Answer:
a. p`± z₀.₀₂₅[tex]\sqrt{ \frac{p`q`}{n}[/tex]
b.0.6 ± 1.96 [tex]\sqrt \frac{0.6* 0.4}{1000}[/tex]
c. { -1.96 ≤ p`± z₀.₀₂₅[tex]\sqrt{ \frac{p`q`}{n}[/tex] ≥ 1.96} = 0.95
Step-by-step explanation:
Here the total number of trials is n= 1000
The number of successes is p` = 600/1000 = 0.6. The q` is 1 - p`= 1- 0.6 = 0.4
The degree of confidence is 95 % therefore z₀.₀₂₅ = 1.96 ( α/2 = 0.025)
a. The formula used will be
p`± z₀.₀₂₅[tex]\sqrt{ \frac{p`q`}{n}[/tex] ( z with the base alpha by 2 (α/2 = 0.025))
b. Putting the values
0.6 ± 1.96 [tex]\sqrt \frac{0.6* 0.4}{1000}[/tex]
c. Confidence Interval in Interval Notation.
{ -1.96 ≤ p`± z₀.₀₂₅[tex]\sqrt{ \frac{p`q`}{n}[/tex] ≥ 1.96} = 0.95
{ -z( base alpha by 2) ≤ p`± z₀.₀₂₅[tex]\sqrt{ \frac{p`q`}{n}[/tex] ≥ z( base alpha by 2) } = 1- α
Judith is planning a birthday party at her house. she has 36 slices of pizza and 24 Capri Suns. What is the maximum number of people she can have at the party so that each person gets the same number of slices of pizza and the same number of Capri Suns? show all work
She can either have 24 people since there are more slices of pizza there will be extras
Please help me out with these questions, ❤️☢️⬅️⬅️☣️⬅️✖️❌❎❎❎❌️️ℹ️⚫▫️▫️▫️
Hi there! Thanks for your questions ;)
The answers are quite easily, go through the steps below so that you can catch it up yourself!!
a)= [tex]\rm{sin (x) = \dfrac{9}{20}}[/tex]
= [tex]\rm{0.45}[/tex]
= [tex]\rm{x = arcsin(0.45)}[/tex]
= [tex]\rm{26.74 \: degrees}[/tex](b) here, h is height.= [tex]\rm{h = 20 \times cos(x)}[/tex]
= [tex]\rm{20 \times cos(26.74)}[/tex]
= [tex]\rm{ 17.86 \: m}[/tex]Hope it is helpful!
A study of the annual population of butterflies in a county park shows the population, B(t), can be represented by the function B(t)=137(1.085)t, where the t represents the number of years since the study started. Based on the function, what is the growth rate?
Answer:
The growth rate is of 0.085 = 8.5% a year.
Step-by-step explanation:
General growth equation:
[tex]B(t) = B(0)(1+r)^{t}[/tex]
In which B(t) is the population of butterflies after t years, B(0) is the initial population and r is the growth rate, as a decimal.
We have:
[tex]B(t)=137(1.085)^{t}[/tex]
Comparing to the general equation, we have that:
[tex]B(0) = 137, 1 + r = 1.085[/tex]
Growh rate:
1 + r = 1.085
r = 1.085 - 1
r = 0.085
The growth rate is of 0.085 = 8.5% a year.
What number must you add to complete the square? x^2+6x=15 A.6 B.12 C.9 D.3
Answer:
C. 9
Step-by-step explanation:
To find the number we add to complete the square, we do (b/2)², or take b (which is 6), divide by 2 (which gives us 3), then square the result (which gives us 9):
6/2 = 3
3² = 9
Answer: 9
Step-by-step explanation: To complete the square, we need a number to create a perfect square trinomial on the left side of the equation.
So the question is, what is that number?
Well it comes from a formula.
The number that we will need to complete the square will always
come from half the coefficient of the middle term squared.
In this case, that's half of 6 which is 3, squared, which is 9.
So we add 9 to both sides of the equation.
This will now allow the left side of the equation to factor.
A 24 inch wire is cut in two and shaped into a square and a regular octagon . What is the minimum possible sum of the two areas?
Answer:
A(t) = 41,47 in²
Step-by-step explanation:
Let´s call "x" the cut of point to get to pieces of wire, we make a square from x and the regular octagon will be shaped with 24-x
Then Area of the square A(s) = x²
Area of the octagon is A(o) = 1/2*p*length of apothem (d)
p = ( 24 - x )
length of apothem (d) :
The side of the octagon is equal to ( 24 - x ) / 8 half the side is
( 24 - x ) / 16
tan α = ( 24- x ) 16 / d since ∡s in octagon are 360 / 8 = 45°
α ( ∡ between apothem and one of the interiors ∡ of the octagon )half of 45 is α = 22,5°
tanα = 0,41
d = (24 - x ) / 16*0,41 d = ( 24 - x ) / 6,56
Then
A(t) = A(s) + A(o)
A(t) = x² + (1/2)* ( 24 - x ) ( 24 - x ) / 6,56
Note A(t) = A(x)
A(x) = x² + (1/2) * (24 - x )²/ 6,56
A(x) = x² + ( 1/ 2*6,56) * ( (24)² -48*x + x² )
Taking derivatives on both sides of the equation
A´(x) = 2*x + ( 1/13,12)* ( - 48 + 2x )
A´(x) = 2*x - 48/ 13,12 + 2*x
A´(x) = 4*x - 3,66
A´(x) = 0 4x = 3,66 x = 0,91 in and d =( 24 - x ) / 6,56
d = ( 24 - 0,91 ) / 6,56 d = 3,52
Then A(s) = (0,91)² A(s) = 0,83 in²
A(o) = 1/2 * ( 24 - 0,91 )* 3,52
A(o) = 40,63 in²
A(t) = 40,63 + 0,83
A(t) = 41,47 in²
here is the picture pls answer another for my lil friend lol
Answer:
Hey there!
The perimeter can be expressed as 140+140+68[tex]\pi[/tex]
This is equal to 493.52 m
Hope this helps :)
Sam invest $4000 in an account that compounds interest continuously and earns 5.5% how long will it take for his money to reach $80,000 round to the nearest 10th of a year
Answer:
54.5 years.
Step-by-step explanation:
From the above question, we are asked to find the time
The formula for Time(t) =
t = log(A/P) / n[log(1 + r/n)]
A = Amount accumulated after a particular interest and period of time = $80,000
P = Principal (Money invested) = $4,000
r = rate = 5.5% = 0.055
n = compounding frequency = compounding continuously
n = number of days in a year × number of hours in a day
= 365 days × 24 hours = 8760
t = log(A/P) / n[log(1 + r/n)]
t = log(80,000/4,000) /8760[log(1 + 0.055/8760)]
t = log(80000 ÷ 4000) ÷ (8760 × [log(1 + 0.0000062785)]
t = 54.468367222 years
Approximately to the nearest tenth of a year, therefore, the length of time it will it take for his money to reach $80,000 is 54.5 years
Answer:
54.5
Step-by-step explanation:
Which set of integers does NOT represent the lengths of the sides of a triangle? A. {6,6,11} B. {9,10,11} C. {4,8,12} D. {4,7,9}
Answer:
C
Step-by-step explanation:
I suppose you have learned that for the sides of a triangle to work, it has to be a + b > c, the 4 is the a, the 8 is the b, the 12 is the c.
So: 4 + 8 > 12; however this is not true, they are equal so the triangle wont be a triangle, it would be lines that never connect.
Daddy's annual salary is $42603.00. If he gets the same salary
each month and a monthly travelling allowance of $1250.00,
what is his monthly earning?
Answer:
$4800.25
Step-by-step explanation:
$42603 is a yearly salary.
There are 12 months in 1 year.
Monthly salary:
$42603/12 = $3550.25
Monthly travelling allowance: $1250
Total amount earned in 1 month:
$3550.25 + $1250 = $4800.25
Simplify and leave in radical form.
Answer:
[tex]\sqrt[4]{xy^3}[/tex].
Step-by-step explanation:
[tex]\sqrt[8]{x^2y^6}[/tex]
= [tex]x^{\frac{2}{8} } y^{\frac{6}{8}}[/tex]
= [tex]x^{\frac{1}{4} } y^{\frac{3}{4}}[/tex]
= [tex]\sqrt[4]{xy^3}[/tex].
Hope this helps!
Use a power reduction identity to simplify 8cos4 x .
Answer:
[tex]8cos^4}x = (3 + 4cos2x + cos4x)[/tex]
Step-by-step explanation:
Using the power reduction identity, we have that:
[tex]cos^{2}x = \frac{1}{2}(1 + cos2x)\\ \\cos^{4}x = (cos^{2}x)^2 = (\frac{1}{2}(1 + cos2x))^2\\\\cos^{4}x = \frac{1}{4} (1 + 2cos2x + cos^{2}2x)\\[/tex]
From the first line:
[tex]cos^{2}2x = \frac{1}{2}(1 + cos4x)[/tex]
Therefore:
[tex]cos^{4}x = \frac{1}{4} (1 + 2cos2x + \frac{1}{2}(1 + cos4x))\\\\cos^4}x = \frac{1}{4} (1 + 2cos2x + \frac{1}{2} + \frac{1}{2} cos4x)\\\\cos^4}x = \frac{1}{4} (\frac{3}{2} + 2cos2x + \frac{1}{2} cos4x)\\\\=> 8cos^4}x = 8 * \frac{1}{4} (\frac{3}{2} + 2cos2x + \frac{1}{2} cos4x)\\\\8cos^4}x = 2 * (\frac{3}{2} + 2cos2x + \frac{1}{2} cos4x)\\\\8cos^4}x = (3 + 4cos2x + cos4x)[/tex]
Answer:
Step-by-step explanation:
A parallelogram has side lengths of 13 and 17 and an
angle that measures 64º.
What is x, the length of the diagonal, to the nearest
whole number?
Answer:
[tex] x = 16 [/tex]
Step-by-step explanation:
x = length of diagonal, can be calculated using the Law of Cosines as explained below:
a² = b² + c² - 2bc(cosA),
Where,
a = x
b = 17
c = 13
A = 64°
Plug in the values into the formula:
[tex] x^2 = 17^2 + 13^2 - 2(17)(13)*cos(64) [/tex]
[tex] x^2 = 289 + 169 - 442*0.4384 [/tex]
[tex] x^2 = 458 - 193.77 [/tex]
[tex] x^2 = 264.23 [/tex]
[tex] x = \sqrt{264.23} [/tex]
[tex] x = 16.255 [/tex]
Length of diagonal, [tex] x = 16 [/tex] (to nearest whole number)
The automatic opening device of a military cargo parachute has been designed to open when the parachute is 155 m above the ground. Suppose opening altitude actually has a normal distribution with mean value 155 and standard deviation 30 m. Equipment damage will occur if the parachute opens at an altitude of less than 100 m. What is the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes
Answer:
the probability that one parachute of the five parachute is damaged is 0.156
Step-by-step explanation:
From the given information;
Let consider X to be the altitude above the ground that a parachute opens
Then; we can posit that the probability that the parachute is damaged is:
P(X ≤ 100 )
Given that the population mean μ = 155
the standard deviation σ = 30
Then;
[tex]P(X \leq 100 ) = ( \dfrac{X- \mu}{\sigma} \leq \dfrac{100- \mu}{\sigma})[/tex]
[tex]P(X \leq 100 ) = ( \dfrac{X- 155}{30} \leq \dfrac{100- 155}{30})[/tex]
[tex]P(X \leq 100 ) = (Z \leq \dfrac{- 55}{30})[/tex]
[tex]P(X \leq 100 ) = (Z \leq -1.8333)[/tex]
[tex]P(X \leq 100 ) = \Phi( -1.8333)[/tex]
From standard normal tables
[tex]P(X \leq 100 ) = 0.0334[/tex]
Hence; the probability of the given parachute damaged is 0.0334
Let consider Q to be the dropped parachute
Given that the number of parachute be n= 5
The probability that the parachute opens in each trail be p = 0.0334
Now; the random variable Q follows the binomial distribution with parameters n= 5 and p = 0.0334
The probability mass function is:
Q [tex]\sim[/tex] B(5, 0.0334)
Similarly; the event that one parachute is damaged is :
Q ≥ 1
P( Q ≥ 1 ) = 1 - P( Q < 1 )
P( Q ≥ 1 ) = 1 - P( Y = 0 )
P( Q ≥ 1 ) = 1 - b(0;5; 0.0334 )
P( Q ≥ 1 ) = [tex]1 -(^5_0)* (0.0334)^0*(1-0.0334)^5[/tex]
P( Q ≥ 1 ) = [tex]1 -( \dfrac{5!}{(5-0)!}) * (0.0334)^0*(1-0.0334)^5[/tex]
P( Q ≥ 1 ) = 1 - 0.8437891838
P( Q ≥ 1 ) = 0.1562108162
P( Q ≥ 1 ) [tex]\approx[/tex] 0.156
Therefore; the probability that one parachute of the five parachute is damaged is 0.156
The graph of a linear function is given below. What is the zero of the function?
Answer:
Option (D)
Step-by-step explanation:
Zero of any function is defined by the x-value of the function when y = 0.
Let the equation of the line given in the graph is,
y = mx + b
where m = slope of the line
b = y-intercept of the line
Slope of a line passing through [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is defined by the formula,
m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
If the passes through (0, -3) and (-2, 0)
m = [tex]\frac{-3-0}{0+2}[/tex]
m = [tex]-\frac{3}{2}[/tex]
Fro the graph,
y-intercept 'b' = -3
Therefore, equation of the line is,
[tex]y=-\frac{3}{2}x-3[/tex]
For y = 0,
[tex]0=-\frac{3}{2}x-3[/tex]
[tex]\frac{3}{2}x=-3[/tex]
x = -2
Therefore, option (D) will be the answer.
Answer:
d- -2
Step-by-step explanation:
In the figure, ∆BAT ≅ ∆CAT. Which statement is not true by CPCTC? ∠CAB ≅ ∠SAB ∠CAS ≅ ∠BAS
Answer:
∠CAB ≅ ∠SAB is not true
Step-by-step explanation:
CPCTC means id ABC = XYZ, than A=X, AB=XY, C=Z and so on. Basically the number numbers that come in the same order as the other one is equal.
So ∠CAS ≅ ∠BAS is true but ∠CAB ≅ ∠SAB is not.
Hope this helps. If you have any follow-up questions, feel free to ask.
Have a great day! :)
Answer:
sap
Step-by-step explanation:
If f(x)=x-9 and g(x)=-6x-3 which statement is true
Answer:
-1 is not in the domain of (f o g)(x)
Step-by-step explanation:
f(x) = sqrt(x - 9)
g(x) = -6x - 3
(f o g)(x) = f(g(x)) = sqrt(g(x) - 9)
(f o g)(x) = sqrt(-6x - 3 - 9)
(f o g)(x) = sqrt(-6x - 12)
Let x = -1:
(f o g)(-1) = sqrt(-6(-1) - 12)
(f o g)(-1) = sqrt(6 - 12)
(f o g)(-1) = sqrt(-6)
Since sqrt(-6) is not a real number, -1 is not in the domain of (f o g)(x).
Please help! I’ll mark you as brainliest if correct
Answer:
You need to add 150 mL of 65% alcohol solution.
Step-by-step explanation:
You have 300 mL of 20% solution.
300 mL of 20% alcohol solution has 20% * 300 mL of alcohol.
You have 65% solution.
Let the volume of 65% solution you add be x.
In 65% solution, 65% of the volume is alcohol, so the amount of alcohol in x amount of 65% solution is 65% * x.
You want 35% solution.
The total amount of 35% solution you will make is 300 mL + x. The amount of alcohol in that amount of solution is 35% * (x + 300).
Equation of alcohol content:
20% * 300 + 65% * x = 35% * (x + 300)
60 + 0.65x = 0.35x + 105
0.3x = 45
x = 150
Answer: You need to add 150 mL of 65% alcohol solution.
The attendance for a week at a local theatre is normally distributed, with a mean of 4000 and a standard deviation of 500. What percentage of the attendance figures would be less than 3500? What percentage of the attendance figures would be greater than 5000? what percentage of the attendance figures would be between 3700 and 4300 each week?
ok its 45.15% trust me
Answer:
Step-by-step explanation:
This curve alone does not give exact percentages with the exception of P(z=0) = .50 or 50%
A Pictorial where 'some' of the % have been added for helps more...
However, most often one needs to use a table, calculator, or an Excel function ect to find exact Percentage,
P(x > 4000) = P(z = 0) = .50 or 50 % |using above pictorial
Using Calculator etc: Here, am using the Excel NORMSDIST function to find the Percentages:
P(z=3/5 - z=-3/5) = .7257 - .2742 =.4515 or 45.15%
Which system of equations represent the matrix shown below?
1 2 -1| 8
-1 0 3| 15
1 -2 4| 18
A. x + 2y + z =8
x + y + 3z =15
x + 2y + 4z =18
B. x + 2y + z =8
x + 3z =15
x + 2y + 4z =18
C. x + 2y - z =8
-x + y + 3z =15
x - 2y + 4z =18
D. x + 2y - z =8
-x + 3z =15
x - 2y + 4z =18
Answer:
the solution to the problem is D
I have a total of 10 gigabytes of data on my computer, x gigabytes are movies, pictures take up half the amount of space that movies do and the rest is music. How many gigabytes of music is stored on my computer?
Answer:
Movies: x gig
pictures: x/2 gig
music: 10 - x - x/2 = 10 - (3/2)x
The amount of gigabytes of music stored on the computer is:
[tex]y = 5 - x[/tex]
In which x is the amount stored in movies.
We solve this question representing the amount of music as a variable, that I will call y.
The total amount of data is 10 gigabytes.
Division of the 10 gigabytes:
Half in pictures, that is, 10/2 = 5 gigabytes.
x are movies.
The rest, y, are music.
Thus, since the sum of this all is 10, we have that:
[tex]5 + x + y = 10[/tex]
[tex]y = 10 - 5 - x[/tex]
[tex]y = 5 - x[/tex]
Thus, the amount of gigabytes of music stored on the computer is [tex]y = 5 - x[/tex], considering x as the amount of gigabytes of movies stored.
A similar question is found at https://brainly.com/question/22789267
there are three oranges in 200g of bag . if the weight of them with bag is 1.4kg. find the weight of an orange.i want full methods
the bag is 200g
total weight with oranges is 1400g
deduct the bags weight from total weight
1400 - 200
1200g
this is the weight of the three oranges
so each orange would be
1200 ÷ 3
400g
Let a and b be real numbers where a=/b=/c=/0 which of the following functions could represent the graph below?
Answer: The second option; y = (x - a)^2*(x-b)^4
Step-by-step explanation:
Ok, we have that a and b are real numbers different than zero.
In the graph, we can see that the line touches the x-axis in two values. Now, if we would have an equation like:
y = x*(x - a)^3*(x - b)^3
then when x = 0 we would have:
y = 0*(0-a)^3*(0-b)^3 = 0
But in the graph, we can see that when x = 0, the value of y is different than zero, so we can discard options 1 and 3.
So the remaining options are:
y = (x - a)^2*(x-b)^4
y = (x - a)^5*(x - b)
Now, another thing you can see in the graph is that it is always positive.
Particularly the second option allows negative values for y because it has odd powers, then we can also discard this option.
(For example, if x > a and x < b we would have a negative value for y)
Then the only remaining option is y = (x - a)^2*(x-b)^4
Answer:
B.y = (x - a)^2*(x-b)^4
Step-by-step explanation:
EDGE 2020 Brainliest please
Safegate Foods, Inc., is redesigning the checkout lanes in its supermarkets throughout the country and is considering two designs. Tests on customer checkout times conducted at two stores where the two new systems have been installed result in the following summary of the data.
System System B
n1=120 n2=100
x1=4.1 minutes x2=3.4 minutes
σ1=2.2minutes σ2= 1.5 minutes
Test at the 0.05 level of significance to determinewhether the population mean checkout times of the two newsystems differ. Which system is preferred?
Answer:
We conclude that the population means checkout times of the two new systems differ.
Step-by-step explanation:
We are given the result in the following summary of the data;
System System B
n1=120 n2=100
x1=4.1 min x2=3.4 min
σ1=2.2 min σ2= 1.5 min
Let [tex]\mu_1[/tex] = population mean checkout time of the first new system
[tex]\mu_2[/tex] = population mean checkout time of the second new system
So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu_1=\mu_2[/tex] {means that the population mean checkout times of the two new systems are equal}
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu_1\neq \mu_2[/tex] {means that the population mean checkout times of the two new systems differ}
The test statistics that will be used here is Two-sample z-test statistics because we know about population standard deviations;
T.S. = [tex]\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{\sqrt{\frac{\sigma_1^{2} }{n_1} + \frac{\sigma_2^{2} }{n_2}} }[/tex] ~ N(0,1)
where, [tex]\bar X_1[/tex] = sample mean checkout time of the first new systems = 4.1 min
[tex]\bar X_2[/tex] = sample mean checkout time of the second new systems = 3.4 min
[tex]\sigma_1[/tex] = population standard deviation of the first new systems = 2.2 min
[tex]\sigma_2[/tex] = population standard deviation of the second new systems = 1.5 min
[tex]n_1[/tex] = sample of the first new systems = 120
[tex]n_2[/tex] = sample of the second new systems = 100
So, the test statistics = [tex]\frac{(4.1-3.4)-(0)}{\sqrt{\frac{2.2^{2} }{120} + \frac{1.5^{2} }{100}} }[/tex]
= 2.792
The value of z-test statistics is 2.792.
Now, at 0.05 level of significance, the z table gives a critical value of -1.96 and 1.96 for the two-tailed test.
Since the value of our test statistics does not lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.
Therefore, we conclude that the population mean checkout times of the two new systems differ.
A new furnace for your small factory will cost $29,000 and a year to install, will require ongoing maintenance expenditures of $1,200 a year. But it is far more fuel-efficient than your old furnace and will reduce your consumption of heating oil by 2,800 gallons per year. Heating oil this year will cost $2 a gallon; the price per gallon is expected to increase by $0.50 a year for the next 3 years and then to stabilize for the foreseeable future. The furnace will last for 20 years, at which point it will need to be replaced and will have no salvage value. The discount rate is 6%.
Answer:
Net present value is $61,058.
Step-by-step explanation:
Net present value is the difference between present value of cash inflows and the present value cash outflows over the period of time. NPV method is used in capital budgeting to analyze profitability of the project.
Less: initial cost is $29,000
Add: Year 1: Cost saving due to new furnace is $5,600 (2,800 oil gallons * $ 2 per gallon)
Year 2: Cost saving due to new furnace is $7,000 (2,800 oil gallons * $ 2.50 per gallon)
Year 3- 20: Cost saving due to new furnace is $8,400 (2,800 oil gallons * $ 3 per gallon)
Less : Maintenance expenditure is $1,200
The furnace will benefit for 20 years and the price per gallon will increase by $0.50 year.
The annuity factor is applied at discount factor of 6% and then present value of each cash inflow and outflow is calculated. The net present value is $61,058.
Help me fast please
give the coordinates of the
foci,vertices,and convertices of the ellipse with equation x²/169 + y²/25 = 1
Answer:
We can see that for this case the vertex is [tex] V= (0,0)[/tex]
The values for a and b are:
[tex] a = \sqrt{169}=13, b= \sqrt{25}=1[/tex]
Then the ellipse have the major axis on x.
In order to find the two foci we need to use the following formula:
[tex] c =\sqrt{a^2 -b^2}[/tex]
And replacing we got:
[tex] c =\sqrt{169-25}= \pm 12[/tex]
And then the two foci are (12,0) and (-12,0)
And the covertex are on this case (-13,0) (13,0) and (0,5) (0,-5) on the y axis
Step-by-step explanation:
For this problem we have the following equation given:
[tex]\frac{x^2}{169} + \frac{y^2}{25}= 1[/tex]
If we compare this with the general expression of an ellipse given by:
[tex] \frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}= 1[/tex]
We can see that for this case the vertex is [tex] V= (0,0)[/tex]
The values for a and b are:
[tex] a = \sqrt{169}=13, b= \sqrt{25}=1[/tex]
Then the ellipse have the major axis on x.
In order to find the two foci we need to use the following formula:
[tex] c =\sqrt{a^2 -b^2}[/tex]
And replacing we got:
[tex] c =\sqrt{169-25}= \pm 12[/tex]
And then the two foci are (12,0) and (-12,0)
And the covertex are on this case (-13,0) (13,0) and (0,5) (0,-5) on the y axis
expand(x+y2)2 plzzzzzzzzzzzzzzzz
Answer:
[tex](x + {y}^{2}) = {x}^{2} + 2x {y}^{2} + {y}^{4} [/tex]
Hope it helps!!❤❤Please mark me as the brainliest!!!Thanks!!!!
An article in Fire Technology, 2014 (50.3) studied the effectiveness of sprinklers in fire control by the number of sprinklers that activate correctly. The researchers estimate the probability of a sprinkler to activate correctly to be 0.7. Suppose that you are an inspector hired to write a safety report for a large ballroom with 10 sprinklers. Assume the sprinklers activate correctly or not independently. (a) What is the probability that all of the sprinklers will operate correctly in a fire
Answer:
probability that all of the sprinklers will operate correctly in a fire: 0.0282
Step-by-step explanation:
In order to solve this question we will use Binomial probability distribution because:
In the question it is given that the sprinklers activate correctly or not independently. The number of outcomes are two i.e. sprinklers activate correctly or not.A binomial distribution is a probability of a success or failures outcomes in an repeated multiple or n times.
Number of outcomes of this distributions are two.
The formula is:
b(x; n, P) = [tex]C_{n,x}*p^{x} * (1 - p)^{n-x}[/tex]
b = binomial probability also represented as P(X=x)
x =no of successes
P = probability of a success on a single trial
n = no of trials
[tex]C_{n,x}[/tex] is calculated as:
[tex]C_{n,x}[/tex] = n! / x!(n – x)!
= 10! / 10!(10-10)!
= 1
According to given question:
probability of success i.e. p = 0.7 i.e. probability of a sprinkler to activate correctly.
number of trials i.e. n = 10 as number of sprinklers are 10
To find: probability that all of the sprinklers will operate correctly in a fire
X = 10 because we have to find the probability that "all" of the sprinklers will operate correctly and there are 10 sprinklers so all 10 of them
So putting these into the formula:
P(X=x) = [tex]C_{n,x}*p^{x} * (1 - p)^{n-x}[/tex]
= C₁₀,₁₀ * 0.7¹⁰ * (1-0.7)¹⁰⁻¹⁰
= 1 * 0.0282 * (0.3) ⁰
= 1 * 0.0282 * 1
P(X=x) = 0.0282
Victor is in the 28% tax bracket.
a. How much will a $900 tax credit save him?
b. how much will a $900 charitable contribution save him if he itemized his deductions?
Incomplete question. I've made some assumptions to provide clarity.
Answer:
a. $45,743.07
b. $44,843.07
Step-by-step explanation:
Let's assume Victor is a single filer with an income of $100,000.
Using the 2017 tax bracket rates for single filers, Victor would be expected to pay:
- 10 percent on the first $9,325 = 10% x 9525 =$932.5
- plus 15 percent of the amount between $9,326 and $37,950 (37950-9326) x 15% = $4293.6
- plus 25 percent of the amount between $37,951 and $91,900 (91900-37,951 ) x25% = $13487.25
- plus 28 percent of the amount over $91,901-$191,650 (191650-91901) x 28% = 27929.72
Total= $46,643.07
Minus $900 tax credit= $46,643.07-$900= $45,743.07
Minus $900 charitable contribution = $45,743.07-$900= $44,843.07
Suppose that 10 fair coins are tossed. Find the numbers of ways of obtaining exactly 1 heads. Round the answer to the nearest whole number
Answer: 10
Step-by-step explanation:
Given : Total number of coins tossed = 10
Possible outcomes to toss a coin = Head or tail
Number of possible outcomes = [tex]2^{10}=1024[/tex]
Number of ways of obtaining exactly 1 heads = [tex]{10}C_1=\dfrac{10!}{1!9!}[/tex] [using combinations [tex]^nC_r=\dfrac{n!}{r!(n-r)!}[/tex] ]
=10
Hence, the numbers of ways of obtaining exactly 1 heads= 10
solve the nonlinear system of equations. State the number of solutions.
Answer:
Step-by-step explanation:
Hello,
Question 15
We can search x such that:
[tex]x^2-4x+4=2x-5\\\\\text{*** subtract 2x-5 from both sides ***}\\ \\x^2-4x-2x+4+5=0\\ \\\text{*** simplify ***}\\ \\x^2-6x+9=0 \\ \\\text{*** we can notice a perfect square ***}\\ \\x^2 -2\cdot x \cdot 3 + 3^2=(x-3)^2=0\\\\\text{*** taking the root ***}\\\\x-3=0\\\\\large \boxed{\sf \ \ x=3 \ \ }[/tex]
There is 1 solution.
Question 16
Again, we search x such that:
[tex]x^2-8x+15=2x-6\\\\\text{*** subtract 2x-6 from both sides ***}\\\\x^2-8x-2x+15+6=0\\\\\text{*** simplify ***}\\\\x^2-10x+21=0 \\ \\\text{*** we are looking for two roots where the sum is 10 and the product is 21 = 7 x 3 ***} \\\\x^2-7x-3x+21=x(x-7)-3(x-7)=(x-3)(x-7)=0\\\\\large \boxed{\sf \ \ x= 3 \ or \ x =7 \ \ }[/tex]There are two solutions.
Hope this helps.
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Thank you