2. BCD uses 6 bits to represent a symbol. a) True b) False​

(a)

11001.1011₂ = 1×2⁴ + 1×2³ + 1×2⁰ + 1×2 ⁻¹ + 1×2 ⁻³ + 1×2 ⁻⁴

… = 16 + 8 + 1 + 1/2 + 1/8 + 1/16

… = 411/16

(b) In base 16, we have A₁₆ = 10 and C₁₆ = 12, so

A3.C₁₆ = 10×16¹ + 3×16⁰ + 12×16 ⁻¹

… = 160 + 3 + 12/16

… = 2620/16 = 655/4

(c)

75.16₈ = 7×8¹ + 5×8⁰ + 1×8 ⁻¹ + 6×8 ⁻²

… = 56 + 5 + 1/8 + 6/64

… = 3918/64 = 1959/32

(d) B₁₆ = 11 and D₁₆ = 13, so

ABCD₁₆ = 10×16³ + 11×16² + 12×16¹ + 13×16⁰

… = 40960 + 2816 + 192 + 13

… = 43981

Answer:

the change in the characteristics of a species over several generations and relies on the process of natural selection.

Explanation:

I HOPE IT WILL HELP YOU

Answer:

Maximum power is

P = V × I

P = 120 × 15

P = 1800 watt

Answer:

ill help'

Explanation:

Answer:

7500kg/mm

Explanation:

Explanation:

Geometric Shapes can be defined as figure or area closed by a boundary which is created by combining the specific amount of curves, points, and lines.

Answer:

The term drum brake usually means a brake in which shoes press on the inner surface of the drum. When shoes press on the outside of the drum, it is usually called a clasp brake. Where the drum is pinched between two shoes, similar to a conventional disc brake, it is sometimes called a pinch drum brake, though such brakes are relatively rare. A related type called a band brake uses a flexible belt or "band" wrapping around the outside of a drum.

Answer:

a

Explanation:

digital identity is the answer

The core domain for Accenture’s multi-party System is that of a digital identity. Ths that option A is correct.

A multiparty system is a shared data infrastructure within the individual and the organizations that drive the efficiency nf new business and lead to the formation of the revenue models. They include the blockchain and distribution database and include a variety of technology and other capabilities.

Find out more information about the multi-party systems.

brainly.com/question/1083660

A

Explanation:

i don't know the answer

Answer:

Tech A

Explanation:

Feel free to consult the details in my answer to 24438105 if you wish to compute the line integral directly. I don't see any specification of which method to use, so I'll do it the faster way.

By Green's theorem,

[tex]\displaystyle \int_C (x^2+y^2)\,\mathrm dx + 3xy^2\,\mathrm dy = \iint_D \frac{\partial(3xy^2)}{\partial x} - \frac{\partial(x^2+y^2)}{\partial y}\,\mathrm dx\,\mathrm dy \\\\ = \iint_D (3y^2-2y)\,\mathrm dx\,\mathrm dy[/tex]

Since D is a disk with radius 2 centered at the origin, consider converting to polar coordinates using x = r cos(t ) and y = r sin(t ). Then

[tex]D = \left\{(r,\theta) \mid 0\le r\le 2\text{ and }0\le t\le2\pi\right\}[/tex]

[tex]x^2+y^2 = r^2[/tex]

[tex]\mathrm dx\,\mathrm dy = r\,\mathrm dr\,\mathrm dt[/tex]

[tex]\implies \displaystyle \iint_D (3y^2-2y) \,\mathrm dx\,\mathrm dy = \int_0^{2\pi}\int_0^2 (3r^2\sin^2(t)-2r\sin(t))r\,\mathrm dr\,\mathrm dt \\\\ = \int_0^{2\pi} \int_0^2 (3r^3\sin^2(t)-2r^2\sin(t))\,\mathrm dr\,\mathrm dt \\\\ = \int_0^{2\pi} \left(12\sin^2(t)-\frac{16}3\sin(t)\right)\,\mathrm dt = \boxed{12\pi}[/tex]

Answer:

A the value of dd because you can see how the value is to the dd

Answer:

no

Explanation:

we all have the freedom to choose whether we want to have something injected in our bodies that we aren't sure about. This would be a violation of our constitutional right to force us to take the vaccine.

Answer:

Explanation:

Generally speaking, flammable liquids will ignite (catch on fire) and burn easily at normal working temperatures. ... Fuels and many common products like solvents, thinners, cleaners, adhesives, paints, waxes and polishes may be flammable or combustible liquids.

The material which is considered flammable is: A. paint.

A chemical property can be defined as the property of a chemical compound (material) that can be observed and is measurable during a chemical reaction.

In Science, some examples of the chemical properties of a material (substance) include the following;

Flammability refers to the ability of a material to support combustion or burn continuously in the presence of air. An example of a material which is considered to be flammable is paint because it contains a high level of solvents.

Read more on flammability here: https://brainly.com/question/14214497

Answer:

here

Explanation:

try not to touch the Glass on Halogen Light Bulbs, even when changing the bulb. This is because when you touch a Halogen Light Bulb, you leave behind a residue on the Light Bulb which can in time cause the bulb to heat up unevenly, and even cause the bulb to shatter as a result.

Answer:

A traction control system is a secondary function of electronic stability control on production motor vehicles, designed to prevent loss of traction of the driven road wheels.

Answer:

business operation Manager

Answer:

ABS makes it so that the wheels of a car do not lock and slide when the driver slams on the brakes for an emergency stop.

ABS system senses when the wheels have locked and then pumps brake fluid in bursts using a friction

To learn more about the ABS system refer to:

https://brainly.com/question/4257031

#SPJ

Answer:

sheet metal

Explanation:

The thermostat is the gauge on your dashboard for checking the engine's temperature. The correct option is D.

The temperature gauge in your car, which is often seen on the dashboard, is used to display the coolant temperature for your engine. You can use this indicator to determine whether the coolant in your engine is cold, normal, or hot.

Your car's temperature gauge is made to gauge the coolant temperature in your engine. This gauge will indicate whether the coolant in your engine is cold, normal, or overheated. It is a crucial dial that may be found on your car's dashboard.

The same thermostat generates signals, typically electrical, combined in a system that includes relays, valves, controllers, and other components whenever the temperature rises or falls below the desired level.

Therefore, the correct option is D. checking the engine's temperature.

To learn more about thermostat gauges, refer to the link:

https://brainly.com/question/16632841

#SPJ6

Answer:

It depends on the circuit. Many would answer with Ohm's law, but that is not accurate because Ohm's law is applicable only to a particular case:

Ohm's law I = U / R; where R is a constant linear resistance, U a voltage, I a current, and no other impedance is in the system.

Ohm's law allway applies to linear constant resistances, but there is much more to an electrical system than just plain resistances.

Besides linear constant resistances there are: inductances, couppled inductances, capacitances, non linear behaviour, voltage and current sources, radiation behaviour, etc.. They all play a role t

Explanation:

Calculating electrical current in D C circuit : I (Intensity of current) =E (electromotive force) / R (Resistance of circuit).(ohm’s law)

Calculating electrical current in A C circuit : Ohm’s law for Capacitive circuit : The current in a capacitive circuit is directly proportional to applied voltage and inversely proportional to the capacitive reactance. I = E/Xc.

If there is a resistance in series with the capacitor,then I = E/Z , Z is the total impedance of, To find Z , square root of R square + Xc square.

Calculating electrical current in A C circuit,: Ohm’s law for Inductive circuit :

I = E/ XL ; 0r square root of R square + XL square =Z impedance. I + E/Z .

(40) It looks like the line integral is

[tex]\displaystyle \int_C (x^2-2xy)\,\mathrm dx + (x^2y+3)\,\mathrm dy[/tex]

where C is the boundary of the region D,

[tex]D = \left\{(x,y) \mid \dfrac{y^2}8\le x\le2\text{ and }-4\le y\le4\right\}[/tex]

(a) To evaluate the line integral directly, split up C into two paths C₁ and C₂, parameterized by

• C₁ : x = t ²/8 and y = -t, where -4 ≤ t ≤ 4

(the y component is negative to make this path have a positive/counterclockwise orientation)

• C₂ : x = 2 and y = t, where -4 ≤ t ≤ 4

Then the line integral over C is the sum of the line integrals over C₁ and C₂ :

[tex]\displaystyle \int_C = \int_C \left(\left(x(t)^2-2x(t)y(t)\right)\dfrac{\mathrm dx}{\mathrm dt} + \left(x(t)^2y(t)-3\right)\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt \\\\ = \int_{-4}^4 \left(\left(\frac{t^3}4+\frac{t^4}{64}\right)\frac t4 - \left(3-\frac{t^5}{64}\right)\right)\,\mathrm dt + \int_{-4}^4 (4t+3)\,\mathrm dt \\\\ = \int_{-4}^4 \left(4t+\dfrac{t^4}{16}+\dfrac{5t^5}{256}\right)\,\mathrm dt = \boxed{\frac{128}5}[/tex]

(b) Using Green's theorem, we have

[tex]\displaystyle \int_C (x^2-2xy)\,\mathrm dx + (x^2+3)\,\mathrm dy = \iint_D \frac{\partial(x^2y+3)}{\partial x} - \frac{\partial(x^2-2xy)}{\partial y}\,\mathrm dx\,\mathrm dy \\\\ = \int_{-4}^4 \int_{y^2/8}^2 (2xy+2x)\,\mathrm dx\,\mathrm dy = \boxed{\frac{128}5}[/tex]

# # #

(41) I assume you meant to use θ in the parameterization, and not 6, so that C is parameterized by x = θ - sin(θ) and y = 1 - cos(θ). There's no range given for θ, so I'll just assume 0 ≤ θ ≤ π.

Then ... (for some reason, the math text won't render properly. I've attached the computation as an image)

(where s = sin(θ) and c = cos(θ))

Answer:

In series:

[tex] \frac{1}{r} = \frac{1}{r_{1} } + \frac{1}{r _{2} } + \frac{1}{r_{3} } [/tex]

[tex] \frac{1}{r} = \frac{1}{4} + \frac{1}{6} + \frac{1}{8} \\ \\ \frac{1}{r} = \frac{13}{24} \\ \\ r = \frac{24}{13} \\ { \underline{r = 1.85 \: Ω}}[/tex]

In parallel:

[tex]r = r _{1} + r _{2} + r _{3} \\ r = 4 + 6 + 8 \\ r = 18Ω[/tex]

Answer:

The signal person is like the eyes and the equipment operator is like the hands.

Explanation: