The work required to raise a 25.0 kg object from the surface of the earth to a height of 3.33 m
Formula: F = 25.0, D = 3.33, and W =?
W = F x D
Putting values together equals 25.0 x 3.33 W = 83.25 j.
Work = force times distance, or W = Fd.
F = W/d for force
Distance: W/F = d
W = work, F = force, and D = distance.
The integral of such a force applied over a displacement distance is referred to as "work." When one engages in work, they are doing something that requires them to use their strength or force.
When energy is transferred to an item, it is considered to have undergone work in science.
The integral of such a force applied over a displacement distance is referred to as work. When one engages in work, they are doing something that requires them to use their strength or force.
When energy is transferred to an item, it is considered to have undergone work in science.
The physics formula for work
The physics equation or formula is:
W = Fd
Work (force times distance)
For force, F = W/d.
Distance: W/F = d
The scalar dot product of force and displacement also yields work.
FDCos = W
Work-related SI unit :
Joule is the SI unit of work (J). The work performed by a force of one newton operating over a distance of one meter is defined as one joule in this context. kgm2s-2 is the SI base unit of work.
Work can be defined as the quantity of energy that a force transfers. Calculate work Another name for physics is the joule calculator. Work is represented by the letter "W."
Work is defined as a motion that is caused by a resisting force and is quantified by the force's product into the motion component that is resolved in the force's direction. The size of it is ML2T-2.
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light travels 300000 km/s,is it velocity or speed
Answer:
speed
Explanation:
Answer:
Velocity
Explanation:
Velocity is km/s
If you pushed against the 3000 kg truck with a force of 1000 N for 5 s, how fast would the truck be moving?
Answer:
V = 1.67 m/s
Explanation:
Given the following data;
Force = 1000 N
Mass = 3000 kg
Time = 5 seconds
To find the speed of the truck;
First of all, we would find the acceleration
Force = mass * acceleration
1000 = 3000 * acceleration
Acceleration = 1000/3000
Acceleration = 0.333 m/s²
Using the first equation of motion, we would determine the speed;
V = u + at
Initial velocity is equal to zero because the truck starts from rest.
V = 0 + 0.333*5
V = 1.67 m/s
PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST THIS IS A SCIENCE QUESTION
Fusion reactions in the sun change nuclear energy into
mechanical energy
chemical energy
electromagnetic energy
potential energy
Answer:
Electromagnetic energy
Which of the following is NOT considered crucial for life to exist on some world?
A. Liquid water
B. At atmosphere
C. Source of nutrients
D. Source of energy that can be used by life
Answer
Atmosphere is not required in some world
A ramp is 12 meters long and I need to use it to raise up a box 4 meters. The box weighs 200 newtons. How much force are you going to need to exert to get the box up the ramp
The force required to raise the box up the ramp when the ramp is 12 meters long, the box is 4 meters and the box weighs 200 newtons is 653.33 N (7840/12)
How do you determine the force required to raise the box up the ramp?To determine the force required to raise the box up the ramp, we can use the work-energy principle.
Work = Change in PE
W = PEf - PEi
where
W = work done (Joules)
PEf = final gravitational potential energy (Joules)
PEi = initial gravitational potential energy (Joules)
The gravitational potential energy of an object is given by the formula:
PE = mgh
where
m = mass of the object (200 N)
g = acceleration due to gravity (9.8 m/s^2)
h = height (4 meters)
We can find the change in potential energy as follows:
PEf = mgh = 200 x 9.8 x 4 = 7840 J
PEi = mgh = 200 x 9.8 x 0 = 0 J
So, the change in potential energy is 7840 J.
Now we can calculate the work done as:
W = PEf - PEi = 7840 - 0 = 7840 J
The work done is equal to the force exerted on the object multiplied by the distance it is moved:
W = F x d
7840 = F x 12
So, the force required to raise the box up the ramp is 653.33 N (7840/12)
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The upper and lower fixed points of a mercury thermometer corresponds to 9.00mV and 16.50mV on the thermocouple thermometer. The temperature of a warm iron giving a reading of 11.21mV to the nearest whole number is.
To find the temperature of the warm iron, we first need to convert the reading on the thermocouple thermometer to a temperature value. To do this, we will use the formula:
Temperature = (Reading - Lower Fixed Point) / (Upper Fixed Point - Lower Fixed Point) * (Upper Temperature - Lower Temperature) + Lower Temperature
In this case, the lower fixed point is 9.00mV and the upper fixed point is 16.50mV. We also know that the lower temperature is 0°C (the freezing point of water) and the upper temperature is 100°C (the boiling point of water). So, we can plug in these values:
Temperature = (11.21mV - 9.00mV) / (16.50mV - 9.00mV) * (100°C - 0°C) + 0°C
Simplifying, we get:
Temperature = (2.21mV / 7.50mV) * 100°C
And further simplifying, we get:
Temperature = 0.2907 x 100°C
So, the temperature of the warm iron is approximately 29.07°C to the nearest whole number.
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Viruses are hard to get rid of
because they spread easily. Which
of the following describes why they
spread easily?
A contain no genetic
material
B. are living organisms
C. cannot reproduce
D. reproduce quickly
The answer is D, they reproduce quickly.
Answer: D. Reproduce quickly
Explanation:
A doesn’t really have much to do with it. B. isn’t true because viruses are not living. C. is also not true because they can, so D.
A car at rest with respect to a building can be in motion with respect to another observer. True/False. Please explain your answer
A cannonball is launched horizontally from the top of a 166 m
cliff with an original speed of 35.9 m/s.
Determine the horizontal displacement (in m) of the cannonball.
The horizontal displacement of the cannonball is 65.75 meter.
What is speed?Speed is characterized as the rate at which an object's position changes in any direction. The distance travelled in relation to the time it took to travel that distance is how speed is defined. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
original speed: u= 35.9 m/s.
acceleration due to gravity: g = 9.8 m/s².
Initial height of the cannonball = 166 m.
Hence, the horizontal displacement of the cannonball = u²/2g
= 35.9²/(2×9.8) meter
= 65.75 meter.
so, the displacement of the cannonball is 65.75 meter.
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A 2.0 kg book is lying on a 0.75-m-high table. You pick it up and place it on a bookshelf 2.3 m above the floor. During this process, your hand does _______ work on the book.
The weight of the book and your lifting power will be the only two forces operating, assuming that air resistance is minimal (gravity).
The book's displacement was x=(2.3-0.75)m=+1.55m.
The book weighs W= m(-g)= 2.0 kg(-10N/kg)= 20 N.
Therefore, the weight's work (energy delivered by the weight) is equal to W.x (-20N).
(+1.55m) = -31 Nm =-31 J.
This outcome, -31J, demonstrates that the weight caused the rising book to lose 31J of kinetic energy, increasing the gravitational potential energy of the book.
You lifted the book, which gave it kinetic energy from the chemical energy stored in your muscles. The weight is thereby decreasing the kinetic energy of the book while the lifting force from you increases it.
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To report the position of an object, first choose a reference point. Then, describe the of the object with respect to the reference point. Next, measure the from the reference point to the object.
We will understand the given concept through an example
The rat serves as your point of reference if you mentioned that the rabbit was to the left of it. You are expressing its position when you specify the distance and direction. The present separation and direction of an object from a reference point is its position.
When something moves with relation to a reference frame, like when a passenger gets off an airline or a lecturer gets up to leave, the object's position changes.the right in relation to a whiteboard. Displacement describes this shift in location.Every location helps you to achieve various location positions.Your position is defined by how you describe your place. The separation in the first illustration is one meter. The reference point helps to locate each and every point.To know more about reference point here
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If an object was traveling horizontally off a cliff at 6 m/s for 3 seconds, how long did it take to
hit the ground?
The time taken by the object to hit the ground is 1.8 seconds.
What do you mean by gravitational force?The attraction that draws two objects together is known as gravitational force, sometimes referred to as gravity. Every mass-containing object pulls on nearby things gravitationally in a sizable way.
The time it takes for an object to hit the ground after being dropped off a cliff can be calculated using the formula:
t = √(2*d/g)
where t is the time, d is the distance fallen, and g is the acceleration due to gravity.
In this case, we don't know the distance fell, but we can use the horizontal velocity and time of travel to find it:
d = v * t
where v is the velocity (6 m/s), and t is time (3 seconds)
d = 6 * 3 = 18 m
Now we can use the distance fallen to calculate the time it takes to hit the ground:
t = √(2*d/g)
g is approximately 9.8 m/s^2
t = √(2*18/9.8) = √ (3.6) = 1.8 seconds
So, it takes 1.8 seconds for the object to hit the ground after traveling horizontally off a cliff at 6 m/s for 3 seconds.
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A 5 kg block is on a frictionless surface. A 15 n force is applied To the the block in a direction parallel to the surface. What is the acceleration of the block?
The acceleration is 3 [tex]m/s^2[/tex] when a block with a mass of 5 kg is pulled with a force of 15 n.
The block will experience a net external force of 15 N due to the frictionless surface it is kept in place on.
The block weighs 5 kg.
F = m × a
There is a net external force (F), mass (m), and acceleration acting on the object in this situation (a).
Using the appropriate values in place of F and m:
15 = 5 × a
15/5 = a
3=a
Taking 5 as a factor, we get 3 = a.
As a result, a 5-kilogram item is drawn over a friction less surface with an acceleration of 15 N is 3 m/s².
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A typical sound wave has a wavelength of 1 meter. The wavelength of green light is about 500 billionths of a meter. Which type of wave will tend to diffract more through a narrow gap that is about 1 centimeter wide? Explain.
Answer: Sound wave diffracts more.
Explanation: Width of gap d is smaller than wavelength λ of the gap.
You can estimate it from equation d sin α = n λ
The constant n is order of diffraction, n = 0,1,2,..
sin α = n λ / d is greater when λ/d is greater.
Sound wave will tend diffract more through a narrow gap that is about 1 centimeter wide.
What is Diffraction?Diffraction is the spreading of waves around obstacles. Diffraction takes place with sound; with electromagnetic radiation, such as light, X-rays, and gamma rays; and with very small moving particles such as atoms, neutrons, and electrons, which show wave like properties.
d sin α = n λ
Width of gap d is smaller than wavelength λ of the gap.
The constant n is order of diffraction, n = 0,1,2,..
sin α = n λ / d
Diffraction is greater when λ/d is greater.
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Una luz (con una longitud de onda de 600 nm y velocidad de la luz de c = 3 × 108 m⁄s), que proviene del aire incide en glicerina con un ángulo de 30°. Después de pasar por la glicerina, entra en diamante, después pasa por cuarzo y por último sale de nuevo al aire. Calcule el ángulo de refracción al pasar el rayo en cada medio, también calcule la velocidad de la luz en cada medio y la longitud de onda en cada medio
Answer:
a) angles 19.8º, 11.9º, 13.8, 20.4
b) speed 3 10⁸ m/s, 2,037 10⁸ m/s, v = 1.24 10⁸ m/s, v = 2.06 10⁸ m/s
c) wavelength 600 nm, 407.3 nm, 248.0 nm, 411.5 nm
Explanation:
For this exercise let's use the law of refraction
n₁ sin θ₁ = n₂ sin θ₂
where subscript 1 is for the middle of the incident ray and subscript 2 for the middle of the refracted ray
the refractive index is related to the speed of the lightning in the middle
n = c / v
When the ray enters a material medium, it is absorbed and re-emitted by the atoms in the medium, the frequency remains constant, it is a resonant system, but as the speed of light changes in the medium, the wavelength must change to keep the equation
in the void
c = λ f
in the material medium
v = λ f
[tex]\frac{c}{\lambda_o} = \frac{c}{\lambda_n}[/tex]
λₙ = [tex]\frac{v}{c} \ \lambda_o[/tex]
λₙ = λ₀ / n
we used these expressions to our case
1) medium incident air n₁ = 1 medium transmitted n₂ = 1.473
sin θ₂= [tex]\frac{n_1}{n_2}[/tex] sin θ₁
sin θ₂ = 1/1,473 sin 30
θ₂ = sin⁻¹ 0.3394
θ₂ = 19.8º
2) medium incident glycerin θ₁ = 19.8, medium transmitted diamond θ₂=2.419
sin θ₂ = 1.473/2.419 sin 19.8
θ₂ = sin⁻¹ 0.2067
θ₂ = 11.9º
3) half incident diamond θ₁ = 11.9º, half transmitted quartz n₂ = 1.458
sin θ₂= 2.419/1.458 sin 11.9
θ₂ = sin⁻¹ 0.3429
θ₂ = 13.8º
4) half incident quartz θ₁ = 13.8, medium transmitted air n₂ = 1
sin θ₂ = 1.458/1 sin 13.8
θ₂ = sin⁻¹ 0.3467
θ₂ = 20,4º
b) we look for the speed of lightning in each medium
air v = c = 3 10⁸ m / s
glycerin v = c / n
v = 3 108 / 1,473
v = 2,037 10⁸ m / s
diamond v = 3 108 / 2.419
v = 1.24 10⁸ m / s
quartz v = 3 108 / 1.458
v = 2.06 10⁸ m / s
c) the wavelength in each medium
air λₙ = λ₀/ n
λₙ = 600/1
λₙ 600 nm
glycerin
λₙ = 600 / 1,473
λₙ = 407.3 nm
Diamond
λₙ = 600 / 2.419
λₙ = 248.0 nm
quartz
λₙ = 600 / 1.458
λₙ = 411.5 nm
Aniyah is driving down 7th street. She drives 150 meters in 25
seconds. Assuming she does not speed up or slow down, what
is her speed in meters per second?
Answer:
6m/s
Explanation:
formula used; S= d/t
the "7th Street"doesn't matter it's just apart of the scenario. The only thing that matters is the distance and time which we have. the speed in seconds is 6. I had the same question on my phsyics quiz lol.
A musical note has a frequency of 512 Hz. If the wavelength of the note is 0.685 m, what is the speed of the sound of that note?
Answer:
350.72 m/s
Explanation:
Formula for velocity of wave is;
v = fλ
Where;
v is speed
f is frequency
λ is wavelength
We are given;
f = 512 Hz
λ = 0.685 m
Thus;
v = 512 × 0.685
v = 350.72 m/s
What is the wavelength of longitudinal wave
A wagon wheel is a ring (hoop) of mass 77.1 kg and radius of 0.630 m. If it has 182 J of rotational KE, what is its angular velocity?
Answer:
3.44
Explanation:
Acellus said it was right. :) Just figure out the inertia first and plug it into the Rotational KE equation.
A car moving with an initial speed v collides with a stationary car that is one- half as massive. After the collision, the first car moves moves in the same direction as before with the speed v/3. a) Find the final speed of the second car b) What type of collision is it (elastic or inelastic)
The final speed of the second car is '2v' and the collision is elastic collision.
What exactly are elastic collisions?The elastic collision is one in which the system does not experience a net loss of kinetic energy as the result of a collision. In elastic collisions, momentum & kinetic energy are both conserved.
v′ = m1v1 + m2v2 /m1+m2
v ′ = m 1 v 1 + m 2 v 2/ m 1 + m 2
in which m1 is mass of body 1, v1 is its initial speed, m2 is mass of body 2, & v2 is the final speed at which the two objects will be moving after colliding.
m1v +0 = mv/3 +m/3v2
v2 = 2v
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A centripetal force of 250 N is exerted on a 2.2 kg discus as it rotates uniformly in a horizontal circle of radius 0.85 m. Calculate the speed of the discus in both m/s and rotations per minute?
Answer:
133m/s
Explanation:
b/c 250÷2.2÷0.85=133
¿Por qué un niño en un carrito parece caer hacía atrás cuando el carrito se le da un súbito empujón hacía delante?
Answer: El tronco ejerce un igual y la fuerza opuesta hacia delante de ti, por la tercera ley de Newton .
Explanation:
What is the reason why a yellow colored object looks white in a dimmed light or low intensity of light?
The reason why a yellow colored object looks white in a dimmed light or low intensity of light the colors wavelength have the colors more farther it means it's getting more dimmed.
The wavelengths of sound waves are similar to the size of objects around you, but the wavelength of light waves are much shorter. As a result, you can hear people talking in a room with an open door even though you can’t see them.
The amount of diffraction or bending of the wave depends on the size of the obstacle the wave encounters. If the size of the obstacle is much larger than the wavelength, very little diffraction occurs. Then there is a shadow behind the object where there are no waves.
As the wavelength increases compared with the size of the obstacle, the amount of diffraction increases. The amount of diffraction is greatest if the wavelength is much larger than the obstacle.
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The centripetal force on object M as it passes
through the rest position is approximately
Since the particle always moves in a circular motion in a direction perpendicular to the radial direction.
The work done by the centripetal force in a circular motion is therefore always zero since the dot product is always zero. A force known as the centripetal force acts on a particle when it is revolving around a specific axis or point. The circular path's center is where this force is directed. The ideal decision is (d) Therefore, the body's weight will be equal to the centripetal force when the angular acceleration reaches the same level as the acceleration caused by gravity. It should be noted that for the centripetal force to equal the weight, there must be a uniform circular motion.
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What is the position of the particle at time t 0?
The position of the particle is zero because the velocity is zero for the particle. The velocity of the particle at t=0 is zero because the particle is in rest position and did not moving at any of the instance or travelling at an uniform speed through out the whole journey or yet did not start from the source point.
Velocity is the rate of change of velocity. At any point on a trajectory, the magnitude of the velocity is given by the rate of change of velocity in both magnitude and direction. Velocity of the body that we can consider is the increasing value of the velocity of any object at a constant rate and that of we can calculate. Hence by the primary information that we have we can formerly consider that the velocity which is acting on the particle at t=0 is zero because the particle is in rest position and did not moving at any of the instance or travelling at an uniform speed through out the whole journey or yet did not start from the source point and the position of the particle is zero because the velocity is zero for the particle.
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The person in the figure below is pulling a heavy load. However, the load is resisting the forward motion. The figure can act as a model for what happens in electrical conductors, cells and batteries, and electrical devices in a circuit.
1. Write a paragraph that explains what you think each circuit component would represent in the model, and why.
2. How does the figure model resistance in a circuit?
The components of an electrical circuit represented by the model are as follows:
the man pulling the load represents the battery or cellthe cord used by the man to pull the load represents the conductors such as wiresthe load pulled by the man represents the resistance.The figure models resistance in a circuit because just as resistance in a circuit opposes the flow of current, the load resists the movement of the man.
What is an electrical circuit?An electrical circuit is a complete path that is provided for the flow of electric current.
Tue components of an electric circuit includes:
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Find the equivalent resistance of this
circuit.
R
R3
420 12
160 12
R₂
320 12
Rea = [?] 52
Answer:
RT = 341.62 Ohms
Explanation:
Given the following data;
R1 = 420 Ohms
R2 = 320 Ohms
R3 = 160 Ohms
To find the equivalent resistance;
From the circuit, we can see that R1 and R2 are connected in parallel;
Mathematically, the total equivalent resistance of resistors connected in parallel is given by the formula;
[tex] RT = \frac {R1*R2}{R1 + R2} [/tex]
Substituting into the formula, we have;
[tex] RT1 = \frac {420*320}{420 + 320} [/tex]
[tex] RT1 = \frac {134400}{740} [/tex]
RT1 = 181.62 Ohms
Next, we resolve the resistors to form a series circuit.
RT = RT1 + R3
RT = 160 + 181.62
RT = 341.62 Ohms
A small cart on a 5.0-m long air track moves with a speed of 0.75 m/s. Bumpers at either end of the track cause the cart to reverse direction and maintain the same speed. Find the period and frequency of this motion.
The frequency of the cart's motion for a distance of 10.0 meters is 0.075 Hz (Hertz), which means the cart completes 0.0775 round trips per second.
1) Period (T):
The period (T) is the time taken for one complete round trip. The cart travels from one end to the other and back in one round trip.
T = (distance/speed)
T = (10.0 / 0.75 )
T = 13.33 seconds
So, the period of the cart's motion for a distance of 10.0 meters is approximately 13.33 seconds.
2) Frequency (f):
The frequency (f) is the number of complete round trips per unit time. It is the reciprocal of the period.
f = 1 / T
f = 1 / 13.33
f = 0.075 Hz
So, the frequency of the cart's motion for a distance of 10.0 meters is approximately 0.075 Hz (Hertz), which means the cart completes approximately 0.0775 round trips per second.
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The process of seafloor spreading
Answer:
Seafloor spreading is a geologic process in which tectonic plates—large slabs of Earth's lithosphere—split apart from each other. ... As tectonic plates slowly move away from each other, heat from the mantle's convection currents makes the crust more plastic and less dense
Explanation:
hope it helps stay safe
Answer:
Magma comes out of the rift valley.
Magma cools to rock and hardens.
Rock is pushed away as new rock is formed at MOR.
Oceanic crust and continental crust meet at the trench.
Oceanic crust bends down under the continental crust.
Gravity pulls rock towards mantle.
Rock melts to mantle.
Explanation:
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What is the magnitude of the passenger's acceleration as she passes through the lowest point in her circular motion
The magnitude of the passenger's acceleration as she passes through the lowest point in her circular motion is the centripetal acceleration.
This is given by the equation a = v^2 / r, where v is the velocity of the passenger and r is the radius of the circle. Therefore, the magnitude of the passenger's acceleration is equal to the square of her velocity divided by the radius of the circle.
For example, if the passenger is travelling at 10 m/s in a circle with a radius of 5 m, then her centripetal acceleration would be 10^2 / 5 = 20 m/s^2.
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