X'Y'Z'The triangle X'Y'Z' is not given in the figure
So, the rigid composition of XYZ to X'Y'Z' cannot be determined
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Which digits replace A, B and C in the
boxes?
+
15.73
32.4 A
C. 16
48.B 4
1
Answer:
Step-by-step explanation:
Which of the following statements about transportation in the United States is NOT true?
A. Most Americans commute to work in a personally owned vehicle.
B. Most Americans who commute to work in car's drive alone.
C. Americans spend more income on transportation than anything else except
housing.
D. The cost of gasoline is higher in the U.S. than anywhere else in the world.
Answer: D
Step-by-step explanation:
The answer is D. The cost of gasoline is higher in the U.S. than anywhere else in the world.
According to the U.S. Energy Information Administration, the average price of a gallon of regular unleaded gasoline in the United States was $3.53 on March 8, 2023. This is higher than the average price of gasoline in many other countries, including Canada ($1.56), Mexico ($1.97), and the United Kingdom ($1.73). However, the cost of gasoline in the United States is lower than the average price in some countries, such as Norway ($6.62), Sweden ($5.62), and Denmark ($5.51).
Here are the facts about the other statements:
A. Most Americans commute to work in a personally owned vehicle. According to the U.S. Census Bureau, in 2019, 77.4% of workers commuted to work by driving alone.
B. Most Americans who commute to work in car's drive alone. According to the U.S. Census Bureau, in 2019, 77.4% of workers who commuted to work by driving did so alone.
C. Americans spend more income on transportation than anything else except housing. According to the U.S. Bureau of Labor Statistics, in 2020, Americans spent an average of $10,564 on transportation, more than any other category except housing ($16,916).
A rectangular classroom is 10m long and 4.6m wide. Make a scale drawing of the classroom using the following scales.
The scale drawing of the classroom have the dimensions of 10 centimeters by 4.6 centimeters
Making a scale drawing of the classroom using the scalesFrom the question, we have the following parameters that can be used in our computation:
Dimension of classroom = 10 meters by 4.6 meters
The scale of the drawing is given as
1 cm : 1 m
Using the above as a guide, we have the following:
Scale factor = 1 cm/1 m
So, we have
Scale factor = 1 cm per m
So, we have
Scale dimension of classroom = (10 meters by 4.6 meters) * 1 cm per m
Evaluate
Scale dimension of classroom = 10 centimeters by 4.6 centimeters
Hence, the scale drawing of the classroom have the dimensions of 10 centimeters by 4.6 centimeters
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Complete question
A rectangular classroom is 10 m long and 4.6 m wide. Make a scale drawing of the classroom using the following scales. 1 cm : 1 m
the mean radius of the earth is 6371.0 kilometers and the mean radius of earths moon is 1737.5 kilometers. what is the approximate difference in the mean circumferences in kilometerse of the earth and earths moon
the approximate difference in the mean circumferences of the Earth and the Moon is about 29153.88 kilometers.
Describe circle.A circle is a particular type of ellipse in mathematics or geometry where the eccentricity is zero and the two foci are congruent.
A circle is also known as the location of points that are evenly spaced apart from the centre. The radius of a circle is measured from the centre to the edge. T
he line that splits a circle into two identical halves is its diameter, which is also twice as wide as its radius.
A circle is a fundamental 2D form whose radius is quantified. The interior and exterior parts of the aircraft are separated by the circles.
The formula for the circumference of a circle is:
C = 2πr
where C is the circumference, π (pi) is a constant approximately equal to 3.14, and r is the radius.
The difference in the mean circumferences of the Earth and the Moon can be found by subtracting the circumference of the Moon from the circumference of the Earth.
The circumference of the Earth is:
C earth = 2π * 6371.0 km = 40075.04 km (rounded to two decimal places)
The circumference of the Moon is:
C moon = 2π * 1737.5 km = 10921.16 km (rounded to two decimal places)
The difference in the mean circumferences of the Earth and the Moon is:
C earth - C moon = 40075.04 km - 10921.16 km ≈ 29153.88 km
Therefore, the approximate difference in the mean circumferences of the Earth and the Moon is about 29153.88 kilometers.
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Match the line described on the left with the slope of the line on the right.
x=-3 , 6x-3y=18 , the line through (7,5) and (8,5) , the line through (4,-2) and (1,7)
Undefined -3 , 0 , 2
The Slope of x = -3 is undefined; 6x-3y=18 is 2; (4,-2) and (1,7) is -3; and (7,5) and (8,5) is 0.
What is the Slope of a Line?Slope of a line (m) = rise/run = change in y / change in x
Note that the slope of vertical lines are always undefined.
Therefore, we have the following:
x = -3 represents the equation of a vertical line, therefore, the slope is undefined.
6x - 3y = 18 is rewritten as y = 2x - 6 in slope-intercept form. The slope is 2.
For (4,-2) and (1,7):
Slope (m) = (7 -(-2))/(1 - 4) = 9/-3 = -3
For (7,5) and (8,5):
Slope (m) = 5 - 5/8 - 7 = 0/1 = 0
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Find the terms: a=_1=8, r=0.7
The formula of the nth term of the sequence is f(n) = 8 *0.7r^(n - 1)
Finding the terms of the sequence:From the question, we have the following parameters that can be used in our computation:
a=_1=8, r=0.7
Express properly
So, we have
First term, a = 8
Common ratio, r = 0.7
The above definition is of a geometric sequence that has a first term of 8 and a common ratio of 0.7
Using the above as a guide, we have the following:
f(n) = a * r^(n - 1)
substitute the known values in the above equation, so, we have the following representation
f(n) = 8 *0.7r^(n - 1)
Hence, the nth term of the sequence is f(n) = 8 *0.7r^(n - 1)
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Which expression is equivalent to 2^3 . 5^-2 ?
How many games did the team play last season?
The number of games that the team did play in the last season is 23.
What is the frequency?The frequency is the number of times an event happens. Therefore, frequency is the number of repetitions of a digit or an event.
The given frequency table represents the frequency of different runs scored by the team in the entire season.
The frequency is written in tally form, which means that each of the vertical lines represents the count of 1, while a group of fours lines such that the four lines are vertical while the fifth line cuts the other four represents a count of 5 as shown in the second column of the second row.
Therefore, the frequency table can be made as:
Number of runs Frequency
0 8
1 5
2 3
3 6
4 1
Total: 23
Hence, the team played 23 games.
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Can you help me with this
Answer:
[tex]\dfrac{\boxed{2}}{\boxed{3}} \times \dfrac{\boxed{1}}{\boxed{2}} = \dfrac{\boxed{1}}{\boxed{3}}[/tex]
Step-by-step explanation:
The square is 1 unit long and 1 unit wide
There are 3 smaller rectangles in the horizontal direction
Length of each rectangle is therefore 1/3 unit
There are 6 rectangles along the vertical direction
The height of each rectangle is therefore 1/6 unit
The shaded area is 2 rectangles wide and 3 rectangles in height
Width of shaded area = 2 x 1/3 = 2/3
Height of shaded region = 3 x 1/6 = 1/2
Area of shaded rectangle is
[tex]\dfrac{\boxed{2}}{\boxed{3}} \times \dfrac{\boxed{1}}{\boxed{2}} = \dfrac{\boxed{1}}{\boxed{3}}[/tex]
pleaseeeee helpppppp
a shape has 3 sides. the bottom edge is 5 inches and the hight is 1 foot. what is the surface area
Answer:
Step-by-step explanation:
find the missing sides of this triangle (Hint: is this a special right triangle?)
(10 on the adjacent and two 45° angles on both ends if anyone can’t see)
Answer:
Both sides are equal, and are equvalent to 5 square root of 2
Step-by-step explanation:
This is a special right angled triangle known as the 45-45-90 triangle
The hypotenuse of a 45-45-90 triangle is x square root 2, with x being both sides of the triangle
10=x square root of 2 (Divide both sides by square root of 2)
10/square root of 2=x (Rationalize)
x=5 square root of 2
what are the answers to these questions
Θ(x) = tan⁻¹(5x / (4(x - 13))), and Θ is maximized when the distance the cow must stand from the billboard x₀ = 26.
How to determine angle and distance?To find Θ, use similar triangles. Let the distance from the cow to the top of the billboard be h. Then, using similar triangles:
h / x = 5 / (x - 13)
Solving for h:
h = 5x / (x - 13)
The vertical angle subtended by the billboard at the cow's eye is equal to the angle whose tangent is given by:
tan(Θ) = h / 4
Substituting for h:
tan(Θ) = 5x / (4(x - 13))
To maximize Θ, find the value of x that maximizes tan(Θ). Taking the derivative of tan(Θ) with respect to x and setting it equal to zero:
d/dx (tan(Θ)) = 5(52 - 26x) / (4(x - 13))² = 0
Solving for x:
x₀ = 26
Substituting x₀ into the expression for Θ:
Θ(x₀) = tan⁻¹(5(26) / 4(13)) = tan⁻¹(5/2)
Therefore, Θ(x) = tan⁻¹(5x / (4(x - 13))), and Θ is maximized when x₀ = 26.
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Suppose you have a 4 foot sub and you have to feed 10 people ,how many cuts will you make?
Answer: Cut 3 inch per person
Step-by-step explanation:
there is a 4 foot sub you take the quadrilatiral and divide it by 10 and you get 3 inches per person remember to multiply the reciprocal by 12 as there are 12 inches in a foot and you have 4 foot so the product of that reciprocal will be equal to 4 divided by your sum from adding the recriptorcal into the quadrilateral remember a quadrilateral not a duolateral or a triolatiral as there is 4 feet in the sub. >:)
Answer:
7 Cuts
Step-by-step explanation:
This is because if you do 48 inches / 6 inches = 8 sections Since each cut will create two sections, you need to make 7 cuts (one fewer than the number of sections) to get 8 equal portions.
Using the following stem & leaf plot, find the five number summary and range for the data.
1 0 2
2 1 2 5 9 9
3
4 2 2 7 9
5 0 2 3 4 8 9
6 0 7
Note that the five number summary and range for the data are given as follows:
Minimum: 102First Quartile (Q1): 225Median (Q2): 329Third Quartile (Q3): 458Maximum: 607.What is the explanation for the above response?The five-number summary and range were calculated using the given stem and leaf plot. The minimum value is 102, the first quartile (Q1) is 226, the median (Q2) is 340, the third quartile (Q3) is 492, and the maximum value is 670. The range is the difference between the maximum and minimum values, which is 568.
The range is calculated by subtracting the minimum value from the maximum value:
Range: 607 - 102 = 505
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The rule to get from one term to the next in a
sequence is
Xn+1 = 2xn - 3
Calculate the value of x3 if
a) x₁ = 7
b) x₁ = 9
Answer:
Step-by-step explanation:
When x_1 =7 then you can figure out by given condition say X_n+1= 2X_n-3
then X_2= 11 by substituting the value of X_1 as 7 similarly you can find out the value of X_3 by substituting X_2 as 11 so X_3 =19.
Similarly you can find out b)
. Suppose that the following represents the graph of the function f(x).
N
a. (5 points) Determine the x intercepts and give a number line for the function
f(x). Are there any horizontal or vertical asymptotes?
b. (5 points) Give a number line for f'(x) and classify any local maxima or minima.
c. (5 points) Give a number line for f"(x) and list any points of inflection.
The x intercepts are (-2, 0), (2, 0) and (3, 0) and it has vertical asymptotes at x = 4 and x = -4
Determining the x interceptsThe x intercepts are the points where the graph intersect with x-axis
In this case, the points are (-2, 0), (2, 0) and (3, 0)
So, the x intercepts are (-2, 0), (2, 0) and (3, 0)
Are there any horizontal or vertical asymptotes?The graph has no horizontal asymptotes
However, it has vertical asymptotes at x = 4 and x = -4
The local maxima or minimaFrom the graph, the local maxima or minima are
Minima (3, -1) and Maxima (-1, 12)
The point of inflectionThis is the points where the graph changes it concave-ness
From the graph, we have the point to be (1, 13/2)
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Recommend what grade 12s could do to minimise the impact of the anxiety they may feel on the day of the examination. In your answers, also indicate how that could enhance their performance in the examination.
Answer:
Experiencing anxiety on the day of the examination is a common problem for many students, especially those in grade 12 who may feel a lot of pressure to perform well. However, there are several strategies that they can use to minimize the impact of anxiety and enhance their performance in the examination. Some of these strategies include:
1. Get enough sleep: Getting enough sleep is essential for students to perform well on the day of the examination. Students should aim to get at least 7-8 hours of sleep before the exam day. A well-rested brain will be able to function better, and students will be less likely to feel anxious or stressed.
2. Eat a balanced breakfast: Eating a balanced breakfast on the day of the examination can help students feel more alert and focused. A healthy breakfast can also provide the necessary energy needed to get through the examination.
3. Plan your day: Plan your day well ahead of the examination. This will help you feel more in control and reduce feelings of anxiety. Set aside time to review notes, relax and mentally prepare for the exam.
4. Practice relaxation techniques: Practice relaxation techniques such as deep breathing or progressive muscle relaxation to help calm your nerves. These techniques can help students reduce stress levels and anxiety, which in turn can enhance their performance.
5. Avoid last-minute cramming: Cramming at the last minute can increase feelings of anxiety and negatively impact performance. Instead, spend time reviewing notes and practicing past papers in the days leading up to the examination.
6. Stay positive: It is essential to stay positive and avoid negative thoughts or self-doubt. Remind yourself of your hard work and preparation for the exam. Believe in your abilities, and focus on what you can do rather than what you cannot.
By implementing these strategies, grade 12 students can minimize the impact of anxiety on the day of the examination, and enhance their overall performance. Remember that exam performance is not just about what you know, but also about how you manage your anxiety and stress levels.
Out of 400 people sampled, 160 preferred
Candidate A. Based on this, estimate what proportion of the voting population (p) prefers Candidate A.
Use a 90% confidence level, and give your answers as decimals, to three places. Use GeoGebra to calculate!
Just by looking at the equation x+6+2x=2x+6+4x+6+2x=2x+6+4 , find the value of x .
Step-by-step explanation:
How do you have two equal to signs omg?
Anyway,
x+6+2x=2x+6+4x+6+2x=2x+6+4
3x+6=8x+12=2x+10
0=5x+6=2x+10
0=3x-4=0
3x-4=0
3x=4
x = 4/3 = 1 ⅓
Select all the polygons that can be formed by the intersection of a plane and a cylinder either parallel or perpendicular to the base?
The polygons that can be formed by the intersection of a plane and a cylinder either parallel or perpendicular to the base include :
B. SquareC. RectangleE. CircleHow to find the polygons ?If a plane intersects three distinct vertices of the cube while bypassing any other vertices, a triangle is produced. To visualize this, suppose a corner of the cube were removed with a knife; picture that cut surface as a triangle.
On the other hand, if a plane coincides with four points on the cube and outlines a square shape, it creates what's called a "square cross-section." This transpires when said plane parallels one side of the cube while intersecting only the midpoints of its opposite face's edges.
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Full question is:
Select all the polygons that can be formed by the intersection of a plane and a cylinder either parallel or perpendicular to the base
A triangle
B square
C. rectangle
D pentagon
E circle
I need help pleaseee
The matrix row operation on the matrix A gives us: 0x + 10y - 25z = 4
How to solve matrix row operations?There are 3 primary basic operations that are utilized on the rows of a matrix when we utilize the matrix to solve a particular system of linear equations . The aim is usually to get the left region of the matrix to resemble the identity matrix .
The three primary operations are:
Switching Rows
Multiplying a Row by a Number
Adding Rows
Now, from the given matrix, the equations are:
x - y + 5z = -1
x - y - 4z = 5
5x + y + 0z = -1
We are told to add -5 times row 1 to row 3 and this gives:
-5x + 5x + 5y + 5y - 25z + 0z = 5 - 1
0x + 10y - 25z = 4
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Consider the data set shown. How does the outlier affect the mean, median, and mode
7, 11, 10, 8, 10, 23, 8
The outlier does not affect the mode
The outlier will increase the mean.
The outlier will not affect the median.
How does outlier affect the mean, median and mode?The outlier will increase the mean because it will significantly increase the sum of the values.
The presence of an outlier will not affect the median, as it only changes the position of the middle value.
The mode is the value that occurs most frequently in a data set. In this case, the mode will not be affected because the outlier is not the most frequent in the data set and only appears once.
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A radioactive substance decays at a continuous rate of 14.4 % per day. After 15 days, what amount of the substance will be left if you started with 140 mg? (a) First write the rate of decay in decimal form. r = (b) Now calculate the remaining amount of the substance. Round your answer to two decimal places.
Answer:(a) The rate of decay is 14.4% per day, which can be written as a decimal by dividing by 100: r = 0.144.
(b) The formula for continuous decay is given by:
A = A₀ * e^(-rt)
where A is the remaining amount of the substance after time t, A₀ is the initial amount, r is the rate of decay, and e is the mathematical constant approximately equal to 2.71828.
Plugging in the given values, we get:
A = 140 * e^(-0.144*15)
A = 140 * e^(-2.16)
A ≈ 47.23
Therefore, after 15 days, approximately 47.23 mg of the radioactive substance will be left, rounded to two decimal places.
Step-by-step explanation: