2. (08.03) A teacher gave her class two exams; 60% of the class passed the second exam, but only 48% of the class passed both exams. What percent of those who passed the second exam also passed the first exam? (2 points) 80% 12% 30% 48%

Answers

Answer 1

Only 80% students passed the second exam and also passed the first exam .

Conditional probability is used to find the probability of an event A given that event B has already occurred.

It is denoted by P(A/B)=P(A∩B)/P(B)  .

In the given question

Let A be the event for students passed in first exam.

Let B be the event for students passed in second exam.

Given

Only 48% passed in both the exam that means

P(A∩B)=48%=0.48   ...(i)

and

60% students passed the second exam , that is

P(B)=60%=0.60       ...(ii)

To find the probability of students passed in second exam given that they passed in first exam , conditional probability is used that is P(A/B), denoted by

P(A/B)=P(A∩B)/P(B)

Substituting the values from equation (i) and (ii) we get

P(A/B) = 0.48/0.60

=48/60

Converting 48/60 to percent

=48/60*100

=80%

Therefore , Only 80% students passed the second exam and also passed the first exam , the correct option is 80%.

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Related Questions

Given P(A) = 0.74, P(B) = 0.85 and P(A|B) = 0.84, find the vi P(A and B), rounding to the nearest thousandth, if necessary.

Answers

The value of the given statement rounding to the nearest thousandth = 0.714.

What exactly are dependent events?

Dependent occurrences are ones that are dependent on previous events. The outcomes of prior events have an impact on these occurrences. Dependent events are two or more occurrences that are dependent on one another. If one event is altered by chance, another is most likely to differ.

What exactly is the distinction between dependent and independent?

The independent and dependent factors are the two most crucial variables in a research experiment. The experimental has authority over the independent variable. The variable that varies in reaction toward the independent variable is known as the dependent variable.

According to the information provided:

P(A) = 0.74

P(B) = 0.85

P(A|B) = 0.84

Using  dependent events formula:

P(A∩B) = P(A/B) × P(B)

            = 0.84 X 0.85

            = 0.714

The value of the given statement rounding to the nearest thousandth = 0.714.

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22 out of 25
math students
bring their
calculators to
class how many
students would
have a
calculafors in a
group of 80
math students

HELP PLEASE

Answers

I think it’s 66 :) please put best

thank you so much for the help!!

Answers

The independent variable in these equations based on how they are written is x, since y is a function of x here so y depends on the value of x, while x can be changed freely.

So, for each of these questions, plug in the given value of the independent variable for x.

Independent variable equal to 10: 0.1*10 + 5 = 6

Independent variable equal to 50: 0.1*50 + 5 = 10

Independent variable equal to 120: 0.1*120 + 5 = 17

find inequality : JoJo can eat no more than 25 carbs per meal. Which inequality describes JoJo's situation?

Answers

Answer:

Jojo is on a low carb diet

If f(x) = 3x2 – 2x + 4 and g(x) = 5x2 + 6x – 8, find (f +g)(x).

Answers

Answer:

[tex](f+g)(x)=8x^{2} +4x-4[/tex]

Step-by-step explanation:

[tex](f+g)(x)=3x^{2} +5x^{2} -2x+6x+4-8=8x^{2} +4x-4[/tex]

Hope this helps

(01.01 MC)
Which value of x would make the expression (75)* equal to 5?
a
b
3
12
C 4
5
d 5
4

Answers

Answer: (sidenote, I'm sorry if I answered incorrectly ;-;)

C: 4/5 or D 5/4

Step-by-step explanation:

if you solve the numbers inside the radical symbol you'll get 16807. it's hard for it to be separated into 4 groups since it can only be separated in 5, that being 7*7*7*7*7.

so, by process of elimination i suggest you answer either c or d

a bricklayers assistant starts building a wall laying 50 bricks per hour. Two hours later the master bricklayer joins the assistant and both lay bricks. The master bricklayer lays 80 bricks per hour. write an equation stating that the assistant and the master have laid the same number of bricks. how long has each one worked when they have laid the same number? ​

Answers

Answer:

80t = 50(t+2)master: 3 1/3 hoursassistant: 5 1/3 hours

Step-by-step explanation:

Given an assistant bricklayer laying 50 bricks an hour has worked 2 hours longer than a master bricklayer laying 80 bricks an hour, you want an equation stating they have laid the same number of bricks. You also want to know how long each has worked.

Rate and output

The output of each bricklayer is the product of the rate at which they lay bricks and the time for which they do it. If t is the time spent by the master bricklayer, their output will be 80t. The time spent by the assistant will be (t+2) hours, and their output will be 50(t+2).

Here is the equation that says their output is the same:

  80t = 50(t+2)

Time

Solving the equation for t, we have ...

  80t = 50t +100

  30t = 100 . . . . . . . . . subtract 50t

  t = 3 1/3 . . . . . . . divide by 30

The master bricklayer has worked 3 1/3 hours when they have laid the same number of bricks.

The assistant bricklayer has worked 5 1/3 hours at that time.

__

Additional comment

Each will have laid (80)(3 1/3) = 266 2/3 bricks.

The quadrilaterals ABCD and JKLM are similar.
Find the length x of MJ.

Answers

Answer:

x = 4.8

Step-by-step explanation:

since the quadrilaterals are similar then the ratios of corresponding sides are in proportion , that is

[tex]\frac{MJ}{DA}[/tex] = [tex]\frac{LM}{CD}[/tex] ( substitute values )

[tex]\frac{x}{6}[/tex] = [tex]\frac{2.4}{3}[/tex] ( cross- multiply )

3x = 6 × 2.4 = 14.4 ( divide both sides by 3 )

x = 4.8

Let f (x) = 3x2 − 2x + 4. Evaluate f (a + h) and simplify your answer as much as possible.

Answers

The expression f(x) = 3 · x² - 2 · x + 4 evaluated at x = a + h is equal to the expression f(x) = 3 · a² + 6 · a · h + 3 · h² - 2 · a - 2 · h + 4.

How to evaluate and simplify a quadratic equation

In this question we find a quadratic equation, which has to be evaluated at x = a + h and simplified afterwards. Then, the complete procedure is shown below:

f(x) = 3 · (a + h)² - 2 · (a + h) + 4

f(x) = 3 · (a² + 2 · a · h + h²) - 2 · a - 2 · h + 4

f(x) = 3 · a² + 6 · a · h + 3 · h² - 2 · a - 2 · h + 4

The expression f(x) = 3 · x² - 2 · x + 4 evaluated at x = a + h is equal to the expression f(x) = 3 · a² + 6 · a · h + 3 · h² - 2 · a - 2 · h + 4.

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Decide whether the table shows a proportional relationship between x and y.

x y
17 2 5/6
5/6 5/36
6 1/6
19 3 1/6

Answers

The table shows a proportional relationship between x and y.

In this question, we have been given a table which contains values of x and y.

We need to decide whether the table shows a proportional relationship between x and y.

x             y

17         2 5/6

5/6       5/36

6            1/6

19          3 1/6

First we convert the improper fraction in the y-column to proper fraction.

2 5/6 = 17/6

and 3 1/6 = 19/6

so, given table would be,

x             y

17          17/6

5/6       5/36

6            1/6

19          19/6

Consider the ratio x/y of each row:

x             y                x/y

17          17/6            1/6

5/6       5/36            1/6

6            1/6              1/6

19          19/6             1/6

As the ratio x/y is constant, x and y are directly proportional.

Therefore, the table shows a proportional relationship between x and y.

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(27/8)-^2/3??????????/

Answers

Answer: 4/9

Step-by-step explanation:

[tex]\displaystyle\\(\frac{27}{8} )^{-\frac{2}{3}} =\\\\(\frac{3*3*3}{2*2*2})^{-\frac{2}{3}}=\\\\ (\frac{3^3}{2^3} )^{-\frac{2}{3}} =\\\\((\frac{3}{2})^3)^{-\frac{2}{3} } =\\\\(\frac{3}{2})^{-\frac{3*2}{3}} =\\\\(\frac{3}{2})^{-2}=\\\\(\frac{2}{3})^2 \\\\\frac{2^2}{3^2} =\\\\\frac{4}{9}[/tex]

2. Select the polynomial functions for which (x+3) is a factor. Select all that apply. (2
f(x)=x²-12x³ +54x² - 108x+81
f(x)=x²-3x³-x+3
f(x)=x+2x¹-23x³-60x²
f(x)= x³ +5x²-3x³-29x²+2x+24

Answers

The polynomial functions for which (x+3) is a factor

A polynomial of degree n is a function of the form

f(x) = anx

n + an−1x

n−1 + . . . + a2x

2 + a1x + a0

where the a is a real number (sometimes called the coefficients of the polynomial). Although

this general formula might look quite complicated, particular examples are much simpler. For

example,

f(x) = 4x

3 − 3x

2 + 2

is a polynomial of degree 3, as 3 is the highest power of x in the formula. This is called a cubic

polynomial, or just cubic.

Theorem Polynomial Division: Suppose d(x) and p(x) are nonzero polynomials were

the degree of p is greater than or equal to the degree of d. There exist two unique polynomials,

q(x) and r(x), such that p(x) = d(x) q(x) + r(x), where either r(x) = 0 or the degree of r is

strictly less than the degree of d.

so, if we put x=-3 then f(x) must be equal to zero

here no function satisfies of none of the option is correct for [x+3] factor

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(x +3) is a factor of the function f(x)= x³ +5x²-3x³-10x²+2x-3.

Here, we are given 4 functions. If (x+3) is a factor of any of these equations, then x = -3 and y = 0 must be a solution. Let us check each function one by one-

1. f(x) = x²-12x³ +54x² - 108x+81

putting x = -3, we get-

f(-3) = -3²-12(-3)³ +54(-3)² - 108(-3)+81

= 9+324+486+324+81

= 1,224

Thus, (x +3) is not a factor.

2. f(x)=x²-3x³-x+3

putting x = -3, we get-

f(-3) = -3²-3(-3)³-(-3)+3

= 9+81+9+3

= 102

Thus, (x +3) is not a factor.

3. f(x)=x+2x¹-23x³-60x²

putting x = -3, we get-

f(-3) = -3+2(-3)¹-23(-3)³-60(-3)²

= -3-6+621+540

= 1,152

Thus, (x +3) is not a factor.

4. f(x)= x³ +5x²-3x³-10x²+2x-3

putting x = -3, we get-

f(-3) = -3³ +5(-3)²-3(-3)³-10(-3)²+2(-3)-3

= -27+45+81-90-6-3

= 0

Thus, (x +3) is a factor of the function f(x)= x³ +5x²-3x³-10x²+2x-3.

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Simplify the expression

Answers

Answer:

-8

Step-by-step explanation:

2x/7 =

2(12)/-3 =

24/-3 =

-8

Answer:

-8

Explanation:

Given expression:

[tex]\rightarrow \sf \dfrac{2x}{y}[/tex]

when  x = 12, y = -3

Substitute values inside expression:

[tex]\rightarrow \sf \dfrac{2(12)}{-3}[/tex]

multiply

[tex]\rightarrow \sf \dfrac{24}{-3}[/tex]

simplify

[tex]\rightarrow \sf -8[/tex]

the estimate closest to the length of a pen​: ​30cm, 160​mm, or 16 mm.

Answers

Answer:

160 mm.

Step-by-step explanation:

the average pen is 149mm. the average pen is 14.9cm. 160mm is closest.

It would have to be the 160mm.

This is because store-bought pens average 130 and 140mm/ 13 – 14 cm. This is closely followed by pens in the 140 – 150mm range.

Hope this helps!

Have a great day and God bless! :)

i am sooooo confused please help

Answers

The simplified form of the function f(x) = (x² - 4x + 4) / (x² - 4) will be f(x) = (x - 2) / (x + 2).

What is a function?

A statement, principle, or policy that creates the link between two variables is known as a function. Functions are found all across mathematics and are required for the creation of complex relationships.

The function is given below.

f(x) = (x² - 4x + 4) / (x² - 4)

Simplify the equation, then we have

f(x) = (x² - 4x + 4) / (x² - 4)

f(x) = (x - 2)² / [(x - 2)(x + 2)]

f(x) = (x - 2) / (x + 2)

The simplified form of the function f(x) = (x² - 4x + 4) / (x² - 4) will be f(x) = (x - 2) / (x + 2).

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Solve.

⎧⎩⎨⎪⎪2x−y+2z=−6−3y+z=−22x−3z=4

Enter your answer, in the form (x,y,z), in the boxes in simplest terms.

Answers

The solution is (x, y, z) = (-1, 0, -2)

Given equations are:

2x−y+2z=−6 ---------------(1)

−3y+z=−2 ------------------(2)

2x−3z=4 -------------------(3)

From (2), z = -2+3y

Substitute this into (1) and (3)

(1)⇒ 2x-y+2(-2+3y) = -6

⇒ 2x+5y-4=-6

⇒2x+5y = -2

and

(3) ⇒ 2x-3(-2+3y)=4

⇒ 2x-9y+6 = 4

⇒ 2x-9y=-2

Now solve 2x+5y = -2 and 2x-9y=-2

Subtracting the equations above,

14y = 0

y=0

Then from 2x-9y=-2, x = -1

From (2),z = -2+3y

z = -2

So the solution is (x, y, z) = (-1, 0, -2)

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Simplify the expression below:

-3/7 ( y-28) - 1/21 y


please show your work and i'll give brainliest :,)

Answers

(-5/7)*(y-28)-((1/21)*y) = 0

(-5/7)*(y-28)+(-1/21)*y = 0

-5/7*(y-28)-y/21 = 0

(-5/7*21*(y-28))/21-y/21 = 0

-5/7*21*(y-28)-y = 0

420-16*y = 0

(420-16*y)/21 = 0

(420-16*y)/21 = 0 // * 21

420-16*y = 0

420-16*y = 0 // - 420

-16*y = -420 // : -16

y = -420/(-16)

y = 105/4

Find the nth term, the fifth term, and the 100th term, of the arithmetic sequence determined by a = 2 and d = 3​

Answers

Answer: an=3n-1    a₅=14   a₁₀₀=299

Step-by-step explanation:

a=2     d=3

[tex]\boxed {a_n=a_1+d(n-1)}\\\\a_n=2+3(n-1)\\\\a_n=2+3n-3\\\\a_n=3n-1\\\\a_{100}=3(100)-1\\\\a_{100}=300-1\\\\a_{100}=299\\\\a_5=3(5)-1\\\\a_5=15-1\\\\a_5=14[/tex]

I can’t find a way to flip the number and to swap it as well

Answers

Answer:

Reflect over the x axis and than turn 90 degrees clockwise about the origin.

4x + 3 = 18 - x help please

Answers

Answer:

the answer is x=3

Step-by-step explanation:

Answer:

Please mark my answer as the brainliest, it would mean a lot to me

x = 5

Step-by-step explanation:

4x + 3 = 18 - x

3x + 3 = 18

3x = 15

x = 5

I’m in need of help with this math problem!!!

Answers

Answer:

Flowers: $19.98Jewelry: $18.92Gift Certificates: $14.52

Step-by-step explanation:

You want the values of three expenditures, given three relations between them.

(The first thing to realize is that the question isn't about averages at all. It is about values that are described as averages.)

Setup

Let f, j, c represent the (average) amounts spent on flowers, jewelry, and gift certificates, respectively. The three given relations are ...

  f + j + c = 53.42

  j = 4.40 + c

  f + c = 15.58 + j

Solution

Using the second equation to substitute for j in the third, we have ...

  f +c = 15.58 +(4.40 +c)

  f = 19.98 . . . . . . . . . . . . . . simplify

Using this and the second equation to substitute into the first, we have ...

  19.98 +(4.40 +c) +c = 53.42

  24.38 +2c = 53.42

  2c = 29.04

  c = 14.52

Then ...

  j = 4.40 +c = 4.40 +14.52 = 18.92

The average expenditures are ...

Flowers: $19.98Jewelry: $18.92Gift Certificates: $14.52

__

Additional comment

This solution is one of many ad hoc methods that could be used. There are also graphing and matrix methods available for solving a set of equations like this. The attachment shows a calculator matrix solution.

Classify the system and identify the number of solutions.
3x + 5y + 4z = −11
2x − 4y − z = −11
4x + 3y − 2z = 11

Answers

Answer:

Hello,

Step-by-step explanation:

Only one solution: x=-2, y=3,z=-5

Answer:

consistent, independent; one

Step-by-step explanation:

The solution is (−2, 3, −5). Because the system has one solution, it is consistent and independent.

In the diagram below, ΔABC ≅ ΔDEF. Complete the statement BC⎯⎯⎯⎯⎯⎯⎯⎯≅ B C ¯ ≅ ___

Answers

Answer:

[tex]\overline{BC} \cong \overline{EF}[/tex]

Step-by-step explanation:

Corresponding parts of congruent triangles are congruent.

another question i need quickly:
what do you do if the median is 0 and 1?

Answers

What if the median is zero?

A variable that can in principle be only zero or positive can only have mean zero if all values in practice are zero. On the other hand, such a variable can and will have median zero if more than half of the values are zero.

Can you have a median of one number?

Median of one number = the number itself.

nate works at a grocery store. he has 7 1/2 pounds of rasins. heis splitting them into 1/8 pound packages. how many packages can he make

Answers

Answer:

Nate can make 60 packages.

Step-by-step explanation:

7 1/2 is equivalent to 7 4/8, or 60/8

Divide 60/8 by 1/8 and you get 60.

The graph of the function y = x^3 + ax^2 + b has a local minimum point at (4, -11). Find the coordinates of the local maximum. Answer: (0, 21)

Answers

Answer:

(0, 21)

Step-by-step explanation:

Stationary points occur when the gradient of a graph is zero.

Therefore, to find the x-coordinate(s) of the stationary points of a function, differentiate the function, set it to zero and solve for x.

Differentiate the given function:

[tex]\begin{aligned}y & = x^3+ax^2+b\\\implies \dfrac{\text{d}y}{\text{d}x}&=3 \cdot x^{3-1}+2 \cdot ax^{2-1}+0\\\implies \dfrac{\text{d}y}{\text{d}x}& = 3x^2+2ax\end{aligned}[/tex]

Set the differentiated function to zero:

[tex]\begin{aligned} \dfrac{\text{d}y}{\text{d}x}& =0\\ \implies 3x^2+2ax & = 0 \\ \implies x(3x+2a)&=0\end{aligned}[/tex]

Therefore the stationary points occur when:

[tex]\implies x=0[/tex]

[tex]\implies 3x+2a=0 \implies x=-\dfrac{2}{3}a[/tex]

There is a stationary point at (4, -11), therefore substitute x = 4 into the expression for x and solve for a:

[tex]\begin{aligned}x & = 4\\\implies -\dfrac{2}{3}a & = 4\\a & = -\dfrac{3}{2}(4)\\a & = -6\end{aligned}[/tex]

Substitute the found value of a and the point (4, -11) into the function and solve for b:

[tex]\begin{aligned}y & = x^3 + ax^2 + b\\\implies -11 & = (4)^3+(-6)(4)^2+b\\ -11 & = 64-96+b\\b & = -11-64+96\\ b & = 21\end{aligned}[/tex]

Therefore, the function is:

[tex]\boxed{y=x^3-6x^2+21}[/tex]

The other stationary point is when x = 0.  Therefore, to find the coordinates of this point, substitute x = 0 into the function:

[tex]\begin{aligned}y & =x^3-6x^2+21\\x=0\implies y & =(0)^3-6(0)^2+21\\ y & =21 \end{aligned}[/tex]

Therefore, the coordinates of the other stationary point are (0, 21).

To determine if a stationary point is minimum or maximum, differentiate the function again:

[tex]\begin{aligned}y & =x^3-6x^2+21\\\implies \dfrac{\text{d}y}{\text{d}x} & = 3x^2-12x\\\implies \dfrac{\text{d}^2y}{\text{d}x^2} & = 6x-12\\\end{aligned}[/tex]

Substitute the x-coordinate of the stationary point into the second derivative:

[tex]\begin{aligned} \dfrac{\text{d}^2y}{\text{d}x^2} & = 6x-12\\x=0 \implies \dfrac{\text{d}^2y}{\text{d}x^2} & = 6(0)-12= -12 \\\end{aligned}[/tex]

[tex]\textsf{As $\dfrac{\text{d}^2y}{\text{d}x^2} < 0$, stationary point $(0,21)$ is a maximum.}[/tex]

Differentiation Rules

[tex]\boxed{\begin{minipage}{4.8 cm}\underline{Differentiating $ax^n$}\\\\If $y=ax^n$, then $\dfrac{\text{d}y}{\text{d}x}=nax^{n-1}$\\\end{minipage}}[/tex]

[tex]\boxed{\begin{minipage}{4cm}\underline{Differentiating a constant}\\\\If $y=a$, then $\dfrac{\text{d}y}{\text{d}x}=0$\\\end{minipage}}[/tex]

Find the average rate of change of the function f(x) = x² + 4x from x₁ = 3 to x₂ = 5.

Answers

The average rate of change of the given function is 12.

The average rate of change of function f on interval [a,b] is:

f(b) -f(a)/b-a

we have interval [x₁,x₂]

[x₁,x₂] = [3,5]

f(3) = x²₊4x

f(3) = 3²+4(3)

f(3) = 21

f(5) = x²₊4x

f(5) = 5²+4(5)

f(5) = 45

f(x₂) -f(x₁)/x₂-x₁

⇒ 45-21/5-3

= 24/2

= 12

The average rate of change of function f(x) = x²+4x on interval [3,5]

is 12.

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Name a point non-coplanar to plane K

Answers

W is the point which is non coplanar to plane k .

WHAT IS A COPLANAR/NON-COPLANAR POINT ?

A group of points that are in the same plane are said to be coplanar. A coplanar line connects any two or three points. It's possible that four or more points are coplanar.

The coplanar points A, B, C, and D are displayed on the left side of the above figure. Additionally, there are other sets of coplanar points in the box to the right. For instance, the left side of the box's left side is the plane that contains the coplanar points P, Q, X, and W. There are four coplanar points on each of the box's six faces, however they are not the only coplanar point groups. Points Q, X, S, and Z, for instance, are coplanar despite the fact that the plane containing them isn't depicted.

Non-coplanar points are a collection of points that are not all located on the same plane.

Points P, Q, X, and Y in the previous figure are not coplanar. Q, X, and Y are located on the box's top, and P, Q, and X are located on the box's left side, however no flat surface has all four points.

CALCULATION

since from the figure we can find out that except two points W , Y all the points are on the plane K .

so according to question and given figure we conclude that one of the point which in non coplanar to K is W.

points highlighted in the figure is non coplanar to point k .

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The temperature at
7:00 P.M is 18°F. At
7:00 A.M. the next
day, the temperature
is -12°F. What integer
represents the change
in temperature?

Answers

Answer: -30 degrees fahrenheit

Step-by-step explanation: 18 + (-12) = -30

A student does an experiment in a lab on the boiling point of water. In the 3 trials, the student gets the temperatures of 99.2, 99.5, 100.2 degrees C. Are these measurements:

Question 2 options:

Accuracy


Neither precision nor accuracy


Both precision and accuracy


Precision

Answers

The measurements are precise. Therefore, the correct option is D.

What is precision?

It should be noted that precision simply means how close a test is when it's repeated.

On the other hand, it should be noted that accuracy simply means how close the results are to the standard value.

Therefore, when the student does an experiment in a lab on the boiling point of water. In the 3 trials, the student gets the temperatures of 99.2, 99.5, 100.2 degrees, they're precise.

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