1How do you calculate magnification on a light microscope?

Answers

Answer 1
To calculate the total magnification of the compound light microscope multiply the magnification power of the ocular lens by the power of the objective lens. For instance, a 10x ocular and a 40x objective would have a 400x total magnification. The highest total magnification for a compound light microscope is 1000x.

Related Questions

Please help me answer this question

Answers

Answer:

d=m/v d=0.94

Explanation:

^^^^^^&&&&^^^^

Doping Se with P would produce a(n) ________ semiconductor with ____________ conductivity compared to pure Se.

Answers

doping Se (group VI elements) with P(group V)elements would produce a P-TYPE semiconductor with HIGHER conductivity compared to pure Se

the reason is P dopant will introduce holes in the Se as P has lesser valence electron

True or False
Matter is the ability to do work or cause change.

Answers

False is the correct answer.

Answer:

False

Explanation:

It is Energy that has the ability to cause change.


The Scanning Electron Microscope, or SEM, uses beams of_______
residue from bullets or ink from a ransom note.

Electricity

Protons

Neutrons

Electrons

Answers

Answer:

Electrons.

Hope it helps.

Polymers are long chains of:

A. crystals.

B. molecules.

C. simple molecules

D. atoms

Answers

Answer:

The answer should be Molecules.

Explanation:

Polymers are said to be synthetic or natural substances that are formed by joining the monomeric units together by bonds. They are long chains of molecules. Thus, option B is correct.

What are polymers?

Polymers are macromolecules that are large and big in size that is composed of multiple chemical units of various molecules linked by chemical bonds. These substances can be natural or man-made.

The polymers are composed of monomeric units that are molecules like the starch polymer made of glucose monomeric units linked by the glycosidic linkages. They are complex and tough structures that often provide structural support and protection.

Proteins, carbohydrates, lipids, and nucleotides are polymers composed of amino acids, sugar, fatty acids, and nucleic acids. Polymers are involved in various functions in living organisms.

Therefore, option B. molecules make long chains of polymers.

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Ceramics make excellent refractory materials. A material is said to be refractory if it:
1 has high refractive index
2 retains its strength at high temperatures
3 resists the flow of electric current 4 all of the mentioned

Answers

Answer:

Option 2 is the correct answer

Explanation:

Ceramics, which mainly consist of oxides, carbides and nitrides, can withstand very high temperatures; furnaces are generally lined with such ceramics.

The rate of a chemical reaction can be found by measuring how ................. the reactants are ................. or how quickly the products are ...............​

Answers

The rate of a chemical reaction can be found by measuring how “fast” the reactants are “used” or how quickly the products are “formed”

What is the oxygen tank and equipment used for and how is it used??

Answers

Answer:

Oxygen tanks are used to store gas for: medical breathing at medical facilities and at home. breathing at altitude in aviation, either in a decompression emergency, or constantly (as in unpressurized aircraft) oxygen first aid kits.

Explanation:

Mark my answer as the brainliest!

Iron ore is converted to iron metal in a reaction with carbon. If 1.07 moles of are used, what amount of is needed and what amounts of and , in moles, are produced

Answers

Answer:

information is missing

Explanation:

chemical equation is needed

A scientist observed that tobacco plants flower only at certain times of the year. After careful consideration of this phenomenon, the scientist conducted an experiment. She grew five tobacco plants and exposed each to light for a specific period of time each day. Study the diagrams below which show the results of this experiment. Then complete the sentences that follow.

1. Since only one variable was changed in this experiment, this is called a
experiment.

2. The independent variable in this experiment is .

3. The dependent variable in this experiment is .

4. List some of the controlled variables in the experiment. (Identify at least three.)

Answers

An experiment is performed to study how the change in some variables affects other related variables.

I can't see the diagrams but I can give you general answers for each statement.

1) We define a good experiment as an experiment where only one variable is tested at the time, this is because this allows the scientists to isolate the impact of that variable in the experiment.

"Since only one variable was changed in this experiment, this is called a good  experiment."

2) The independent variable is the variable that the scientists can change in an experiment, in this case, we know that she does change the hours of light that each plant gets, so we can conclude that the independent variable is the time of light exposition that each plant gets.

"The independent variable in this experiment is the time of light exposition"

3) The dependent variable in an experiment is the variable that reacts to the changes in the independent variable, it usually is the thing that the scientist wants to study. In this case, we know that she is studying the floration times of tobacco plants, so:

"The dependent variable in this experiment is the flowering time of tobacco plants"

4) Controlled variables are, in principle, independent variables, that are fixed for the whole experiment. We can't see the controlled variables because there are no graphs, but we can think about what we should fix in this type of experiment.

The temperature: All the plants should grow in the same temperature, as it can affect the flowering times.

The humidity: The humidity also could impact on the flowering of the plants, so we need to fix it for the 5 plants.

The strain: All 5 tobacco plants need to be from the same genetics, we know that different genetics from different parts of the world may react differently to changes in light or temperature, so the strains need to be equal.

Substrates: All the plants should be on the same substrate, so she can be sure that all the plants are getting exactly the same nutrients from the soil.

These are just some examples, if you were designing this experiment, you would see that there are a lot of variables that need to be controlled.

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calculate the density of the object that has a mass of 5.0 g and occupies the volume of 10.0 cm3

Answers

Density = Mass/Volume.

In this problem, you just need to divide 5.0g by 10.0cm³.

Density = 5.0g/10.0cm³= 0.5gcm^-3

What are precautions to be taken when doing titrations? A-Make sure to always vigorously shake that flask after every drop if the end point is still unknown. It may be that the remaining volume of the titrant needed to reach the end point is just adhering on the wall. This is to ensure accuracy. B-The amounts of solid and liquid should be weighed and pipetted with high accurac This is because all the data that will be produced will mainly depend on this. C- If the end point is unknown, dropwise addition of the titrant is recommended. D- Always make sure that the indicator is added. E- All of the above​

Answers

Answer:

E

Explanation:

This is because all steps from A-D are important to obtain an accurate result

5. A Brønsted-Lowry acid
A. is any species that donates a proton.
B. is any species that accepts a proton.
C. has a lower pH than vinegar.
D. is limited to aqueous solutions.

Answers

Answer:

A. is any species that donates a proton.

Explanation:

A Bronsted-Lowry acid is a chemical species that donates one or more hydrogen ions in a reaction.

In contrast, a Bronsted-Lowry base accepts hydrogen ions.

Determine the redox reaction represented by the following cell notation: Mg(s) | Mg2 (aq) || Cu2 (aq) | Cu(s)

Answers

oxidation: Mg (s) —> Mg2+ (aq) + 2e
reduction: Cu2+ (aq) +2e —> Cu(s)

redox reaction: Mg(s) + Cu2+(aq)—> Mg2+(aq) + Cu(s)

D
Question 3
1 pts
In olden times, apothecaries used to dispense medicine using their own system of measurements
that are listed below. Use these conversions to determine how many milligrams would be in a
sample of 1.250 scruples.
1 apothecary pound = 12 ounces
1 ounce = 8 drams
3 scruples = 1 dram
1.2153 apothecary pound = 1 English pound
1 kg = 2.205 English pounds
Enter your answer to the correct number of significant digits. Do not include the units.

Answers

Changing 1.250 scruples to milligrams.

To convert from a unit to another, First write the conversion guide

then cross multiply in such a way that the  unit  both top and bottom

cancel out each other together with dividing or multiplying  the values associated with them.

To get to the answer we have to wor it out step by step.

First step

3 scruples = 1 dram

1.250 scruples=

= [tex]\frac{1.250 scruples x 1 dram}{3scruples}[/tex] = 0.41667dram

2nd step

8 drams=1 ounce

0.41667drams   =

[tex]\frac{0.41667drams x 1}{8 drams }[/tex]  =0.05208 ounces

3rd step

1 apothecary pound = 12 ounces

?apothecary pound =0.05208 ounces

[tex]\frac{0.05208 ounces x 1apothecary pound }{12 ounces}[/tex] =0.00434 apothecary pound

4th step

1.2153 apothecary pound = 1 English pound

0.00434 apothecary pound =

[tex]\frac{0.00434 apothecary pound x 1 English pound}{1.2153 apothecary pound }[/tex] 

==0.003571 English pound

5th step

1 kg = 2.205 English pounds

 ??kg      =0.003571 English pound

[tex]\frac{0.003571 English pound x 1kg }{2.205 English pounds}[/tex]

=0.00161950kg

6th step

1kg =0.00161950kg

0.00161950kg=

[tex]\frac{0.00161950kg x 0.00161950kg}{1kg}[/tex]

=1,619.50mg

Therefore, 1.250 scruples=1,619.50mg

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The SARS-Cov2 spike protein has a large N-terminal domain, a transmembrane helix and a short C-terminal region. Before the structure of the protein was known, researchers analysed its amino acid sequence using hydropathy plot analysis to predict the position of loops exposed to an aqueous environment because these show as:

A broad peak (>20 residues) of mixed positive and negative hydropathy

A broad peak (>20 residues) of positive hydropathy

A narrow (5-10 residues) of positive hydropathy

A narrow peak (5-10 residues) of negative hydropathy

Answers

Answer:

Explanation:

-g

Write electronic configuration of Na and Ca on the basis of subshell.​

Answers

Na:-

Sodium has 11 electrons so the EC followed by

[tex]\\ \sf\Rrightarrow 1s^22s^22p^63s^1[/tex]

Ca:-

Calcium has 20electrons so the EC followed by

[tex]\\ \sf\Rrightarrow 1s^22s^22p^63s^23p^63d^2[/tex]

why does beryllium not liberate hydrogen from acid readily

Answers

Beryllium does not react directly with hydrogen unlike other alkaline earth metals to form ionic hydride. This is because the oxidation potential of beryllium is very low and thus it does not donate its electrons easily to hydrogen.

The orbit of a planet is an ellipse with the sunat one of the foci.. This is Kepler's........ second law third law first law​

Answers

Answer:

its keplers first law

Explanation:

answer from gauth math

An atom has 30 protons and 30 neutrons. What is its mass number?

Answers

No of protons=30No of neutrons=30

Mass number=No of protons+No of neutrons

[tex]\\ \sf\longmapsto Mass\:No=30+30[/tex]

[tex]\\ \sf\longmapsto Mass\:No=60[/tex]

Explanation:

Here,

Protons(p+)=30

Neutrons(N⁰)=30

We know,

Atomic mass(z)=(P+)+(N⁰)

=30+30

=60

Where did you put H an He? What are your reasoning for placement?

Answers

Answer:

On the placement of hydrogen and helium in the periodic system

H1=1

He2=2

Use VSEPR Theory to predict the molecular geometry around the central atom in each of the following molecules. Which of the following molecular geometries are correct?
1. XeF4, square planar
2. ICI., tetrahedral
3. SF4, seesaw
a. 1 and 2
b. 3 only
c. 1 and 3
d. 2 only
e. 1, 2 and 3

Answers

1. in XeF4, the central atom Xe has 2 pairs of free electron pairs and 4 bonded electron pairs hence it is square planar (correct)
2. I-Cl is only composed of 2 atoms, the only possible shape is linear
3. in SF4 the central atom S has 1 pair of free electron pair and 4 bonded electron pairs, hence the shape is seesaw (correct)

so the correct answer is 1 and 3

6.3 gram of HNO3 as mass of nitrate

Answers

Moles of HNO  3

​  = 6.3/63 = 0.1 moles  

HNO3  has 1 atom of H , 1 atom of N , 3 atoms of O

No of atoms = moles of molecule × atomicity of atom × avogadro number

No of atoms of H =0.1×1×6.023×10^23

 = 6.023×10^22  

 

No of atoms of N =0.1×1×6.023×10^23

 = 6.023×10  ^22

 

No of atoms of O =0.1×3×6.023×10  ^23

 =  18.069×10 ^22

What are your main fears about this class (if any)?​

Answers

Answer:

sitting n front of class

reading out loud

and being stressed

and being bullied

Explanation:

Calculate the amount of heat required to melt 2108 g of water. The enthalpy of fusion of water is ΔHfus=6.010 kJ/mol.

Answers

since the unit for the heat of fusion is kJ/mol, you're going to have to convert the grams into moles in order to cancel out the unit. After that, you can solve like normal.

Specific heat capacity of a substance is the amount of heat required to raise the temperature by one degree Celsius of one gram of a substance. Therefore, the amount of heat required to melt 2108 g of water is 703.7kJ.

What is Enthalpy?

Enthalpy term is basically used in thermodynamics to show the overall energy that a matter have. Mathematically, Enthalpy is directly proportional to specific heat capacity of a substances.

Mathematically,

q = n ×ΔH

where

q = amount of heat=?

ΔH = enthalpy=6.010 kJ/mol

n = no of moles

n = w / M.M

w = given mass

M.M = molar mass

moles of water=2108 g ÷18g/mol

                             =117.1 mol

substituting all the given values in the above equation, we get

q =6.010 kJ/mol ×117.1 mol

    =703.7kJ

Therefore, the amount of heat required to melt 2108 g of water is 703.7kJ.

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How many atoms are in 0.100 mol of C3H8

Answers

number of atoms = mole x Avogadro’s Number

= 0.1 x 6.022 x 10^23
= 6.022 x 10^22

What is the mass ratio for NH3?

Answers

Answer:

ratio by mass

14 3

mass ratio atomic mass

14/14 = 1 3/1=3

The procedure was applied to a new sample of 9.00 milliliters of the liquid mixture to extract component C. Due to the loss of volume from the procedure, the extracted volume of component C was only 90.0% of the original volume of this component. What was the extracted volume of component C, in milliliters

Answers

The extracted volume of component C is 8.1 mL

Percentage volume of substance in a mixture can be obtained by the following equation:

[tex]Percentage volume = \frac{Volume of sub.}{Total Volume} * 100\\\\[/tex]

Considering the question given above, the following data were obtained:

Total volume of mixture = 9 mL

Percentage of C extracted = 90%

Volume of C extracted =?

[tex]Percentage of C = \frac{Volume of C }{Total Volume} \\\\90 percent = \frac{Volume of C}{9}[/tex]

Cross multiply

Volume of C = 90% × 9

Volume C = 0.9 × 9

Volume of C = 8.1 mL

Therefore, the volume of C extracted is 8.1 mL

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Salt water has a density of 1.183g/mL. A ball has a density of 0.0134 g/mL. Will the ball float or sink?

Answers

The ball will float as it’s density is less than the salt water.

How many centimeters are there in 5.44 meters?

Answers

Answer:

544 cm!

I hope this helped.

Answer:

The answer of your question is 544 cm

Explanation:

5.44 × 100

544 cm

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