Answer:
Its convergent
Explanation:
There areas where plates move toward each other and collide Also known as compressional pr destructive boundaries.
What magnification is best for the observation of most tissue slides? Explain why this has proved to be true?
Answer:
The 10X objective is use for the identification of actual size of histology tissues and 4X magnification is best for observation of most tissues slides
Explanation:
4X magnification is best for observation of most tissues slides because it has an objective lens that have lower power and have great high field overview which make it very easier to locate specimens on the slide. It is use to get the overview of histology slides. It is use to showcase more detailed observations about histology.
The 40X objective is use majorly to identify tissue , to observe the finer details and study tissue organization on the histology slide.
A
6N
11 N
What is the net force ?
Answer:
66n
Explanation:
4376
We eat pizza from the inside out???
Answer:
what
Explanation:
what I dont get it??
Answer:
that makes me confused I don't think of pizza the same again LOL
Explain period motion of oscillatory body.
Answer:
motion repeating itself is referred to as periodic or oscillatory motion. An object in such motion oscillates about an equilibrium position due to a restoring force or torque. ... This motion is important to study many phenomena including electromagnetic waves, alternating current circuits, and molecules.
Explanation:
Answer:
Moves to and from about it's mean position in a fixed time interval.
Without a battery , why would a circuit not work
Answer:
The cell will have no electromotive force in it.
Explanation:
The battery provides the chemical energy that produces the force needed to move electron around the circuit and to generate electrical energy.
electrochemical cells are devices in which chemical reactions produce electric current. The electromotive force inherent in a cell provides the driving force for the current to flow. Without this force, there would not be enough energy to move the electrons.Cheetah mothers perform a number of different behaviors. They and their cubs stay in one place for only four days, moving on before they leave too strong a smell behind in one area. They also expend time and energy teaching their cubs to hunt successfully. In one or two sentences, explain how these behaviors affect cheetah reproductive success.(2 points)
Answer:
Cheetah cubs are in danger from predators like lions and hyenas which can track their prey by scent and so the mother and her cubs leave an area when their scent is too strong so that they are not hunted and the cubs survive.
Mother Cheetahs also train their cubs to hunt so that they may get food for themselves which will ensure their survival as well thus showing that both of these practices can impact on reproductive success.
when an objects motion is not changing , the object is moving at a ___
I got this information for a lab but I don't know how to do the hypothesis and the conclusion please can you guys help me with it quickly
Answer:
A hypothesis is what you think will happen.
A conclusion is the results of an experiment summarized.
Hope this helps.
HELP HURRY MULTIPLE CHOICE 100 POINTS!!!!!!!!
Answer Yes you answered correctly.
Explanation:
Gases, such as the air or helium inside a balloon, take the shape of the containers they're in. They spread out so that the space is filled up evenly with gas molecules. The gas molecules are not connected.
Answer:
Yea ur right
Explanation:
Two parallel plates, each of area 3.37 cm2, are separated by 5.40 mm. The space between the plates is filled with air. A voltage of 8.55 V is applied between the plates. Calculate the magnitude of the electric field between the plates. Tries 0/20 Calculate the amount of the electric charge stored on each plate. Tries 0/20 Now distilled water is placed between the plates and the capacitor is charged up again to the same voltage as before. Calculate the magnitude of charge stored on each plate in this case. (Use κ = 83.0 for the dielectric constant of water.)
Answer:
1, 1583.33 V/m
2, 4.72*10^-12 C
3, 39.2*10^-11 C
Explanation:
1
E = V / d
E = 8.55 / 5.4*10^-3
E = 8.55 / 0.0054
E = 1583.33 V/m
2
Capacitance, C = (k * e0 * A) / d, where k = 1
A = area of capacitor, 3.37 cm² = 3.37*10^-4 m²
d = plate separation, 5.4 mm
e0 = Constant, 8.85*10^-12
Applying these, we have
C = (1 * 8.85*10^-12 * 3.37*10^-4) / 5.4*10^-3
C = 29.82*10^-16 / 0.0054
C = 5.52*10^-13 F
Since Q = CV, then
Q = 5.52*10^-13 * 8.55
Q = 4.72*10^-12 C
3
We are given that k = 83, so
Capacitance, C = (k * e0 * A) / d
C = (83 * 8.85*10^-12 * 3.37*10^-4) / 5.4*10^-3
C = 2.475*10^-13 / 0.0054
C = 4.58*10^-11 F
Q = CV
Q = 4.58*10^-11 * 8.55
Q = 39.2*10^-11 C
Which is one property of coal that makes it ideal for use in a power plant?
It burns easily.
It makes ash.
It is renewable.
It contains mercury.
Answer:
It burns easily & It produces a lot of energy
Explanation:
Coal burns easily and thus is ideal for use in a power plant.
• To generate electric power in the United States, the main fuel used is coal.
• It is used as it is burned easily and thus producing enormous amount of energy.
• In the power plants, the lignite, bituminous coal, or subbituminous coal is burned.
• The heat generated by the burning of the coal is used to transform water into high pressure steam that mediates a turbine, which generates electricity.
• About 23 percent of the electricity in the United States is produced by the burning of coal.
Thus, the correct answer is that coal burns easily.
To know more about:
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show that the motion of Bob of simple pendelum is simple harmonic. find it's time period.
Answer:
a) = 11.29°
b) = 1.93 m/s²
Explanation:
θ = θ(m) sin(w(n).t + Φ)
w(n) = 2π / t
w(n) = 6.284 / 1.3
w(n) = 4.834 rad/s
θ• = θ(m).w(n).cos (w(n).t + Φ)
θ•(m) = θ(m).w(n)
v(m) = L.θ•(m)
v(m) = L.θ(m).w(n)
θ(m) = v(m) / L.w(n)
For a simple pendulum,
w(n) = √(g / l)
l = g / w(n)²
l = 9.8 / 4.834²
l = 9.8 / 23.368
l = 0.42 m
Remember, θ(m) = v(m) / l.w(n)
θ(m) = 0.4 / (0.42 * 4.834)
θ(m) = 0.4 / 2.03
θ(m) = 0.197 rad
Converting to °, we have
0.197 * 360 * 1/2π
0.197 rad = 11.29°
Thus, the amplitude of the motion is 11.29°
a(t) = l.θ(t)
Tangential acceleration occurs when θ(t) is maximum, so
θ(t) = -θ(m).w(n)².sin(w(n)t + Φ)
θ(t max) = θ(m).w(n)²
a(t max) = l.θ(m).w(n)²
a(t max) = 0.42 * 0.197 * 4.834²
a(t max) = 1.93 m/s²
Explanation:
Determine the beginning and end of the solar maximum or minimum.
Please help will give brainliest
Answer:
5 billion years ago...ends 4.9 billion years later
Answer:
That's correct... you can mark them brainliest now. You have to have both slots answered before you can mark them. So, you're welcome :)
Explanation:
A man throws a ball straight up to his friend on a balcony who catches it at its highest point. The ball was thrown with an initial velocity of 17.9 m/s2. What height does the ball reach?
Answer:
The maximum height reached by the ball is 16.35 m.
Explanation:
Given;
initial velocity of the ball, u = 17.9 m/s
the final velocity of the ball at the maximum height, v = 0
The maximum height reached by the ball is given by;
v² = u² + 2gh
During upward motion, gravity is negative
v² = u² + 2(-g)h
v² = u² - 2gh
0 = u² - 2gh
2gh = u²
h = u² / 2g
h = (17.9)² / (2 x 9.8)
h = 16.35 m
Ttherefore, the maximum height reached by the ball is 16.35 m.
Answer and i will give you branilest
Answer:
nice cool math and jim jake jr as a baby and just jim jake baby and nice pfp d00d XD
Explanation:
Francesco, a pizza chef preparing the dough for your pizza is throwing it to expand it. In this process, you notice that a chunk of it comes off, flying separately from the rest and on to the floor. If Francesco is 6 feet and 3 inches tall, and the chunk flies off vertically straight up from this height at a speed of 1 m/s, with what speed does the chunk hit the ground?
Answer:
6.12 m/s
Explanation:
In order to solve this we have two parts of this problem, first we have the time that the pizza dough spent going upwards and after that we have a free fall from there, so we will use the free fall formula after we figured out whats the final height the dough reached after being thrown from Francesco's height which is 6ft3inches or 1.90 meters
We first have to find out how much time the dough spent in the air before reaching 0 as final speed and then started the free falling:
The formula would be:
[tex]Vf=Vo-at\\0=1-(-9.81t)\\1=9.81t\\t=\frac{1}{9.81}\\t=.101[/tex]
The formula to find out final height would be:
[tex]y = \frac{ h + Vy (t-gt^{2})}{2} \\[/tex]
Now we just insert the values we know
[tex]y = h+ \frac{ Vy (t-gt^{2})}{2} \\\\y = 1.90 +\frac{ .101-(-9.81)(.101)^{2})}{2} \\\\y=1.91[/tex]
So from 1.91 meteres the free fal started we have to just calculate the final velocity with the formula for free fall and velocity:
[tex](vf)^{2} =Vo^2 +2ad[/tex]
Since Vo is 0 because we are talking about free falling we just insert the values we know:
[tex](vf)^{2} =Vo^2 +2ad\\(vf)^{2} =2ad\\(vf)^{2} =2(9.81)(1.91)\\vf=\sqrt{37.4742} \\Vf=6.12m/s[/tex]
So the final speed that the dough hit the ground with is 6.12 m/s
Question 10 of 25
In recent years, assistive technologies have been developed to give people
with disabilities equal access to resources. Examples include wheelchair
ramps, voice-recognition software, and screen readers. Which statement best
explains how societal demand guided the development of these
technologies?
A. Engineers developed assistive technologies first and then began a
public-awareness campaign to educate people on how the
technologies can be used to provide equal access.
B. Businesses recognized the lack of equality for people with
disabilities and lobbied the government to make laws that required
the implementation of assistive technologies.
C. When new assistive technologies became available, consumers
began to demand their inclusion in all places of business,
D. Engineers developed and improved solutions in response to
consumer demand for equal access for people with disabilities.
Answer:engineers developed and improved solutions in response to consumer demand for equal access for people with disabilities.
Explanation:
Apex
The average speed and kinetic energy of the particles in a gas are proportional to the measured what of the gas
Answer: Temperature
Explanation:
The average kinetic energy of the particles in a gas is proportional to the temperature of the gas. Because the mass of these particles is constant, the particles must move faster as the gas becomes warmer.
What is kinetic energy?
"The kinetic energy of an object is the energy that it possesses due to its motion."
What is average kinetic energy?
"The product of the half of the mass of each gas molecule and the square of RMS speed."
Know more about average kinetic energy here
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the law conservation of____ states that matter can not be created or destroyed on changed from one to another
Answer:
energy
Explanation:
Energy can't be destroyed or created, just transferred.
What are some What are some of the possible advantages of memory being a constructive process?
if you apply force on an object such as a ball, what will possibly happen to it?
what formula do I use?
Explanation:
(a) Given:
Δy = 0 m
v₀ᵧ = 20.0 m/s sin 53° = 16.0 m/s
aᵧ = -9.8 m/s²
Find: t
Use an equation that doesn't include final velocity, v.
Δy = v₀ᵧ t + ½ aᵧt²
0 m = (16.0 m/s) t + ½ (-9.8 m/s²) t²
0 = 16t − 4.9t²
0 = t (16 − 4.9t)
t = 3.26 s
(b) Given:
v₀ₓ = 20.0 m/s cos 53° = 12.0 m/s
aₓ = 0 m/s²
t = 3.26 s
Find: Δx
Use an equation that doesn't include final velocity, v.
Δx = v₀ₓ t + ½ aₓt²
Δx = (12.0 m/s) (3.26 s) + ½ (0 m/s²) (3.26 s)²
Δx = 39.24 m
(c) Given:
v₀ᵧ = 20.0 m/s sin 53° = 16.0 m/s
vᵧ = 0 m/s
aᵧ = -9.8 m/s²
Find: Δy
Use an equation that doesn't include t.
vᵧ² = v₀ᵧ² + 2aᵧ Δy
(0 m/s)² = (16.0 m/s)² + 2 (-9.8 m/s²) Δy
Δy = 13.02 m
Alternatively, use t/2 = 1.63 seconds, and use an equation that doesn't include the final velocity, v.
Δy = v₀ᵧ t + ½ aᵧt²
Δy = (16.0 m/s) (1.63 s) + ½ (-9.8 m/s²) (1.63 s)²
Δy = 13.02 m
Which parts of the warm-up did you find most difficult? Why?
Answer:
Can't really answer that for now. More context please?
Explanation:
I will answer it in a comment when you give some context.
1. An astronaut in a spacesuit has a mass of 80 kilograms. What is the weight of this astronaut on the surface of the Moon where the strength of gravity is approximately 1/6 that of Earth? (2 Points)
Consider the following True/False statements:
6. (0.5 Points) If the spacing between two electronic energy levels in atom A is smaller than in atom B, then the wavelength of the light emitted by atom B will be longer. (True/False)
7. (0.5 Points) If the spacing between two electronic energy levels in atom A is smaller than in atom B, then fewer photons will be emitted by atom B. (True/False)
8. (0.5 Points) Photons are emitted as electrons in the atom jump up in energy. (True/False)
9. (0.5 Points) The colors emitted by an atom does not depend on how much kinetic energy the free electron has when it hits the atom. (True/False)
10. (0.5 Points) When a free electron hits an atom, the atom can be excited to an energy level higher than the KE of the electron. (True/False)
11. (0.5 Points) The kinetic energy of the free electron at the point of collision increases as the voltage of the battery increases. (True/False)
12. (0.5 Points) The kinetic energy of the free electron at the point of collision is higher if the atom is farther from the source of electrons. (True/False)
13. (0.5 Points) The only way to emit infrared (IR) photons is if there are empty electronic energy levels really close to the ground state (lowest energy level). (True/False)
14. (0.5 Points) When atomic electrons are excited to a higher level, they ultimately return to their lowest energy level. (True/False)
Answer:
6) False
7) True
8) False
9) False
10) False
11) True
12) True
13) True
14) True
Explanation:
The spacing between two energy levels in an atom shows the energy difference between them. Clearly, B has a greater value of ∆E compared to A. This implies that the wavelength emitted by B is greater than A while B will emit fewer, more energetic photons.
When atoms jump from lower to higher energy levels, photons are absorbed. The kinetic energy of the incident photon determines the frequency, wavelength and colour of light emitted by the atom.
The energy level to which an atom is excited is determined by the kinetic energy of the incident electron. As the voltage increases, the kinetic energy of the electron increases, the further the atom is from the source of free electrons, the greater the required kinetic energy of free electron. When electrons are excited to higher energy levels, they must return to ground state.
During an experiment, your teacher dropped a tennis ball out the window. The ball hits the ground 3.0 second
later. What was the ball's final velocity just before it hit the ground?
Answer:
29.4m/s
Explanation:
Given.
Time (t) = 3.0s
Required
Determine the final velocity
Since, it's a vertical motion, we make use of the following formula to solve for the final velocity (v).
v = u + gt
Where u = 0, g = 9.8m/s² and t = 3s
v = 0 + 9.8m/s² *3s
v = 0 + 29.4m/s
v = 29.4m/s
Hence, the final velocity is 29.4m/s
I WILL MARK YOU AS BRAINLIEST IF RIGHT
You fall off the top of the Sears Tower and begin accelerating 9.8 m/s^2 toward the ground. If you fall for 10 seconds, how fast will you be going when you hit the ground ?
Answer:
Falling from the Sears Tower
• After 5 seconds, the ball falling from the
Sears Tower will have fallen
distance = ½ • 32 ft/s2 • (5 s)2 = 16 • 25
= 400 feet.
• We can turn the formula around to figure
out how long it would take the ball to fall all
the way to the ground (1450 ft)
Ætime = square root of (2 x distance/g)
Explanation:
PICTURE ABOVE !
What could the mother do to make sure each of her kids follows her "cookie rule"?
Answer:
she should ve the one handing out the cookies each day, to make sure each child gets only one cookie a day.
2. A carpenter tosses a shingle off a 9.4 m high roof, giving it an initial horizontal
velocity of 7.2 m/s.
(a) What is the final vertical velocity of the ball?
(b) How long does it take to reach the ground?
(c) How far does it move horizontally in this time?
Sounds like the shingle/ball is thrown from the roof horizontally, so that the distance it travels x after time t horizontally is
x = (7.2 m/s) t
The object's height y at time t is
y = 9.4 m - 1/2 gt²
where g = 9.80 m/s² is the magnitude of the acceleration due to gravity, and its vertical velocity is
v = -gt
(a) The object hits the ground when y = 0:
0 = 9.4 m - 1/2 gt²
t² = 2 * (9.4 m) / (9.80 m/s²)
t ≈ 1.92 s
at which time the object's vertical velocity is
v = -g (1.92 s) = -18.8 m/s ≈ -19 m/s
(b) See part (a); it takes the object about 1.9 s to reach the ground.
(c) The object travels a horizontal distance of
x = (7.2 m/s) * (1.92 s) ≈ 13.8 m ≈ 14 m
Determine the ratio β = v/c for each of the following.
(a) A car traveling 120 km/h.
(b) A commercial jet airliner traveling 270 m/s.
(c) A supersonic airplane traveling mach 2.7. (Mach number = v/vsound. Assume the speed of sound is 343 m/s.)
(d) The space shuttle, traveling 27,000 km/h.
(e) An electron traveling 30 cm in 2 ns.
(f) A proton traveling across a nucleus (10-14 m) in 0.38 ✕ 10-22 s.
Answer:
a) [tex]\beta = 1.111\times 10^{-7}[/tex], b) [tex]\beta = 9\times 10^{-7}[/tex], c) [tex]\beta = 3.087\times 10^{-6}[/tex], d) [tex]\beta = 2.5\times 10^{-5}[/tex], e) [tex]\beta = 0.5[/tex], f) [tex]\beta = 0.877[/tex]
Explanation:
From relativist physics we know that [tex]c[/tex] is the symbol for the speed of light, which equal to approximately 300000 kilometers per second. (300000000 meters per second).
a) A car traveling 120 kilometers per hour:
At first we convert the car speed into meters per second:
[tex]v = \left(120\,\frac{km}{h} \right)\times \left(1000\,\frac{m}{km} \right)\times \left(\frac{1}{3600}\,\frac{h}{s} \right)[/tex]
[tex]v = 33.333\,\frac{m}{s}[/tex]
The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 33.333\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])
[tex]\beta = \frac{33.333\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]
[tex]\beta = 1.111\times 10^{-7}[/tex]
b) A commercial jet airliner traveling 270 meters per second:
The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 270\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])
[tex]\beta = \frac{270\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]
[tex]\beta = 9\times 10^{-7}[/tex]
c) A supersonic airplane traveling Mach 2.7:
At first we get the speed of the supersonic airplane from Mach's formula:
[tex]v = Ma\cdot v_{s}[/tex]
Where:
[tex]Ma[/tex] - Mach number, dimensionless.
[tex]v_{s}[/tex] - Speed of sound in air, measured in meters per second.
If we know that [tex]Ma = 2.7[/tex] and [tex]v_{s} = 343\,\frac{m}{s}[/tex], then the speed of the supersonic airplane is:
[tex]v = 2.7\cdot \left(343\,\frac{m}{s} \right)[/tex]
[tex]v = 926.1\,\frac{m}{s}[/tex]
The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 926.1\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])
[tex]\beta = \frac{926.1\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]
[tex]\beta = 3.087\times 10^{-6}[/tex]
d) The space shuttle, travelling 27000 kilometers per hour:
At first we convert the space shuttle speed into meters per second:
[tex]v = \left(27000\,\frac{km}{h} \right)\times \left(1000\,\frac{m}{km} \right)\times \left(\frac{1}{3600}\,\frac{h}{s} \right)[/tex]
[tex]v = 7500\,\frac{m}{s}[/tex]
The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 7500\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])
[tex]\beta = \frac{7500\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]
[tex]\beta = 2.5\times 10^{-5}[/tex]
e) An electron traveling 30 centimeters in 2 nanoseconds:
If we assume that electron travels at constant velocity, then speed is obtained as follows:
[tex]v = \frac{d}{t}[/tex]
Where:
[tex]v[/tex] - Speed, measured in meters per second.
[tex]d[/tex] - Travelled distance, measured in meters.
[tex]t[/tex] - Time, measured in seconds.
If we know that [tex]d = 0.3\,m[/tex] and [tex]t = 2\times 10^{-9}\,s[/tex], then speed of the electron is:
[tex]v = \frac{0.3\,m}{2\times 10^{-9}\,s}[/tex]
[tex]v = 1.50\times 10^{8}\,\frac{m}{s}[/tex]
The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 1.5\times 10^{8}\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])
[tex]\beta = \frac{1.5\times 10^{8}\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]
[tex]\beta = 0.5[/tex]
f) A proton traveling across a nucleus (10⁻¹⁴ meters) in 0.38 × 10⁻²² seconds:
If we assume that proton travels at constant velocity, then speed is obtained as follows:
[tex]v = \frac{d}{t}[/tex]
Where:
[tex]v[/tex] - Speed, measured in meters per second.
[tex]d[/tex] - Travelled distance, measured in meters.
[tex]t[/tex] - Time, measured in seconds.
If we know that [tex]d = 10^{-14}\,m[/tex] and [tex]t = 0.38\times 10^{-22}\,s[/tex], then speed of the electron is:
[tex]v = \frac{10^{-14}\,m}{0.38\times 10^{-22}\,s}[/tex]
[tex]v = 2.632\times 10^{8}\,\frac{m}{s}[/tex]
The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 2.632\times 10^{8}\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])
[tex]\beta = \frac{2.632\times 10^{8}\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]
[tex]\beta = 0.877[/tex]