10. The Earth's radius is about 6370 km. An object that has a mass of 20 kg is taken to a
height of 160 km above the Earth's surface. How much does the object weigh at this
height?

Answer: 0.2 m/s²

Explanation:

Acceleration= (20-14)/30 = 0.2 m/s²

Oxygen deficiency in closed spaces may not be noticeable, but this does not mean that it is not dangerous.

If we are locked up in a classroom with our classmates, then the reduction in oxygen levels in the classroom could be due to the continues respiration process being performed by all the living beings present in the classroom.

The very first thing we will do is to knock on the door—and knock hard—and will ask, “Is anyone there?" until we get a response from outside.

Also we can check for the window in the room, if it exists, then by breaking it from inside we can brake out of the room.

Also it is very important to stay calm and avoid freaking out on that occasion.

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Answer:

The solar potential in Nepal is 50,000 terawatt-hours per year, which is 100 times larger than Nepal's hydro resource and 7,000 times larger than Nepal's current electricity consumption. Solar can easily meet all future energy needs in Nepal. Solar energy is cheaper than fossil fuels, nuclear and hydro.

The time taken is 369.23 s

Length is measured in distance. For instance, the length of a road is its distance. The most popular units of measurement for distance in the metric system are millimeters, centimeters, meters, and kilometers.

First, the train travels 2.1 kilometers.

then travels for 400 seconds at a steady speed of 24 m/s

Distance = V x t = 24 x 400 = 9600m, or 9.6 km.

then it decreases in speed from 24 m/s to 0

hence it requires

Vf- V0=at

0-24=-0.065 xt => t=369.23 s

that indicates that it will endure for

Distance = V0t+1/2 gt2 = 24 x 369.23 - 1/2 (0.065 x 369.23) = 8849.52m, or 8.8km

2.1 + 9.6 + 8.8 = 20.5 kilometers.

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Answer:

108 km/hr = 1.8 km/min

90 km/hr = 1.5 km/min

V1 = (-39.6, 0)

V2 = (-10.6, -10.6)         (10.6^2 + 10.6^2)^1/2 = 15    1.5 km/min * 10 min

V = (-50.2, -10.6)       final displacement vector

Total time = 22 + 10 = 32 min

S = (50.2^2 + 10.6^2)^1/2 = 51.3 km

Average speed = (1.8 * 22 + 1.5 * 10) / 32 = 1.71 km / min

Displacement = 51.3 km

Average velocity = 51.3 / 32 = 1.60 km/min

Direction = 10.6 / 50.2 = .211 or 11.9 deg S of W

The correct responses are;

1) No the density of an object is not always the same as its mass

2) The density of an object is calculated from mass/volume

3) After completing the liquids portion of the lab, oil has the lest density

4) It is a false statement that the density of the liquids depends on the order in which they are added to the column.

5) The golf ball has a greater density than the ping pong ball

The term density refers to the mass per unit volume of an object. This implies that if measure the mass of the object and divide this value by the volume of the object then we obtain the density of the object. The density is an empirical property hence it does not change.

Let us now answer the questions individually;

1) No the density of an object is not always the same as its mass

2) The density of an object is calculated from mass/volume

3) After completing the liquids portion of the lab, oil has the lest density

4) It is a false statement that the density of the liquids depends on the order in which they are added to the column.

5) The golf ball has a greater density than the ping pong ball

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Answer:

See below

Explanation:

The forces are equal but opposite directions

the velocities of the two differ because of the different masses of the two objects....the bullet is light compared to the rifle/shooter.

I would not want to fire a heavy projectile...the 'kick' or 'recoil' of the rifle would be quite large.....and painful!

Answer: 1.2 mm

Explanation:

Time= 140 sec

Initial Velocity= 0

Average Velocity= 2.4 mm/s

Displacement=  0.5* (2.4/140) *140 = 1.2 mm

Answer:

(i) A body has a uniform acceleration if its velocity changes by equal amounts in equal intervals of time. The motion of a freely falling body is an example of uniform acceleraion.

(ii) A body has a non-uniform acceleration if its velocity changes by unequal intervals of time. The motion of a car on a crowded city road is an example of non-uniform acceleration.

Answer:

22m/s

Explanation:

This is a vector addition problem. First identify the two vectors: 20m/s in the -x direction and 9m/s in the -y direction. Since neither vector shares an axis component you can use the formula [tex]\sqrt{20^2+9^2\\[/tex] =21.93 (This is the Pythagorean Theorem where your non-hypotenuse sides are your velocity vectors). Round to 2 significant figures and you'll get 22m/s.

When body is changing its velocity at a constant rate then the body is said to be in uniform acceleration.

When a body is changing its velocity at different rates than my body is said to be moving with non uniform acceleration.

acceleration - The rate of change of velocity with respect to time.

It is a vector quantity.

a = dv / dt

SI unit is m/s²

direction of acceleration is the direction of change in velocity.

types of acceleration

When body is changing its velocity at a constant rate then the body is said to be in uniform acceleration.

When a body is changing its velocity at different rates than my body is said to be moving with non uniform acceleration.

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E=15.23

Given:

Q=−3.350 nC

Position 1=0.00 m

Position 2=1.1600 m,

Second charge and location is 4.600 nC and is located at 2=1.100 m, 2=0.600

Formula :

E=kq/r^2

E=9×10^9×3.350×4.600/2^2=15.23 N/C

When charge is present in any form, an electric field is linked with each point in space. The value of E, also known as electric field strength, electric field intensity, or simply the electric field, expresses the magnitude and direction of the electric field. Knowing the value of the electric field at a place, without knowing what caused the field, is all that is required to predict what will happen to electric charges near that point.

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The name of the ionic compounds are

Ionic compounds that has only two types of elements are named by mentioning cation first followed by the anion name.

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Compost briquettes decrease deforestation because they are less expensive than traditionally created charcoal made from wood.

A compressed block of flammable material, such as charcoal, sawdust, wood chips, peat, or paper, is called a briquette (sometimes written briquet) and is used as both fuel and kindling to start a fire.

Briquettes are similar to fast food in that they are readily available, inexpensive, and trustworthy; however, you really don't want to know what is in them.

Briquettes, as opposed to pure lump charcoal, are manufactured wood by-products that have been compacted with additives to make them easier to light and maintain a constant burn.

Therefore, The emission of extra greenhouse gases that contribute to climate change is prevented by the compost briquettes' increased efficiency and cleaner burning.

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Point Z produces is the strongest electric field.

A notion that gives a "map" of electric field lines was put out by Michael Faraday. The lines of the electric field are also known as lines of force since the electric field is the electric force per unit charge. The distribution of electric field lines also reveals the size or strength of the field. Lines are more closely spaced, therefore the electric field is stronger.

The lines are more dispersed at greater separations when the electric field is weaker. In general, it is true that areas with tighter field lines have a greater electric field. The number of lines per unit area traveling perpendicularly through a surface is proportional to the strength of the electric field regardless of the number of charges present.

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Joe travels 28 kilometers in the direction of +x before travelling 14 metres at an angle of 25° above the +x axis.

Joe moves 6 m backwards throughout the entire excursion.

The parameters are as follows: Joe's initial location is x1 = 8 m, and his ultimate position is x2 = 2 m.

The alteration of an object's location is known as displacement. The shortest distance between the final location and the starting position is another way to express it.

Movement = x = x2 - x1

Make the forward motion negative.

Make the reverse direction positive.

Relocation = -2 - (-8)

Position = -2 + 8

displacement = 6 m in the reverse

Therefore, Joe moves 6 m backwards over the entire excursion.

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Sound cannot travel through a vacuum because there are no particles to carry the vibrations.

Explanation:

When travelling through air, the speed of sound is about 330 metres per second (m/s).

Answer:

what is the best result of

Answer:

Vectors A and C are equal

Explanation:

If we have a certain vector [tex]\displaystyle \overrightarrow{A}[/tex], the components of the vector [tex]\displaystyle \mathrm {A_x\;and\;A_y}[/tex] are  given by:
[tex]A_x = Acos\theta\\A_y=Asin\theta[/tex]

where
[tex]\textrm {$\theta$ is the angle formed by the vector on the x-axis}[/tex]

For vector A, we have Ax = 80m and Ay=60m

For vector C we have
Cx = |C| cosθ = 100 cos(36.9) ≈ 100 x 0.8 = 80m
Cy = |C| sinθ = C sin(36.9) ≈ 100 x 0.6 = 60m

So A and C are equal

We can eliminate B since Bx = 60 and Ax=80 so they cannot be equal

The orbital speed of the proton is 4.7 x 10⁶ m/s.

The orbital speed of the proton is calculated by applying the following equations as shown below.

Centripetal force of the proton = magnetic force of the proton

Fc = qVB

mv²/r = qvB

mv² = qvBr

v² = qvBr/m

v = qBr/m

where;

The orbital speed of the proton is calculated as follows;

v = (1.6 x 10⁻¹⁹ x 0.35 x 0.14) / (1.67 x 10⁻²⁷)

v = 4.7 x 10⁶ m/s

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The acceleration of the runner 10 sec later will be 0.08 meters per second square (m/s²).

Average acceleration is defined as the average rate of change of velocity with time. Mathematically -

a = Δv/Δt

Given is a runner sprinting at 3 m/s and after 10 s the same runner is sprinting at 3.8 m/s. Therefore, we can write -

Initial velocity [u] = 3 m/s

Final velocity [v] = 3.8 m/s

time taken [Δt] = 10 s

The average acceleration of the sprinter can be calculated as follows -

a = Δv/Δt

Δv = v - u

Δv = 3.8 - 3 = 0.8 m/s

Δt = 10 s

Therefore -

a = 0.8/10 = 0.08 m/s².

Therefore, the acceleration of the runner 10 sec later will be 0.08 meters per second square (m/s²).

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Answer:

200N in Player 1's direction

Player 2 is knocked back

Explanation:

Let's start by working out the force exerted by each player by using the equation F=ma, Force = Mass x Acceleration.

Player 1 has an acceleration of 4m/s2 and a mass of 150kg, therefore their force will be: [tex]F = (150)(4)[/tex], [tex]F=600N[/tex]

Player 2 has an acceleration of 2m/s2 and a mass of 200kg, therefore their force will be: [tex]F = (200)(2)[/tex], [tex]F=400N[/tex]

They are both coming from different directions so we can find the net force by subtracting one from the other: [tex]600-400=200N[/tex]

Player 1 has the higher force so the net force will be 200N in the direction Player 1 is travelling in and Player 2 will be the one knocked back.

Hope this helped!

Answer:

[tex]1:1[/tex]

Explanation:

Given:-

To find:-

Answer:-

The nuclear densities for all atoms is same and it doesn't depends on mass number.

So the ratio of the nuclear densities will be 1:1 .

[tex]\implies \underline{\underline{\green{ \rm Ratio= 1:1}}}[/tex]

_________________________________________

Additional information:-

Here I would be providing you the proof for the same .

Firstly we know that the volume of nucleus is directly proportional to its mass number ( Why ? because as the mass number increases , nucleons increases so volume increases) . Therefore;

[tex]\implies V = \dfrac{4}{3}\pi r^3 \\[/tex]

And ,

[tex]\implies V \propto A \\[/tex]

So ,

[tex]\implies \dfrac{4}{3}\pi r^3 \propto A \\[/tex]

[tex]\implies r^3 \propto A \\[/tex]

[tex]\implies r\propto A^{\dfrac{1}{3}} \\[/tex]

[tex]\implies r = r_0 A^{\dfrac{1}{3}} \dots\rm{(1)} \\[/tex]

where,

Now in order to find out the nuclear density , say [tex]\rho[/tex] ; we have ;

[tex]\implies \rho =\dfrac{Mass_{\rm nucleus}}{Volume_{\rm nucleus}} \\[/tex]

Now let's assume that there are m nucleons and their average mass number is A . So the average mass of m nucleons would be mA .

[tex]\implies \rho = \dfrac{mA}{ \dfrac{4}{3}\pi r^3}\\[/tex]

From equation (1) , we have ;

[tex]\implies \rho = \dfrac{mA}{\dfrac{4}{3}\pi (r_0 A^{\dfrac{1}{3}})^3} \\[/tex]

[tex]\implies \rho = \dfrac{mA}{\dfrac{4}{3}\pi r_0^3 A} \\[/tex]

[tex]\implies \underline{\underline{\green{\rho = \dfrac{3m}{4\pi r_0^3}}}} \\[/tex]

Now we can see that all the terms in the RHS of the equation are constants. This implies that nuclear density is also constant for all atoms independent of their mass numbers .

And we are done!

It takes 2.7 times approximately to breath frequently on top of Mount Everest as you do at sea level.

Pressure is force per unit area. Pressure in fluid is the product of fluid density, acceleration due to gravity and the height. Pressure is measured in  N/m²

Given that the pressure at the top of Mount Everest is 0.31×105N/m2, and the temperature is −30∘C.

From Ideal gas law, PV = nRT

Where

P = 31000 N/m²

T = - 30 + 273 = 243 K

n/V =  ?

R = 8.314 1/K/Mol

n/V = P / RT

n/V = 31000 / (8.314 × 243)

n/V = 31000 / 2020.302

n/V = 15.34

When the pressure at sea level is 1.0×105N/m2, and the temperature is 20∘C, then

T = 20 + 273 = 293 K

n/V = 100000 / (8.314 × 293)

n/V = 100000 / 2436.002

n/V = 41.05

To determine how much more frequently you need to breathe on top of Mount Everest to inhale the same amount of oxygen as you do at sea level, you divide the two values. That is,

41.05 / 15.34 = 2.67

Therefore, it takes 2.7 times approximately to breath frequently on top of Mount Everest as you do at sea level.

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The Independent variable here in this sentence is the type of drink each group was subjected to intake.

Independent variable in a experiment is the one which stands independent and acts as a control which influences the experiment's outcome. Independent variables are employed in a experiment to test whether the dependent variable changes accordingly.

Here, in this experiment the dependent variable, i.e., the theory to be tested is the memory of the patients. The independent variable here is the type of juice given to the patients, which acts as a control of the experiment's outcome. Any variable which alters the final result of the experiment and which can be controlled through out the experiment is termed as Independent variable.

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Answer:

W = 15 N

Explanation:

The moments from the center mus be equal for balance to occur

 center is at 25 cm  ( for a 1/2 meter stick)

moment one :   15 cm * 20 N

moment two :   20 cm * W         these must be equal

   15 * 20 = 20 * W        W = 15 N