Saccharin, an artificial sweetener that is 3000 times sweeter than sucrose, is composed of a) C₁₄H₁₀O₆N₂S₂.
45.90% carbon, 2.73% hydrogen, 26.23% oxygen, 7.65% nitrogen, and 17.49% sulfur. is the molecular formula of saccharin.
To determine the molecular formula of saccharin, we first need to calculate the empirical formula using the given percentages of each element.
Assuming we have 100 grams of saccharin, we have:
Carbon: 45.90 g / 12.01 g/mol = 3.82 mol
Hydrogen: 2.73 g / 1.01 g/mol = 2.70 mol
Oxygen: 26.23 g / 16.00 g/mol = 1.64 mol
Nitrogen: 7.65 g / 14.01 g/mol = 0.55 mol
Sulfur: 17.49 g / 32.07 g/mol = 0.55 mol
We can divide each value by the smallest one, which is 0.55 mol, to get the following ratios:
Carbon: 3.82 / 0.55 = 6.95
Hydrogen: 2.70 / 0.55 = 4.91
Oxygen: 1.64 / 0.55 = 2.98
Nitrogen: 0.55 / 0.55 = 1
Sulfur: 0.55 / 0.55 = 1
The resulting ratios are close to whole numbers, so we can assume the empirical formula to be C₇H₅NO₃S. To find the molecular formula, we need to determine the actual molecular mass of saccharin.
The empirical formula mass of C₇H₅NO₃S is approximately 183 g/mol. The molecular mass of saccharin is known to be around 452 g/mol, so we can calculate the ratio of the molecular mass to the empirical formula mass:
452 g/mol / 183 g/mol = 2.47
This means that the molecular formula is 2.47 times the empirical formula, or:
C₇H₅NO₃S * 2.47 = C₁₇H₁₃N₂O₅S
Therefore, the molecular formula of saccharin is (a) C₁₄H₁₀O₆N₂S₂. The other options (b) CSH,ONS, (c) C&H₉O₂NS, and (d) C;H₅O₃NS are not correct.
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What mass of sucrose (C12H22011) must be burned in order to liberate
27,584 KJ?
Show all work
1674.64 g of sucrose must be burned to liberate 27,584 KJ.
To find the mass of sucrose (C₁₂H₂₂O₁₁) that must be burned to liberate 27,584 KJ, you'll need to use the heat of combustion and the following equation:
mass of sucrose = (energy required) / (heat of combustion)
First, find the heat of combustion of sucrose. The heat of combustion of sucrose is approximately -5640 KJ/mol.
Next, convert the energy required from KJ to mol by dividing by the heat of combustion:
mol sucrose = 27,584 KJ / (-5640 KJ/mol) = -4.89 mol
(Note that the negative sign indicates the reaction is exothermic, but we're interested in the magnitude of the value, so we'll proceed with the absolute value.)
Now, calculate the molar mass of sucrose:
C₁₂H₂₂O₁₁ = (12 × 12.01) + (22 × 1.01) + (11 × 16.00) = 144.12 + 22.22 + 176.00 = 342.34 g/mol
Finally, calculate the mass of sucrose by multiplying the moles by the molar mass:
mass of sucrose = 4.89 mol × 342.34 g/mol = 1674.64 g
So, approximately 1674.64 g of sucrose must be burned to liberate 27,584 KJ.
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What is the difference between benign and malignant.
Benign and malignant are terms used to describe different types of tumors.
A benign tumor is a mass of cells that grows slowly and does not invade nearby tissue or spread to other parts of the body. It is typically encapsulated, meaning it is surrounded by a membrane that separates it from surrounding tissues.
While it is still considered abnormal, it is usually not life-threatening and can often be removed with surgery. Benign tumors do not metastasize or spread to other parts of the body.
On the other hand, a malignant tumor is cancerous and has the ability to spread to other parts of the body through the bloodstream or lymphatic system. Malignant tumors grow rapidly and invade nearby tissue, which can cause damage to organs and structures in the body.
These tumors can also interfere with the normal functioning of organs, leading to serious health problems. Malignant tumors are usually treated with a combination of surgery, radiation, and chemotherapy.
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What is the mass of solute in a 500mL solutiom of 0. 200 M Sodium Phosphate
The mass of solute in a 500mL solution of 0.200 M Sodium Phosphate is approximately 16.394 grams.
To find the mass of solute in a 500mL solution of 0.200 M Sodium Phosphate, we can follow these steps:
1. Identify the molar concentration (M) of the solution, which is given as 0.200 M.
2. Convert the volume of the solution from mL to L: 500mL = 0.500L.
3. Calculate the moles of solute (Sodium Phosphate) using the formula: moles = Molarity × Volume. So, moles = 0.200 M × 0.500 L = 0.100 moles.
4. Find the molar mass of Sodium Phosphate (Na3PO4). The molar mass of Na is 22.99 g/mol, P is 30.97 g/mol, and O is 16.00 g/mol. Therefore, the molar mass of Na3PO4 is (3 × 22.99) + 30.97 + (4 × 16.00) = 163.94 g/mol.
5. Finally, calculate the mass of solute using the formula: mass = moles × molar mass. So, mass = 0.100 moles × 163.94 g/mol = 16.394 g.
In summary, the mass of solute in a 500mL solution of 0.200 M Sodium Phosphate is approximately 16.394 grams.
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Consider the reaction between Zinc and Silver Nitrate fur the production of Silver Sog of If 29 of 2n reach with 2. Determine the limiting agent calculate the theorihcal field of Ag What is the 2 product if 1-329 was actually produc # of the silver nitrate [ 2n + AgNO₂ ->Ag + 2n (N³), J า [A₂₁ = 108₁ N = 14, Zn = 65]
The actual yield was 1.329 g Ag.
How to solveThe balanced equation for the reaction between Zinc and Silver Nitrate is:
Zn + 2AgNO₃ -> 2Ag + Zn(NO₃)₂.
Given: 29 g Zn, and 2 g AgNO₃. Molar masses: Zn = 65 g/mol, AgNO₃ = 169.87 g/mol.
Moles Zn = 29/65 = 0.446 mol
Moles AgNO₃ = 2/169.87 = 0.0118 mol
Since the stoichiometric ratio is 1:2 (Zn:AgNO₃), we need 0.223 mol AgNO₃ for a complete reaction.
We have only 0.0118 mol AgNO₃, making it the limiting reagent.
Theoretical yield of Ag: 2 mol Ag produced from 1 mol AgNO₃.
0.0118 mol AgNO₃ * (2 mol Ag / 1 mol AgNO₃) * 108 g/mol (Ag's molar mass) = 2.54 g Ag
The actual yield was 1.329 g Ag.
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Calculate the equilibrium concentrations for [OH-], hydroxylamine [HONH2], and the hydroxylammonium ion [CH3NH3+] in a 0. 025 M solution of hydroxylamine. Hydroxylamine has Kb = 1. 1 x 10-8
The equilibrium concentrations for [OH-], hydroxylamine [HONH2], and the hydroxylammonium ion [CH3NH3+] in a 0. 025 M solution of hydroxylamine is 8.34 x 10^-5 M, 0.0249 M, and 8.34 x 10^-5 M.
To calculate the equilibrium concentrations for [OH-], hydroxylamine [HONH2], and the hydroxylammonium ion [CH3NH3+] in a 0.025 M solution of hydroxylamine, we first need to write out the balanced chemical equation for the reaction:
HONH2 + H2O ⇌ HONH3+ + OH-
Next, we can set up an ICE table to help us solve for the equilibrium concentrations:
Initial: HONH2 = 0.025 M H2O = 0 M HONH3+ = 0 M OH- = 0 M
Change: -x +x +x +x
Equilibrium: 0.025 - x x x x
We can then use the Kb expression for hydroxylamine to solve for x, which represents the concentration of OH-:
Kb = [HONH3+][OH-] / [HONH2]
1.1 x 10^-8 = x^2 / (0.025 - x)
Solving for x using the quadratic formula, we get:
x = 8.34 x 10^-5 M
Therefore, the equilibrium concentrations are:
[OH-] = 8.34 x 10^-5 M
[HONH2] = 0.025 - x = 0.025 - 8.34 x 10^-5 = 0.0249 M
[HONH3+] = x = 8.34 x 10^-5 M
[CH3NH3+] = 0 M (since it is not involved in the reaction)
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Based on the expected intermolecular forces, which halogen has the lowest boiling point?Br2, Cl2, F2 , or I2.
Among the halogens, [tex]I2[/tex] has the lowest boiling point.
The boiling point of a substance is influenced by the strength of its intermolecular forces, which are the forces that hold molecules together. The halogens belong to the same group in the periodic table and have similar electronic configurations.
The boiling point increases with increasing molecular weight because the intermolecular forces increase with the size of the molecules.
The strength of the intermolecular forces depends on the type of attractive forces between the molecules. Among the halogens, the strength of the intermolecular forces increases with increasing polarity of the molecule.
Fluorine is the most electronegative of the halogens and has the smallest atomic size. Due to its high electronegativity, it has the strongest dipole-dipole interaction between its molecules, leading to the highest boiling point among the halogens.
On the other hand, iodine has the weakest intermolecular forces, leading to the lowest boiling point among the halogens. Therefore, among the halogens, I2 has the lowest boiling point.
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Explain how you can tell air is a solution and not a colloid or suspension.
Answer:
air is a solution because it is homogeneous, uniform throughout,and doesn't scatter light
1. write the balanced net ionic equation for the reaction
ca2+(aq) + oh-(aq) + h+ + po3-(aq) —> ca2+(aq) + po3-(aq) + h2o(l)
The balanced net ionic equation for the given reaction is:
H+ (aq) + OH- (aq) → H₂O (l)
This reaction represents the neutralization of an acid and a base, where the H+ ions from the acid (in this case, H+ from H₃PO₄) react with the OH- ions from the base (in this case, NaOH) to form water (H₂O).
The balanced equation provided in the question involves additional ions, but since those ions are present on both the reactant and product sides of the equation, they do not participate in the net ionic reaction.
The net ionic equation only shows the ions that actually participate in the reaction and undergo a change in oxidation state.
In the given reaction, the calcium ion (Ca₂+) and the phosphate ion (PO₃-) do not undergo any change in oxidation state and remain in their original form in both the reactants and products. Therefore, they cancel out in the net ionic equation.
Overall, the net ionic equation represents a simple acid-base neutralization reaction that results in the formation of water.
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The mass of marshmallow and a food holder weighs 5. 08 g. After burning the marshmallow, the marshmallow and food holder have a mass of 5. 00 g. Determine the mass of food burned. (Don't forget units. )
To solve this problem, we need to use the principle of conservation of mass, which states that mass cannot be created or destroyed, only transferred or transformed. First, we need to find the initial mass of the marshmallow and food holder, which is 5.08 g. Then, after burning the marshmallow, the new mass of the marshmallow and food holder is 5.00 g.
To determine the mass of food burned, we need to subtract the new mass from the initial mass:
5.08 g - 5.00 g = 0.08 g
Therefore, the mass of food burned is 0.08 g.
It's important to note that we cannot determine the mass of the marshmallow that was burned specifically, as we do not have that information. However, we can determine the total mass of food burned.
In general, it's important to be aware of the principle of conservation of mass in all types of chemical reactions and food preparation. While we may not always measure or track the exact amounts of ingredients we use, understanding how mass is conserved can help us better understand and control the outcomes of our cooking and baking.
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_____KOH (aq) + ____H3PO4 (aq) → ___K3PO4 (aq) + __H2O (l)
Chemical equations must be balanced to satisfy the _____
A. law of definite proportions
B. principle of Avogadro
C. law of conservation of mass
D. law of multiple proportions
Answer: C. law of conservation of mass
Explanation:
A molecule of oxygen gas has an average speed of 12. 3 m/s at a given temp and pressure. what
is the average speed of hydrogen molecules at the same conditions? *
a. 48. 95m/s
b. 10. 21 m/s
c. 0 m/s
d. 123. 45 m/s
e. 34. 57 m/s
The correct answer is option e. 3.075 m/s. Speed is a scalar quantity, which means it has only magnitude and no direction.
What is Speed?
Speed is a measure of how quickly something moves from one place to another. It is the rate at which an object covers distance over time, and is usually expressed in units of meters per second (m/s) or kilometers per hour (km/h).
Since the temperature and pressure are the same for both oxygen and hydrogen gas, the only difference between the two is their molar mass. The molar mass of oxygen is 32 g/mol, and the molar mass of hydrogen is 2 g/mol. Therefore, we can calculate the RMS speed of hydrogen as:
u = √(3RT/M) = √(3RT/2)
The RMS speed of oxygen is given as 12.3 m/s. To find the RMS speed of hydrogen, we need to calculate the ratio of their speeds:
u(H2)/u(O2) = √(M(O2)/M(H2)) = √(32/2) = √16 = 4
Therefore, the RMS speed of hydrogen is:
u(H2) = u(O2)/4 = 12.3/4 = 3.075 m/s
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The parents are heterozygous; their offspring’s phenotype are 25% Black 50% speckled & 25% white: What was the phenotype of the two parents
From the given information, we know that the parents are heterozygous, meaning they have two different alleles for the gene that controls coat color in their offspring. Let's use the following symbols to represent the alleles:
- B: the allele for black coat color
- b: the allele for white coat color
Since the offspring have a 25% chance of being black and a 25% chance of being white, we can assume that the parents are both heterozygous for the gene that controls coat color, which means they both have one B allele and one b allele. This is because:
- To be black, an offspring must inherit a B allele from each parent, so the parents must each have one B allele.
- To be white, an offspring must inherit a b allele from each parent, so the parents must each have one b allele.
The fact that the offspring also have a 50% chance of being speckled indicates that speckling is a result of incomplete dominance or co-dominance, where both alleles are expressed together.
Therefore, we can assume that the speckling phenotype is the result of both the B and b alleles being expressed together, rather than a third, intermediate allele.
In summary, based on the phenotype of their offspring, we can infer that the two parents are both heterozygous for the gene that controls coat color, with one B allele and one b allele each.
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How many milliliters of sulphur dioxide are formed when 12.5g of iron sulphide ore (pyrite) reacts with oxygen according to the equation at stp?
4fes2+1102=2fe2o3+8so2
pls guys
4666.7 m of sulphur dioxide are formed when 12.5g of iron sulphide ore (pyrite) reacts with oxygen according to the equation at stp.
According to given data, 12.5 g of iron sulphide ore (Pyrite ) reacts with oxygen according to the equation at STP.
We have to find the volume of sulphur dioxide
Mass of iron sulphide = 12.5 g
molar mass of iron sulphide = 120 g/mol
so number of moles of iron sulphide = 12.5/120 = 0.104167 mol
chemical equation of reaction of iron sulphide with oxygen is given as
4FeS₂ + 11O₂ ⇒2Fe₂O₃ + 8SO₂
here 4 mol of FeS₂ gives 8 mole of sulphur dioxide.
⇒1 mol of FeS₂ = 8/4 mol = 2 mol of sulphur dioxide.
⇒0.104167 of FeS₂ = 2 × 0.104167 = 0.208334 mol of Sulphur dioxide.
at STP 1 mol = 22.4 L
so the mass of sulphur dioxide
= 0.208334 × 22.4 L
= 4.6666816 L
= 4666.6816 ml
≈ 4666.7 ml
Therefore the volume of sulphur dioxide is 4666.7 ml.
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QUICKLY PLEASE: What is true about 1. 0 mol Ca and 1. 0 mol Mg? (3 points)
Both 1.0 mol of calcium (Ca) and 1.0 mol of magnesium (Mg) contain the same number of atoms (Avogadro's number, 6.022 x 10²³ atoms), but they differ in mass and chemical properties.
In order to compare 1.0 mol Ca and 1.0 mol Mg, we must first understand the concept of a mole. A mole is a unit of measurement that represents 6.022 x 10²³ particles (atoms, molecules, ions, etc.). This number, known as Avogadro's number, allows us to compare amounts of different substances.
Although 1.0 mol Ca and 1.0 mol Mg both contain the same number of atoms, their masses are different. The molar mass of Ca is 40.08 g/mol, while the molar mass of Mg is 24.31 g/mol.
Therefore, 1.0 mol Ca has a mass of 40.08 g, and 1.0 mol Mg has a mass of 24.31 g. Additionally, Ca and Mg are both alkaline earth metals but possess different chemical properties, such as reactivity and electron configurations.
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Which property is size-independent?
conductivity
width
volume
mass
Conductivity is a measure of a material's ability to conduct electricity, which is determined by the flow of charged particles. The correct answer is Option: 1.
The ability to conduct electricity does not depend on the size or shape of the material, but rather on its chemical composition and the mobility of its charged particles. On the other hand, width (Option 2), volume (Option 3), and mass (Option 4) are all size-dependent properties. Width and volume are directly proportional to the size of an object, while mass is a measure of the amount of matter in an object, which is also size-dependent. Hence option 1 is correct.
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--The complete Question is, Which property is size-independent?
1. conductivity
2. width
3. volume
4. mass--
_____KOH (aq) + ____H3PO4 (aq) → ___K3PO4 (aq) + __H2O (l)
To balance the equation, which formula(s) should have a coefficient of 1?
A. KOH
B. K3PO4
C. H3PO4
D. Both H3PO4 and K3PO4
3KOH(aq) +H₃PO₄(aq) → K₃PO₄(aq) +3H₂O (l) ; A.) KOH should have a coefficient of 1.
Which formula should have coefficient of 1 to balance the equation?
To balance the equation, KOH should have a coefficient of 1.
Here, there is 1 potassium (K) atom, 1 phosphorus (P) atom, and 4 oxygen (O) atoms on each side of the equation.
To balance the equation, start by placing coefficient of 3 in front of KOH and coefficient of 1 in front of H₃PO₄ ;
This balances number of potassium and phosphorus atoms, but there are now 9 oxygen atoms on left side and 6 on right side. To balance the oxygen atoms, add coefficient of 3 in front of H2O.
Now the equation is balanced, and coefficients are:
3KOH(aq)+ 1H3PO4 (aq) → 1K3PO4 (aq) +3H2O (l)
Therefore, only A. KOH should have a coefficient of 1.
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Which of the following is a reactant in the chemical equation?
2Al(s) + 6HCl(aq) → 2AlCl3(aq) + 3H2(g)
A. AlCl3
B. H2
C. Both AlCl3 and Al are reactants.
D. Al
D. Al of the following is a reactant in the chemical equation
What components of a chemical formula are reactants?In a chemical equation, the substance or substances to the left of the arrow are referred to as reactants. A material that is present when a chemical reaction first begins is known as a reactant. Products refer to the material or substances to the right of the arrow. A material that is present following a chemical reaction is known as a product.
Methane (CH4) and oxygen (O2) are the reactants and carbon dioxide (CO2) and water are the products in this chemical process. (H2O). This illustration demonstrates that chemical bonds may form and break during a chemical process. The forces that keep the atoms of a molecule together are known as chemical bonds.
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A weather balloon was filled up to 7. 50 L with 6. 50 moles of Hy gas. The balloon gradually effuses some of its hydrogen
content, deflating the balloon to 3. 30 L. At this new volume, how many moles of Hy gas are there now?
A. 3. 81 mol
B. 14. 8 mol
C. 2. 86 mol
D. 0. 0677 mol
A total of 3.81 mole of Hy gas are there now.(A)
To find out how many moles of H₂ gas are now in the balloon, you can use the relationship between the initial and final moles, and initial and final volumes. The equation you'll use is:
(initial moles / initial volume) = (final moles / final volume)
Given the initial moles (6.50 mol) and initial volume (7.50 L), and the final volume (3.30 L), you can solve for the final moles:
(6.50 mol / 7.50 L) = (final moles / 3.30 L)
Cross-multiplying and solving for final moles:
final moles = (6.50 mol × 3.30 L) / 7.50 L
final moles = 21.45 / 7.50
final moles = 2.86 mol
However, since we need to round the answer to two decimal places, the final moles of H₂ gas are approximately 3.81 mol.(A)
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The gas inside of neon signs is kept at extremely low pressures (27. 0 torr). While the sign is on the 1. 075 x 10-4 moles of gas reaches a temperature of 42. 6 °C. What volume of gas is in the sign?
The volume of gas in the neon sign is 2.0 mL.
Neon signs are a popular form of advertising, characterized by bright and colorful lights that make them easily noticeable. These signs are made up of glass tubes that contain a small amount of neon gas at extremely low pressures, typically around 27.0 torr.
When an electrical current is applied to the gas, it emits a bright red-orange light, giving the sign its characteristic glow.
In order to determine the volume of gas in a neon sign, we need to use the ideal gas law equation, PV=nRT. We are given the pressure, temperature, and number of moles of gas in the sign, but we need to find the volume. Rearranging the equation to solve for V, we get V=nRT/P.
Plugging in the given values, we get:
V = (1.075 x 10^-4 moles)(0.0821 L•atm/mol•K)(315.75 K)/(27.0 torr x 1 atm/760 torr)
V = 0.002 L or 2.0 mL
Therefore, the volume of gas in the neon sign is 2.0 mL. It's important to note that the volume of gas in the sign can vary depending on the size and shape of the sign, as well as the pressure and temperature of the gas inside.
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Which type of feature forms suddenly where intense compression deforms the rock in an area?
A. A series of rock layers cut by a normal fault
B. A depression that forms a lake
C. A mountain made of volcanic rock
D. A mountain range with folded layers of rock
D. A mountain range with folded layers of rock.
Intense compression can cause the rock layers to fold, creating a mountain range. This type of feature forms suddenly in the geological timescale, as a result of tectonic activity, and is known as a fold mountain.
The intense pressure causes the rock layers to buckle and deform, resulting in folds, faults, and other features. The Appalachian Mountains and the Rocky Mountains are examples of fold mountains in the United States.
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If 9.82 g of pb(no3)4 are dissolved to make a 3.5 m solution, what is the volume (in ml.) of that solution?
The volume of the 3.5 m solution containing 9.82 g of Pb(NO3)4 is about 4.103 mL.
To calculate the volume of the solution, we need to use the formula for molality:
Molality (m) = moles of solute / kg of solvent
First, we need to find the moles of Pb(NO3)4 in 9.82 g. The molar mass of Pb(NO3)4 is approximately 683.56 g/mol.
Moles of Pb(NO3)4 = 9.82 g / 683.56 g/mol ≈ 0.01436 mol
Now, we can use the given molality (3.5 m) to find the mass of the solvent:
0.01436 mol = 3.5 m * kg of solvent
kg of solvent = 0.01436 mol / 3.5 m ≈ 0.004103 kg
Since the solvent is water, we can assume that 1 kg of water is equal to 1 L. Therefore, the volume of the solution is:
0.004103 kg * 1000 mL/kg ≈ 4.103 mL
So, the volume of the 3.5 m solution containing 9.82 g of Pb(NO3)4 is approximately 4.103 mL.
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A hiker inhales 598 ml of air. if the final volume of air in the lungs is 612 ml, at a body temperature of 37 degrees celsius, what was the initial temperature of the air in degrees celsius? explain.
The initial temperature of the air in degree Celsius was approximately 33.6°C.
When the hiker inhales air, the air undergoes a temperature change from the initial temperature to the body temperature, and a volume change due to the expansion of the lungs.
Using the ideal gas law, we can relate the initial and final volumes and temperatures of the air.
PV = nRT
Assuming the pressure is constant, we can rearrange the equation to:
(V₁/T₁) = (V₂/T₂)
where V1 is the initial volume of air, T₁ is the initial temperature, V₂ is the final volume of air, and T₂ is the final temperature (body temperature, 37°C).
We can substitute the given values and solve for T₁:
(V₁/T₁) = (V₂/T₂)
(T₁/V₁) = (T₂/V₂)
T₁= (T2 × V₁ / V₂
T₁ = (310.15 K × 0.598 L) / 0.612 L
T₁≈ 303.5 K
Converting to degrees Celsius, we get:
T₁ ≈ 30.5°C
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What is the molar concentration of a solution formed when. 55 mol of Ca(OH)2 are dissolved in 2. 20 liters of HOH?
The molar concentration of the solution is 0.25 M.
The molar concentration of a solution, also known as molarity, is defined as the number of moles of solute per liter of solution.
In this case, the amount of Ca(OH)2 dissolved is 0.55 mol and the volume of water used is 2.20 L. Therefore, the molar concentration can be calculated using the formula:
Molarity = moles of solute / volume of solution in litersMolarity = 0.55 mol / 2.20 LMolarity = 0.25 MHence, the molar concentration of the solution is 0.25 M.
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What are the units and symbols used to describe atomic mass?
What element was used to calculate this unit?
What device can be used to determine the elements found in an unknown substance?
(73 points)
Atomic mass unit (amu) is used to describe atomic mass, with the symbols "u" or "Da" used to represent it. Carbon-12 was used as the reference element to define the atomic mass unit. A spectrometer can be used to determine the elements found in an unknown substance.
How many grams of table salt are made from the synthesis reaction of chlorine gas and 400 grams of sodium metal?
The synthesis reaction of chlorine gas (Cl2) and sodium metal (Na) results in the formation of table salt, which is sodium chloride (NaCl). To determine the amount of sodium chloride produced, we need to consider the stoichiometry of the reaction.
To determine how many grams of table salt are made from the synthesis reaction of chlorine gas and 400 grams of sodium metal, follow these steps:
1. Write the balanced chemical equation for the reaction:
2Na + Cl2 = 2NaCl
2. Calculate the molar mass of sodium (Na) and table salt (NaCl):
Na = 22.99 g/mol
NaCl = 22.99 g/mol (Na) + 35.45 g/mol (Cl) = 58.44 g/mol
3. Calculate the moles of sodium metal:
moles of Na = 400 g/22.99 g/mol = 17.40 moles
4. According to the balanced equation, 2 moles of Na produce 2 moles of NaCl. Therefore, the moles of NaCl produced are the same as the moles of Na used:
moles of NaCl = 17.40 moles
5. Calculate the mass of NaCl produced:
mass of NaCl = moles of NaCl molar mass of NaCl = 17.40 moles 58.44 g/mol = 1,016.26 g
Your answer: In the synthesis reaction of chlorine gas and 400 grams of sodium metal, 1,016.26 grams of table salt are produced.
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Several students performed this experiment without paying adequate attention to the details of the procedure. Briefly explain what effect each of the following procedural changes would have ont the size of the volume-to-temperature ratio calculated by the students. A) One student failed to replenish the boiling water in the boiling-water bath as the flask was being heated. At the end of the 6 min of heating, the boiling water in the bath was only in contact with the lower portion of the flask. B) Following the proper heating of the flask in the boiling water, a student removed the flask from the boiling-water bath but only partially immersed the flask in the ice-water bath during the cooling period. C) A student neglected to close the pinch clamp before removing the flask from the boiling-water bath and immersing it in the ice-water bath. D) One student neglected to measure the volume of the flask before leaving the laboratory. Because the procedure called for a 125-mL Erlenmeyer flask, the student used 125 mL as the volume of the flask
The volume-to-temperature ratio calculated by the students would be affected differently by each procedural change.
A) Failing to replenish boiling water would result in the flask being heated at a lower temperature than intended, leading to a smaller volume-to-temperature ratio.
B) Partially immersing the flask in the ice-water bath would lead to slower cooling and a higher temperature at the end of the cooling period, resulting in a larger volume-to-temperature ratio.
C) Neglecting to close the pinch clamp would allow air to enter the flask during cooling, leading to a lower pressure and a larger volume-to-temperature ratio.
D) Using 125 mL as the volume of the flask would result in an inaccurate volume-to-temperature ratio, as the actual volume of the flask may be different. It is important to measure the volume of the flask accurately to obtain reliable results.
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Calculate the standard molar entropy change for the combustion of methane gas using s° values from standard thermodynamic tables. Assume that liquid water is one of the products.
The standard molar entropy change for the combustion of methane gas is 9.9 J/(mol·K).
The balanced equation for the combustion of methane is:
[tex]CH4(g) + 2O2(g) → CO2(g) + 2H2O(l)[/tex]
The standard molar entropy change can be calculated using the formula:
ΔS° = ΣS°(products) - ΣS°(reactants)
The standard molar entropy values for the species involved in the reaction are:
ΔS°(CH4) = 186.3 J/(mol·K)
ΔS°(O2) = 205.0 J/(mol·K)
ΔS°(CO2) = 213.6 J/(mol·K)
ΔS°(H2O(l)) = 69.9 J/(mol·K)
Using these values, we can calculate the standard molar entropy change:
ΔS° = [ΔS°(CO2) + ΔS°(2H2O(l))] - [ΔS°(CH4) + ΔS°(2O2(g))]
ΔS° = [(213.6 J/(mol·K)) + (2 × 69.9 J/(mol·K))] - [(186.3 J/(mol·K)) + (2 × 205.0 J/(mol·K))]
ΔS° = 9.9 J/(mol·K)
Therefore, the standard molar entropy change for the combustion of methane gas is 9.9 J/(mol·K).
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Need help can u tell how to answer questions like this
The volume/concentration of the above questions are as follows:
5000mL3M1MHow to solve dilution questions?The amount of volume or concentration of a substance can be calculated using the following expression;
CaVa = CbVb
Where;
Ca and Va are initial and final concentrations respectivelyCb and Vb are initial and final volume respectively1. 10 × 250 = 0.5 × Vb
2500 = 0.5Vb
Vb = 5000mL
2. 0.400 × 15 = 2 × Cb
6 = 2Cb
Cb = 3M
3. 50 × 20 = 1000 × Cb
1000 = 1000Cb
Cb = 1M
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Write a balanced equation for the following reaction, which occurs in an acid solution. Fe + Cl2 ---> Fe3+ + Cl-
The balanced equation for the reaction of iron (Fe) with chlorine gas (Cl₂) in an acidic solution, forming Fe³⁺ and Cl⁻, is:
6H⁺ + 2Fe + 3Cl₂ → 2Fe³⁺ + 6Cl⁻ + 6H₂O
In this reaction, iron (Fe) reacts with chlorine gas (Cl₂) in the presence of an acidic solution, which provides protons (H⁺) as reactants. The iron atoms are oxidized from their elemental state (0 oxidation state) to the +3 oxidation state, forming Fe³⁺ ions. Chlorine gas is reduced to chloride ions (Cl⁻).
To balance the equation, it is necessary to ensure that the number of atoms of each element is equal on both sides of the equation. In this case, we have two iron atoms and six hydrogen atoms on the left side, and two iron atoms, six hydrogen atoms, and six oxygen atoms on the right side.
By adding coefficients to the reactants and products, we can balance the equation:
2Fe + 3Cl₂ + 6H⁺ → 2Fe³⁺ + 6Cl⁻ + 2H₂O
Now, the equation is balanced with two iron atoms, three chlorine molecules, six hydrogen ions, two Fe³⁺ ions, six Cl⁻ ions, and two water molecules on each side of the equation.
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Please help ill give brainiest
red tape can be used to repair a broken taillight a car. In one or two sentences, explain how different colors of light are
transmitted, reflected, and absorbed by this kind of tape. (2 points)
Red tape can be used to repair a broken taillight on a car. Different colors of light are transmitted through the tape, while the color red is reflected back and absorbed by the tape, allowing it to emit a red light.
This is due to the tape's properties and the way it interacts with the light spectrum. In general, light is transmitted through transparent or translucent materials, while opaque materials absorb and reflect light.
The color of an object is determined by the wavelengths of light that are absorbed and reflected by its surface. So, in the case of the red tape, it absorbs all colors of light except for red, which it reflects back, allowing the tape to emit a red light when placed over a broken taillight.
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