Answer:
soz i need points n
Step-by-step explanation:
cuz
Edulastic
Full explanation please
Will Give Brainl3$t
complementary angles have sum 90°
6x-4+x+17=907x+13=907x=77x=11m<A
6(11)-466-462°A bag contains 3 basketballs, 10 baseballs, 7 golf balls, and is chosen at random, not replaced, then another is chosen. find each probability.
The probability of picking a golfball then a basketball is 7/200
The probability of picking two baseballs is 3/20.
The probability of picking a baseball then a football is 1/12.
The probability of picking two footballs is 1/30
What is the probability?Probability is used to calculate the likelihood of an event happening. The odds the event occurs is 1 and the probability that the event does not occur is 0.
The probability of picking a golfball then a basketball = 7/25 x 3/24 = 7/200
The probability of picking two baseballs = 10/25 x 9/24 =18/120 = 3/20
The probability of picking a baseball then a football = 10/25 x 5/24 = 1/12
The probability of picking two footballs = 5/25 x 4/24 = 1/30
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A weight attached to a spring is at its lowest point, 9 inches below equilibrium, at time t = 0 seconds. when the weight it released, it oscillates and returns to its original position at t = 3 seconds. which of the following equations models the distance, d, of the weight from its equilibrium after t seconds? d = negative 9 cosine (startfraction pi over 3 endfraction t) d = negative 9 cosine (startfraction 2 pi over 3 endfraction t) d = negative 3 cosine (startfraction pi over 9 endfraction t) d = negative 3 cosine (startfraction 2 pi over 9 endfraction t)
The equation which models the distance (d) of the weight from its equilibrium after time (t) is equal to d = -9cos(2π/3)t.
What is the period of a cosine function?The period of a cosine function simply means the total length (distance) of the interval of values on the x-axis over which a graph lies and it's repeated.
Since the weight attached is at its lowest point at time (t = 0), therefore, the amplitude of equation will be negative nine (-9)
For the angular velocity at time period (t = 3s), we have:
ω = 2π/T
ω = 2π/3
Mathematically, the standard equation of a cosine function is given by:
y = Acos(ω)t
Substituting the given parameters into the formula, we have;
d = -9cos(2π/3)t.
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Answer:
B. d = -9cos ( 2 pi/3 t)
Step-by-step explanation:
Have a good day
3/4 Winston had 48 tokens to play arcade games. He used of his tokens to play 1/4 video games, and of his remaining tokens to play air hockey. How many tokens did Winston have left after playing these games?
A.9
B.36
C.12
D.25
Quadratic functions g (x) and h (2) are graphed on the same coordinate gri
The vertex of the graph of h (2) is 12 units above the vertex of the graph
of g (2).
Which pair of functions could have been used to create the graphs
The derivative of h(x) in A is 2x+24
h'(x)=0 g'(x)=0
2x+24=0 2x=0
x=-12 x=0
Similarly the derivative of h(x) in D is 2x-24
h'(x)=0 g'(x)=0
x=12 x=0
Knowing that B & C give the same x-value when solving for the derivative=0We know that the only difference comes down to the y-value when substituting x=0 in h(x).
The y-value of the vertex of h(x) must be +12 the y-value of the vertex of g(x).
We have to add 12 to get to the x-value, which means that the third option or C is your answer.
HELP!!! PLEASE!!
Given u= (5,-8) and v= (-4,7) what is v-u
(-9,15)
(9,-15)
(-1,1)
(1,-1)
Answer:
(9,-15)
Step-by-step explanation:
( 5 - (-4), -8 -7 )
( 9 , -15)
I hope my answer helps you.
Answer:
(-9,15)
Step-by-step explanation:
v-u = ((-4-5),(7-(-8)))
= (-9,(7+8))
= (-9,15)
hepppppppplppppppplppppppppp
Answer:
A = 3 ft, B = 7 ft, C = 4 ft, D = 5 ft, Surface Area = 96 ft^2
Step-by-step explanation:
Step 1: Determine the sides
A → 3 ft
B → 7 ft
C → 4 ft
D → 5 ft
Step 2: Determine the surface area
Area of the sides
[tex]A= 4\ ft * 7\ ft = 28\ ft^2[/tex]
[tex]A= 5\ ft * 7\ ft = 35\ ft^2[/tex]
[tex]A= 3\ ft * 7\ ft = 21\ ft^2[/tex]
Area of the top and bottom triangles
[tex]A= \frac{h\ *\ b}{2} = \frac{3\ ft\ *\ 4\ ft}{2} = \frac{12\ ft^2}{2} = 6\ ft^2 = 2(6\ ft^2) = 12\ ft^2[/tex]
Total Area
[tex]28\ ft^2 + 35\ ft^2 + 21\ ft^2 + 12\ ft^2[/tex]
[tex]96\ ft^2[/tex]
Answer: A = 3 ft, B = 7 ft, C = 4 ft, D = 5 ft, Surface Area = 96 ft^2
Answer:
Surface Area = 96 ft^2
Step-by-step explanation:
A = 3 ft.
B = 7 ft.
C = 4 ft.
D = 5 ft.
Surface Area:
Triangle: Area = 1/2 * Base * Height
Top Triangle: Area = 1/2 * 4 * 3 = 1/2 * 12 = 6 ft^2
Bottom Triangle: Area = 6 ft^2
Rectangle: Area = Length * Width
Left Rectangle: Area = 7 * 4 = 28 ft^2
Mid Rectangle: Area = 7 * 5 = 35 ft^2
Right Rectangle: Area = 7 * 3 = 21 ft^2
Surface Area = TopTri + BotTri + LeftRect + MidRect + RightRect
Surface Area = 6 + 6 + 28 + 35 + 21 = 96 ft^2
Mrs. Ruiz bought 5 bags of balloons for a party. Each bag contained 70 balloons. Andy said Mrs. Ruiz bought a total of 75 balloons. Andy is incorrect. What error did Andy make when calculating the total number of balloons? And What is the total number of balloons Mrs. Ruiz bought?
Answer:
Andy made the error of adding the values of the bags and the ballons, when instead they should be multiplied. The total number of baloons Mrs. Ruiz bought is 350 because 70*5 is 350. You multiple because there are five bags and in each of the five bags, there are 70 balloons.
Which function is graphed below?
fx) = -cos(x)
f(x) = cos(x)
f(x) = sin(x)
F(x)=-sin(x)
Answer:
f ( x ) = sin ( x )
Step-by-step explanation:
Answer:
that is a f(X)=sin(x) curve
Step-by-step explanation:
the curve cuts the origin as it moves upwards and has the same amplitude
Solve the following inequality
What is 1/3 as a mixed number?
1/3 is a proper fraction
hope it helps...!!!
Which of the following sets of ordered pairs does not represent a function?
A. (-6,0), (3,0), (-2,0), (0,0), (9,0)
B. (3.5,-1), (3.5,-5), (3.5,10), (3.5,0), (3.5-1.5)
C. (-9,-3),(4/5,4/5), (6/7, 2/7), (-1/4, -1/12), (1 4/5, 3/5)
Answer:
B
Step-by-step explanation:
B there is two values of y for x = 3.5 so ....not a function
pls hlpppppp!!!!!!!!!!
Step-by-step explanation:
1/100 .................
Which table represents a linear function?
Answer:
The Third table down is the answer, as it has a consistant rate of change for both X and Y
Answer:
The Answer is C.
Step-by-step explanation:
By looking at the y-axis we can see if they go up by the values by down by 8.
Pls help a b c d or e
Answer:
Answer is B.
Step-by-step explanation:
Domain: All real numbers except -6
Set denomator of x + 6 = 0
x + 6 = 0
x ≠ -6
If we plug in x = -6 into the equation we get 4/0 making it undefined. So exclude x = -6 on domain.
Range: All real numbers except 0
y ≠ 0
A school production sold 480 tickets, including 325 tickets to adults. The rest were sold to
students.
Write the ratio of adult tickets to student tickets in simplest form.
911...EMERGENCY, OVERSLEPT AND MISSED CLASS,HAVE NO IDEA WHAT I SHOULD BE DOING, CAN SOMEONE HELP ME
Answer:
Don't worry, we all over sleep sometimes. This is quiet simple. So you need to find x. 12 went from 12, to 4. So 12/_=4 The __ would be 3.
x on the other hand should be 3 as well. I could be wrong. But 12/3=4. So that'd be 12/3 Then it would be 4/3.
Step-by-step explanation:
X=3. I could be wrong.
5. Choose the correct answer.
is a price decrease from an original price of an item.
Retail
Markup
Wholesale
Markdown
Answer:
Markdown
Step-by-step explanation:
For example: the price of the shirt was $10.00 It had a markdown of 15%. This would be $8.5.
Answer:
the fourth anwser
markdown
What is the slope of the line passing through the points (0, 4) and (6, 13)
Answer:
The slope is [tex]\frac{3}{2}[/tex]
Step-by-step explanation:
Hi there!
We are given the points (0, 4) and (6, 13)
We want to find the slope of the line containing these two points
Slope (m) is the steepness of the line. When calculating from two points, you use the equation [tex]\frac{y_2-y_1}{x_2-x_1}[/tex], where [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] are points
Although we have what we need to find the slope, let's label the values of the points to avoid confusion and mistakes.
[tex]x_1=0\\y_1=4\\x_2=6\\y_2=13[/tex]
Substitute these values into the equation
m=[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
m=[tex]\frac{13-4}{6-0}[/tex]
Subtract
m=[tex]\frac{9}{6}[/tex]
Simplify
m=[tex]\frac{3}{2}[/tex]
The slope of the line is 3/2
Hope this helps!
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Given that 6 > –2, which statements are true? Check all that apply. (2)(6) > (–2)(2) StartFraction 6 over 2 EndFraction less-than StartFraction negative 2 over 2 EndFraction (–2)(6) > (–2)(–2) StartFraction 6 over negative 2 EndFraction less-than StartFraction negative 2 over negative 2 EndFraction (2)(6) < (–2)(2) StartFraction 6 over 2 EndFraction less-than StartFraction negative 2 over 2 EndFraction
We get that statements 2 and 3 are correct statements.
We have given that the
6>-2
We have to find the correct statement from the given statement,
What is the meaning of less than inequality?Less than or equal to relation is one of the inequalities used to represent the relation between two non-equal numbers or other mathematical expressions.
1) 6/2<2/-2
3<-1
This is not possible therefore first statement is not correct
2) 6/-2<-2/-2
-6<1
This is the correct statement.
3)
6/2<-2/2
3<-1
This is the correct condition.
Therefore this is a correct statement.
Therefore we get that statements 2 and 3 are a correct statements.
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Answer:
A D F
Step-by-step explanation:
dont waste your time :)
Prove or disprove that the point (√5, 12) is on the circle centered at the origin and containing the point (-13, 0). Show your work.
Using the equation of the circle, it is found that since it reaches an identity, the point (√5, 12) is on the circle.
What is the equation of a circle?
The equation of a circle of center [tex](x_0, y_0)[/tex] and radius r is given by:
[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]
In this problem, the circle is centered at the origin, hence [tex](x_0, y_0) = (0,0)[/tex].
The circle contains the point (-13,0), hence the radius is found as follows:
[tex]x^2 + y^2 = r^2[/tex]
[tex](-13)^2 + 0^2 = t^2[/tex]
[tex]r^2 = 169[/tex]
Hence the equation is:
[tex]x^2 + y^2 = 169[/tex]
Then, we test if point (√5, 12) is on the circle:
[tex]x^2 + y^2 = 169[/tex]
[tex](\sqrt{5})^2 + 12^2 = 169[/tex]
25 + 144 = 169
Which is an identity, hence point (√5, 12) is on the circle.
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CAN SOMEONE HELP ME. PLEASE I NEED NOW. please help me
Answer:
1. Mean is 14.5 Median is 13.5 Mode is 13
2. Mean is 84 Median is 84 Mode is 84
3. Mean is 26.6 Median is 27 Mode is 20
4. Mean is 87 Median is 87 Mode is 87
5. Mean is 14.6 Median is 14 Mode is 14,12
Step-by-step explanation:
Hope this helps!! May not be entirely right but tried to do it quick for you
What is the median of the data
44,13,36,52,19,27,33
Answer:33
Step-by-step explanation:
Find the length of UV.
The table below represents a linear function. What is the slope?
The data in the table shows a sinusoidal relationship between the number of seconds an object has been moving and its velocity v (x), measured in centimeters per second
What is true of the cosine function that models the data in the table?
Drag a value into each box to correctly complete the statements.
The period of the cosine function is The equation of the midline of the cosine function is y = 20 The amplitude of the cosine function is
Answer:
The period is the change in x required for the function to return to the same value, changing in the same direction. The first two table entries are v(x) = 41.7 and 35.7. The next time that sequence appears is when x=44, so the period is ...
period = 44 -4 = 40 . . . seconds
__
The minimum table value is 20; the maximum is 44, so the midline of the function is their average:
midline = (20 +44)/2 = 32
__
The amplitude is the maximum deviation from the midline, so is ...
amplitude = 44 -32 = 12
Step-by-step explanation:
To create a histogram of the data given, identify the frequency for the given intervals. the interval 44-47 has a frequency of . the interval 48-51 has a frequency of . the interval 56-59 has a frequency of .
An interval can be defined as a set of real numbers. The interval (44-47), (48-51), and (56-59) will have frequencies of 3, 4, and 1.
What is Interval?A collection of real numbers between two specified values known as the interval's endpoints is referred to as an interval.
The data set given to us is 42, 43, 46, 47, 47, 48, 49, 50, 51, 53, 55, 55, 59. Therefore, the frequency can be written as,
The interval 44-47 includes {46, 47, 47}, thus, having a frequency of 3.The interval 48-51 includes {48, 49, 50, 51}, thus, having a frequency of 4.The interval 56-59 includes {59}, thus, having a frequency of 1.Thus, the interval (44-47), (48-51), and (56-59) will have frequencies of 3, 4, and 1.
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Answer:
3 4 1
Step-by-step explanation:
I took the assignment and got it right
Flora wants to create a scale drawing of
the Empire State Building on an 8 inch
by 11 inch piece of paper. She wants the
drawing to be as large as possible. Which
shows the scale she should use?
Length- 1,792
With- 195
Answer:
The scale drawing is 1 centimeter to 50 meters ⇒ answer E
Step-By-Step Explanation:
* Lets explain how to solve the problem
- The height of the empire state building is about 1450 feet long and
400 feet wide
- Andre wants to make a scale drawing of the front view of it on an
8 1/2 inches by 11 inches piece of paper
- We need to select one of these scales that we think is the most
appropriate for the scale drawing
A. 1 inch to 1 foot
B. 1 inch to 100 feet
C. 1 inch to 1 mile
D. 1 centimeter to 1 meter
E. 1 centimeter to 50 meters
F. 1 centimeter to 1 kilometer
- For scale A , B , and D the scaled image will not fit the page
- For scale C and F the drawing will be very small because 1 mile
is 5280 feet and 1 kilometer is 3280.84 feet
- E is most appropriate because 1 meter is 3.28084 feet, then the
height of the empire state is 442 m dividing by 50 m gives about
8.8 cm and the height of the paper is 11 inches which is about 28 cm
and the width of the empire state is about 122 m dividing by 50 m
gives about 2.5 cm and the width of the paper is 8 1/2 inches which
is about 22 cm then the drawing will be appropriate for drawing
∴ The scale drawing is 1 centimeter to 50 meters
Line s has an equation of y=1/3-X-5. Line t is perpendicular to line s and passes through (-2, 9). What is the equation of line t?
Write the equation in slope-intercept form. Write the numbers in
the equation as simplified proper fractions, improper fractions, or
integers.
Answer:
y = 3x + 15
Step-by-step explanation:
1. Find the reciprocal of the slope and change signs: -3
2. y = 3x + b
3. Plug in x and y --> b = 15
4. Make your equation using y = mx + b: y = 3x + 15
The equation of the perpendicular line 't' will be equal to y = -3x + 3.
What is an equation of the line?An equation of the line is defined as a linear equation having a degree of one. The equation of the line contains two variables x and y. And the third parameter is the slope of the line which represents the elevation of the line.
The general form of the equation of the line:-
y = mx + c
m = slope
c = y-intercept
Slope = ( y₂ - y₁ ) / ( x₂ - x₁ )
Given that line, s has an equation of y=1/3-X-5. Line t is perpendicular to line 's' and passes through (-2, 9).
The equation of the line will be calculated as,
For the perpendicular line, the slope is reciprocal with a negative sign,
m = -3
The equation of the line will be written as,
y = mx + c
y = -3x + c
9 = ( -3 x - 2) +c
c = 9 - 6
c = 3
The equation is,
y = mx + c
y = -3x + 3
Therefore, the equation of the perpendicular line 't' will be equal to y = -3x + 3.
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Given the formula, find the first five terms and the 10th term of each
sequence.
a n = 8 – 5n
My attempt:
a1 = 8(5)5 =a1 =5
a2=8(5)6-5=10
a3=8(5)7-5=15
a4=8(5)8-5=20
a5=8(5)9-5=25
a10=8(5)10-5=a1050?
[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
Let's calculate the Given terms ~
[tex] \textbf{1st Term :} [/tex]
[tex]\qquad \sf \dashrightarrow \:a_1 = 8 - 5(1)[/tex]
[tex]\qquad \sf \dashrightarrow \:a_1 = 8 - 5[/tex]
[tex]\qquad \sf \dashrightarrow \:a_1 = 3[/tex]
[tex] \textbf{2nd Term :} [/tex]
[tex]\qquad \sf \dashrightarrow \:a_2 = 8 - 5(2)[/tex]
[tex]\qquad \sf \dashrightarrow \:a_2 = 8 - 10[/tex]
[tex]\qquad \sf \dashrightarrow \:a_2 = - 2[/tex]
[tex] \textbf{3rd Term :} [/tex]
[tex]\qquad \sf \dashrightarrow \:a_3 = 8 - 5(3)[/tex]
[tex]\qquad \sf \dashrightarrow \:a_3 = 8 - 15[/tex]
[tex]\qquad \sf \dashrightarrow \:a_3 = - 7[/tex]
[tex] \textbf{4th Term : } [/tex]
[tex]\qquad \sf \dashrightarrow \:a_4 = 8 - 5(4)[/tex]
[tex]\qquad \sf \dashrightarrow \:a_4 = 8 -20[/tex]
[tex]\qquad \sf \dashrightarrow \:a_4 = - 12[/tex]
[tex] \textbf{5th Term :} [/tex]
[tex]\qquad \sf \dashrightarrow \:a_5 = 8 - 5(5)[/tex]
[tex]\qquad \sf \dashrightarrow \:a_5 = 8 - 25[/tex]
[tex]\qquad \sf \dashrightarrow \:a_5 = -17[/tex]
[tex] \textbf{10th Term :} [/tex]
[tex]\qquad \sf \dashrightarrow \:a_{10} = 8 - 5(10)[/tex]
[tex]\qquad \sf \dashrightarrow \:a_{10} = 8 - 50[/tex]
[tex]\qquad \sf \dashrightarrow \:a_{10} = - 42[/tex]
#1
a_1=8-5(1)=8-5=3#2
a_2=8-5(2)=8-10=-2#3
a_3=8-5(3)=8-15=-7#4
a_4=8-5(4)=8-20=-12#5
a_5=8-5(5)=8-25=-17#10
a_10=8-5(10)=8-50=-42