2) A pool is being filled with a hose. The equation y=12x represents the relationship between
the number of gallons of water in the pool (y) and the number of minutes the water runs (X). If
this relationship is represented on a graph, which ordered pair would not lie on the line?
NEED HELP ASAP PLS AND THANK YOU SO MUCH

9514 1404 393

Answer:

Step-by-step explanation:

The difference in ratio units is 5 - 4 = 1. The difference in actual quantity is 3, so 1 ratio unit must represent 3 students.

There are 5×3 = 15 boys.

There are 4×3 = 12 girls.

9514 1404 393

Answer:

  (a)  -4

Step-by-step explanation:

The picture is fuzzy, but perhaps you want to evaluate ...

  [tex]-1\left|\dfrac{2}{3}-4\right|\div\dfrac{5}{6}=-1\left|-\dfrac{10}{3}\right|\div\dfrac{5}{6}\\\\=-\dfrac{10}{3}\div\dfrac{5}{6}=-\dfrac{20}{6}\div\dfrac{5}{6}=-\dfrac{20}{5}=\boxed{-4}[/tex]

Answer:

I believe a is -14

Step-by-step explanation:

its -14 because if it is in the exact same spot below water, think of the water as point 0. the bird is 14 and the fish is -14. Hope this helped

Answer:

No pictures so can't help ya.

Answer:

6z + 9

Step-by-step explanation:

distribute 3/4 by 8z to get 6z

distribute 3/4 by 12 to get 9

Answer:

$4.61

Step-by-step explanation:

To calculate a tip of 20%, you would perform the following:

$92.18 * 0.20 = $18.436

Similarly, for a tip of 15%:

$92.18 * 0.15 = $13.827

The difference would just be subtracting the two tip amounts from each other!

$18.436 - $13.827 = $4.609

Then you round to the nearest cent.

$4.609 ≈ $4.61

Answer:

7.81

Step-by-step explanation:

Step-by-step explanation:

[tex]distance = \sqrt{(x2 - x1) ^{2} + (y2 - y1) ^{2} } [/tex]

Now, substitute the numbers into the equation,

[tex] \sqrt{(2 + 4) ^{2} +( 5 - 0)^{2} } [/tex]

distance = 7.81

brianlist me??

Explanation:

A solution is where the lines intersect. Graph A shows exactly one solution, and it is at (-2,2)

Graph B doesn't have any solutions since the lines are parallel, and parallel lines never intersect. We consider this system to be inconsistent.

Graph C has infinitely many solutions. The two lines perfectly overlap, meaning there are infinitely many intersection points. All solutions here are of the form (x,y) = (x,2x-1)

Answer:

are there any equations for this possibly? and if not it is just a smaller scale version of the dilated trapezoid.

[tex]3x - (2x + 1) \\ = 3x - 2x - 1 \\ = x - 1[/tex]

x - 1

Answer: x-1

Step-by-step explanation: in the picture

Answer:

[tex]x =[/tex] [tex]-30[/tex]

Step-by-step explanation:

Solve for [tex]x[/tex] by simplifying both sides of the equation, then isolating the variable.

Call me when you want, call me when you need

Call me in the morning, I'll be on the way

Call me when you want, call me when you need

Call me out by your name, I'll be on the way like

Step-by-step explanation:

arithmetic sequence : every new item of the sequence is created by adding a constant term to the previous item - in this case 195.

a1 = 3087 (that's our starting value)

a2 = a1 + 195

a3 = a2 + 195 = a1 + 2×195

an = a1 + (n-1)×195

a)

when he is 45 years old, that is 20 years (and 20 annual increments) plus to our starting value.

so, n = 1+20 = 21

a21 = a1 + 20×195 = 3087 + 20×195 = 6987

so, when he is 45 years old, his monthly salary will be RM6,987

b)

how many years (= how big is n) until he gets 8937 ?

8937 = a1 + (n-1)×195 = 3087 + (n-1)×195 =

= 3087 + n×195 - 195 = 2892 + n×195

6045 = n×195

n = 6045/195 = 31

so, a31 = 8937

and that means, he has to work 30 additional years (31 minus the starting level 1) to earn monthly RM8,937.

that means he will be 25+30 = 55 years old.

Answer:

The amount is $18548.38 and the interest is $2548.38

Steps for solution:

First you want to use the formula A=P(1+[tex]\frac{r}{n}[/tex])^n*t. A= total amount, P= principle or amount of money deposited, r= annual interest rate, n= number of times compounded per year. and t= time in years. In the problem we have P= $16000, r= 3%, n= 1 and t= 5 years. The first picture is the formula used to find the total amount. After we use the formula A=P+I, since A=18548.38 and P=16000. The second picture represents the interest after 5 years.

Step-by-step explanation:

260000*0*54*30

$421200

Answer: In this equation, let "x" equal the rate at which the tub will be filled. The tub holds 32 gallons, which will be one-half of the equation. The tub already contains 12 gallons, so this will be half of the other side of the equation. The rate is "x" gallons per minute, and the time it required was 5 minutes, so this would be "5x". Placing all these parts together gives an equation of (32 = 5x + 12) gallons per minute dispensed.

no solution,

48x+43=47x+43

     -43         -43

48x=47x

if x= 1

48 is not equal to 1

B

Answer:

B

Step-by-step explanation:

It's impossible to let these 2 equation have same answer!

Answer:

2 2 y = a x 2 + b x + c ; a ≠ 0 2

Step-by-step explanation:

Answer: lotion- semisolid

capsule- solid

suspension- liquid

Step-by-step explanation:

Parameterize this surface by

r (u, v) = 9 cos(u) sin(v) i + 9 sin(u) sin(v) j + 9 cos(v) k

with 0 ≤ u ≤ 2π and 0 ≤ v ≤ arccos(4/9)

See the attached sketch to see how we arrive at the upper limit for v.

Take the normal vector to the surface to be

n = ∂r/∂u × ∂r/∂v

n =  -81 cos(u) sin²(v) i -  81 sin(u) sin²(v) j - 81 sin(v) cos(v) k

which has magnitude

||n|| = 81 sin(v)

Then the surface area is

[tex]\displaystyle \iint_S \|\mathbf n\| \,\mathrm du\,\mathrm dv = 81 \int_0^{2\pi} \int_0^{\arccos(4/9)} \sin(v)\,\mathrm dv\,\mathrm du \\\\ = 162\pi \int_0^{\arccos(4/9)} \sin(v)\,\mathrm dv \\\\ = -162\pi (\cos\left(\arccos\left(\frac49\right) - \cos(0)\right) \\\\ = 162\pi \left(1 - \dfrac49\right) \\\\ = \boxed{90\pi}[/tex]

If you're not familiar with surface integrals, you can instead use what's sometimes called the projection method. Let

z = f(x, y) = √(81 - x ² - y ²)

(where we take the positive square root because we're looking at a part of the top half of the sphere)

Projecting the surface down onto the (x, y)-plane, we see that it casts a "shadow" of a disk with radius √(9² - 4²) = √65. (Use the Pythagorean theorem to solve for the missing side of the triangle in the sketch.)

Then the surface S considered above is hovering over the set in the (x, y)-plane,

D = {(x, y) : x ² + y ² ≤ 65}

The area is then

[tex]\displaystyle \iint_D \sqrt{1 + \left(\dfrac{\partial f}{\partial x}\right)^2 + \left(\dfrac{\partial f}{\partial y}\right)^2} \,\mathrm dx\,\mathrm dy[/tex]

It's easier to compute this integral in polar coordinates, so we take

x = r cos(t )

y = r sin(t )

dx dy = r dr dt

and the region D is given by the set

{(r, t ) : 0 ≤ r ≤ √65 and 0 ≤ t ≤ 2π}

Then the integral would be

[tex]\displaystyle \iint_D \sqrt{1 + \left(\dfrac{\partial f}{\partial x}\right)^2 + \left(\dfrac{\partial f}{\partial y}\right)^2} \,\mathrm dx\,\mathrm dy = \iint_D \sqrt{1 + \frac{x^2+y^2}{81-x^2-y^2}}\,\mathrm dx\,\mathrm dy \\\\ = \iint_D \sqrt{\frac{81}{81-x^2-y^2}}\,\mathrm dx\,\mathrm dy \\\\ = \int_0^{2\pi} \int_0^{\sqrt{65}} r \sqrt{\frac{81}{81-r^2}}\,\mathrm dr\,\mathrm dt[/tex]

Substitute s = 81 - r ² and ds = -2r dr :

[tex]\displaystyle \int_0^{2\pi} \int_0^{\sqrt{65}} r \sqrt{\frac{81}{81-r^2}}\,\mathrm dr\,\mathrm dt = 2\pi \int_0^{\sqrt{65}} r \sqrt{\frac{81}{81-r^2}}\,\mathrm dr \\\\ = -9\pi \int_{81}^{16} \frac{\mathrm ds}{\sqrt s} \\\\ = 9\pi \int_{16}^{81} s^{-1/2}\,\mathrm ds \\\\ = 18\pi \left(\sqrt{81} - \sqrt{16}\right) \\\\ = \boxed{90\pi}[/tex]

Answer:

(3, -3.5)

Step-by-step explanation:

Using midpoint formula:

M = (x1 + x2/2 , y1 + y2/2)

By inserting the points you'll find the answer:

M = (5 + 1/2 , -2 + -5/2)

M = (6/2 , -7/2)

M = (3 , -3.5)

Answer:

8:36

Step-by-step explanation:

if you sharpened 8 pencils out of 44 that means 8 pencils are sharpened and the other 36 aren't